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Transcript
```II Nonlinear wave equations
2.1 Introduction
•
•
•
•
Introduction
Solitary waves
Korteweg-deVries (KdV) equation
Nonlinear Schrodinger equation
Introduction
Linear wave equations
• Simplest (second order) linear wave equation
utt – c2uxx = 0
• D’Alembert’s solution
u(x,t) = f(x-ct) + g(x+ct)
f, g arbitrary functions
Dispersionless
Dissipationless
Dispersion relation w = ck
Introduction
Linear wave equations
• Simplest Linear
ut – cux = 0
or
ut + cux = 0
u(x,t) = f(x+ct)
or
u(x,t) = f(x-ct)
• Simplest Dispersive, Dissipationless
ut + cux + auxxx = 0
u(x,t) = exp[i(kx – wt)]
w = ck - ak3
• Simplest Nondispersive, Dissipative
ut + cux - auxx = 0
u(x,t) = exp[i(kx – wt)]
w = ck – iak2
Introduction
Nonlinear wave equations
• Simplest Nonlinear
ut + (1+u)ux = 0
u(x,t) = f(x-(1+u)t)
Sharpens at leading and trailing edges (shock formation)
• Korteweg deVries (KdV) Equation (1895)
ut + (1+u)ux + uxxx = 0

c
2  c
 ( x - ct - x o 
u(x, t)   sech 
2
 2

Solitary wave/soliton behaviour
Dispersion and tendency to shock formation in balance
2.2 Solitary waves
Over one hundred and fifty years ago,
while conducting experiments to
determine the most efficient design for
canal boats, a young Scottish engineer
named John Scott Russell (1808-1882)
Here is an extract from
John Scott Russell’s ‘Report on waves’
Solitary waves
Russell’s report on waves
“I was observing the motion of a boat which was rapidly drawn along a
narrow channel by a pair of horses, when the boat suddenly stopped - not
so the mass of water in the channel which it had put in motion; it
accumulated round the prow of the vessel in a state of violent agitation,
then suddenly leaving it behind, rolled forward with great velocity,
assuming the form of a large solitary elevation, a rounded, smooth and
well-defined heap of water, which continued its course along the channel
apparently without change of form or diminution of speed. I followed it
on horseback, and overtook it still rolling on at a rate of some eight or
nine miles an hour, preserving its original figure some thirty feet long
and a foot to a foot and a half in height. Its height gradually diminished,
and after a chase of one or two miles I lost it in the windings of the
channel. Such, in the month of August 1834, was my first chance
interview with that singular and beautiful phenomenon which I have
called the Wave of Translation”.
2.3 Korteweg deVries (KdV) equation
• The wave of translation (or solitary wave) observed by
John Scott Russell is described by a nonlinear wave
equation known as the Korteweg-deVries (KdV) equation.
u t - 6uu x  u xxx  0
• We review various possible types of nonlinearity in wave
equations before studying two specific equations – the
KdV and the nonlinear Schrodinger (NLS) equations.
Korteweg deVries (KdV) equation
Numerical solution (strong dispersive term)
'wave.dat'
1.8
1.6
1.4
1.2
1
0.8
0.6
0.4
0.2
0
-0.2
0
2
20 40
1.5
60 80
1
0.5
100 120
1400
3
2.5
4
3.5
Korteweg deVries (KdV) equation
Numerical solution (weak dispersive term)
'wave.dat'
2
1.8
1.6
1.4
1.2
1
0.8
0.6
0.4
0.2
0
-0.2
0
2
20 40
1.5
60 80
1
0.5
100 120
1400
3
2.5
4
3.5
Korteweg deVries (KdV) equation
Effect of nonlinear term ut = -(1+u)ux
1.5
The sequence of plots at t = 0, Dt
and 2Dt illustrate how a pulse
forms and splits off from the
leading edge of a smooth front.
1
u(Dt)
-(1+u(Dt))ux(Dt)
0.5
2
4
6
1
10
-0.5
ux(Dt)
-1
1.5
8
1.5
u(0)
1
u(2Dt)
-(1+u(0))ux(0)
0.5
0.5
2
-0.5
-1
4
6
ux(0)
8
10
2
-0.5
-1
4
6
8
10
Korteweg deVries (KdV) equation
Effect of dispersive term ut = - uxxx
1.5
1
u(0)
-uxxx(0)
0.5
2
4
6
8
10
Combined effects of nonlinear
and dispersive terms
-0.5
-1
1.5
1
1.5
u(0)
u(2Dt)
u(Dt)
1
0.5
0.5
2
4
6
8
10
2
-0.5
-0.5
-1
-1
4
6
8
10
Korteweg deVries (KdV) equation
Soliton simulations
These simulations come from
Klaus Brauer's webpage (Osnabrück)
Korteweg deVries (KdV) equation
Solution for PBC and sinusoidal initial conditions
This animation by K. Takasaki shows the sinusoidal initial
state breaking up into a soliton train. Zabusky and Kruskal
(1966).
Korteweg deVries (KdV) equation
Analytic solution
•KdV equation u t 6uux  u xxx  0
•Let the solution be u = u(x,t) and consider a change of
variables x = x – ct and t = t
•Call the function in new variables f(x,t)
•The change in u or f brought about by translations (dx, dt) or
(x, t) is
du  u dx  u dt
x
t
df  f dx  f dt
x
t
dx  dx - c dt
dt  dt
Korteweg deVries (KdV) equation
Analytic solution
• If we convert the change in f brought about by translations
through (dx, dt) into changes in f brought about by translations
through (dx, dt)
df  f dx - c dt   f dt

x 
t
df  f dx  f -c f dt
x
t x
•Since u and f represent the same function the same translation
(dx, dt) must produce the same change in either. Hence







u  f
x x
u  f -c f
t t x







Korteweg deVries (KdV) equation
Analytic solution
• When transforming the pde from (x, t) to (x, t) we must
make the replacements
  
x x
   -c 
t t x
• In the (x, t) variables a soliton moves along the x axis as
•In the (x, t) variables a soliton is stationary in time provided
we choose c in the transformation to be the soliton velocity
Korteweg deVries (KdV) equation
Analytic solution
• The conventional form for the KdV equation is
u t - 6uu x  u xxx  0
• Travelling wave solutions have the form
u(x, t)  f(x )
x  x - ct
c is the wave velocity
• Substituting for u in the KdV equation and setting the time
derivative to zero we obtain
- cf x - 6ff x  f xxx  0
Korteweg deVries (KdV) equation
Analytic solution
•Integrate twice wrt x
 dx - cf x - 6ff x  f xxx   0
- cf - 3f 2  f xx  A


2
d
x
f
cf
3f
 f xx   dxf x A
 x
c 2
1
2
3
- f - f  f x   Af  B
2
2
1
2
3 c 2
f x   f  f  Af  B
2
2
Korteweg deVries (KdV) equation
Analytic solution
• A and B are constants of integration. In order to have a
localised traveling wave packet, we impose boundary
conditions: f, f x , f xx all tend to zero as |x| goes to infinity.
• To ensure these conditions we set A = B = 0. Solutions
also exist at zeros of the polynomial in f.
• The solution with A = B = 0 obeys
f 
x
2
 f 2 2f  c
• Rearrange to
df
 f 2f  c    dx
Korteweg deVries (KdV) equation
Analytic solution
• Make change of variable
c
f  - sech 2
2
df
 f 2f  c becomes
 d
c sech 2 tanh 
c
- sech 2 c tanh 2 
2
xo
2

 x 
c
c
-
2
d

c
• Last term on rhs is constant of integration
Korteweg deVries (KdV) equation
Analytic solution
• Rearrange to
c
 x - x o 

2
• Make back substitution

c
2  c
 ( x - ct - x o 
f   sech 
2
 2

2
sech   
e  e 
d
sech   - sech  tanh 
d
2.4 Nonlinear Schrödinger equation
• The naming of the nonlinear Schrödinger (NLS) equation
becomes obvious when it is compared to the time-dependent
Schrödinger equation from quantum mechanics
iψ  P ψxx  Q ψ 2 ψ  0
t
2

iψ 
ψxx  V ψ  0
t 2m
• The NLS can be derived for wave packets localised in k
space for systems where the dispersion relation depends on
2
wave intensity w  w (k,  )
Nonlinear Schrödinger equation
Derivation from dispersion relation
• Consider the superposition of 2 waves of similar
wavenumber and frequency
ψ1  cos[(k  Dk)x - (w  Dw ) t]
ψ 2  cos[(k  Dk)x - (w  Dw ) t]
ψ1  ψ 2  2 cos [Dk x - Dwt] cos[kx - wt]
• The result is a slow envelope wave with group velocity
vg = Dw/ D k and a rapid carrier wave with velocity w/k
• Simulation with Dw/Dk = 1 and w/k = 20
Nonlinear Schrödinger equation
Derivation from dispersion relation
• The NLS is derived from the dispersion relation for the
envelope function which has a slow time variation cf the
carrier waves
2
• Suppose that the dispersion relationship is w  w (k,  )
Make a Taylor expansion of this about ko and zero intensity
ω
ω - ωo 
k

1 ω
(k  k o ) 
2! k 2
2
wo


  ...
2
2
o
2
wo
(k  k o ) 2  ...
Nonlinear Schrödinger equation
Derivation from dispersion relation
• Let
Ωω-ω
Kk –k
o
ω
v 
g
k ω ,  2
o
2P 
o
o
 2ω
k 2 ω ,  2
o
o
Q
ω
ψ2
ω ,ψ
• Then the Taylor expanded dispersion relation becomes
  v g K  PK  Q 
2
2
o
2
o
Nonlinear Schrödinger equation
Derivation from dispersion relation
• Consider a wavepacket constructed from a small group of
waves in slow variables X = ex, T = et e <<1

 (x, t)   (k, w ) exp[i(kx - wt)] dk dw
-

KX T
   (K, ) exp[i(
)] dK d * exp[i(k o x - w o t)]
e
e
-

KX T
 (X, T)    (K, ) exp[i(
)] dK d * carrier wa ve
e
e
-
• The latter is the envelope function in ‘slow’ variables X,T
Nonlinear Schrödinger equation
Derivation from dispersion relation

 
KX T
 (X, T) 
)] dK d
  (K, ) exp[i(
X
X - 
e
e
iK 
KX T

)] dK d
  (K, ) exp[i(
e -
e
e
iK
  (X, T)
e

iK


K  ie
X
e
X

i


  ie
T
e
T
Nonlinear Schrödinger equation
Derivation from dispersion relation
• The dispersion relation
  v g K  PK  Q 
2
2
becomes
2

 
 
2


2
ie
  v g  - ie
  P - ie
   e Q 
T
X 
X 


ie T  - iev g X  e P XX  e Q 
2
2
• Make further change of variables
x  X - v g T t  eT

 



e
 vg
X
x T
t
x
2
Nonlinear Schrödinger equation
Derivation from dispersion relation
ie T  - iev g X  e P XX  e Q 
2
2
2
becomes
i  P 
t
i  
t
 Q   0
2
xx
 q   0
2
xx
• This is the conventional form for the NLS equation. It has
an envelope solution with a sech profile. (See handout)
Nonlinear Schrödinger equation
Application to lattice dynamics
• Hooke’s Law plus additional nonlinear term
1 2 AK 4
U(r)  Kr 
r
2
4
dU(r)
F(r)   -Kr  AKr 3
dr
• Equation of motion

mu n  K(u n 1  2u n  u n 1 )  AK (u n 1  u n ) 3  (u n  u n -1 ) 3
• Solution and dispersion relation
u n  R exp[i(kna - wt)]  c.c.
K  ka 
2
2  ka 
ω2
sin  1  6A R sin  
m  2 
 2 

Nonlinear Schrödinger equation
Application to lattice dynamics
• We have just seen that introduction of a nonlinear term in the
force law for a 1-D chain of atoms leads to a dispersion
relation which depends on |R|2. At the website below, use the
monatomic chain applet to see some of these localised modes.
•Intrinsic localised modes in lattice dynamics of crystals
K  ka  
2
 ka 
sin   1  6A R sin 2  
m  2 
 2 
K  ka 
ω2
sin  
m  2
ω2
1
0.8
0.6
0.4
0.2
k
0.5
1
1.5
2
2.5
3
Nonlinear Schrödinger equation
Application to lattice dynamics
• Click on monatomic 1-D chains and then on the link in the
title to the page (works best with Internet Explorer)
•You will find stationary ILM with
• envelope function (c.f. solutions of NLS equation) is
composed of groups of waves centred on the Brillouin zone
boundary (k = p) (group velocity zero)
• moving ILM composed of groups of waves centred away
from the Brillouin zone boundary (group velocity nonzero)
Nonlinear Schrödinger equation
Application to lattice dynamics
• You will also find
• molecular dynamics simulations showing ILM in 3-D
crystals (click on 3-D Ionic crystals)
•Simulations showing ILM in 1-D chains of interacting spins
Nonlinear Schrödinger equation
Application to optical communications
• Read the introductory articles on
• Solitons in optical communications by Ablowitz et al.
• Historical aspects of optical solitons by Hasegawa
• Soliton propagation in optical fibres
```
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