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CMV6120 Foundation Mathematics Unit 1 Indices and logarithms Learning Objectives The students should be able to: Use the laws of indices to solve simple problems. Use the properties of logarithms to solve simple problems. Unit 1:Indices and Logarithms Page 1of 10 CMV6120 Foundation Mathematics Indices In dealing with expressions containing exponents along with addition or subtraction or multiplication or division, we work with the exponents first. Lets consider the following examples. Example 1 (a) 3 2 2 3 _________ (b) 2 4 5 3 16 125 = ___________ (c) 3 x 10 4 3 x _______ = __________ Example 2 Write each of the following in another way by using exponents. (a) (ab)(ab)(ab) (b) –a.a.a.a (c) 4.a.b.4.b.a.a.a Solution: Example 3 Evaluate each of the following : (a) -34 (b) (-3)4 (c) 2(1.1)3 Solution: Unit 1:Indices and Logarithms Page 2of 10 CMV6120 1. Foundation Mathematics Multiplication of Exponential Numbers Consider 23.24 = (2.2.2)(2.2.2.2) = 2.2.2.2.2.2.2 = 27 a2.a3 = (a.a)(a.a.a) = a.a.a.a.a = a5 am.an = am+n In general, 2. Division of Exponential Numbers Consider 4 7 4.4.4.4.4.4.4 4.4.4 43 =44 a 5 a.a.a.a.a a.a.a a3 = a2 In general , am a mn n a Example 4 Simplify the following : 319 a) 11 31911 ________ 3 X9 b) _________ X3 a10b 8 c) a 103b 85 ________ 3 5 a b an a nn an = a0………………..(1) On the other hand an 1............................(2) an Compare (1) & (2): a0 = 1 Consider where a is any real number and a 0 Unit 1:Indices and Logarithms Page 3of 10 CMV6120 Foundation Mathematics For examples, 20 = 1, (-3)0 = 1 and 100 = 1 am a m n ………………( ) an 23 222 1 4 2222 2 2 Recall Consider If we use the division rule ( ) 23 2 34 2 1 4 2 1 2-1= 2 a-n = a0-n = In general a-n = Consider 34 3333 1 2 6 333333 3 3 If we use the division rule ( ) 34 3 46 3 2 6 3 1 3-2 = 2 3 a0 an 1 an n n n n (a b) = a b Example 5 (a) an a n b b (am)n = amn Simplify the following : (a2 b)3 (b) ( x3 2 3 2 ) (y) y Solution : Unit 1:Indices and Logarithms Page 4of 10 CMV6120 Foundation Mathematics Example 6 Carry out each of the following operation. Write all answers with positive exponents and simplify where possible. (a) 7-1 (b) 2-4 (c) 5(5-3) (d) 2 5 23 Solutions: (a) (c) 1 7 5(5-3) =51 5-3 7 1 = = 3. 1 1 or 4 16 2 (b) 2 4 = (d) 2 5 23 = Radicals If x2 = y , then x is a square root of y for example 72 = 49 ∴ 7 = 2 49 similarly, 81 or = 9 49 7= (∵ 92=81 ) If x3 = y , then x is a cube root of y for example, 43 = 64 (∵ 3 64 4 ) In general, if xn = y , where n is a positive integer, then x is a nth root of y. for example, 24=16 ∴ 4 16 2 Unit 1:Indices and Logarithms Page 5of 10 CMV6120 Foundation Mathematics Example7 (a) (b) (c) Find the values of the following : 6 64 5 100000 4 81 Solution : 144=9 16 144 12 9 16 3 4 =12 ∴ 144 9 16 Consider and 9 16 3 4 In general ab a b Note that ab a b e.g. a a b b 25 = 16 9 16 9 4 3 7 but 25 5 ∴ 16 9 16 9 In general Example 8 (a) (b) n a na b nb n ab n a n b Find the values of the following functions : x f(x) = when x = 25 64 f(x) = x0.5 when x = 0.027 Unit 1:Indices and Logarithms Page 6of 10 CMV6120 Foundation Mathematics Solution : 25 25 64 64 =__________ 3 27 27 f(0.027) = 3 3 1000 1000 =_________ (a) f(25) = (b) 4. Fractional Indices n 1 n 1n a a n =a1 = a Consider 1 ∴ ann a n am Similarly , am/n = ( n a )m = Example 9 Evaluate the following: (a) 81 3 4 (b) 1000 1 2 3 (c) 9 2 25 Solutions: 3 4 4 3 (a) 81 = ( 81 ) = __________ (c) 9 9 2 =_______ = 25 25 (b) 2 3 1000 = ( 3 1000 )2 = ________ 1 Unit 1:Indices and Logarithms Page 7of 10 CMV6120 Example 10 Foundation Mathematics In the compound interest formula A = P (1+r)n , if A = 54874.32 , P = 25000, n = 6, find the value of r . Solution: A = P ( 1+r)n 54874.32 = ( 25000)( 1 + r )6 54874.32 6 1 r 25000 54874.32 1 r 6 25000 r = ____________% 5. Definition of Logarithms If a number X = ay, where a is positive and a≠1, the index y is called the logarithm of the number X to the base a. In symbol, y = log aX. N.B. logaX is undefined only for positive values of X For example, 23 = 8 log28 = 3 34 = 81 log381 = 4 When the base a is not stated in logaX, it may be assumed a = 10. This is called the common logarithm. For example, log 1000 = log101000 =3 log 0.01 = -2 1 ( 10-2 = 2 = 0.01) 10 Unit 1:Indices and Logarithms Page 8of 10 CMV6120 6. Foundation Mathematics Properties of Logarithms : 1. logaa = 1 2. loga1 = 0 3. logaMN = logaM + logaN 4. loga 5. logaXn = n logaX M N = logaM - logaN Example 11 Find the values of the following: 1 (a) log711 + Log7 11 (b) log6 – log60 (c) log5125 Solution: 1 (a) log711 + log7 11 1 log7 11 = log71= __________ 11 (b) log 6 – log 60 log 6 1 = log =____________ 60 10 (c) log5125 = log553 = 3 log55 =______________ Unit 1:Indices and Logarithms Page 9of 10 CMV6120 Example 12 Foundation Mathematics In the compound interest formula A = P ( 1 + r )n , if A = 20000, P = 10000, r = 12%, find n correct to 2 decimal places. Solutions: A = P ( 1 + r )n 20000 = 10000 ( 1 + 12% ) 20000 (1 0.12) n 10000 2 = ( 1.12 )n Taking logarithm on both sides, log2 = log(1.12)n log2 = n log 1.12 n log 2 log 1.12 n = _________ Unit 1:Indices and Logarithms Page 10of 10