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Patterns of Inheritance Worksheet Name: ________________________ 1. Complete the following monohybrid cross. The P generation is true breeding. Cross a plant that produces yellow seeds with a plant that produces green seeds. Yellow is dominant. Use Y for yellow, y for green. P generation phenotype: genotype: yellow seeds YY green seeds yy gametes produced: all Y all y F1 generation phenotype: genotype: yellow seeds Yy gametes produced: 1/2 Y, 1/2 y F2 generation (cross F1 with F1) Y y Y YY Yy y Yy yy Possible phenotypes: Yellow, Green Ratios: 3/4, 1/4 Possible genotypes: YY, Yy, yy Ratios: 1/4, 2/4, 1/4 ______________________________________________________________________________ 2. Complete the following monohybrid cross. The P generation is true breeding. Cross a tall plant with a short plant. Tall is dominant. Use T for tall, t for short P generation phenotype: genotype: tall TT short tt gametes produced: all T all t F1 generation phenotype: genotype: Tall Tt gametes produced: 1/2 T, 1/2 t F2 generation (cross F1 with F1) T t T TT Tt t Tt tt Possible phenotypes: Tall, Short Ratios: 3/4, 1/4 Possible genotypes: TT, Tt, tt Ratios: 1/4, 2/4, 1/4 Page 1 of 4 3. Complete the following dihybrid cross for seed pod traits. Assume the genes are linked. Green is dominant. Use G for green, g for yellow. Inflated is dominant. Use I for inflated, i for constricted. P generation phenotype: genotype: yellow constricted pod gi gi green inflated pod GI GI gametes produced: all gi all GI F1 generation phenotype: genotype: green inflated pod GI gi gametes produced: 1/2 GI, 1/2 gi F2 generation (cross F1 with F1) GI gi GI GGII GgIi gi GgIi ggii Possible phenotypes: green inflated pod, yellow constricted pod Ratios: 3/4, 1/4 Possible genotypes: GGII, GgIi, ggii Ratios: 1/4, 2/4, 1/4 __________________________________________________________________________________ 4. Complete the following dihybrid cross for seed pod traits. Assume the genes are NOT linked. Green is dominant. Use G for green, g for yellow. Inflated is dominant. Use I for inflated, i for constricted. P generation phenotype: yellow constricted pod green inflated pod genotype: gi GI gametes produced: all gi all GI F1 generation phenotype: genotype: green inflated pod GgIi gametes produced: GI, Gi, gI, gi F2 generation (cross F1 with F1) GI Gi gI gi GI GGII GGIi GgII GgIi Gi GGIi GGii GgIi Ggii gI GgII GgIi ggII ggIi gi GgIi Ggii ggIi ggii Possible phenotypes: green inflated, green constricted, yellow inflated, yellow constricted Ratios: 9/16 3/16 3/16 1/16 Possible genotypes: GGII, GGIi, GgII, GgIi, GGii, Ggii, ggII, ggIi, ggii Ratios: 1/16, 2/16, 2/16, 4/16, 1/16, 2/16, 1/16, 2/16, 1/16 Page 2 of 4 5. For the following results of a dihybrid F2 cross, determine whether of not the genes are linked. a) 1 white short plant, 9 purple tall plants, 3 white tall plants and 3 purple short plants. Genes are not linked. Purple is dominant, white is recessive. Tall is dominant, short is recessive (from lecture notes & book). Ratio is 9:3:3:1, with dominant phenotype for both traits at 9 and recessive phenotype for both traits at one. This matches the phenotype reached in a dihybrid cross when the genes are not linked. b) 12 purple tall, 4 white short Genes are linked (in this example). This ratio shows a 3:1 phenotypic ratio (divide each number by 4), with 3 dominant phenotypes and 1 recessive phenotype. 6. You have a purple flowered plant, but do not know whether or not it is true breeding or not. How could you determine whether it is homozygous or heterozygous for that trait? Show all your work. Perform a test cross and analyze results. Cross between unknown genotype of purple flowered plant, with a recessive (and true breeding) white flowered plant Cross: purple flower white flower P_ pp Results: Possibility one: Purple flower is homozygous P P p Pp Pp p Pp Pp All offspring will have purple flowers Possibility two: Purple flower is heterozygous P p p Pp pp p Pp pp 1/2 of offspring purple, 1/2 of offspring white Note: it is possible, under the rules of probability, never to get white offspring in the 2nd possibility. The test cross is only really definitive if you do get white offspring, or if you do a very large number of crosses and never get white offspring. 7. You are a genetics counselor at a hospital. A couple, both of whom are carriers of cystic fibrosis, a recessive disease, want to know what the chances are that their offspring would have cystic fibrosis. What would you tell them? Show all your work. C = normal, c = cystic fibrosis Both parents are carriers, so both heterozygous (Cc) C c C CC Cc c Cc cc They have a 1/4 chance of producing a child with cystic fibrosis, every time they have a child. Page 3 of 4 8. The same couple decide to use a healthy sperm donor with the mother’s egg. What are their chances that their offspring would have cystic fibrosis? What about being a carrier? C = normal, c = cystic fibrosis Mother is carrier, so is heterozygous (Cc) Sperm donor is normal, so homozygous dominant (CC) C C C CC CC c Cc Cc They will not produce a child with cystic fibrosis, however, they do have a 50% possibility of producing a child who is a carrier of cystic fibrosis, every time they have a child. 9. A human female "carrier" who is heterozygous for the recessive, sex-linked trait causing red-green color blindness, marries a normal male. What proportion of their female children will have red-green color blindness? What proportion of their male children will have red-green color blindness? Show all your work. C = normal, c = red-green color blind Female = XCXc Male = XCY C X Xc XC XC XC XCXc Y XC Y XcY Females = 100% normal (50% carriers) Males = 50% normal, 50% red-green color blind Page 4 of 4