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MM150 Unit Six Seminar Professor DeLong profsdelong (AIM name) Copyright © 2009 Pearson Education, Inc. Gosh, I love geometry… let’s get started!!! Slide 9 - 1 6.1 Points, Lines, Planes, and Angles Copyright © 2009 Pearson Education, Inc. Slide 9 - 2 Basic Terms A point, line, and plane are three basic terms in geometry that are NOT given a formal definition, yet we recognize them when we see them. A line is a set of points. Any two distinct points determine a unique line. Any point on a line separates the line into three parts: the point and two half lines. A ray is a half line including the endpoint. A line segment is part of a line between two points, including the endpoints. Copyright © 2009 Pearson Education, Inc. Slide 9 - 3 Basic Terms Description Diagram Line AB Ray AB A Copyright © 2009 Pearson Education, Inc. B B A A AB AB B A Ray BA Line segment AB Symbol B BA AB Slide 9 - 4 Angles An angle is the union of two rays with a common endpoint; denoted R. The vertex is the point common to both rays. The sides are the rays that make the angle. There are several ways to name an angle: RABC, RCBA, RB Copyright © 2009 Pearson Education, Inc. Slide 9 - 5 Angles The measure of an angle is the amount of rotation from its initial to its terminal side. Angles can be measured in degrees, radians, or, gradients. Angles are classified by their degree measurement. Right Angle is 90 Acute Angle is less than 90 Obtuse Angle is greater than 90 but less than 180 Straight Angle is 180 Copyright © 2009 Pearson Education, Inc. Slide 9 - 6 Types of Angles Adjacent Angles-angles that have a common vertex and a common side but no common interior points. Complementary Angles-two angles whose sum of their measures is 90 degrees. Supplementary Angles-two angles whose sum of their measures is 180 degrees. Copyright © 2009 Pearson Education, Inc. Slide 9 - 7 Example If RABC and RCBD are supplementary and the measure of ABC is 6 times larger than CBD, determine the measure of each angle. C m ABC m CBD 180 6 x x 180 7 x 180 x 25.7 Copyright © 2009 Pearson Education, Inc. A B D mRABC 154.2o mRCBD 25.7o Slide 9 - 8 More definitions Vertical angles are the nonadjacent angles formed by two intersecting straight lines. Vertical angles have the same measure. A line that intersects two different lines, at two different points is called a transversal. Special angles are given to the angles formed by a transversal crossing two parallel lines. Copyright © 2009 Pearson Education, Inc. Slide 9 - 9 6.2 Polygons Copyright © 2009 Pearson Education, Inc. Slide 9 - 10 Polygons Polygons are named according to their number of sides. Number of Sides 3 Name Triangle Number of Sides 8 Octagon 4 Quadrilateral 9 Nonagon 5 Pentagon 10 Decagon 6 Hexagon 12 Dodecagon 7 Heptagon 20 Icosagon Copyright © 2009 Pearson Education, Inc. Name Slide 9 - 11 The sum of the measures of the interior angles of an n-sided polygon is (n 2)180. Example: A certain brick paver is in the shape of a regular octagon. Determine the measure of an interior angle and the measure of one exterior angle. Copyright © 2009 Pearson Education, Inc. Slide 9 - 12 Determine the sum of the interior angles. 1080 135 8 S (n 2)180 (8 2)(180 ) 6(180 ) 1080 Copyright © 2009 Pearson Education, Inc. The measure of one interior angle is The exterior angle is supplementary to the interior angle, so 180 135 = 45 Slide 9 - 13 Types of Triangles Acute Triangle All angles are acute. Copyright © 2009 Pearson Education, Inc. Obtuse Triangle One angle is obtuse. Slide 9 - 14 Types of Triangles continued Right Triangle One angle is a right angle. Copyright © 2009 Pearson Education, Inc. Isosceles Triangle Two equal sides. Two equal angles. Slide 9 - 15 Types of Triangles continued Equilateral Triangle Three equal sides. Three equal angles (60º) each. Copyright © 2009 Pearson Education, Inc. Scalene Triangle No two sides are equal in length. Slide 9 - 16 Similar Figures Two polygons are similar if their corresponding angles have the same measure and the lengths of their corresponding sides are in proportion. 9 6 4 4 3 Copyright © 2009 Pearson Education, Inc. 6 6 4.5 Slide 9 - 17 Example Catherine Johnson wants to measure the height of a lighthouse. Catherine is 5 feet tall and determines that when her shadow is 12 feet long, the shadow of the lighthouse is 75 feet long. How tall is the lighthouse? x 5 75 Copyright © 2009 Pearson Education, Inc. 12 Slide 9 - 18 Example continued ht. lighthouse lighthouse's shadow = ht. Catherine Catherine's shadow x 75 5 12 12x 375 x x 31.25 5 75 12 Therefore, the lighthouse is 31.25 feet tall. Copyright © 2009 Pearson Education, Inc. Slide 9 - 19 Congruent Figures If corresponding sides of two similar figures are the same length, the figures are congruent. Corresponding angles of congruent figures have the same measure. Copyright © 2009 Pearson Education, Inc. Slide 9 - 20 Quadrilaterals Quadrilaterals are four-sided polygons, the sum of whose interior angles is 360. Quadrilaterals may be classified according to their characteristics. Copyright © 2009 Pearson Education, Inc. Slide 9 - 21 Classifications Trapezoid Two sides are parallel. Copyright © 2009 Pearson Education, Inc. Parallelogram Both pairs of opposite sides are parallel. Both pairs of opposite sides are equal in length. Slide 9 - 22 Classifications continued Rhombus Both pairs of opposite sides are parallel. The four sides are equal in length. Copyright © 2009 Pearson Education, Inc. Rectangle Both pairs of opposite sides are parallel. Both pairs of opposite sides are equal in length. The angles are right angles. Slide 9 - 23 Classifications continued Square Both pairs of opposite sides are parallel. The four sides are equal in length. The angles are right angles. Copyright © 2009 Pearson Education, Inc. Slide 9 - 24 6.3 Perimeter and Area Copyright © 2009 Pearson Education, Inc. Slide 9 - 25 Formulas Figure Rectangle Square Parallelogram Triangle Trapezoid Copyright © 2009 Pearson Education, Inc. Perimeter Area P = 2l + 2w A = lw P = 4s A = s2 P = 2b + 2w A = bh P = s1 + s2 + s3 A 21 bh P = s1 + s2 + b1 + b2 A 21 h(b1 b2 ) Slide 9 - 26 Example Marcus Sanderson needs to put a new roof on his barn. One square of roofing covers 100 ft2 and costs $32.00 per square. If one side of the barn roof measures 50 feet by 30 feet, determine a) the area of the entire roof. b) how many squares of roofing he needs. c) the cost of putting on the roof. Copyright © 2009 Pearson Education, Inc. Slide 9 - 27 Example continued a) The area of the roof is A = lw A = 30(50) A = 1500 ft2 1500 2 (both sides of the roof) = 3000 ft2 b) Determine the number of squares area of roof 3000 30 area of one square 100 Copyright © 2009 Pearson Education, Inc. Slide 9 - 28 Example continued c) Determine the cost 30 squares $32 per square $960 It will cost a total of $960 to roof the barn. Copyright © 2009 Pearson Education, Inc. Slide 9 - 29 Pythagorean Theorem The sum of the squares of the lengths of the legs of a right triangle equals the square of the length of the hypotenuse. leg2 + leg2 = hypotenuse2 Symbolically, if a and b represent the lengths of the legs and c represents the length of the hypotenuse (the side opposite the right angle), then c 2 2 2 a a +b =c Copyright © 2009 Pearson Education, Inc. b Slide 9 - 30 Example Tomas is bringing his boat into a dock that is 12 feet above the water level. If a 38 foot rope is attached to the dock on one side and to the boat on the other side, determine the horizontal distance from the dock to the boat. 38 ft rope 12 ft Copyright © 2009 Pearson Education, Inc. Slide 9 - 31 Example continued a2 b2 c 2 122 b 2 38 2 144 b 2 1444 b 2 1300 b 2 1300 b 36.06 12 38 b The distance is approximately 36.06 feet. Copyright © 2009 Pearson Education, Inc. Slide 9 - 32 Circles A circle is a set of points equidistant from a fixed point called the center. A radius, r, of a circle is a line segment from the center of the circle to any point on the circle. A diameter, d, of a circle is a line segment through the center of the circle with both end points on the circle. The circumference is the length of the simple closed curve that forms the circle. Copyright © 2009 Pearson Education, Inc. Slide 9 - 33 Example Terri is installing a new circular swimming pool in her backyard. The pool has a diameter of 27 feet. How much area will the pool take up in her yard? (Use π = 3.14.) A r 2 A (13.5) The radius of the pool is 13.5 ft. A 572.265 The pool will take up about 572 2 square feet. Copyright © 2009 Pearson Education, Inc. Slide 9 - 34 6.4 Volume and Surface Area Copyright © 2009 Pearson Education, Inc. Slide 9 - 35 Volume Volume is the measure of the capacity of a figure. It is the amount of material you can put inside a three-dimensional figure. Surface area is sum of the areas of the surfaces of a three-dimensional figure. It refers to the total area that is on the outside surface of the figure. Copyright © 2009 Pearson Education, Inc. Slide 9 - 36 Volume Formulas Figure Rectangular Solid Cube Formula V = lwh Cylinder V = r2h Cone Sphere Copyright © 2009 Pearson Education, Inc. Diagram V = s3 V 31 r 2 h V r 4 3 3 Slide 9 - 37 Surface Area Formulas Figure Formula Rectangular SA = 2lw + 2wh +2lh Solid Cube SA= 6s2 SA = 2rh + 2r2 Cylinder Cone Diagram SA r Sphere Copyright © 2009 Pearson Education, Inc. 2 r r 2 SA 4 r h 2 2 Slide 9 - 38 Example Mr. Stoller needs to order potting soil for his horticulture class. The class is going to plant seeds in rectangular planters that are 12 inches long, 8 inches wide and 3 inches deep. If the class is going to fill 500 planters, how many cubic inches of soil are needed? How many cubic feet is this? Copyright © 2009 Pearson Education, Inc. Slide 9 - 39 Example continued We need to find the volume of one planter. V lwh V 12(8)(3) V 288 in.3 Soil for 500 planters would be 500(288) = 144,000 cubic inches 144,000 83.33 ft 3 1728 Copyright © 2009 Pearson Education, Inc. Slide 9 - 40 Polyhedron A polyhedron is a closed surface formed by the union of polygonal regions. Copyright © 2009 Pearson Education, Inc. Slide 9 - 41 Euler’s Polyhedron Formula Number of vertices number of edges + number of faces = 2 Example: A certain polyhedron has 12 edges and 6 faces. Determine the number of vertices on this polyhedron. # of vertices # of edges + # of faces = 2 x 12 6 2 x 6 2 x 8 Copyright © 2009 Pearson Education, Inc. There are 8 vertices. Slide 9 - 42 Volume of a Prism V = Bh, where B is the area of the base and h is the height. Example: Find the volume of the figure. Area of one triangle. Find the volume. A 21 bh A 21 (6)(4) V Bh V 12(8) 4m A 12 m2 8m V 96 m3 6m Copyright © 2009 Pearson Education, Inc. Slide 9 - 43 Volume of a Pyramid V 31 Bh where B is the area of the base and h is the height. Example: Find the volume of the pyramid. Base area = 122 = 144 V 31 Bh V 31 (144)(18) 18 m V 864 m3 12 m 12 m Copyright © 2009 Pearson Education, Inc. Slide 9 - 44 If I need help, I won’t lay an egg, I’ll contact Professor DeLong! Copyright © 2009 Pearson Education, Inc. Slide 9 - 45