Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
equivalent formulations of normality∗ CWoo† 2013-03-22 4:00:29 Recall that a logic in a modal propositional language is a set of wff’s containing all the tautologies and is closed under modus ponens. Depending on the intended meaning of the modal connective , one may extend the logic by adding wff’s and/or imposing additional inference rules. Among the more common modal inference rules are the following: RK : n≥0 RR : (A1 ∧ · · · ∧ An ) → A , (A1 ∧ · · · ∧ An ) → A RM : (A ∧ B) → C (A ∧ B) → C A→B A → B RN (necessitation rule): A A The most common modification is what is known as the normal modal logic. It is obtained from a logic by adding the schema K: (A → B) → (A → B) and the rule of necessitation RN. As it turns out, this is not the only way to formulate the notion of normality, as the following proposition illustrates: Proposition 1. Let L be a logic. Then the following are equivalent: 1. L is normal 2. L is closed under RK 3. L contains > and is closed under RM and RR, where > is ¬ ⊥. 4. L contains schemas (A → A), A ∧ B → (A ∧ B), and is closed under RM 5. L contains schemas (A → A), K, and is closed under RM ∗ hEquivalentFormulationsOfNormalityi created: h2013-03-2i by: hCWooi version: h42565i Privacy setting: h1i hFeaturei h03B45i † This text is available under the Creative Commons Attribution/Share-Alike License 3.0. You can reuse this document or portions thereof only if you do so under terms that are compatible with the CC-BY-SA license. 1 First, three quick observations: 1. If L is closed under RK, then it is closed under RR, RM, and RN. Proof. RR, RM, and RN are RK with n = 2, 1, and 0 respectively. 2. If L is closed under RN, then L contains (A → A), and in particular >. Proof. Since A → A is a tautology, we have ` (A → A) by RN. Letting A be ⊥ gives us ` >. 3. If L is closed under RM, and contains B for some wff B, then L is closed under RN. Proof. For any wff A in L, by modus ponens on tautology A → (B → A), we have ` B → A, and so by RM, ` B → A. But ` B by assumption, ` A by modus ponens. Now, we prove the proposition. Proof. We will prove the following implications 1 ⇒ 2 ⇒ 3 ⇒ 4 ⇒ 5 ⇒ 1. 1 ⇒ 2. See this entry12558. 2 ⇒ 3. By the first observation, L is closed under RM and RR, and RN, and therefore contains > based on the second observation. 3 ⇒ 4. Apply RR to A ∧ B → A ∧ B, we get ` A ∧ B → (A ∧ B). Apply the third observation to >, L is closed under RN, and therefore contains (A → A) by the second observation. 4 ⇒ 5. Apply the third observation to ` (A → A), we see that L is closed under RN. Next, we show that L contains K. From the tautologies A ∧ (A → B) → A ∧ B and A ∧ B → B, we get the tautology A ∧ (A → B) → B by the law of syllogism, so that ` (A ∧ (A → B)) → B by RM. Now, ` A ∧ (A → B) → (A ∧ (A → B)) by assumption, ` A ∧ (A → B) → B by the law of syllogism. From the tautologies X ∧ Y ↔ Y ∧ X and (X ∧ Y → Z) → (X → (Y → Z)), we get `K by the substitution theorem and modus ponens. 5 ⇒ 1. Similarly, L is closed under RN. Since L contains K, it is normal. 2