Download Chemistry 160 Th 13 Mar 2008 In-Class Worksheet A. Each of the

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

2-Norbornyl cation wikipedia , lookup

Asymmetric induction wikipedia , lookup

Hydroformylation wikipedia , lookup

Homoaromaticity wikipedia , lookup

Aromaticity wikipedia , lookup

Strychnine total synthesis wikipedia , lookup

Alkene wikipedia , lookup

Transcript
Chemistry 160
Th 13 Mar 2008
In-Class Worksheet
A. Each of the following names is wrong. Draw structures based on them, and correct
the names.
1. 2-ethylpentane
In this molecule, the longest chain is actually a hexane. The true name is 3methylhexane.
2. 3,3-methyl-4-ethyloctane
First of all, the name should include “di” in front of methyl, since the numbering
indicates that there are two methyl groups. And also, the substituents should be listed in
alphabetical order in the name, which would give you
4-ethyl-3,3-dimethyloctane
3. 3,3-dimethylbutane
Numbering of a substituent should be the lowest possible. If you number the molecule
from the other end (probably from the right instead of from the left), you can also call
this molecule 2,2-dimethylbutane, which is technically the correct answer.
B. There is only one compound that is named 1,2-dichloroethane, but there are two
distinct compounds that can be named 1,2-dichloroethene. Why?
Ethene contains a double bond, and ethane has a single bond between the two carbons.
In order to create a double bond, the carbons overlap their p orbitals, which are
perpendicular to the sigma bond formed between the carbons. The reason that no
rotation can occur between the carbons is that rotation would break the contact between
the p orbitals, thus destroying the pi bond that actually forms the double bond in the first
place.
All that having been said – C-C single bonds can rotate freely, and C=C double bonds
cannot. This allows for cis-trans isomerism in 1,2-dichloroethene, but not in 1,2dichloroethane.
C. In each of the following, circle and name the functional groups:
1. Contains carboxyl group/carboxylic acid,, and aldehyde.
2. Contains amide, and ester
3. Contains alkene and ester
D. Draw five alcohols with the formula C5H12O.
There are many… I’ll see how much space I have.
CH3CH2CH2CH2CH2OH
CH3CH2CHCH2CH3
|
OH
CH3
|
CH3CHCHCH2CH3
|
OH
CH3CH2CH2CHCH3
|
OH
CH3
|
CH3CCH2CH2CH3
|
OH
CH3 OH
|
|
CH#CHCH2CHCH3
CH2OH
|
CH3CCH3
|
CH3