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34) Graph the line y = -2x-2. 35) Graph the line 5x-2y=-2 36) Graph the line with slope -2/3 passing through the point (5,4) Using slope = rise/run = -2/3 First plot the point (5, 4) and then move down 2 steps and then move three steps to the right, we will get the point (8, 2). Draw the line through both the points. 39) Graph the inequality below on a number line. A is greater or equal to -2 40) Find both the X-intercept and the Y -intercept of the line given by the equation 2x+6y+10=0 For finding x-intercept, put y = 0 2x + 10 = 0 2x = -10 x = -5 x-intercept is (-5, 0). For finding y-intercept, put x = 0 6y + 10 = 0 6y = -10 y = -10/6 = -5/3 y-intercept is (0, -5/3). 41) Find the slope of the line 2x=5y-3 We can write equation as 5y = 2x + 3 y = (2/5)x + (3/5) Slope = 2/5 43) A line passes through the point (x,y)=(7,-8) and has a slope of -6 . Write an equation for this line. The equation of line of slope m and passing though (x1, y1) will be (y – y1) = m(x – x1) y – (-8) = -6(x – 7) y + 8 = -6x + 42 y = -6x + 42 – 8 y = -6x + 34 Equation of line will be y = -6x + 34 45) Write equations for the vertical and the horizontal lines passing through the point (4,6) in(x,y) -coordinates. Vertical line will be x = 4 and horizontal line will be y = 6. 48) Find the values of x and y that solve the following system of equations: 2x-3y = -14 --------------(i) 3x-7y = -21 --------------(ii) Multiply equation (i) by 3 and (ii) by 2, we will get 6x – 9y = -42----------(iii) 6x – 14y = -42--------(iv) Now subtract (iv) from (iii), we will get 5y = 0 y=0 Substitute value of y in (i), we will get 2x – 0 = -14 x = -7 The solution is x = -7, y = 0 49) Find two numbers whose sum is 52 and such that one is 3 times as large as the other. (We will call the two numbers x and y.) Sum is 52. Therefore equation will be x + y = 52-----------(i) one is 3 times as large as the other. Let x = 3y x -3y = 0------------(ii) Subtract (ii) from (i) 4y = 52 y = 13 We know that x + y = 52 x = 52 – 13 = 39 The numbers will be 39 and 13. 50) Fill in the blank to make the two fractions equivalent. 4/5 = /30 Let the missing number be x Then 4/5 = x/30 Cross-multiply 120 = 5x => x = 120/5 = 24 Answer: 4/5 = 24/30