Pdf slides - Daniel Mathews
... Models of the hyperbolic plane Shortest distance between two points? I Between (x, y1 ) and (x, y2 ): a vertical line. I For other points: the hyperbolic line between them is not a straight Euclidean line. I Turns out it’s a circle intersecting the x-axis orthogonally. I So given point p and line l ...
... Models of the hyperbolic plane Shortest distance between two points? I Between (x, y1 ) and (x, y2 ): a vertical line. I For other points: the hyperbolic line between them is not a straight Euclidean line. I Turns out it’s a circle intersecting the x-axis orthogonally. I So given point p and line l ...
List all pairs of congruent angles, and write a proportion that relates
... Write a proportion using the given information. Let x be the actual width of balcony. 1 foot = 12 inches. So, 7 feet = 84 inches. ...
... Write a proportion using the given information. Let x be the actual width of balcony. 1 foot = 12 inches. So, 7 feet = 84 inches. ...
Section 8.2 – The Law of Sines
... For an oblique triangle ABC with opposites of length a, b, and c respectively, sin(A) a ...
... For an oblique triangle ABC with opposites of length a, b, and c respectively, sin(A) a ...
Polygon Angle-Sum Theorem - Mustang-Math
... Classifying Polygons Polygon: Closed plane figure with at least three sides that are segments intersecting only at their endpoints, and no adjacent sides are collinear. ...
... Classifying Polygons Polygon: Closed plane figure with at least three sides that are segments intersecting only at their endpoints, and no adjacent sides are collinear. ...
Practice B Triangle Congruence: CPCTC
... ASA. By CPCTC, FJ is congruent to HJ and GJ is congruent to IJ . So FJI is congruent to GHJ by SSS. But HIJ is also congruent to FIJ by SSS. And so all four triangles are congruent by the Transitive Property of Congruence. By CPCTC and the Segment Addition Postulate, FH is congruent to GI . By C ...
... ASA. By CPCTC, FJ is congruent to HJ and GJ is congruent to IJ . So FJI is congruent to GHJ by SSS. But HIJ is also congruent to FIJ by SSS. And so all four triangles are congruent by the Transitive Property of Congruence. By CPCTC and the Segment Addition Postulate, FH is congruent to GI . By C ...
Name: Ammie Hamilton S
... a. A dilation takes a line not passing through the center of the dilation to a parallel line, and leaves a line passing through the center unchanged. b. The dilation of a line segment is long ...
... a. A dilation takes a line not passing through the center of the dilation to a parallel line, and leaves a line passing through the center unchanged. b. The dilation of a line segment is long ...
Trigonometry notes - Iowa State University
... course of the next year I taught trigonometry two more times and those notes grew into the book that you see before you. My major motivation for creating these notes was to talk about topics not usually covered in trigonometry, but should be. These include such topics as the Pythagorean theorem (Lec ...
... course of the next year I taught trigonometry two more times and those notes grew into the book that you see before you. My major motivation for creating these notes was to talk about topics not usually covered in trigonometry, but should be. These include such topics as the Pythagorean theorem (Lec ...
to view a detailed breakdown. Year 9 Higher
... Construct: -a region bounded by a circle and an intersecting line a given distance from a point and a given distance from a line equal distances from 2 points or 2 line segments regions which may be defined by ‘nearer to’ or ‘greater than’ Find and describe regions satisfying a combination of loci U ...
... Construct: -a region bounded by a circle and an intersecting line a given distance from a point and a given distance from a line equal distances from 2 points or 2 line segments regions which may be defined by ‘nearer to’ or ‘greater than’ Find and describe regions satisfying a combination of loci U ...