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Exam 1
Quiz 1
Quiz 2
A series RLC circuit has a resistance
of 25.0, a capacitance of 50.0mF,
and an inductance of 0.300 H. If
driven by a 120v, 60Hz source, find:
(a) the impedance of the circuit.
(b) the current in the circuit.
(c) the phase angle between current
and voltage.
(d) the rms voltage drop across each
component.
(e) the power dissipated in the circuit.
(f) What f would make this circuit completely resistive?
(g) What would the power dissipated in the resistor be then?
XC
XL
f
f
XC
XL
fo
f
Z
R
fo
f
A copper coil is set
just behind the wire
loop of this circuit.
As the switch is closed,
1) a clockwise current is induced in the copper loop.
2) a counter clockwise current is induced in the copper loop.
3) no current appears in the copper loop.
A copper coil rests flat on a tabletop next to the wire loop
of this simple circuit. As the switch is opened,
1) a clockwise current is induced in the copper loop.
2) a counter clockwise current is induced in the copper loop.
3) no current appears in the copper loop.
A copper coil is set
just behind the wire
loop of this circuit.
As the switch is opened,
1) a clockwise current is induced in the copper loop.
2) a counter clockwise current is induced in the copper loop.
3) no current appears in the copper loop.
A
B
6V
Compared to the voltage drop across coil A,
the voltage across coil B is
1) less than 6 V
2) 6 V
3) greater than 6 V
A
B
6V
Compared to the voltage drop across coil A, the voltage
across coil B is
1) less than 6 V
2) 6 V
3) greater than 6 V
The voltage across B is zero
Only a changing magnetic flux
induces an EMF.
Batteries provide DC current.
1 Amp
120 V
240 V
What is the voltage
1)
2)
3)
120 V
across the light bulb?
60 V
120 V
240 V
1 Amp
120 V
240 V
What is the voltage
1)
2)
3)
120 V
across the light bulb?
60 V
120 V
240 V
What is the current through the light bulb?
1) 1/2 Amp
2) 1 Amp
3) 2 Amps
1 Amp
120 V
240 V
120 V
What is the voltage across the light bulb?
A)
60 V
B) 120 V
C) 240 V
Twice as many loops voltage doubles.
THEN: half as many loops, voltage halves
What is the current through the light bulb?
A) 1/2 Amp
B)
1 Amp
C)
2 Amps
Power in = Power out
Voltage out = 120 V
240 V  1 Amp = 120 V  I
so I = 2 Amp