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AND Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 1 Chapter 13 Statistics Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 2 WHAT YOU WILL LEARN • Mode, median, mean, and midrange • Percentiles and quartiles • Range and standard deviation Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 3 Section 5 Measures of Central Tendency Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 4 Definitions An average is a number that is representative of a group of data. The arithmetic mean, or simply the mean, is symbolized by x , when it is a sample of a population or by the Greek letter mu, , when it is the entire population. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 5 Mean The mean, x , is the sum of the data divided by the number of pieces of data. The formula for calculating the mean is x x n where x represents the sum of all the data and n represents the number of pieces of data. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 6 Example-find the mean Find the mean amount of money parents spent on new school supplies and clothes if 5 parents randomly surveyed replied as follows: $327 $465 $672 $150 $230 x $327 $465 $672 $150 $230 x n $1844 $368.80 5 Copyright © 2009 Pearson Education, Inc. 5 Chapter 13 Section 5 - Slide 7 Median The median is the value in the middle of a set of ranked data. Example: Determine the median of $327 $465 $672 $150 $230. Rank the data from smallest to largest. $150 $230 $327 $465 $672 middle value (median) Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 8 Example: Median (even data) Determine the median of the following set of data: 8, 15, 9, 3, 4, 7, 11, 12, 6, 4. Rank the data: 3 4 4 6 7 8 9 11 12 15 There are 10 pieces of data so the median will lie halfway between the two middle pieces (the 7 and 8). The median is (7 + 8)/2 = 7.5 3 4 4 6 7 8 9 11 12 15 Median = 7.5 Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 9 Mode The mode is the piece of data that occurs most frequently. Example: Determine the mode of the data set: 3, 4, 4, 6, 7, 8, 9, 11, 12, 15. The mode is 4 since it occurs twice and the other values only occur once. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 10 Midrange The midrange is the value halfway between the lowest (L) and highest (H) values in a set of data. lowest value + highest value Midrange = 2 Example: Find the midrange of the data set $327, $465, $672, $150, $230. $150 + $672 Midrange = $411 2 Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 11 Example The weights of eight Labrador retrievers rounded to the nearest pound are 85, 92, 88, 75, 94, 88, 84, and 101. Determine the a) mean b) median c) mode d) midrange e) rank the measures of central tendency from lowest to highest. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 12 Example--dog weights 85, 92, 88, 75, 94, 88, 84, 101 (continued) a. Mean 85 92 88 75 94 88 84 101 x 8 707 88.375 8 b. Median-rank the data 75, 84, 85, 88, 88, 92, 94, 101 The median is 88. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 13 Example--dog weights 85, 92, 88, 75, 94, 88, 84, 101 c. Mode-the number that occurs most frequently. The mode is 88. d. Midrange = (L + H)/2 = (75 + 101)/2 = 88 e. Rank the measures, lowest to highest 88, 88, 88, 88.375 Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 14 Measures of Position Measures of position are often used to make comparisons. Two measures of position are percentiles and quartiles. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 15 To Find the Quartiles of a Set of Data 1. Order the data from smallest to largest. 2. Find the median, or 2nd quartile, of the set of data. If there are an odd number of pieces of data, the median is the middle value. If there are an even number of pieces of data, the median will be halfway between the two middle pieces of data. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 16 To Find the Quartiles of a Set of Data (continued) 3. The first quartile, Q1, is the median of the lower half of the data; that is, Q1, is the median of the data less than Q2. 4. The third quartile, Q3, is the median of the upper half of the data; that is, Q3 is the median of the data greater than Q2. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 17 Example: Quartiles The weekly grocery bills for 23 families are as follows. Determine Q1, Q2, and Q3. 170 330 225 75 95 210 80 225 160 172 Copyright © 2009 Pearson Education, Inc. 270 170 215 130 190 270 240 310 74 280 270 50 81 Chapter 13 Section 5 - Slide 18 Example: Quartiles (continued) Order the data: 50 74 75 80 81 95 130 160 170 170 172 190 210 215 225 225 240 270 270 270 280 310 330 Q2 is the median of the entire data set which is 190. Q1 is the median of the numbers from 50 to 172 which is 95. Q3 is the median of the numbers from 210 to 330 which is 270. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 19 Section 6 Measures of Dispersion Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 20 Measures of Dispersion Measures of dispersion are used to indicate the spread of the data. The range is the difference between the highest and lowest values; it indicates the total spread of the data. Range = highest value – lowest value Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 21 Example: Range Nine different employees were selected and the amount of their salary was recorded. Find the range of the salaries. $24,000 $32,000 $26,500 $56,000 $48,000 $27,000 $28,500 $34,500 $56,750 Range = $56,750 $24,000 = $32,750 Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 22 Standard Deviation The standard deviation measures how much the data differ from the mean. It is symbolized with s when it is calculated for a sample, and with (Greek letter sigma) when it is calculated for a population. x x 2 s Copyright © 2009 Pearson Education, Inc. n 1 Chapter 13 Section 5 - Slide 23 To Find the Standard Deviation of a Set of Data 1. Find the mean of the set of data. 2. Make a chart having three columns: Data Data Mean (Data Mean)2 3. List the data vertically under the column marked Data. 4. Subtract the mean from each piece of data and place the difference in the Data Mean column. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 24 To Find the Standard Deviation of a Set of Data (continued) 5. Square the values obtained in the Data Mean column and record these values in the (Data Mean)2 column. 6. Determine the sum of the values in the (Data Mean)2 column. 7. Divide the sum obtained in step 6 by n 1, where n is the number of pieces of data. 8. Determine the square root of the number obtained in step 7. This number is the standard deviation of the set of data. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 25 Example Find the standard deviation of the following prices of selected washing machines: $280, $217, $665, $684, $939, $299 Find the mean. x 280 217 665 684 939 299 x n 3084 514 6 Copyright © 2009 Pearson Education, Inc. 6 Chapter 13 Section 5 - Slide 26 Example (continued), mean = 514 Data 217 280 299 665 684 939 Data Mean 297 234 215 151 170 425 0 Copyright © 2009 Pearson Education, Inc. (Data Mean)2 (297)2 = 88,209 54,756 46,225 22,801 28,900 180,625 421,516 Chapter 13 Section 5 - Slide 27 Example (continued), mean = 514 s= 421,516 6- 1 s= 421,516 » 290.35 5 The standard deviation is $290.35. Copyright © 2009 Pearson Education, Inc. Chapter 13 Section 5 - Slide 28