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Information Extraction
from the World Wide Web
Part III: HMM Learning & CRFs
CSE 454
Administrivia
• Congratulations
– ACM Programming Contest
– #2 - The Ministry of Silly Walks
Jason Kivlighn, Scott Shawcroft, Alyssa Harding
© Daniel S. Weld
Landscape of IE Techniques: Models
Classify Pre-segmented
Candidates
Lexicons
Abraham Lincoln was born in Kentucky.
member?
Alabama
Alaska
…
Wisconsin
Wyoming
Boundary Models
Abraham Lincoln was born in Kentucky.
Abraham Lincoln was born in Kentucky.
Sliding Window
Abraham Lincoln was born in Kentucky.
Classifier
Classifier
which class?
which class?
Try alternate
window sizes:
Finite State Machines
Abraham Lincoln was born in Kentucky.
Context Free Grammars
Abraham Lincoln was born in Kentucky.
BEGIN
Most likely state sequence?
NNP
NNP
V
V
P
Classifier
PP
which class?
VP
NP
BEGIN
END
BEGIN
NP
END
Each model can capture words, formatting, or both
VP
S
Slides from Cohen & McCallum
Hidden Markov Models (HMMs)
standard sequence model in genomics, speech, NLP, …
Graphical model
Finite state model
S t-1
St
S t+1
...
...
observations
...
O
Generates:
State
sequence
Observation
sequence
transitions
Ot
t -1
O t +1

|o|
o1
o2
o3
o4
o5
o6
o7
o8
 
P(s , o )   P(st | st 1 ) P(ot | st )
t 1
Parameters: for all states S={s1,s2,…}
Start state probabilities: P(st )
Transition probabilities:
P(st|st-1 )
Usually a multinomial over
atomic, fixed alphabet
Observation (emission) probabilities: P(ot|st )
Training:
Maximize probability of training observations (w/
prior)
Slides
from Cohen & McCallum
Definition of a hidden Markov model
Definition: A hidden Markov model (HMM)
• Alphabet
 = { b1, b2, …, bM }
• Set of states Q = { 1, ..., K }
• Transition probabilities between any two states
1
2
K
…
aij = transition prob from state i to state j
ai1 + … + aiK = 1, for all states i = 1…K
• Start probabilities a0i
a01 + … + a0K = 1
• Emission probabilities within each state
ei(b) = P( xi = b | i = k)
ei(b1) + … + ei(bM) = 1, for all states i = 1…K
Slides from Serafim Batzoglou
Example: The Dishonest Casino
A casino has two dice:
• Fair die
P(1) = P(2) = P(3) = P(5) = P(6) = 1/6
• Loaded die
P(1) = P(2) = P(3) = P(5) = 1/10
P(6) = 1/2
Casino player switches back-&-forth between
fair and loaded die once every 20 turns
Game:
1. You bet $1
2. You roll (always with a fair die)
3. Casino player rolls (maybe with fair die,
maybe with loaded die)
4. Highest number wins $2
Slides from Serafim Batzoglou
The dishonest casino model
0.05
0.95
FAIR
P(1|F) = 1/6
P(2|F) = 1/6
P(3|F) = 1/6
P(4|F) = 1/6
P(5|F) = 1/6
P(6|F) = 1/6
0.95
LOADED
0.05
P(1|L) = 1/10
P(2|L) = 1/10
P(3|L) = 1/10
P(4|L) = 1/10
P(5|L) = 1/10
P(6|L) = 1/2
Slides from Serafim Batzoglou
Information Extraction with HMMs
• Example - Research Paper Headers
© Daniel S. Weld
Slide by Okan Basegmez
8
HMMs for Info Extraction
For sparse extraction tasks :
• Separate HMM for each type of target
• Each HMM should
– Model entire document
– Consist of target and non-target states
– Not necessarily fully connected
Given HMM, how extract info?
© Daniel S. Weld
Slide by Okan Basegmez
9
A parse of a sequence
Given a sequence x = x1……xN,
A parse of x is a sequence of states  = 1, ……, N
1
1
1
…
1
2
2
2
…
2
…
…
…
K
K
K
x1
x2
x3
…
…
K
xK
Slides from Serafim Batzoglou
Question # 1 – Evaluation
GIVEN
A sequence of observations (e.g., rolls by the casino player)
1245526462146146136136661664661636616366163616515615115146123562344
QUESTION
How likely is this sequence, given our HMM ?
This is the EVALUATION problem in HMMs
Slides from Serafim Batzoglou
Question # 2 – Decoding
GIVEN
A sequence of rolls by the casino player
1245526462146146136136661664661636616366163616515615115146123562344
QUESTION
What portion of the sequence was generated with the fair die, and
what portion with the loaded die?
This is the DECODING question in HMMs
Slides from Serafim Batzoglou
Question # 3 – Learning
GIVEN
A sequence of rolls by the casino player
1245526462146146136136661664661636616366163616515615115146123562344
QUESTION
How “loaded” is the loaded die? How “fair” is the fair die? How often does
the casino player change from fair to loaded, and back?
This is the LEARNING question in HMMs
Slides from Serafim Batzoglou
Decoding Problem
Find the best parse of a
sequence
Slides from Serafim Batzoglou
Decoding
GIVEN x = x1x2……xN
We want to find  = 1, ……, N,
such that P[ x,  ] is maximized
1
1
1
…
1
2
2
2
…
2
…
…
…
K
K
K
x1
x2
x3
…
…
K
* = argmax P[ x,  ]
We can use dynamic programming!
xK
Let Vk(i) = max{1,…,i-1} P[x1…xi-1, 1, …, i-1, xi, i = k]
= Probability of most likely sequence of states ending at
state i = k
Slides from Serafim Batzoglou
Decoding – main idea
Given that for all states k,
and for a fixed position i,
Vk(i) = max{1,…,i-1} P[x1…xi-1, 1, …, i-1, xi, i = k]
What is Vl(i+1)?
From definition,
Vl(i+1) = max{1,…,i}P[ x1…xi, 1, …, i, xi+1, i+1 = l ]
= max{1,…,i}P(xi+1, i+1 = l | x1…xi,1,…, i) P[x1…xi, 1,…, i]
= max{1,…,i}P(xi+1, i+1 = l | i ) P[x1…xi-1, 1, …, i-1, xi, i]
= maxk [P(xi+1, i+1 = l | i = k) max{1,…,i-1}P[x1…xi-1,1,…,i-1, xi,i=k]]
= el(xi+1) maxk akl Vk(i)
Remember:
Vk(i) = probability of most likely state seq ending with state i = k
Slides from Serafim Batzoglou
The Viterbi Algorithm
Dynamic Programming
x1 x2 ……xi xi+1……………………………..xN
State 1
2
j
Vj(i+1)
K
Time:
O(K2N)
Space:
O(KN)
Remember:
Vk(i) = probability of most likely state seq ending with state i = k
Slides from Serafim Batzoglou
Decoding = Extraction
• Example - Research Paper Headers
Pedro Domingos
Fig from Okan Basegmez
© Daniel S. Weld
18
Evaluation Problem
What’s the probability that this
observations sequence would have
been generated by HMM ?
Slides from Serafim Batzoglou
Why Do We Care?
• It will be important for learning…
The Forward Algorithm
We want to calculate
P(x) = probability of x, given the HMM
Sum over all possible ways of generating x:
P(x) =  P(x, ) =  P(x | ) P()
To avoid summing over an exponential number of paths , define
fk(i) = P(x1…xi, i = k)
(the forward probability)
Slides from Serafim Batzoglou
Forward Probabilities
• What is the probability that, given an HMM
at time t,
– the state is si, and
– the partial observation o1 … ot has been emitted?

t (i)  P(o1... ot , qt  si | )
ft
© Daniel S. Weld
Slide by Bonnie Dorr
23

Problem 1:
Probability of an Observation Sequence
• What is P(O |  ) ?
• The probability of an observation sequence is
– the sum of the probabilities of all possible state
sequences in the HMM times the chance that they
 emitted the observations
• Naïve computation is very expensive.
– Given T observations and N states, there are NT
possible state sequences.
• Even small HMMs, e.g. T=10 and N=10,
– contain 10 billion different paths
• Solution to this and problem 2 is
– Use dynamic programming
© Daniel S. Weld
Slide by Bonnie Dorr
24
Forward Probabilities
t (i)  P(o1...ot , qt  si | )

© Daniel S. Weld
Slide by Bonnie Dorr
N

 t ( j)   t1(i) aij b j (ot )
i1

25
Relation between Forward and Viterbi
VITERBI
FORWARD
Initialization:
V0(0) = 1
Vk(0) = 0, for all k > 0
Initialization:
f0(0) = 1
fk(0) = 0, for all k > 0
Iteration:
Iteration:
Vj(i) = ej(xi) maxk Vk(i-1) akj
Termination:
P(x, *) = maxk Vk(N)
fl(i) = el(xi) k fk(i-1) akl
Termination:
P(x) = k fk(N) ak0
Slides from Serafim Batzoglou
Backward Probabilities
t (i)  P(ot 1...oT | qt  si, )

© Daniel S. Weld
Slide by Bonnie Dorr
N

 t (i)   aijb j (ot 1) t 1 ( j) 


j1

27
Computational Complexity
What is the running time, and space required, for Forward, and Backward?
Time: O(K2N)
Space: O(KN)
Useful implementation technique to avoid underflows
Viterbi:
sum of logs
Forward/Backward: rescaling at each position by multiplying by a
constant
Slides from Serafim Batzoglou
Learning Problem
Find the most likely HMM
given observed sequence
Slides from Serafim Batzoglou
We Need to Learn This ?!?
Definition: A hidden Markov model (HMM)
• Alphabet
 = { b1, b2, …, bM }
• Set of states Q = { 1, ..., K }
• Transition probabilities between any two states
1
2
K
…
aij = transition prob from state i to state j
ai1 + … + aiK = 1, for all states i = 1…K
• Start probabilities a0i
a01 + … + a0K = 1
• Emission probabilities within each state
ei(b) = P( xi = b | i = k)
ei(b1) + … + ei(bM) = 1, for all states i = 1…K
Slides from Serafim Batzoglou
How Learn HMM?
• Two questions: structure & parameters
© Daniel S. Weld
36
Simplest Case
• Fix structure
• Learn transition & emission probabilities
• Training data…?
– Label each word as target or non-target
• Challenges
– Sparse training data
– Unseen words have…
– Smoothing!
© Daniel S. Weld
37
Problem 3: Learning
• So far: assumed we know the underlying model
– A, E, A0
  (A,B,  )
• Often these parameters are estimated on annotated
training data, which has 2 drawbacks:
– Annotation is difficult and/or expensive

– Training data is different from the current data
• We want to maximize the parameters with respect to
the current data, i.e., we’re looking for a model ' ,
such that
' argmax P(O | )

© Daniel S. Weld
Slide by Bonnie Dorr
38
Problem 3: Learning
• Unfortunately, there is no known way to
analytically find a global maximum, i.e., a
model ' , such that ' argmax P(O | )

• But it is possible to find a local maximum!

 model  , we can always find
• Given an initial
a model ' , such that
P(O | ')  P(O |  )

© Daniel S. Weld
Slide by Bonnie Dorr


39
Parameter Re-estimation
• Use a hill-climbing algorithm
– Called the forward-backward algorithm
– (or Baum-Welch) algorithm
• Idea:
– 0. Use an initial parameter instantiation
– 1. Loop
• Iteratively re-estimate the parameters
• Improve the probability that given observation are
generated by the new parameters
– 2. Until estimates don’t change much
© Daniel S. Weld
Slide by Bonnie Dorr
40
Parameter Re-estimation
• Three parameters need to be re-estimated:

– Initial state distribution:
i
– Transition probabilities: ai,j
– Emission probabilities: ei(ot)

© Daniel S. Weld
Slide by Bonnie Dorr
41
Expectation Maximization
• The forward-backward algorithm is an instance
of the more general EM algorithm
– The E Step: Compute the forward and backward
probabilities for a give model
– The M Step: Re-estimate the model parameters
© Daniel S. Weld
Slide by Bonnie Dorr
42
Chicken & Egg Problem
• If we knew the actual sequence of states
– It would be easy to learn ai,j and ei(ot)
– But we can’t observe states, so we don’t!
• If we knew transition & emission probabilities,
• Then it’d be easy to estimate the sequence of states
• Viterbi Algorithm
• But we don’t know them!
© Daniel S. Weld
43
Expectation Maximization (EM)
(high-level version)
• Pretend we do know the parameters
– Initialize randomly
• [E step] Compute probability of instance
having each possible value of the hidden
variable (e.g. which state)
• [M step] Treating each instance as fractionally
having every value,
compute the new parameters (e.g. ai,j, ei(ot) )
• Iterate until convergence!
© Daniel S. Weld
44
Simplest Version
• Mixture of two distributions
.01 .03 .05 .07 .09
• Know: form of distribution & variance, % =5
• Just need mean of each distribution
© Daniel S. Weld
45
Input Looks Like
.01
© Daniel S. Weld
.03
.05
.07
46
.09
We Want to Predict
?
.01
© Daniel S. Weld
.03
.05
.07
47
.09
Chicken & Egg
Note that coloring instances would be easy
if we knew Gausians….
.01
© Daniel S. Weld
.03
.05
.07
48
.09
Chicken & Egg
And finding the Gausians would be easy
If we knew the coloring
.01
© Daniel S. Weld
.03
.05
.07
49
.09
Expectation Maximization (EM)
• Pretend we do know the parameters
– Initialize randomly: set
1=?; 2=?
.01 .03 .05 .07 .09
© Daniel S. Weld
50
Expectation Maximization (EM)
• Pretend we do know the parameters
– Initialize randomly
• [E step] Compute probability of instance having each
possible value of the hidden variable
.01
© Daniel S. Weld
.03
.05
.07
51
.09
Expectation Maximization (EM)
• Pretend we do know the parameters
– Initialize randomly
• [E step] Compute probability of instance having each
possible value of the hidden variable
.01
© Daniel S. Weld
.03
.05
.07
52
.09
Expectation Maximization (EM)
• Pretend we do know the parameters
– Initialize randomly
• [E step] Compute probability of instance having each
possible value of the hidden variable
[M step] Treating each instance as fractionally
having both values compute the new parameter
values
.01
© Daniel S. Weld
.03
.05
.07
53
.09
ML Mean of Single Gaussian
Uml = argminu
© Daniel S. Weld
 (x – u)
i
i
2
.01 .03 .05 .07 .09
54
Expectation Maximization (EM)
•
• [E step] Compute probability of instance having each
possible value of the hidden variable
[M step] Treating each instance as fractionally having
both values compute the new parameter values
.01
© Daniel S. Weld
.03
.05
.07
55
.09
Expectation Maximization (EM)
• [E step] Compute probability of instance having each
possible value of the hidden variable
.01
© Daniel S. Weld
.03
.05
.07
56
.09
Expectation Maximization (EM)
• [E step] Compute probability of instance having each
possible value of the hidden variable
[M step] Treating each instance as fractionally having
both values compute the new parameter values
.01
© Daniel S. Weld
.03
.05
.07
57
.09
Expectation Maximization (EM)
• [E step] Compute probability of instance having each
possible value of the hidden variable
[M step] Treating each instance as fractionally having
both values compute the new parameter values
.01
© Daniel S. Weld
.03
.05
.07
58
.09
Iterate
© Daniel S. Weld
59
Until Convergence
• Problems
– Need to assume form of distribution
– Local Maxima
• But
– It really works in practice!
– Can easilly extend to multiple variables
• E.g. Mean & Variance
• Or much more complex models…
© Daniel S. Weld
60
Parameter Re-estimation
• Use a hill-climbing algorithm
– Called the forward-backward algorithm
– (or Baum-Welch) algorithm
• Idea:
– 0. Use an initial parameter instantiation
– 1. Loop
• Iteratively re-estimate the parameters
• Improve the probability that given observation are
generated by the new parameters
– 2. Until estimates don’t change much
© Daniel S. Weld
Slide by Bonnie Dorr
61
Parameter Re-estimation
• Two parameters need to be re-estimated:
– Transition probabilities: ai,j
– Emission probabilities: ei(ot)
– Can use forward & backward algorithms
© Daniel S. Weld
Slide by Bonnie Dorr
62
Re-estimating Transition
Probabilities
 t (i, j)  P(qt  si , qt 1  s j | O, )

 t (i, j) 
© Daniel S. Weld
Slide by Bonnie Dorr
 t (i) ai, j b j (ot 1 )  t 1 ( j)
N
N
  (i)64 a
t
i1 j1
i, j
b j (ot 1 )  t 1 ( j)
That was HMMs
We want More than an Atomic View of Words
Would like richer representation of text:
many arbitrary, overlapping features of the words.
S t-1
identity of word
ends in “-ski”
is capitalized
is part of a noun phrase
is “Wisniewski”
is in a list of city names
is under node X in WordNet
part of
ends in
is in bold font
noun phrase
“-ski”
is indented
O t 1
is in hyperlink anchor
last person name was female
next two words are “and Associates”
St
S t+1
…
…
Ot
O t +1
Slides from Cohen & McCallum
Problems with Richer Representation
and a Joint Model
These arbitrary features are not independent.
– Multiple levels of granularity (chars, words, phrases)
– Multiple dependent modalities (words, formatting, layout)
– Past & future
Two choices:
Model the dependencies.
Each state would have its own
Bayes Net. But we are already
starved for training data!
Ignore the dependencies.
This causes “over-counting” of
evidence (ala naïve Bayes).
Big problem when combining
evidence, as in Viterbi!
S t-1
St
S t+1
S t-1
St
O
Ot
O t +1
O
Ot
t -1
t -1
S t+1
O
Slides fromt +1
Cohen & McCallum
Conditional Sequence Models
• We prefer a model that is trained to maximize a
conditional probability rather than joint
probability:
P(s|o) instead of P(s,o):
– Can examine features, but not responsible for
generating them.
– Don’t have to explicitly model their dependencies.
– Don’t “waste modeling effort” trying to generate what
we are given at test time anyway.
Slides from Cohen & McCallum
Conditional Finite State Sequence Models
[McCallum, Freitag & Pereira, 2000]
[Lafferty, McCallum, Pereira 2001]
From HMMs to CRFs

s  s1 , s2 ,...sn

o  o1 , o2 ,...on
St-1
St
St+1
...

|o|
Joint
 
P( s , o )   P( st | st 1 ) P(ot | st )
t 1
Conditional
 
P( s | o ) 
Ot-1
Ot
Ot+1
...

|o|
1
  P( st | st 1 ) P(ot | st )
P(o ) t 1
St-1
St
St+1
...

|o|
1
    s ( st , st 1 ) o (ot , st )
Z (o ) t 1

where  o (t )  exp 

Ot-1
Ot
Ot+1
...

  k f k ( s t , ot ) 
k

(A super-special case of
Conditional Random Fields.)
Slides from Cohen & McCallum
Conditional Random Fields
[Lafferty, McCallum, Pereira 2001]
1. FSM special-case:
linear chain among unknowns, parameters tied across time steps.
St
St+1
St+2
St+3
St+4
 
P( s | o ) 

|o |
O = Ot, Ot+1, Ot+2, Ot+3, Ot+4
1

 
  exp    k f k ( st , st 1 , o , t ) 
Z (o ) t 1
 k

2. In general:
CRFs = "Conditionally-trained Markov Network"
arbitrary structure among unknowns
3. Relational Markov Networks [Taskar, Abbeel, Koller 2002]:
Parameters tied across hits from SQL-like queries ("clique templates")
4. Markov Logic Networks [Richardson & Domingos]:
Weights on arbitrary logical sentences
Slides from Cohen & McCallum
Feature Functions

Example f k (st , st 1, o, t ) :
1 if Capitalize d(ot )  si  st 1  s j  st

f Capitalized,si , s j  ( st , st 1 , o, t )  
0 otherwise
o = Yesterday Pedro Domingos spoke this example sentence.
o1
o2
s1
s2
s3
s4
o3
o4
o5
o6
o7

f Capitalized , s1 , s3  ( s1 , s2 , o,2)  1
Slides from Cohen & McCallum
Learning Parameters of CRFs
Maximize log-likelihood of parameters  {k} given training data D

|o |
 1

2k
 
L   log    exp   k f k ( st , st 1 , o, t )     2
s , o D
 k
  k 2
 Z (o ) t 1
Log-likelihood gradient:
L

k
k
 
  (i )
  (i )
 #k (s , o )   P (s '| o ) #k (s ' , o )  2
 
s , o D
i

s'

 

where #k ( s , o )   f k (st 1 , st , o , t )
t
Methods:
• iterative scaling (quite slow)
[Sha & Pereira 2002] & [Malouf 2002]
• conjugate gradient (much faster)
• limited-memory quasi-Newton methods, BFGS (super fast)
Slides from Cohen & McCallum
General CRFs vs. HMMs
• More general and expressive modeling technique
• Comparable computational efficiency
• Features may be arbitrary functions of any or all
observations
• Parameters need not fully specify generation of
observations; require less training data
• Easy to incorporate domain knowledge
• State means only “state of process”, vs
“state of process” and “observational history I’m keeping”
Slides from Cohen & McCallum
Person name Extraction
[McCallum 2001,
unpublished]
Slides from Cohen & McCallum
Person name Extraction
Slides from Cohen & McCallum
Features in Experiment
Capitalized
Xxxxx
Mixed Caps
XxXxxx
All Caps
XXXXX
Initial Cap
X….
Contains Digit
xxx5
All lowercase
xxxx
Initial
X
Punctuation
.,:;!(), etc
Period
.
Comma
,
Apostrophe
‘
Dash
Preceded by HTML tag
Character n-gram classifier
Hand-built FSM person-name
says string is a person
extractor says yes,
name (80% accurate)
(prec/recall ~ 30/95)
In stopword list
Conjunctions of all previous
(the, of, their, etc)
feature pairs, evaluated at
the current time step.
In honorific list
(Mr, Mrs, Dr, Sen, etc)
Conjunctions of all previous
feature pairs, evaluated at
In person suffix list
current step and one step
(Jr, Sr, PhD, etc)
ahead.
In name particle list
All previous features, evaluated
(de, la, van, der, etc)
two steps ahead.
In Census lastname list;
All previous features, evaluated
segmented by P(name)
one step behind.
In Census firstname list;
segmented by P(name)
In locations lists
(states, cities, countries)
In company name list
(“J. C. Penny”)
Total number of features = ~500k
In list of company suffixes
(Inc, & Associates, Foundation)
Slides from Cohen & McCallum
Training and Testing
• Trained on 65k words from 85 pages, 30
different companies’ web sites.
• Training takes 4 hours on a 1 GHz Pentium.
• Training precision/recall is 96% / 96%.
• Tested on different set of web pages with
similar size characteristics.
• Testing precision is 92 – 95%,
recall is 89 – 91%.
Slides from Cohen & McCallum
Limitations of Finite State Models
• Finite state models have a linear structure
• Web documents have a hierarchical
structure
– Are we suffering by not modeling this structure
more explicitly?
• How can one learn a hierarchical extraction
model?
Slides from Cohen & McCallum
IE Resources
• Data
– RISE, http://www.isi.edu/~muslea/RISE/index.html
– Linguistic Data Consortium (LDC)
• Penn Treebank, Named Entities, Relations, etc.
– http://www.biostat.wisc.edu/~craven/ie
– http://www.cs.umass.edu/~mccallum/data
• Code
– TextPro, http://www.ai.sri.com/~appelt/TextPro
– MALLET, http://www.cs.umass.edu/~mccallum/mallet
– SecondString, http://secondstring.sourceforge.net/
• Both
– http://www.cis.upenn.edu/~adwait/penntools.html
Slides from Cohen & McCallum
References
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Slides from Cohen & McCallum
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