Question Bank (Class XI - Chemistry)
... The formulae for all reactants and products must be correct. It should be arithmetically balanced, i.e., the number of atoms of each element on both sides of arrow should be equal. ...
... The formulae for all reactants and products must be correct. It should be arithmetically balanced, i.e., the number of atoms of each element on both sides of arrow should be equal. ...
CHAPTER 4 REACTIONS IN AQUEOUS SOLUTIONS
... compounds. In each case oxygen has an oxidation number of −2 (rule 3). These oxidation numbers should then be compared to the range of possible oxidation numbers that each element can have. Molecular oxygen is a powerful oxidizing agent. In SO3 alone, the oxidation number of the element bound to oxy ...
... compounds. In each case oxygen has an oxidation number of −2 (rule 3). These oxidation numbers should then be compared to the range of possible oxidation numbers that each element can have. Molecular oxygen is a powerful oxidizing agent. In SO3 alone, the oxidation number of the element bound to oxy ...
Laboratory Works and Home Tasks in General Chemistry
... 2) the reaction must go directly according to the chemical equation without formation of subproducts; 3) the reaction must occur rather quickly; 4) there must be a method for determination of the end of the reaction, i. e. of the equivalence point fixation. It is obvious that in the titration analy ...
... 2) the reaction must go directly according to the chemical equation without formation of subproducts; 3) the reaction must occur rather quickly; 4) there must be a method for determination of the end of the reaction, i. e. of the equivalence point fixation. It is obvious that in the titration analy ...
Chapter 4 - Chemistry
... Strategy: What happens when ionic compounds dissolve in water? What ions are formed from the dissociation of K3PO4 and Sr(NO3)2? What happens when the cations encounter the anions in solution? Solution: In solution, K3PO4 dissociates into K and PO43 ions and Sr(NO3)2 dissociates into Sr2 and NO3 ...
... Strategy: What happens when ionic compounds dissolve in water? What ions are formed from the dissociation of K3PO4 and Sr(NO3)2? What happens when the cations encounter the anions in solution? Solution: In solution, K3PO4 dissociates into K and PO43 ions and Sr(NO3)2 dissociates into Sr2 and NO3 ...
Quantitative Chemical Analysis
... One of our most pressing problems is the need for sources of energy to replace oil. The chart at the right shows that world production of oil per capita has probably already peaked. Oil will play a decreasing role as an energy source and should be more valuable as a raw material than as a fuel. Ther ...
... One of our most pressing problems is the need for sources of energy to replace oil. The chart at the right shows that world production of oil per capita has probably already peaked. Oil will play a decreasing role as an energy source and should be more valuable as a raw material than as a fuel. Ther ...
SCH3U: Final Exam Review Note: These questions a
... a) pH = 0.1 of HCl b) pH = 2.4 of HCH3CO2 c) pH = 0.014 H2SO4 49. Identify the conjugate acid-base pairs in the following reaction: H3PO4 (aq) + H2O(l) → H2PO4-(aq) + H3O+(aq) 50. Name each acid. a) HBr(aq) b) H3PO2(aq) c) H2SO3(aq) d) HIO3(aq) e) HBrO4(aq) 51. Write the chemical formula of each aci ...
... a) pH = 0.1 of HCl b) pH = 2.4 of HCH3CO2 c) pH = 0.014 H2SO4 49. Identify the conjugate acid-base pairs in the following reaction: H3PO4 (aq) + H2O(l) → H2PO4-(aq) + H3O+(aq) 50. Name each acid. a) HBr(aq) b) H3PO2(aq) c) H2SO3(aq) d) HIO3(aq) e) HBrO4(aq) 51. Write the chemical formula of each aci ...
- Chemistry
... C-N-H bend of an amine C≡N stretch of a nitrile C=O and O-H stretches of a carboxylic acid N-H and C=O stretches of an amide ...
... C-N-H bend of an amine C≡N stretch of a nitrile C=O and O-H stretches of a carboxylic acid N-H and C=O stretches of an amide ...
Infrared - ResearchGate
... the product of a reaction as a known compound. (require access to a file of standard spectra) • At another extreme , different bands observed can be used to deduce the symmetry of the molecule and force constants corresponding to vibrations. • At intermediate levels, deductions may be drawn about th ...
... the product of a reaction as a known compound. (require access to a file of standard spectra) • At another extreme , different bands observed can be used to deduce the symmetry of the molecule and force constants corresponding to vibrations. • At intermediate levels, deductions may be drawn about th ...
irm_ch17
... 17.49 Since the tertiary amine (ethylmethylpropylamine) has three different alkyl groups, the secondary amine used to prepare it would have two of these alkyl groups and the alkyl halide would contain the third. The three possible combinations are: ethylmethylamine and propyl chloride, ethylpropylam ...
... 17.49 Since the tertiary amine (ethylmethylpropylamine) has three different alkyl groups, the secondary amine used to prepare it would have two of these alkyl groups and the alkyl halide would contain the third. The three possible combinations are: ethylmethylamine and propyl chloride, ethylpropylam ...
for the exam on 14 feb
... You’re only halfway to the second equivalence point, here. But when you’re halfway there, you’re at the half-equivalence point for the second pKa value, meaning [HA] = [A-], and you can say that pH = pKa2. Therefore, pH here = - log Ka2 = 9.62. c. How many mol NaOH in 20.0 mL? 0.0200 L (0.100 mol/L) ...
... You’re only halfway to the second equivalence point, here. But when you’re halfway there, you’re at the half-equivalence point for the second pKa value, meaning [HA] = [A-], and you can say that pH = pKa2. Therefore, pH here = - log Ka2 = 9.62. c. How many mol NaOH in 20.0 mL? 0.0200 L (0.100 mol/L) ...
COMPETITION PTOBLEMS 1
... them such a form that they may be used in practice and further chemical education. Consequently, it was necessary to make some corrections in order to unify the form of the problems. However, they did not concern the contents and language of the problems. Many of the first problems were published se ...
... them such a form that they may be used in practice and further chemical education. Consequently, it was necessary to make some corrections in order to unify the form of the problems. However, they did not concern the contents and language of the problems. Many of the first problems were published se ...
Ryoji Noyori - Nobel Lecture
... intrinsically achiral metal atoms must possess suitable three-dimensional structures and functionality to generate sufficient reactivity and the desired stereoselectivity. Sometimes the properties of achiral ligands are also important. The chiral catalyst can permit kinetically precise discriminatio ...
... intrinsically achiral metal atoms must possess suitable three-dimensional structures and functionality to generate sufficient reactivity and the desired stereoselectivity. Sometimes the properties of achiral ligands are also important. The chiral catalyst can permit kinetically precise discriminatio ...
organic chemistry - carey - problems solutions
... chlorine. When bonded to carbon, hydrogen and lithium bear a partial positive charge, and carbon bears a partial negative charge. Conversely, when chlorine is bonded to carbon, it bears a partial negative charge, and carbon becomes partially positive. In this group of compounds, lithium is the least ...
... chlorine. When bonded to carbon, hydrogen and lithium bear a partial positive charge, and carbon bears a partial negative charge. Conversely, when chlorine is bonded to carbon, it bears a partial negative charge, and carbon becomes partially positive. In this group of compounds, lithium is the least ...
Part 3-ICHO-31-35
... The standard enthalpy of formation of CO2(g) and H2O(l) at 25.00 °C are –393.51 and –285.83 kJ mol-1, respectively. The gas constant, R = 8.314 J K-1 mol-1. (Relative atomic masses : H = 1.0; C = 12.0; O = 16.0) A sample of solid Q that weighs 0.6000 g, is combusted in an excess of oxygen in a bomb ...
... The standard enthalpy of formation of CO2(g) and H2O(l) at 25.00 °C are –393.51 and –285.83 kJ mol-1, respectively. The gas constant, R = 8.314 J K-1 mol-1. (Relative atomic masses : H = 1.0; C = 12.0; O = 16.0) A sample of solid Q that weighs 0.6000 g, is combusted in an excess of oxygen in a bomb ...
CHAPTER 12 | The Chemistry of Solids
... The orbital energy diagram for these metals will be similar to that of zinc in Figure 12.3. 12.27. Collect and Organize We are asked why it might be important to exclude phosphorus contaminants in the manufacture of silicon chips. Analyze The difference between silicon and phosphorus is that phospho ...
... The orbital energy diagram for these metals will be similar to that of zinc in Figure 12.3. 12.27. Collect and Organize We are asked why it might be important to exclude phosphorus contaminants in the manufacture of silicon chips. Analyze The difference between silicon and phosphorus is that phospho ...
SCH3U: Final Exam Review
... 24. Iron reacts with antimony trisulphide in a single replacement reaction. Antimony and iron (II) sulphide are produced. Calculate the mass of iron that is needed to react with 15.6 g of antimony trisulphide. 25. The theoretical yield of a reaction is 62.9 g, but the actual yield is 47.8 g. Calcula ...
... 24. Iron reacts with antimony trisulphide in a single replacement reaction. Antimony and iron (II) sulphide are produced. Calculate the mass of iron that is needed to react with 15.6 g of antimony trisulphide. 25. The theoretical yield of a reaction is 62.9 g, but the actual yield is 47.8 g. Calcula ...
X Science Practice Paper - Brilliant Public School Sitamarhi
... Q 35 (a) Name two edible acids. (b) Classify aqueous solution of carbon dioxide as acid or base. (c)Which acid will produce large number of H + ions and why? (i) aq. solution of acetic acid (ii) aq. solution of hydrochloric acid Marks (3) Q 36 Represent the following by a balanced chemical reaction: ...
... Q 35 (a) Name two edible acids. (b) Classify aqueous solution of carbon dioxide as acid or base. (c)Which acid will produce large number of H + ions and why? (i) aq. solution of acetic acid (ii) aq. solution of hydrochloric acid Marks (3) Q 36 Represent the following by a balanced chemical reaction: ...
SCH3U0FinalExamReview - Savita Pall and Chemistry
... (d) O, O2-, S, S210. Which ion would be larger: (a) Fe2+ or Fe3+, (b) O- or O2-? 11. What two factors are most important in determining the size of an atom? 12. Explain the relative sizes of the atoms within a given group of the periodic table. Illustrate your answer with specific examples. 13. Comp ...
... (d) O, O2-, S, S210. Which ion would be larger: (a) Fe2+ or Fe3+, (b) O- or O2-? 11. What two factors are most important in determining the size of an atom? 12. Explain the relative sizes of the atoms within a given group of the periodic table. Illustrate your answer with specific examples. 13. Comp ...
Workshop materials for Class XII
... Consider this from your perspective, and from the point of view of the people around you. Don’t be modest or shy , be as objective as you can. If you have any difficulty with this write down a list of your personal charecteristics. Some of these will hopefully be strengths. ...
... Consider this from your perspective, and from the point of view of the people around you. Don’t be modest or shy , be as objective as you can. If you have any difficulty with this write down a list of your personal charecteristics. Some of these will hopefully be strengths. ...
IB Chemistry Online SAQ_Ans
... 7 Carbon-60 was first detected as an unusually abundant species in mass spectra recorded on carbon clusters produced by laser vaporization of graphite in a flow of helium gas. The most abundant carbon cluster had a molecular mass of 720. ...
... 7 Carbon-60 was first detected as an unusually abundant species in mass spectra recorded on carbon clusters produced by laser vaporization of graphite in a flow of helium gas. The most abundant carbon cluster had a molecular mass of 720. ...
4134gdisk doc..4134gdisk chapter .. Page501
... kinetics of the slow release of NO in the reduction of R,S,S-trans-[RuCl(NO)(cyclam)]2+ suggest that this complex may have potential as a low-release vasodilator.85 The oxidation of cis- and trans-[OsIII(terpy)Cl2(NH3)](PF6) gives [OsVI(terpy)Cl2(N)]+, and oxidation of [Os(terpy)(bpy)(NH3)](PF6)2 gi ...
... kinetics of the slow release of NO in the reduction of R,S,S-trans-[RuCl(NO)(cyclam)]2+ suggest that this complex may have potential as a low-release vasodilator.85 The oxidation of cis- and trans-[OsIII(terpy)Cl2(NH3)](PF6) gives [OsVI(terpy)Cl2(N)]+, and oxidation of [Os(terpy)(bpy)(NH3)](PF6)2 gi ...
Nucleophilic acyl substitution
Nucleophilic acyl substitution describe a class of substitution reactions involving nucleophiles and acyl compounds. In this type of reaction, a nucleophile – such as an alcohol, amine, or enolate – displaces the leaving group of an acyl derivative – such as an acid halide, anhydride, or ester. The resulting product is a carbonyl-containing compound in which the nucleophile has taken the place of the leaving group present in the original acyl derivative. Because acyl derivatives react with a wide variety of nucleophiles, and because the product can depend on the particular type of acyl derivative and nucleophile involved, nucleophilic acyl substitution reactions can be used to synthesize a variety of different products.