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TRIGONOMETRIC FUNCTIONS Paper 1 1. Solve the equation 15 sin 2 x = sin x + 4 sin 30 for 0 x 360 [4 marks] Answer: .......................... 2. Solve the equation cos x + sin 55 = 0 for 0 x 360 . [3 marks] Answer: .......................... 3. Given tan x = 12 dan 90 x 360 . Find the value of sin x. 5 [3 marks] Answer: .......................... 1 4. Given sin x = 2 cos x, find the values of x for 0 x 360 . [3 marks] Answer: .......................... 5. Given 5 cot x = 2, find the values of x for 0 x 360 [3 marks] Answer: .......................... 6. Given tan x = t, 0 x 90 , express, in terms of t: (a) cot x (b) sin ( 90 – x) [3 marks] Answer: (a).......................... (b).......................... 2 7. Solve the equation 6 sek 2 x – 13 tan x = 0, for 0 x 360 [3 marks] Answer: .......................... 8. Solve the equation 3 cos 2x = 8 sin x – 5 for 0 x 360 9. Solve the equation cos x – sin x = sin x for 0 x 360 2 2 [4 marks] Answer: .......................... [4 marks] Answer: .......................... 3 PAPER 2 10. Sketch the graph of y = cos 2x for 0 x 2 . [3 marks] 11. Sketch the graph of y = – 2sin x for 0 x 180 . [3 marks] 12. Sketch the graph of y = 1 + sin x for 0 x 360 [3 marks] 13. Sketch the graph of y = sin 2 x for 0 x 360 . [3 marks] 3 x for 0 x 2 . [3 marks] 2 (b) Find the equation of a suitable straight line for solving the equation 3 3 x –1. cos x = 2 4 Hence, using the same axes, sketch the straight line and state the number of 3 3 x –1 for 0 x 2 solutions to the equation cos x = [3 marks] 2 4 14. (a) Sketch the graph of y = 2 cos 15. (a) Sketch the graph of y = –2 cos x for 0 x 2 . [4 marks] (b) Hence, using the same axes, sketch a suitable graph to find the number of solutions to the equation + 2 cos x = 0 for 0 x 2 . State the number of solutions. x [3 marks] 4 TRIGONOMETRIC FUNCTIONS ANSWERS 1. 23 35 ' , 156 25 ' ,199 268, 340 32 ' 2. 145 , 215 3. – 4. 63.4 , 243.4 or 63 26 ' , 243 26 ' 5. 68.2 , 248.2 6. (a) 7. 33.69 , 56.31 , 213.69 , 236.31 or 33 41 ' , 56 19 ' , 213 41 ' , 236 19 ' 8. 41.81 , 138.19 9. 30 , 150 , 270 12 13 1 t (b) 1 t 1 2 10. y 1 2 x -1 11. y 2 o 90 180 x -2 5 12. y 2 1 o 180 90 270 360 x 13. y 1 o 90 270 180 360 x -1 14. y 2 0 2 x -2 3 x –2 2 Number of solutions = 3 y= 15 y 2 0 /2 3/2 2 x -2 Number of solutions = 2 6