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Probability and Statistics EQT 272
Semester 2
2012/2013
TUTORIAL 2
1) Determine whether the following random variables are discrete or continuous.
i. The number of eggs that a hen lays in a day.
ii. The amount of milk a cow produces in one day.
iii. The cost of making a randomly selected movie.
iv. The number of goals scored by a randomly selected football player in a soccer
tournament.
2) Determine the value c so that the following function is a probability function for a
discrete random variable.
f ( x) c(
x2 5
) for x 0,1,2,3,4
2 2
ans: 2/55
3) A box contains three marbles (one blue, one red and one yellow). Two marbles are
drawn with replacement. This means a marbles is selected, its colour is observed and
then it is replaced in the box. A second marble is then selected and its colour is
observed. Let B denotes “blue” , R denotes “red” and Y denotes “yellow”.
i. List the possible outcomes (the elements in the sample space S)
ans: S = {BB, BR, BY, RB, RR, RY, YB, YR, YY}
ii. Let X be a random variable giving the number of “yellow” marbles. List the outcomes
for the random variable X.
ans: X={0, 1, 2, 3}
iii. Find the probability for each value of X.
ans: 4/9, 4/9, 1/9
4) A factory manufactures DVDs. Batches of DVDs are randomly selected. The number
of defects (X) for each batch is observed and the following distribution is obtained.
X
0
1
2
3
4
5
P(X=x)
0.502
0.365
0.098
0.023
0.011
0.001
i. Verify whether this distribution is a probability distribution.
ii. Find P(X ≥ 2)
ans: 0.133
iii. Find P(0<X<4)
ans: 0.486
Probability and Statistics EQT 272
Semester 2
2012/2013
5) Let the probability density function of a random variable Y be
y,
f ( y ) 2 y,
0
0 y 1
1 y 2
otherwise
i. Find F(Y)
ii. Find P(0.5≤Y≤0.9)
ans: 0.28
iii. Find P(0.75≤Y≤1.5)
ans: 0.594
6) Suppose X is a random variable with the following distribution function.
0,
x3
3
F ( x)
(4 x 2 ),
3
256
1,
x0
0 x8
x8
i. Find P(-1≤ X ≤ 2)
ans: 0.156
ii. Find f (x)
7) Let Y be a continuous random variable with the following probability density
function.
y,
f ( y ) 2 y ,
0,
0 y 1
1 y 2
otherwise
Calculate
i. E(Y)
ans: 1
ii.
Var (Y)
ans: 1/6
iii. Y
ans: 0.408