Download Review Sheet – Test 1 – Honors

Review Sheet – Test 2– Honors
Metric System:
1. units and prefixes
2. density
3. derived units
4. rules for sig figs
5. rules for multiplying and dividing and adding and subtracting with sig figs
6. rules for scientific notation
7. rules for multiplying and dividing and adding and subtracting with scientific
notation
8. dimensional analysis
9. lab measurement – you will have to go in the lab and measure items
10. temperature conversions
11. difference between mass and weight
12. accuracy and precision
13. percent error
Practice Problems:
1. The density of silver (Ag) is 10.5 g/cm 3. Find the mass of Ag that occupies 965 cm 3 of space.
10100 grams (DV)
2. A 2.75 kg sample of a substance occupies a volume of 250.0 cm 3. Find its density in g/cm 3.
0.0110 kg/cm3 (M/V)
3. Under certain conditions, oxygen gas (O2) has a density of 0.00134 g/mL. Find the volume
occupied by 250.0 g of O2 under the same conditions.
18700 mL (M/D)
4. Find the volume of a container that measures 23.56 cm high, 29.22 cm wide, and
10.67 cm long.
7345 cm3 (L x W x H)
5. Convert the following numbers to Scientific Notation:
a) 5,213 = 5.213 x 103
b) 73,200 = 73.2 x 104
c) 23.21 = 2.321 x 101
d) 0.02 = 2 x 10-2
e) 0.000314 = 3.14 x 10-4
6. Convert the following numbers to "normal notation" (eg, 1000)"
a) 2 x 103 = 2000
b) 2.331 x 105 = 233100
c) 5 x 10-3 = 0.005
d) 7.6278 x 10-5 = 0.000076278
7. Calculate
a) (7.2 x 105 ) x (2.12 x 10-2 ) = 15264 = 15000
b) (2.3 x 107) / (9.2 x 102) = 25000
8. Determine the number of sig figs:
a. 409.10 5
b. 4091.00 6
c. 0.004091 4
d. 308,000 3
e. 30,860. 5
f. 0.00056030 5
9. Calculate the answer – be sure to write the answer with the correct number of sig
figs.
a) 9.25+4.10-2.05 =11.3 =11.30 (2 decimal places)
b) 4.49+0.507+10.0 = 14.997 = 15.0 (1 decimal place)
e) 4.18x0.051960 = 0.2171928 = 0.217 (3 sig figs)
f) 0.50/4.12=
0.1213592233 = 0.12 (2 sig figs)
10. Use Dimensional Analysis for the following:
a. 0.0024 km to dm
?dm = 0.0024 kmx 1000 m x 10 dm = 24 dm
1 km
1m
b. 3.5 g to mg
?mg = 3.5g x 1000 mg = 3500 mg
1 g
b. 95 yards to cm ( 3 feet in a yard; 2.54 cm in 1 inch)
?cm = 95 yds x 3 feet x 12 in x 2.54 cm = 8700 cm
1 yd 1 ft 1 in
d. A child's sandbox is 4.0 ft. wide, 4.0 ft. long and 9.0 in deep. If there are, on
the average, 55 grains of sand per mm3, how many grains of sand are there in
the sandbox?
VOID
11. Temperature Conversions – convert to Kelvin
a. 22 °C = 295 K
b. 242 °C= 515 K
c. 115 °C= 388 K
d. -63 °C= 210 K