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Problem-solving guidelines: Understanding the problem Developing a plan and strategy Carrying out the plan Checking the answer Problem-Solving Strategies: Guessing and checking Drawing a table/diagram Writing an equation Simplifying the problem Looking for patterns Using logical reasoning EXAMPLE 1 Drawing a Diagram Silage, fodder preserved and stored by farmers to provide nutritious feedstuff for livestock in the winter. The large, round, brick or metal storage container commonly found on farms in the U.S. is known as a silo. Originally, corn, sorghum, and sunflower were staple silage crops in the U.S., but these have been replaced by the more protein-rich alfalfa. A silo shown below has been built from metal. The top part of the silo is a cylinder with a diameter of 4 m and the height of 8 m. The bottom part of the silo is a cone of slant height of 3 m. The silo has a circular opening of a radius of 30 cm on the top. (Look at the diagram below) a. What area of metal (to the nearest m2) which is needed to build the silo? b. If it costs Rp 25,000.00 per m2 to cover the surface with an anti-rust material, how much will it cost to cover the silo completely? Mathematics for Junior High School Grade 9 / 67 Solution: 1. Understanding the problem a. What is the unknown? The area of the metal and its cost to cover the surface b. What are the data? A cylinder with a diameter of 4 m and height of 8 m. The bottom part of the silo is a cone with a slant height of 3 m. The silo has a circular opening with a radius of 30 cm on the top. It costs Rp 25,000.00 per m2 to cover the surface with an anti-rust material 2. Developing a plan and strategy a. Find the surface area of the top face. b. Find the area of the curved surface of the cylinder. c. Find the area of the curved surface of a cone. d. Find the area of the silo by adding the area of the top face, the curved surface of the cylinder and the curved surface of a cone. e. The total cost can be obtained by multiplying total area by the cost per m2. 3. Carrying out the plan a. The area of the top face = the area of a large circle – the area of a small circle (the opening). = 3.14(22) - 3.14(0.32) = 3.14(4 - 0.09) = 12.28 m2 b. The area of the curved surface of the cylinder = 2(3.14)(2)(8) = 100.48 m2 c. The area of the curved surface of cone = 3.14rs = 3.14 (2)(3) = 18.84 m2 d. The area of the silo = 12.28 m2 + 100.48 m2 + 18.84 m2 = 131.6 m2 e. Total cost = 132 x (Rp 25,000.00) = Rp 3,300,000.00 68 / / Student’s Book – Problem Solving An object is made of a cuboid at the bottom and a hemisphere on the top (see picture below). Find the volume of the object. Give your answer to the nearest tenth. EXAMPLE 2 Solution: 1. Understanding the problem a. What is the unknown? The volume of the cuboid and hemisphere b. What are the data? A cuboid having the edge of 4 cm and the height of 2 cm. The radius of hemisphere is 2 cm. 2. Developing a plan and strategy The object is made up of a cuboid and a hemisphere. Find the volume of the cuboid first, then the volume of the hemisphere. The volume of the object is the total volume of both the cuboid and the hemisphere. 3. Carrying out the plan a. The volume of the cuboid is 4(4)(2) = 32 cm3 b. The volume of the hemisphere is 0.5(4/3)(3.14)(23) = 16.77 cm3 c. The total volume is 32 cm3 + 16.77 cm3 = 48.77 cm3 4. Checking the answer The answer refers to the original question. Recheck the volume of the cuboid and the hemisphere, and the total volume found. Mathematics for Junior High School Grade 9 / 69 Use the strategy drawing diagram and/or writing equation to solve each problem. 1. A right triangle, whose right sides are 15 cm and 20 cm, is revolved with respect to its hypotenuse. Find the volume and the surface area of the double cone object which is formed. 2. A warehouse building is in the form as shown in the figure below. 7m 3m 10 m The building consists of two parts: a cuboid shape and a half cylinder shape. If the radius of the circular cylinder base is 3.5 m and the dimension of the cuboid is 10 m x 7 m x 3 m, find the volume of the building and the inner surface area of the building excluding the floor. 3. A cylinder whose radius of its base is 7 cm and whose height is 10 cm. If another cylinder is made with the radius of its base is doubled, what is the volume of the second cylinder compared to the first one ? (take = 22/7) 4. A sphere is inside a cylinder as given on the figure below. The sphere touches the lateral face, the top, and the base of the cylinder. Show that the area of the lateral face of the cylinder is the same as the surface area of the sphere. 70 / / Student’s Book – Problem Solving 5. A cylinder has a base whose radius is r. It is reduced in such a way that its radius is ½ r. If the initial volume of the cylinder is 480 cm3, find its volume after the reduction. 6. A metal sphere is put into a full-of-water cylinder. The radius of the cylinder is the same as that of the sphere, namely 10 cm, and = 3.14. Find how much water is left in the cylinder after the sphere is put inside. 7. A toy is in the form of a cone mounted on a hemisphere with the same radius. The diameter of the base of the conical part is 6 cm and its height is 4 cm. Determine the surface area of the toy (using = 3.14). 8. A solid is composed from a cylinder and two hemispheres at the ends of the cylinder. If the total length of the solid is 104 cm and the radius of each of the hemisphere is 7 cm, find the cost of polishing the surface of the solid at the rate of Rp 100 per cm2. 9. Find the mass of a 3.5 m long pipe, if the external diameter of the pipe is 2.4 cm, the thickness of the pipe is 2 mm and the mass of 1 cm3 of pipe is 11.4 kg. 10. A solid of toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2 cm and the diameter of the base is 4 cm. If a right circular cylinder circumscribes the solid, find how much more space it will cover. Mathematics for Junior High School Grade 9 / 71