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QMS 202 Distributions of Sample Proportions Consider the Population: Y,N,N,N,N,N,N,N,N,N ... 10% Y’s and 90% N’s Define p as the proportion of Y’s QMS 202 Distributions of Sample Proportions Now consider all possible samples of size n=100 which can be taken from the population above where the 1st item selected is replaced before the 2nd item is selected etc. [This sampling procedure is equivalent to sampling from an infinite population]. The Count the number of Y’s in the samples this forms a Binomial Distribution. Distribution of Sample Counts X (# Y’s) ...... 6 7 8 9 10 11 12 13 14 ..... 100 P(X) .06 .09 .11 .13 .13 .12 .10 .07 .05 Which is approximately normal with the same mean and standard deviation as the binomial distribution. Using Binomial formula with p = .1 and n=100 Note: All binomial distributions where approximately normal. are QMS 202 Distributions of Sample Proportions Now consider the Distribution of Sample Proportions, p, created by dividing the counts, X, by n (100). p Distribution Sample Probability( p) Proportions 0 ...... 6/100=.06 .06 .07 .09 .08 .11 .09 .13 .10 .13 .11 .12 .12 .10 .13 .07 .14 .05 ..... 1 Which is approximately normal with a mean of provided and and standard deviation are both $5 are approximately normal. QMS 202 Distributions of Sample Proportions 35% of students have cell phones. If a sample of 50 students is randomly selected what is the probability that the proportion of students in the sample that have cell phones will be less that 30%? (Note that this is equivalent to the binomial question : What is the probability that less than 15 of the students sampled have cell phones?) p - proportion of students in the sample that have a cell phone. Since , p’s are normally distributed. Using the standard normal distribution we get