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Chapter 9: Power Target Goal: I can make really good decisions . 9.1d h.w: pg 548: 23, 25 Hand draw Type I/II Curves • The probability of a Type II Error tells us the probability of accepting the null hypothesis when it is actually false. • The complement of this would be the probability of not accepting (in other words rejecting) the null hypothesis when it is actually false. (good decision!) Power • To calculate the probability of rejecting the null hypothesis when it is actually false, compute Power = 1 – P(Type II Error), Or, (1 – b). This is called the power of a significance test. • A P-value describes what would happen supposing that the null hypothesis is true. • Power describes what would happen supposing that a particular alternative hypothesis is true. Ex: Exercise is good Can a six month exercise program increase the total body mineral content (TBBMC) of young women? A team of researchers is planning a study to examine this question. Type II error calculated to be = .20. Power = 1 – β = 0.80 Interpret results: This significance test correctly rejects the null hypothesis that exercise has no effect on TBBMC 80% of the time if the true effect of exercise is a 1% increase in TBBMC. Power: the probability of rejecting the null hypothesis when it is actually false. We must use the shifted curve! How Does Power Change? Suppose Suppose that s = $85 and n = 100. H0: µ = 500 We would reject H0 for x > 513.98. Ha: μ > 500 Power is the probability of correctly rejecting H0. What is the power of the test if µ = 520? Power = 1 - .239 = .761 = .239 Rejection Region Notice that power is in the SAME curve as Power = 1 – H0: μ = 500 Suppose that s = $85 and n = 100. Ha: µ > 500 We would reject H0 for x > 513.98. Notice that, as the distance between the null hypothesized value for m and our alternative value for m increases, decreases AND power Find b and power. increases. If we reject H0, then m > 500. What if m = 530? b = .03 Power = .97 vs, Rejection Region 530 520 . H0: m = 500 Suppose that s = $85 and n = 100. Ha: m > 500 We would reject H0 for x > 513.98. Find and power. = .03 = .68 If the null hypothesis is false, then m > 500. that, as the distance What if m = 510? between Notice the null hypothesized value for μ and our alternative value for μ decreases, β power = .97 vs. increases AND power decreases. power = .32 Rejection Region Suppose that s = $85 and n = 100. H0: m = 500 Ha: m > 500 What happens if we use = .01? and power will willaincrease decrease. Rejection Region Rejection Region Power Power What happens to a, , & power when standard deviation the sample size isTheincreased? Thedecrease significance level (a) will making remains thetaller same –and so theand the curve β decreases Reject H0where the rejection value skinnier. power increases! Fail to Reject H0 region begins must move. a m0 Power ma If power is too small, increase the Power 1. Increase α. 2. Consider an alternative that is further away from μo. 3. Increase the sample size. 4. Decrease σ. What does this look like? Increase α. Slides reference point to the left. Consider an alternative that is further away from μo. Shift “new” curve to the right. Increase the sample size. Less spread and narrower curve. Decrease σ. Less spread and narrower curve. Read 542 - 544 • Explore on your own applet on page 543.