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Conditional Probability • Idea – have performed a chance experiment but don’t know the outcome (ω), but have some partial information (event A) about ω. Question: given this partial information what’s the probability that the outcome is in some event B? • Example: Toss a coin 3 times. We are interested in event B that there are 2 or more heads. The sample space has 8 equally likely outcomes. HHH , HHT , HTH , THH , HTT , THT , TTH , TTT The probability of the event B is … Suppose we know that the first coin came up H. Let A be the event the first outcome is H. Then A HHH , HHT , HTH , HTT and A B HHH , HHT , HTH The conditional probability of B given A is 3 3 8 P A B 4 week 3 48 P A 1 • Given a probability space (Ω, F, P) and events A, B F with P(A) > 0 The conditional probability of B given the information that A has occurred is P B | A P A B P A • Example: We toss a die. What is the probability of observing the number 6 given that the outcome is even? • Does this give rise to a valid probability measure? • Theorem If A F and P(A) > 0 then (Ω, F, Q) is a probability space where Q : F R is defined by Q(B) = P(B | A). Proof: week 3 2 • The fact that conditional probability is a valid probability measure allows the following: PB | A 1 PB | A , A, B F, P(A) >0 PB1 B2 | A PB1 | A PB2 | A PB1 B2 | A for any A, B1, B2 F, P(A) >0. week 3 3 Multiplication rule • For any two events A and B, P( A B) PB | AP A • For any 3 events A, B and C, P A B C P APB | APC | A B • In general, n 1 n P Ai P A1 P A2 | A1 P A3 | A1 A2 P An | Ai i 1 i 1 • Example: An urn initially contains 10 balls, 3 blue and 7 white. We draw a ball and note its colure; then we replace it and add one more of the same colure. We repeat this process 3 times. What is the probability that the first 2 balls drawn are blue and the third one is white? Solution: week 3 4 Law of total probability • Definition: For a probability space (Ω, F, P), a partition of Ω is a countable collection Bi of events such that Bi F , Bi B j and Bi . i • Theorem: If B1 , B2 ,... is a partition of Ω such that PBi 0 i then P A P A | Bi PBi • Proof: for any A F . i week 3 5 Examples 1. Calculation of PB2 for the Urn example. 2. In a certain population 5% of the females and 8% of the males are lefthanded; 48% of the population are males. What proportion of the population is left-handed? Suppose 1 person from the population is chosen at random; what is the probability that this person is left-handed? week 3 6 Bayes’ Rule • Let B1 , B2 ,... be a partition of Ω such that PBi 0 for all i then PB j | A PA | B j PB j P A | B PB i for any A F . i i • Example: A test for a disease correctly diagnoses a diseased person as having the disease with probability 0.85. The test incorrectly diagnoses someone without the disease as having the disease with probability 0.1 If 1% of the people in a population have the disease, what is the probability that a person from this population who tests positive for the disease actually has it? (a) 0.0085 (b) 0.0791 (c) 0.1075 (d) 0.1500 (e) 0.9000 week 3 7 Independence • Example: Roll a 6-sided die twice. Define the following events A : 3 or less on first roll B : Sum is odd. • If occurrence of one event does not affect the probability that the other occurs than A, B are independent. week 3 8 • Definition Events A and B are independent if P A B P APB • Note: Independence ≠ disjoint. Two disjoint events are independent if and only if the probability of one of them is zero. • Generalized to more than 2 events: A collection of events A1 , A2 ,... An is (mutually) independent if for any subcollection Ai , Ai ,... Ai 1 2 m P Ai1 Ai2 Aim P Ai1 P Ai2 P Aim • Note: pairwize independence does not guarantee mutual independence. week 3 9 Example • Roll a die twice. Define the following events; A: 1st die odd B: 2nd die odd C: sum is odd. week 3 10 Example • Let R, S and T be independent, equally likely events with common probability 1/3. What is PR S T ? • Solution: week 3 11 Claim • If A, B are independent so are A, B and A, B and A, B . • Proof: week 3 12