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ANSWER KEY for HSPA-PREP Assignment #4 Part-I: Pre-Algebra and Algebra basic material Open-ended HSPA questions: Assignment pages 5, 8 and 11. PSAT/SAT material: Begins on page 12 PART-I Practice with Patterns and Numbers 1. C 49 (use x-3) 2. C 6 3. 16, 19, 21 4. 94, 90 (use x-2): 96-2=94; 92-2=90 5. 1,625 (use 5x): (3)(5)=15; (15)(5)=75; (75)(5)=325; (325)(5)=1625 6. 125, 62.5, 31.25 Divide by 2 or multiply by 0.5 7. multiply by -2 (3)(-2)= -6; (-6)(-2)=12; (12)(-2)= -24 8. multiply by -0.5 or divide by -2 9. multiply by -4 (2)(-4)= -8; (-8)(-4)=32; (32)(-4)= -128 10. 82, 244, 730 (28)(3)-2 = 84-2 = 82; (82)(3)-2=246-2=244; (244)(3)-2=732-2=730 11. 256; 65,536 (use x2): 2(2)=4, 4(4)=16, (16)(16)=256; (256)(256)=65,536 12. 677 (use x2 +1): (26)2 +1 = 676 +1=677 Practice Solving Linear Equations 1. B x = -7 2. C a=8 3. A b = -3 4. D x=4 5. B w = 15 6. B x = 12/9 which reduces to 4/3 7. C -9 = a 8. C Z = 80 9. D x = -16 10. A y = -80 Practice Recognizing Lines and Slopes 1. Sketches will vary but slopes should be the same 2/2 or 1 They are perpendicular because the slope of one line is the negative reciprocal of the slope of the other line. 2. C Two lines are parallel 3. A Parallel 2y – 4x = 12 can become y – 2x = 12, then y = 2x + 12 which is parallel to the line y = 2x +5 (the coefficient of x is the slope and they are both 2). 4. B 3 2y = 6x + 10; divide both sides by 2 and get y = 3x +10; slope is 3 5. B 6 6. B 2 y-2x = 14; add 3x to both sides and get y = 2x +14; slope is 2 7. A 4 1 slope = 8. B and D 9. y1 y 2 40 4 = = 2 3 1 x1 x2 3 4 1 1 4 3 1 and D. 52 3 5 4 9 3 Table A: input x = 4 output (2)(4)+1 = 9 input x = 7 output (2)(7)+1 = 15 2 2 Table B: input x = 3 output X = 3 = 9 Input x = 5 output X2 = 52 = 25 If you deposit $50 and use Table A; 2(50)+1 = 101 You would have $101. If you deposit $50 and use Table B; (50)2 = (50)(50) = 2,500 You would have $2,500. B. Sample correct response: In Table A Bank the amount you deposit is only multiplied by 2 and $1 added; but in Table B Bank your money grows exponentially; the $50 is multiplied times itself and (50)(50) gives you a much larger amount. 10. Equation for perimeter: 2(x-2) + 2(x+5) = 22 or x-2 + x-2 + x+5 + x + 5 = 22 Solving for x: x =4 Longer side is x + 5 = 4 + 5 = 9; Shorter side is x – 2 = 4 – 4 = 2 Check: 2 (x-2) + 2 (x+5) = 2 (4-2) + 2(4+5) = 2(2) + 2(9) = 4 + 18 = 22 correct Area of rectangle is (length)(width); (9)(2) = 18 square units 11. Equation for perimeter of triangle would be 2(3x+2) +2x = 100 or 3x+2 + 3x+3 + 2x = 100 Solving the equation you find that x = 12 Base = 2(x) = 2(12) = 24 Each side = 3x+2 = 3(12)-2 = 36-2 = 38 Check: 38 + 38 + 24 = 100 correct it matches the original equation and perimeter given 12. Equation for perimeter of the equilateral triangle is 3(x+6) = 108 Solving the equation you find that x =30 Each side is x+6 or 30 + 6 which = 36 Check: 3 (x+6) = 3 (30+6) = 3(36) = 108, correct 13. Equation: x + 2x + 3x = 180o x = 180/6 = 30 o Angle B = 2x = (2)(30) = 60 o Angle C = 3X = 3(30) = 90 o Side AB is largest because it is opposite the largest angle. Practice with Expressions and Equations 1. D 4n-6 2. A 3. D 4. A 10n = .20n Real-Life Applications 1. C A = P (1 + .029)3 Remember, you write 2.9% as .029 A = 5300(1.029) 3 A = 5300(1.08954…) A = $5,774.60 Mixed Practice 1. geometric series 2. C add 34 to both sides 3. D In example A: 4a=48 and a = 12 In example B: -2b=-24 and b = 12 In example C: 3x = 36 and x = 12 In example D: 3y = -12 and y = -12 not 12 4. B 14.55 per hour 40x + 10(2x) = 873; 40x +20x = 873; 60x = 873; x = 14.55 5. D $9.00 2(3x) + 3x = 6x + 3x = 9x = 27; x =3 Adult ticket = 3x = (3)(3) =9 2 6. A 5 =n-6 7. D same slope 8. B y = 1/3x -4/3 b4 9 C c= a 10. A x=6 2x+3(x-2)=24; 2x+3x–6=24; 5x = 30, x = 6 11. C 3 y = 4x +3 slope is 4 y = 4x slope is 4 3y=x, slope is ¼ 16x-4y=24; becomes 4y=16x-24, then y = 4x-6 slope is 4 y + 4x =6; becomes y = -4x +6, then slope is -4 Open-ended question 13 x + 2x + 4 + 3x = 100cm = perimeter x = 16 6x + 4 = 100; 6x = 96; x = 16 AB = x = 16cm BC = 2x + 4 = 3 + 4 = 36cm CA = 3x = 3(16) = 48cm (b)( h) (36)(8) (36)(4) = 144 sq. cm. Area = = 2 2 Open-ended question 14 PART-III HSPA/PSAT/SAT QUESTIONS 13. B 20 (Remember to divide by x or 10) 14. C 32 (See which ones you can eliminate first) 15. D ½ (Remember, you can substitute x for r+s and then solve for x.) 16. A 12 (Note: if 2u + 2v = 60; then u + v = 30 and you can substitute that into the other equation: t + u + v = 42, or t + 30 = 42; then just solve for t. 17. E 56 18. B -1 19. A 10 20. C 3 8 You should notice that the line has a negative slope. So you can eliminate D and E. Look at the two coordinates given and you see that the slope is 2 2 or which is -1. 2 2 Put the two equations in the correct form so you can compare them. Y = ax + 5 Here ‘a’ is the slope. 3x + 8y = 10; becomes 8y = -3x + 10; then y = -3/8x +10/8 21. A -8 Just solve for x in the first equation: 2x + 4 = 10, 2x = 6, x =3 Then substitute 3 for x in the next expression: 4(x)-20 = 4(3)-20 = 12-20 = -8 22. 2x = ½ or 0.5 (Notice you can use substitution again.) If yz = 10, then substitute 10 for yz in the other equation. 2xyz = 5 then becomes 2x(10) = 5; then 2x = 5/10 or 1/2