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CIE Centre A-level Pure Maths P2 Chapter 1 © Adam Gibson Identities and Equations Look at this equation: x 3 x Always true An equation tells you that something is true in a particular situation, not always! Now look at this equation: x2 y 2 ( x y)( x y) Always true Certainly! The LHS and RHS are identically equal x y ( x y)( x y) 2 2 This is called an “identity” Polynomials … are mathematical expressions of the form: n a x k k 0 The above expression represents a polynomial in x of nth degree, or an “nth degree polynomial”. What is a 0-degree polynomial? A constant What kind of polynomial is a quadratic? A second degree polynomial Is this a polynomial in x? What degree is it? f ( x) x 2 16 x 5 x 4 Yes, 4th degree y sin x x3 is not a polynomial k Some basics •A polynomial of degree zero is a constant •A polynomial of degree 1 is called linear e.g. - f ( x ) 3 x 8 •A polynomial of degree 2 is called quadratic 2 e.g. – f ( x) 7 x 70 x 5 “Degree” is also sometimes called “order” •Degree 3 – cubic, 4 – quartic, 5 – quintic etc. f ( x) 8x6 9 x5 x4 11x3 2 x 2 x 30 descending order f ( x) 30 x 2 x 2 11x3 x 4 9 x5 8x6 ascending order f ( x) 2 x2 8x6 11x3 x 4 30 x 9 x5 unordered Equating coefficients n n k 0 k 0 k k F ( x ) a x G ( x ) b x If: k k k , ak bk This may be obvious, but it’s very useful! Example: 3x3 4 x 2 10 x 60 Ax3 Bx 2 Cx D A 3, B 4, C 10, D 60 Identical polynomials have identical coefficients The algebra of polynomials •Polynomials can be added, subtracted or multiplied quite easily. •Division is harder! ÷ Problem: Divide By 2 x 4 3x3 5 x 5 x2 8 The correct method for finding the solution requires thinking about two things: the degree of a product of two polynomials, and equating coefficients To find the solution, use this identity: a ( x ) b( x ) q ( x ) r ( x ) a ( x) 2 x 3x 5 x 5 4 b( x ) x 2 8 3 (see textbook p.9) has degree 4 is the divisor and has degree 2 •The quotient, q(x), must have degree: 2 •The remainder, r(x), must have degree: 1 The identity can therefore be written in the following form: 2 x4 3x3 5x 5 ( x 2 8)( Ax 2 Bx C ) Gx H What next? Equate coefficients! 2=A 3=B q( x) 2 x 3x 16, r ( x) 19 x 133 2 0 = C - 8A -5 = G - 8B 5 = H – 8C so, finally we get: a ( x) 2 x 4 3 x 3 5 x 5 ( x 8)(2 x 3x 16) 19 x 133 2 2 The “remainder” and “factor” theorems Let’s return to the formula: a ( x ) b( x ) q ( x ) r ( x ) Now let’s consider a linear divisor: a ( x) ( x )q ( x) r ( x) What can we say about r(x)? A: It will be a constant (degree zero), so: a ( x) ( x )q ( x) R The remainder theorem contd. Setting x=alpha: What does this prove? a ( ) 0 R It proves that if x is a factor of a(x), then a(α) is zero. You can say x “divides a(x) exactly”. If (x-3) divides p(x) exactly, what does it tell you about the graph of p(x)? It tells you that 3 is a root of the equation p(x)=0, or equivalently that the graph cuts the x-axis at 3. This tomb holds Diophantus. Ah, what a marvel! And the tomb tells scientifically the measure of his life. God vouchsafed that he should be a boy for the sixth part of his life; when a twelfth was added, his cheeks acquired a beard; He kindled for him the light of marriage after another seventh, and in the fifth year after his marriage He granted him a son. Alas! late-begotten and miserable child, when he had reached the measure of half his father's life, the chill grave took him. After consoling his grief by this science of numbers for four years, he reached the end of his life. How old was Diophantus when he died? Diophantine equations x 94 y 1 , x, y 2 2 the smallest solutions are: x 2,143, 295, y 221, 064 Diophantus only looked for positive integer solutions; he considered negative and irrational solutions as foolish. Diophantus of Alexandria - Διόφαντος ο Αλεξανδρεύς – was a Greek mathematician. He was known for his study of equations with variables which take on integer values and these Diophantine equations are named after him. Diophantus is sometimes known as the "father of Algebra". He wrote a total of thirteen books on these equations. Diophantus also wrote a treatise on polygonal numbers. Diophantine equations Examples: ax by d Bezout’s identity It can be shown that if a and b are integers, and d is the greatest common divisor of a and b, then there exist solutions for x and y to this equation. This is a linear Diophantine equation. xn y n z n n=2; Pythagorean triples. n>2, no solutions. The study of Diophantine equations is part of number theory and is actually a very advanced topic.