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7.3. If X is uniform-[0, 1], then If Y is uniform=[b, a + b], then ! " #1 eit(a+b) − eitb it(aX+b) it(ax+b) E e e dx = . = iat 0 $ itY % # E e = b a+b eity eit(a+b) − eitb dy = . a iat −i The uniqueness theorem does the rest. Next suppose Z is uniform-[0, 1]. Then Z = ∑∞ i=1 2 Zi where the Zi ’s are i.i.d. with values in {0, 1} with probability 21 each. From Problem 1.15 we know that X = 2Z − 1 is uniform[−1, 1]. But ∞ ∞ ∞ X = ∑ 2 2Zi − 1 = ∑ 2 (2Zi − 1) = ∑ 2−i Xi , i=1 −i i=1 −i i=1 and it follows easily that the Xi ’s are i.i.d. taking values ±1 with probability 1 2 each.