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determining from angles that a triangle is isosceles∗ Wkbj79† 2013-03-21 23:07:29 The following theorem holds in any geometry in which ASA is valid. Specifically, it holds in both Euclidean geometry and hyperbolic geometry (and therefore in neutral geometry) as well as in spherical geometry. Theorem 1. If a triangle has two congruent angles, then it is isosceles. Proof. Let triangle 4ABC have angles ∠B and ∠C congruent. A B C Since we have • ∠B ∼ = ∠C • BC ∼ = CB by the reflexive property of ∼ = (note that BC and CB denote the same line segment) • ∠C ∼ = ∠B by the symmetric property of ∼ = ∗ hDeterminingFromAnglesThatATriangleIsIsoscelesi created: h2013-03-21i by: hWkbj79i version: h39528i Privacy setting: h1i hTheoremi h51M04i h51-00i † This text is available under the Creative Commons Attribution/Share-Alike License 3.0. You can reuse this document or portions thereof only if you do so under terms that are compatible with the CC-BY-SA license. 1 we can use ASA to conclude that 4ABC ∼ = 4ACB. Since corresponding parts of congruent triangles are congruent, we have that AB ∼ = AC. It follows that 4ABC is isosceles. In geometries in which ASA and SAS are both valid, the converse theorem of this theorem is also true. This theorem is stated and proven in the entry angles of an isosceles triangle. 2