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Algebra 1 Chapter 7 Practice Test Name _______________________________ Simplify. Assume that no denominator is equal to zero. 1) 4a2b7 9a4b3 2x5y2 4 4x4y5 2 2) 1) ___________________ 2) ___________________ 2 3) 4a5b 6 x 0 y3 4) 3) ___________________ y2 4) ___________________ 5) 56x2y 4z0 63 6) 3 2 8x y 5) ___________________ 6) ___________________ 7) 4a 5b9 56a2b9c7 3 1 2 2 x y 2 8) 4y 2 2 7) ___________________ 8) ___________________ Identify the expression as a monomial, binomial or trinomial. 9) 6x3 2x2 9) ___________________ Simplify. 10) 4x 5xy 3y 3y 6x 8xy 10) __________________ 11) 9x3 13 3x 5x2 5x 2x3 x2 8x 4 12) 5d2 4d2 2d 7 11) __________________ 13) (7x 6)(2x 4) 12) __________________ 13) __________________ 14) 4x x2 8x 6 3 2x3 5x2 2 15) 5ab 3a2b 4a 14) __________________ 15) __________________ 16) 3n 52n2 7n 8 17) 6y 82 16) __________________ 17) __________________ Solve. 18) 2xx 4 7 x 20 2xx 1 19) 7 y 2y 3 2 18) __________________ 19) __________________ 20) Solve by first writing a system of equations. Sally has $21.40 in dimes and quarters for a total of 100 coins. How many of each kind of coin does Sally have? Equation 1: ________________ Equation 2: ________________ Sally has ____ dimes ____ quarters. Algebra 1 Chapter 7 Practice Test 1) –36a6b10 12) –20d4 + 10d3 – 35d2 2) 256x28y18 13) 14x2 – 16x – 24 14) –2x3 – 17x2 + 24x – 6 15) 15a3b2 + 20a2b 16) 6n3 + 11n2 – 59n + 40 17) 36y2 – 96y + 64 18) 13 5 19) y > –1 20) d + q = 100 0.10d + 0.25q = 21.40 3) 4 a10b2 9 4) y 5) –7xy6 6) 1 216 7) c7 14a7 8) 32x6y10 9) binomial 10) –2x – 3xy 11) 11x3 – 6x2 – 9 Sally has 24 dimes and 76 quarters. Ch 7 Practice Test