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1964] A PRIMER ON THE FIBONACCI SEQUENCE - PART V 65 so that M M 1 1 ) Tan" -=r^ H. 2n+l n=l + Tan" | 6 X = 2 ^ Tan* 1 ~ + Tan" 1 H, -2n ^2M+2 n=l -1 -I -1 The limit on the left tends to Tan 1 + Tan 1/3 = Tan 2 and the right-hand -1 side tends to this same limit and since Tan 1 / L ? M 9 -*0 9 then Theorem 6: I n=l rp Tan -1 1 ^ T — = Tan -1 ^ 5 " 1 1 „, ' - 1 „ —-75-— = •$ Tan 2 2n Compare with Theorem 5 in Part IV, We shall continue this interesting discussion in the next issue. CORRECTIONS FOR VOLUME 1, NO. 2 Page 45: In the tenth line up from the bottom, the subscripts on the Fibonacci numbers should be reversed. Page 47: Replace "Lamda" by "Lambda" in the title. Page 52: In line 6, replace (Rn) with \(R n ), In line 12, the author's name is Jekuthiel Ginsburg. Page 55: In problem H-18, part a, replace = by 4= . a b .,, / a b Page 57: In E2, replace — , — with , , , , , . Page 58: Add three dots after the 4 on the last line. Page 60: The title "Letters to the Editor" was omitted from Fibonacci Formul a s , and, in that article, the "Correct Formula" due to the late Jekuthiel Ginsburg is I * + 2 - 3J#n + 1*_ 2 = 3 F 3 n . 66 CORRECTIONS Feb. 1964 CORRECTIONS FOR VOLUME 1, NO. 2 Page 68: The right side of identity xix should read I n + l " F nVl - !> •. and in identity xx, the subscript n-1 should be n-i. The correct page number in reference 1 is 98. Page 75: Insert three dots after /32, in line 15. Page 80: In the last line, replace pN by p | N and p(2 • 3 • 5- • -p ) by p | (2 • 3 • 5 • • • p n ) . Page 81: Replace T + 1 by T in the left side of the first displayed equation. Page 86: In B-12, L = fa ], a34 = i = \T-l instead of zero. Page 87: Change the equations in problem B-16 to read F2 F F n-1 n-1 n Rn = 2 F - F F2 - F nF 1 n-1 n n+1 n-1 n F2 F F n n n+1 See also solution in this issue. Page 88: F2 n 2F F x 1 n n+1 F2 n+1 See the last written line for notational error due to exclamation point punctuation.