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Monday: Announcements
• This is last week for 3rd grading period
• Today’s assignments are the last grades
• Unit 7 Reassessment sign-ups on the round table.
Deadline is Friday morning to reassess.
• Unit 8 is a 2 part unit (calculator and noncalculator)
• Afternoon tutorials this week start at 4:10pm
because of teacher duty
Add, Subtract,
Multiply, and Divide
Polynomials
Unit 8
Objectives
• I can add, subtract, and multiply polynomial
expressions.
• I can divide polynomial expressions using
Long Division
Polynomials
• A polynomial is a monomial or sum of
monomials.
• The monomials that make up the polynomial are
called terms of the polynomial.
• A trinomial has 3 unlike terms
• A binomial has 2 unlike terms
Standard Format
Exponents in descending ORDER
8 x  3x  3x  5 x  8 x  19
5
4
3
2
Standard Format
Exponents in descending ORDER
3x  2 x  3x  2 x  10 x  10
3
5
8
2
3x  2 x  3x  2 x  10 x  10
8
5
3
2
Addition and Subtraction
• Polynomials and monomials may only be
subtracted or added if they have like terms.
Addition and subtraction cannot be done on
unlike terms.
• To add or subtract, you just COMBINE
LIKE TERMS
Addition or Subtraction
•
•
•
•
Simplify the following:
(4x2 – 3x) – (x2 + 2x – 1)
4x2 – 3x – x2 - 2x + 1
3x2 – 5x + 1
Example #2
• Simplify: (3x + y) – (x + y) – (x + 3y)
• 3x + y – x - y – x - 3y
• x – 3y
Example 3
• Simplify (z2 – 6z – 10) + (2z2 + 4z – 11)
• z2 – 6z – 10 + 2z2 + 4z – 11
• 3z2 –2z - 21
EXAMPLE 1
Add polynomials vertically and horizontally
a. Add 2x3 – 5x2 + 3x – 9 and x3 + 6x2 + 11 in a vertical
format.
SOLUTION
a.
2x3 – 5x2 + 3x – 9
+ x3 + 6x2
+ 11
3x3 + x2 + 3x + 2
GUIDED PRACTICE
for Examples 1 and 2
Find the sum or difference.
1. (t2 – 6t + 2) + (5t2 – t – 8)
SOLUTION
t2 – 6t + 2
+ 5t2 – t – 8
6t2 – 7t – 6
Multiply with Distributive Prop
• Simplify: 3x(5x4 – x3 + 4x)
• 15x5 – 3x4 + 12x2
nd
2
Example:
• (x + 3)(x2 + 3x + 9)
• x3 + 3x2 + 9x + 3x2 + 9x + 27
• x3 + 6x2 + 18x + 27
Example 3
• Simplify: -3x2y(2x3y2 – 3x2y2 + 4x3y)
• -6x5y3 + 9x4y3 –12x5y2
Dividing Numbers
Quotient
When you divide a number
by another number and
there is no remainder:
Divisor
4
4 16
Then the divisor is a
factor!!
Dividend
Also the quotient becomes
another factor!!!
16
Dividing Polynomials
Long division of polynomials is similar to long division of
whole numbers.
When you divide two polynomials you can check the answer
using the following:
dividend = (quotient • divisor) + remainder
The result is written in the form:
remainder
d iv id e n d  d iv is o r  quotient +
divisor
17
Dividing Polynomials
Example: Divide x2 + 3x – 2 by x + 1 and check the answer.
2
x
1. x x 
x
x
2. x ( x  1 )  x 2  x
x + 2
2
x  1 x2  3x  2
x2 +
x
2x – 2
2x + 2
–4
3. ( x 2  3 x )  ( x 2  x )  2 x
4. x 2 x  2 x  2
x
5. 2 ( x  1 )  2 x  2
remainder
Answer: x + 2 +
6. ( 2 x  2 )  ( 2 x  2 )   4
–4
x 1
18
Example: Divide 4x + 2x3 – 1 by 2x – 2 and check the answer.
x2 + x + 3
Write the terms of the dividend in
descending order.
2x  2 2x  0x  4x  1
3
2
2x3 – 2x2
Since there is no x2 term in the
dividend, add 0x2 as a placeholder.
2x2 + 4x
2x2 – 2x
6x – 1
6x – 6
5
Answer:
x2
+x+3
3
2
x
1.
2. x 2 ( 2 x  2 )  2 x 3  2 x 2
 x2
2x
2
2
x
3
3
2
2
3. 2 x  ( 2 x  2 x )  2 x
4.
x
2x
5. x ( 2 x  2 )  2 x 2  2 x
5
6. ( 2 x 2  4 x )  ( 2 x 2  2 x )  6 x
8. 3 ( 2 x  2 )  6 x  6
7. 6 x  3
2x
9. ( 6 x  1 )  ( 6 x  6 )  5  re m a in d e r
2x  2
19
Example: Divide x2 – 5x + 6 by x – 2.
x – 3
x  2 x2  5x  6
x2 – 2x
– 3x + 6
– 3x + 6
0
Answer: x – 3 with no remainder.
20
Homework
• WS 8-1
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