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Transcript
AE 3003 Governing Equations (Continued)
Derivation of the Momentum Equations
In this section we will derive the conservation of u-momentum equation, and
extend the resulting form to the conservation of v- and w- momentum equations in a
straightforward manner.
The u- momentum equation is an extension of Newton’s law which states that
“the rate of change of momentum of a particle (i.e. a system with fixed mass) is equal to
the force acting on the particle.” In our work, we are dealing with open systems, i.e.
control volumes, whose mass may change with time as a result of fluid entering or
leaving the control volume. We therefore say
“The rate of change of u-momentum of particles within a control volume = Forces along
the x-Direction acting on the control volume + Net rate at which u-momentum enters the
control volume through the boundaries.”
As before, we consider a control volume V, surrounded by stationary boundaries

S. The outward-facing unit normal at any point on the surface S is called n .
Let dV be an infinitesimal volume within V. Then,
Mass with dV = dV
u - Momentum within dV = udV
u - Momentum within the entire control volume V =
 udV
V
d
Rate of Change of u - momentum within V =
udV
dt 
V
Interchanging the integration and differentiation operations for a fixed control volume,
Rate of change of u - momentum within V =

V
  u
dV
t
See the previous handout titled Chapter II to find out what the triple integrals
mean, and why we could interchange the time derivative and spatial integration
operations.
We have now derived an expression for the left hand side of the conservation of
u- momentum equation. We now turn our attention to the right hand side, which consists
of two contributions – X- component of forces acting on V, rate at which u- momentum
enters V through S. Let us consider these two issues one at a time.
Forces Acting on V: The forces may be divided into two broad categories – body forces
and surface forces.
Body Forces: These are forces acting on every fluid particle within V. Examples of body
forces include gravity, electrostatic forces, and magnetic forces. Let us assume the
symbol a X represents the x- component of all these effects acting on the fluid particles
within V. The quantity a X may vary with x,y,z or t. Then,
Body force along the x - direction acting on all paticles wthin dV = a x dV
Body force along the x - direction acting on all paticles wthin V =  a x dV
V
Surface Pressure Forces: The control volume V is surrounded by the surface S. Pressure
from surrounding fluid (or solid) acts on this surface S. Pressure forces are always
directed towards the fluid within, and is always normal to the surface. The pressure

forces acting on S may therefore be written as   pndS . Notice the negative sign. It is
S

there because the normal vector n is pointing outwards, whereas the pressure forces are
acting inwards. The x- component of these pressure forces is found by performing a dot
product of this expression with

i
.
Thus,
 
X  component of Surface Forces acting on V=   pn  i dS
Surface Viscous forces: The surrounding fluid can exert an additional type of force on the
surface S, called a “viscous” force. This force may have a component normal to the
surface S, and components tangential to the surface. We will study the effects of viscosity
in more detail in AE 3005, or its semester equivalent. For now, we will call this
contribution Fx-Viscous.
We can finally turn our attention to the rate at which the u- momentum is brought
into V though the surface S. Let dS be an infinitesimal element on S. Then rate at which

u-momentum enters the control volume through dS is  uV  ndS. Summing up
contributions over the entire surface S, we get:
 
Rate at which u - momentum enters V through S = -  uV  ndS
S
We have independently found all the terms on the left and right hand side of the
u-momentum equation. Bringing over all the terms, except the viscous forces and the
body-forces, to the left-hand side, we get:

V
  u
 

dV    pi  uV   ndS   a x  Body dV  Fx Viscous
t
S
V
(1)
The above equation is the conservation of u- momentum equation in integral
form.
We can similarly derive the v- and w- momentum equations. Or simply replace all

places where u appears with v, i with j , etc. Then we get
Conservation of v- momentum Equation in Integral Form:
  v 
 

dV

pj


vV

  ndS   a y  Body dV  Fy Viscous

S
t
V
V
(2)
Conservation of w- momentum Equation in Integral Form:

  w
 
dV

pk
 wV   ndS   a z  Body dV  Fz Viscous



t
V
S
V
(3)
In this course, we will henceforth neglect the viscous forces acting on the fluid.
Needless to say, neglecting this effect is an approximation, and all the resulting solutions
only approximate real flows. Viscous forces are small except in regions of high velocity
gradient. In many flows, velocity varies slowly. Neglecting viscous effects turns out to be
an acceptable compromise.
We will also neglect body forces such as gravity, electrical and magnetic effects.
These effects are small in many applications compared to the rest of the terms in the
momentum equations. There are applications such as formation of weather systems where
gravity does play a part. In ionized flows, the ions are attracted and deflected by electrical
and magnetic forces. This is what causes the Aurora Borealis phenomenon! We neglect
these forces because they are small compared to other forces acting on the control
volume.
The effect of these approximations is that the right hand sides of the integral
forms of u- v- and w- momentum equations (1-3) disappear, leaving us only with the lefthand side terms.