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Int. Alg. Notes Section 8.1 Page 1 of 5 Sections 8.1: Solving Quadratic Equations by Completing the Square Big Idea: Quadratic equations that can’t be factored can still be solved by converting the quadratic equation to the square of a binomial equals a constant, and then taking the square root of both sides. Big Skill: You should be able to solve any quadratic equation by completing the square. The Square Root Property If x 2 p then x p or x p . To Solve a Quadratic Equation Containing Only a Square and Constant Term: Isolate the square term. Use the square root property. Comparison Example: Solve x 2 16 0 using factoring. x 2 16 0 x 4 x 4 0 x 4 0 OR x40 x4 OR x 4 Solve x 2 16 0 using the square root property. x 2 16 0 x 2 16 x 16 OR x 16 x4 x 4 OR Note: Instead of writing x 16 OR x 16 , mathematicians use the shorthand “plus-minus” notation of x 16 . x 4 Algebra is: the study of how to perform multi-step arithmetic calculations more efficiently, and the study of how to find the correct number to put into a multi-step calculation to get a desired answer. Int. Alg. Notes Section 8.1 Page 2 of 5 Another Example: Note that the square term can be the square of a quantity. y 3 100 0 2 y 3 100 2 y 3 100 OR y 3 100 y 3 10 OR y 3 10 y7 OR y 13 Here is how to write the solution using “plus-minus” notation: y 3 2 100 y 3 2 100 y 3 10 y 3 10 y 3 10 OR y 3 10 y7 y 13 OR Practice: Solve the following quadratic equations: 1. z 2 24 0 2. 7r 2 112 Algebra is: the study of how to perform multi-step arithmetic calculations more efficiently, and the study of how to find the correct number to put into a multi-step calculation to get a desired answer. Int. Alg. Notes Section 8.1 Page 3 of 5 3. z 2 16 4 4. x 3 5. a 2 2 2 16 12 0 The last complication in solving quadratic equations occurs when the quadratic equation has a linear term and is prime (i.e., it can’t be factored), like x 2 2 x 1 0 . Algebra is: the study of how to perform multi-step arithmetic calculations more efficiently, and the study of how to find the correct number to put into a multi-step calculation to get a desired answer. Int. Alg. Notes Section 8.1 Page 4 of 5 In cases like this, we manipulate the equation so that it becomes the square of a binomial plus a constant, like in practice problems #4 and #5. This manipulation involves taking the first two terms, and finding out what we have to add to them to make a perfect square trinomial, which can be replaced with the square of a binomial. So, for x 2 2 x 1 0 , the first two terms are identical to the first two terms of the perfect square trinomial 2 x 2 2 x 1 , which comes from the square of the binomial x + 1: x 1 x 2 2 x 1 . So, here is what we do: x2 2x 1 0 x2 2x 1 x2 2x 1 1 1 x 1 2 2 x 1 2 2 x 1 2 x 1 2 x 1 2 OR x 1 2 x 0.414 OR x 2.414 To Solve a Quadratic Equation by Completing the Square : (i.e, writing a quadratic trinomial as a perfect square trinomial plus a constant) Get the constant term on the right hand side of the equation. i.e., if x 2 bx c 0 , then write the equation as x 2 bx c Make sure the coefficient of the square term is 1. Identify the coefficient of the linear term; multiply it by ½ and square the result. 2 1 i.e., Find the number b in x bx c and compute b 2 Add that number to both sides of the equation. 1 1 i.e., x bx b c b 2 2 Write the resulting perfect square trinomial as the square of the binomial . 1 1 i.e., x b c b 2 2 Use the square root property to solve the equation. 2 2 2 2 2 2 Algebra is: the study of how to perform multi-step arithmetic calculations more efficiently, and the study of how to find the correct number to put into a multi-step calculation to get a desired answer. Int. Alg. Notes Section 8.1 Page 5 of 5 Practice: Solve the following quadratic equations: 6. n 2 10n 6 0 7. x 2 16 x 7 0 8. z 2 7 z 1 0 9. 3 x 2 6 x 5 0 Algebra is: the study of how to perform multi-step arithmetic calculations more efficiently, and the study of how to find the correct number to put into a multi-step calculation to get a desired answer.