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Welcome to Genetics: Unit 2 Seminar! Please feel free to chat with your classmates! 1 Agenda • Brief Review • Genetics Problem – #1, #2, 2.3, 2.5 and 3.1 • Question 2 Alleles Alleles are pairs of genes that carry the same traits and are found at the same locations on pairs of chromosomes. From Father From Mother 3 Autosomal Inheritance Dominant – only one allele of a gene necessary to express the trait GENES Recessive – both alleles of a gene must be identical to express that trait GENES 4 Genetic Terms Homozygous Trait - Both genes for that trait are the same. A pea plant with two genes for tallness. Heterozygous Trait - Both genes for that trait are not the same. A pea plant with one gene for tallness and one for shortness. 5 Human Molecular Genetics • Homozygous - a diploid cell or organism carry two identical copies of a gene • Heterozygous - a diploid cell or organism having two different alleles of a particular gene heterozygous homozygous 75% 25% 6 Human Molecular Genetics • Genotype – entire genetic constitution of an individual cell or organism, usually with emphasis on the particular alleles at one or more specific loci. GENES • Phenotype – the detectable physical and physiological characteristics of a cell or organism determined by its genotype; also, the specific trait associated with a particular allele. 7 Practice Problem 1 • Beak color is an autosomal trait in chickens. Red beaks are dominant over white beaks. The allele for red beaks is R. The allele for white beaks is r. 8 Practice Problem 1 • Claude is a chicken that has a red beak and has a genotype of Rr. If this chicken mates with a white-beaked chicken named Filette, what will the baby chickens look like? What would be their phenotypes and genotypes? Claude Filette Rr rr 9 Practice Problem 1 X Claude Rr ? Filette rr What is their Genotype? What is their Phenotype? 10 Practice Problem 1 X Claude Rr Filette rr Genotype is Rr Phenotype is white beak 50% Genotype is rr Phenotype is white beak 50% 11 Practice Problem 2 • John is homozygous dominant for the T allele decides to have children with a Jane who is homozygous recessive. • We will say the T allele is a Tall gene: • T = tall • t = short *Note: In reality, there is no tall gene. 12 Practice Problem 2 • John is homozygous dominant for the T allele decides to have children with a Jane who is homozygous recessive. First what is John and Jane’s genotypes? John Jane 13 Practice Problem 2 • John is homozygous dominant for the T allele decides to have children with a Jane who is homozygous recessive. First what is John and Jane’s genotypes? John TT Jane tt 14 Practice Problem 2 • What will their children be like? Again, include the children's genotypes and phenotypes. John TT X Jane tt 15 Practice Problem 2 John and Jane’s Children Both are tall John Junior Tt Jane Junior Tt 16 Discussion Question 2.3 • A woman is affected with a trait due to a dominant gene that shows 50% penetrance. What is the probability that , if she has a child, it will be affected? 17 Incomplete Dominance • Incomplete dominance = the phenotype of the heterozygous genotype is intermediate between the phenotypes of the homozygous genotypes • Incomplete dominance is often observed when the phenotype is quantitative rather than discrete 18 Discussion Question 2.5 • With independent assortment, how many different types of gametes are possible from the genotype K/k; L/l; M/m; P/p and in what proportions are they expected? 19 Discussion Question 2.5 • With independent assortment, how many different types of gametes are possible from the genotype K/k; L/l; M/m; P/p and in what proportions are they expected? • Gametes – egg or sperm. • Each gene has two possible alleles; K or k. • Therefore, the number of possible types of gametes are 2 X 2 X 2 X 2 = 16 • The occur at an equal frequency. 20 Discussion Question 3.1 • A somatic cell has 32 chromosomes aligned at metaphase. How many chromosomes are present at anaphase immediately after the centromeres have splits? 21 Fig. 3.3 Mitosis 22 Questions? 23