Physics 11 Assignment #2
... A cable on an elevator exerts a 6 N upward force. The downward force of gravity on the elevator is 4 N. The elevator could be a. moving upward with constant speed. b. downward with a constant speed. c. moving upward with decreasing speed. d. moving upward with increasing speed. ...
... A cable on an elevator exerts a 6 N upward force. The downward force of gravity on the elevator is 4 N. The elevator could be a. moving upward with constant speed. b. downward with a constant speed. c. moving upward with decreasing speed. d. moving upward with increasing speed. ...
JKeehnLtalk
... • v is the velocity we are looking for. • u = 0.58c = the velocity of the spaceship • v' = -0.69c = the velocity of the rocket in the reference frame of the star cruiser • v = (v' + u) / (1 + v'u/c2) • v = (0.58c - 0.69c) / (1 + (0.58c)(0.69c)/c2) • v = -0.11c/0.5998 = -0.18c • Compared to –0.11c ...
... • v is the velocity we are looking for. • u = 0.58c = the velocity of the spaceship • v' = -0.69c = the velocity of the rocket in the reference frame of the star cruiser • v = (v' + u) / (1 + v'u/c2) • v = (0.58c - 0.69c) / (1 + (0.58c)(0.69c)/c2) • v = -0.11c/0.5998 = -0.18c • Compared to –0.11c ...
Document
... Example: The Twin Paradox. Twin brothers part company when one of the twins launches off in a spaceship for a trip to a star 30 light-years away. The ship traveling at a speed 0.99 c reaches the star, turns around and returns to Earth. Since the spaceship is traveling near c, to the Earth twin the ...
... Example: The Twin Paradox. Twin brothers part company when one of the twins launches off in a spaceship for a trip to a star 30 light-years away. The ship traveling at a speed 0.99 c reaches the star, turns around and returns to Earth. Since the spaceship is traveling near c, to the Earth twin the ...
“thought experiment” regarding time dilation
... train. If an observer sitting in the position M’ in the train did not possess this velocity, then he would remain permanently at M, and the light rays emitted by the flashes of lightning A and B would reach him simultaneously, i.e. they would meet just where he is situated. Now in reality (considere ...
... train. If an observer sitting in the position M’ in the train did not possess this velocity, then he would remain permanently at M, and the light rays emitted by the flashes of lightning A and B would reach him simultaneously, i.e. they would meet just where he is situated. Now in reality (considere ...
Minkowski diagram
The Minkowski diagram, also known as a spacetime diagram, was developed in 1908 by Hermann Minkowski and provides an illustration of the properties of space and time in the special theory of relativity. It allows a quantitative understanding of the corresponding phenomena like time dilation and length contraction without mathematical equations.The term Minkowski diagram is used in both a generic and particular sense. In general, a Minkowski diagram is a graphic depiction of a portion of Minkowski space, often where space has been curtailed to a single dimension. These two-dimensional diagrams portray worldlines as curves in a plane that correspond to motion along the spatial axis. The vertical axis is usually temporal, and the units of measurement are taken such that the light cone at an event consists of the lines of slope plus or minus one through that event.A particular Minkowski diagram illustrates the result of a Lorentz transformation. The horizontal corresponds to the usual notion of simultaneous events, for a stationary observer at the origin. The Lorentz transformation relates two inertial frames of reference, where an observer makes a change of velocity at the event (0, 0). The new time axis of the observer forms an angle α with the previous time axis, with α < π/4. After the Lorentz transformation the new simultaneous events lie on a line inclined by α to the previous line of simultaneity. Whatever the magnitude of α, the line t = x forms the universal bisector.