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Quiz 1: Electric Fields Lab Solutions 1/19/2006 10pts 1. (5pts) Derive the electric field strength E in terms of electric potential difference V, and distance d, using that: W V = (1) q We define work as the force required to move a charge a certain distance d v r W = F ⋅ d (2) Where W is work, F is force and d is distance. Substituting Eq. (2) into Eq. (1) we get: Fd V = (3) q The force exerted on a particle in an electric field is given by, F = Eq (4) Substituting Eq. (4) into Eq. (3) we find the electric field strength in terms of V and d. V E= (5) d 2. (5pts) What are the standard units for electric field strength? In what units will we be measuring electric field strength? Show that the two are equivalent. (Hint: A volts is J/C) i. ii. iii. N (newtons ) C (Coulomb) V (volts ) V (volts) or In the experiment we measure in m(meter ) cm(centimeter ) V J N ⋅m N J = = = where V = and J = N ⋅ m m C ⋅m C ⋅m C C The standard SI units of electric field are