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SAMPLE PROBLEM--MEAN MILES-PER-GALLON OF TWO AUTOMOBILES 1. Use spreadsheet << T12MEANS >> to conduct estimation and hypothesis testing on the population mean miles-per-gallon of two different automobiles. Each car was fitted with an automatic miles-per-gallon computing device, and was driven by the same driver over the same 40-mile route. Car X Car Y 27.3, 25.5, 29.6, 32.3, 25.9, 24.1, 22.9, 24.6, 23.2, 20.0, 24.3 28.6, 26.3, 25.3, 24.8, 25.9, 22.5, 32.4, 24.6, 24.3 a. The sample size is: Car X: 11 Car Y: 9 b. The sample mean is: Car X: 25.4273 Car Y: 26.0778 c. The estimated population standard deviation is: Car X: 3.36009 Car Y: 2.88954 d. The point estimate of the population mean is: Car X: 25.4273 Car Y: 26.0778 e. The sampling standard deviation (standard error) of the sample means is: Car X: 1.01310 Car Y: 0.963180 f. The 95% confidence interval for the population mean is: (use point estimate ± error factor format, not LCL and UCL) Car X: μx = 25.42733 ± 2.25734 Car Y: μy = 26.0778 ± 2.22110 Test the H0 that each population mean is 27.00 m.p.g. against the Ha that it is not 27.00. g. State the H0: Car X: μx = 27.00 Car Y: μy = 27.00 h. State the Ha: Car X: μx ≠ 27.00 Car Y: μy ≠ 27.00 i. Use α = 0.05. State the tt, table-t, or critical value: Car X: tt = ± 2.228 Car Y: tt = ± 2.306 j. The tc, calculated-t or test statistic is: Car X: tc = - 1.55238 Car Y: tc = - 0.957476 k. The hypothesis-test conclusion is: Car X: H0 is not rejected.* Car Y: H0 is not rejected.** * The difference between the sample mean, 25.43, and the null hypothesis, 27.00, is not statistically significant at the 0.05 level. The population mean could be 27.00. ** The difference between the sample mean, 26.08, and the null hypothesis, 27.00, is not statistically significant at the 0.05 level. The population mean could be 27.00. l. What is the p-value in this test? Car X: 0.151619 Car Y: 0.366364 2. Using the same data, conduct estimation and hypothesis testing on the difference between population mean miles-per-gallon of car X and car Y. a.The point estimate of the difference between population means is: - 0.650505 b. The sampling standard deviation (standard error) of the differences between sample means is: 1.42014 c. The 95% confidence interval for the difference between population means is (use point estimate ± error factor format, not LCL and UCL) (μ1 - μ2) = - 0.650505 ± 2.98361 Test the H0 that the population means are equal against the Ha that they are not equal. d. State the H0: (μ1 - μ2) = 0 e. State the Ha: (μ1 - μ2) ≠ 0 f. Use α = 0.05. State the tt, table-t, or critical value: g. The tc, calculated-t or test statistic is: ± 2.10092 - 0.458056 h. The hypothesis-test conclusion is: H0 is not rejected. * * The difference between the sample means, 0.6505, is not statistically significant at the 0.05 level. The population means could be equal. i. What is the p-value in this test? 0.652394