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Chapter 8
Rational
Exponents,
Radicals, and
Complex
Numbers
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
11
CHAPTER
8
Rational Exponents, Radicals,
and Complex Numbers
8.1
8.2
8.3
8.4
8.5
8.6
8.7
Radical Expressions and Functions
Rational Exponents
Multiplying, Dividing, and Simplifying
Radicals
Adding, Subtracting, and Multiplying
Radical Expressions
Rationalizing Numerators and
Denominators of Radical Expressions
Radical Equations and Problem Solving
Complex Numbers
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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8.7
Complex Numbers
1. Write imaginary numbers using i.
2. Perform arithmetic operations with complex
numbers.
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Imaginary unit: The number represented by i, where
i  1 and i2 = 1.
Imaginary number: A number that can be expressed
in the form bi, where b is a real number and i is the
imaginary unit.
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Example
Write each imaginary number as a product of a real
number and i.
a. 16
b. 21
c. 32
Solution
a. 16
b.
21
c.
32
 116
 1 21
 1 32
 1  16
 i4
 4i
 1  21
 1  32
 i 21
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
 i 16  2
 4i 2
5
Rewriting Imaginary Numbers
To write an imaginary number  n in terms of the
imaginary unit i,
1. Separate the radical into two factors, 1  n .
2. Replace 1 with i.
3. Simplify n .
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Complex number: A number that can be expressed in
the form a + bi, where a and b are real numbers and i
is the imaginary unit.
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Example
Add or subtract. (9 + 6i) + (6 – 13i)
Solution
We add complex numbers just like we add
polynomials—by combining like terms.
(9 + 6i) + (6 – 13i) = (9 + 6) + (6i – 13i )
= –3 – 7i
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Example
Add or subtract. (3 + 4i) – (4 – 12i)
Solution
We subtract complex numbers just like we subtract
polynomials.
(3 + 4i) – (4 – 12i) = (3 + 4i) + (4 + 12i)
= 7 + 16i
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Example
Multiply.
a. (8i)(4i)
b. (6i)(3 – 2i)
Solution
a. (8i)(4i)  32i 2
b. (6i)(3 – 2i)
2

18
i

12
i
 32(1)
 18i  12(1)
 32
 18i 12
 12 18i
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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continued
Multiply.
c. (9 – 4i)(3 + i)
d. (7 – 2i)(7 + 2i)
Solution
c. (9 – 4i)(3 + i)
 27  9i  12i  4i 2
d. (7 – 2i)(7 + 2i)
 49  14i  14i  4i 2
 27  3i  4(1)
 49  4( 1)
 27  3i  4
 49  4
 31  3i
 53
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Complex conjugate: The complex conjugate of a
complex number a + bi is a – bi.
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Example
7
Divide. Write in standard form. 3i
Solution Rationalize the denominator.
7
7 i
7i
 

3i
3i i
3
7i
 2
3i
7i

3(1)
7i

3
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Example
3  5i
Divide. Write in standard form.
5i
Solution Rationalize the denominator.
15  3i  25i  5
3  5i 3  5i 5  i



25  1
5i
5i 5i
10  28i
2

15  3i  25i  5i

26
2
25  i
10 28i
15  3i  25i  5(1)



26 26
25  (1)
5 14i
 
13 13
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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Example
40
Simplify. a. i
b. i33
Solution
a. i
40
= i

4 10
= 110 = 1
Write i40 as (i4)10.
b. i 33 = i 32  i
= i

4 8
= 1 i
i
Write i32 as (i4)8.
Replace i4 with 1.
=i
Copyright © 2015, 2011, 2007 Pearson Education, Inc.
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