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Q3 Test 2: Factoring/Solving Quadratics/Word Problems C,D, and G Periods: Tuesday, 4/1/08 E Period: Wednesday, 4/2/08 Part I: Factoring 1) x2 – 5x – 84 4) x2 – 21x + 90 7) 8x2 – 24x – 320 10) 7x8 – 175x6 13) 9x16 – 81x1 16) 6x10 – 84x9 + 270x8 19) 225x2 – 36 22) 2x2 – 7x - 22 25) 18y2 + 21y + 5 28) 12s2 – 8s - 20 2) x2 + 2x – 80 5) x2 – 121 8) x9 + 13x8 + 36x7 11) 36x2 – 16 14) 100x8 – 4x2 17) 7x2 – 63x – 154 20) 81x6 – 144x4 23) 12s2 + 23s + 5 26) 15f2 – 46f + 3 29) 24d2 – 4d - 42 3) x2 + 15x + 54 6) 9x2 – 196 9) 9x7 + 9x6 – 504x5 12) 144x4 – 64x2 15) 10x2 + 30x – 700 18)12x5 + 144x4 + 384x3 21) 196x15 – 49x13 24) 36c2 + 18c - 4 27) 45k2 + 21k - 24 30) 21w2 + 93w + 36 Part II: Solve By Factoring: 1) x2 – 4x = 45 4) 6x2 + 144 = 60x 6) 3x2 + 5x – 11 = 6x2 - 9x – 59 8) 10x3 = 20x2 + 350x 11) 8x2 – 8x - 19 = 7x2 – 8x + 17 2) x2 + 64 = -16x 3) 77 – 4x = x2 3 2 5) 3x + 30x + 63x = 0 7) 3x2 – 11x - 33 = 7x2 – 3x – 33 9) x2 + 10x = 96 10) 4x6 + 20x5 = 144x4 12) 7x2 – 8x – 13 = 6x2 + 3x – 17 Part III: Quadratic Word Problems: 1) The area of a rectangle is 112 cm2. The width is stated as x – 2 and the length is stated as x + 7. Find the value of x and then use x to find the perimeter. 2) Find 5 positive consecutive integers such the product of the 3rd and the 5th is 528 3) Find 4 consecutive negative odd integers such that the product of the 2nd and 4th is 1,085. 4) The product of two negative numbers is 96. The smaller number is 4 less than double the larger. Find both numbers. Find the difference of the two numbers. 5) Three positive numbers are multiplied and the product is 1,000. The first number is 5. The 2nd # is x and the 3rd number is x + 10. Find the sum of the three numbers. 6) The area of a rectangle is 165 in2. The width is 4 less than the length. Find the perimeter of the rectangle.