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H H H H H H H H | | | | | | | | H-C-C-C-C-C-C-C-C-H | | | | | | | H H H H H H H H H H | | | H-C-C-C-C-H | | | H H H H-C-H | H-C-H | H Here’s a structural diagram of a typical hydrocarbon It has 14 C’s and 30 H’s so the formula is C14H30 since each C is surrounded by 4 bonds typically, for ease of drawing, the H’s are left out to form a carbon skeleton diagram To name the parent chain prefixes at the beginning of the C-C-C-C-C-C-C-C word are used. | These prefixes are C - C- C - C | This parent chain has 9 determined by the C | C so it starts with non. number of C C If there are no double atoms in the bonds it ends with ane parent chain. Nonane is the name of the parent chain Find the longest continuous carbon chain. This structure is called the parent chain. Find the longest continuous carbon chain. This structure is called the parent chain. If the carbon chain is 1 C starts with meth 2 C starts with eth 3 C starts with prop C-C-C-C-C-C-C-C 4 C starts with but | 5 C starts with pent C - C- C - C 6 C starts with hex | This parent chain has 9 7 C starts with hept C | C so it starts with non. 8 C starts with oct C If there are no double 9 C starts with non bonds it ends with ane 10 C starts with dec Nonane is the name of the parent chain 5 6 7 8 9 C-C-C-C-C-C-C-C 5 4 3 2 1 | Using the red C CC C 4 numbers the 1st Next you must number 6 3 7 | side chain is the parent chain Chains can be numbered 2 C 8 encountered at from either direction so the 5th C | the rule to follow states: Using the blue 9 C Number the chain so the 1 lowest possible number is used when the 1st side chain is encountered numbers the 1st side chain is encountered at the 3rd C 5 6 7 8 9 C-C-C-C-C-C-C-C | 3 C side chain is 4C - C- C - C 3 called | 2 C side propyl 2 C chain is Next, identify the | called side chains and 1 C ethyl where they are attached Notice all side chains end in yl 5 6 7 8 9 Now lets consider the names which have been determined C-C-C-C-C-C-C-C | 4C - C- C - C Parent chain is nonane 3 | side chains are 3-ethyl and 2 C 5-propyl the complete name is | 1 C 3-ethyl-5-propylnonane Side chains appear 1st and are always alphabetized, (ethyl before propyl), parent chain appears last Now draw the skeleton structure for 5-butyl6-ethyl-2-methyl decane 1st identify the parent chain 5-butyl-6-ethyl-2-methyldecane (decane means 10 C’s with no double bonds C-C-C-C-C-C-C-C-C-C Side chains are: | | | 2-methyl C C C (1 C attached to the 2nd C) | | C C 5-butyl | 4 C’s attached to the 5th C C 6-ethyl | 2C’s attached to the 6th C C Now draw the skeleton structure for 3,3diethyl-2,5,6-trimethylheptane 1st identify the parent chain 3,3-diethyl -2,5,6-trimethylheptane (heptane means 7C’s with no double bonds C Side chains are: | 3,3-diethyl C | (2C attached to each side C-C-C-C-C-C-C of the 3rd C) | | | | C C C C 2,5,6-trimethyl | 1C’s attached to the 2nd, 5th and 6th C C Name the following: C C-C C | | | C-C-C-C-C-C-C-C | | | | C C C C octane Parent Chain is 2,2,3,4,7,7 hexamethyl Final Answer is 6 - ethyl 6 - ethyl - 2,2,3,4,7,7 - hexamethyloctane Side Chains are Naming Cyclic Hydrocarbons with Side Chains What is this structure called? Number the carbons in the ring using the lowest possible numbers. CH2 CH3 5 H2C 4 1 CH2 CH3 3 CH2 2 CH2 CH3 1,2,4-trimethyl cyclopentane Draw 2,3-diethyl-1-methylcyclohexane CH3 CH2 HC H2C CH CH2 CH3 CH2 HC CH2 CH3 Aromatics with Side-Chains CH2CH2CH3 Name? 1,3-dipropylbenzene CH2CH2CH3 Sometimes compounds are more easily named when the benzene ring is considered to be a side chain. CH 3 CH2 H3C CH3 HC CH CH3 C CH3 C CH CH HC CH CH Name? 2,2,3-trimethyl-4-phenylhexane Draw 2,3-dimethyl-2,3-diphenylpentane C CH CH CH HC CH C C C C C CH3 C H3C H3C CH2 C CH3 C C CH CH HC CH CH C Alkyl Halides-Hydrocarbons containing F, Cl, Br, I When a halogen is introduced into a hydrocarbon molecule naming proceeds as if the halogen were simply a branch. CH3CH2CHCH2CH3 | Cl is named 3-chloropentane so CH3CH2CH2CH2CH2CH2Br is named 1-bromohexane Draw the complete structural diagram for 4-bromo-2,5-dimethylheptane HH HH H HH | | | | | | | H-C-C -- C-C - C -- C-C-H | | | | | | | H CH3 H Br CH3 H H (CH3)2CHCH2CHBrCH(CH3)2 named H H H H H HC H HC C C C C H H H C H H Br H C H H H H H H H H HC H HC C C C C H H H C H H Br H C H H H The parent chain is Hexane the rest of it is 3 - bromo 2,5 - dimethyl, so the complete name is 3-bromo-2,5-dimethylhexane If double bonds are present, the hydrocarbon is still named as if the halogen were absent. F-CH=CH-CH2-CH3 is named 1-fluoro-1-butene CH3-CH=CH-CH2I is 1-iodo-2-butene CH2-CH=CH-CH2 | | Br Br is named 1,4-dibromo-2-butene The condensed structural diagram for 1-chloro-6-iodo-2,4-hexadiene is CH2-CH=CH-CH=CH-CH2 | | I Cl Cis and Trans Isomers Molecules with double and triple bonds cannot rotate in opposite directions on each side of the double bond so when side chains, like Cl atoms for example, are attached on each side of the double bond 2 different structures are possible. Cl Cl CH CH cis-1,2-dichloroethene Cl CH CH Cl trans-1,2-dichloroethene Br CH2 H3C C C CH3 Br Name trans-2,3-dibromo-2-pentene H2C H CH2 Cl H2C H CH2 Cl H2C H CH2 Cl H2C H CH2 Cl H2C H CH2 Cl H2C H CH2 Cl H2C H CH2 Cl H3C CH2Cl H H C H C H H Cl H H C H C H H Cl H H C H C H H Cl H H C H C H H Cl H H C H C H H Cl H H C H C H H Cl H H C H H C H Cl H H H C C H Cl H Addition Reaction Hydrohalogenation of an Alkene to an alkyl halide C2H4 + HCl ethene C2H5Cl chloroethane Addition Reaction Hydrohalogenation of an Alkene to an alkyl halide C2H4 + HCl ethene C2H5Cl chloroethane Markovnikov’s Rule When non-identical atoms are added 2 products are theoretically possible. Experiments show only 1 main product is formed. The H atom will bond to the C atom which already has more H’s attached. 2H’s H-CH=CH-CH3 + HBr H2C – CH – CH3 or H2C – CH –CH3 H Br Br H 2-bromopropane 1-bromopropane Main product The “rich” get “richer” Predict the product for the reaction below H Br H HH H C C C H H C H H H Br H HH H C C C H H C H H H H HH Br H C C C H H C H H H Br H H HH C C C H H C H H H H HH H Br C C C H H C H H H HH H H Br C H C C H C H H H HH H C Br C C C H H H H H H H Br C H H HH C C H C H H H H HH H Br C C C H H C H H H Br H H HH C C C H H C H H H Br H H HH C C C H H C H H H Br H HH H C C C H H C H H H Br H HH H C C C H H C H H H Br H HH H C C C H H C H H Br H H HH H C C C H H C H H Br H H HH H C C C H H C H H Br H H HH H C C C H H C H H Br H H HH H C C C H H C H H Br H H HH H C C C H H C H H Br H H H HH C C C H H C H H The H atom will bond to the C atom with the most H atoms already attached. H HH Br H H C H C C H C H H H H H H H C C C H Br 2-bromobutane H C H H Draw structural diagrams showing the reaction of HF and 1-pentene H H HF + H C C H C H C C H H H H H H H C H C H H F H C H C C H H 2-fluoropentane H H H2C Cl CH2 Cl H2C Cl CH2 Cl H2C Cl CH2 Cl H2C Cl CH2 Cl H2C Cl CH2 Cl H2C Cl CH2 Cl H2C Cl CH2 Cl H2C Cl CH2 Cl ClH2 C CH2Cl H H C H C H Cl Cl H H C H C H Cl Cl H H C H C H Cl Cl H H C H C H Cl Cl H H C C H Cl Cl H H H C H Cl C Cl H H H H C Cl C Cl H H H H C C Cl Cl H Addition Reaction Halogenation of an Alkene to an alkyl halide C2H4 + Cl2 ethene C2H4Cl2 1,2-dichloro ethane H H H C H Cl CH H Cl H H H C H Cl CH H Cl H H H C H Cl CH H Cl H H H C H Cl CH H Cl H H H C H Cl CH H Cl H H H C CH H Cl H Cl H H H C CH H Cl Cl Cl H H H C CH H Cl Cl Cl H H H C CH H Cl Cl Cl H H H C Cl CH H Cl Cl H H H C Cl CH H Cl Cl H H H C Cl CH Cl H Cl H H CH Cl H C Cl H Cl Substitution Reaction Changing an Alkane to an alkyl halide C2H6 + 2Cl2 ethane C2H4Cl2 +2HCl 1,2 dichloro ethane Halogens have large electronegativities so their presence on a hydrocarbon chain creates a polar region which is localized. If they are present in a balanced symmetrical pattern, the polarity is nulified and the molecule is non-polar. (C2Cl6 for example). Alkyl halides have stronger intermolecular forces than their corresponding hydrocarbons due to this polarity, so they have higher MP and BP and are more soluble in polar solvents than hydrocarbons. The more halogenated the hydrocarbon, the greater the polarity and the higher the MP and BP. are characterized by the presence of an OH group (hydroxyl). The alcohol whose parent hydrocarbon is propane can have two possible structures which are derived by replacing an H atom with an OH group. H OH H OH H OH | | | H - C - C - C - OH H OH H | | | OH OH OH H OH H H Notice the OH group is either attached to the 1st or the 2nd C so the 2 possible names are 1-propanol 2-propanol Alcohols end in ______ol. Name this structure CH3(CH2)7OH 1-octanol Name this structure CH3 CH2 CH2 CH CH2 CH2CH2CH3 | CH2 CH2OH When a functional group like OH is present find the longest carbon chain which contains the functional group. The OH group is on the 1st carbon. 3-propyl-1-heptanol. Name this structure CH3 CH2 CHCH3 | OH 2-butanol not 3 butanol is the correct name CH3 CH2 CH2 CH(OH) CH2 CH3 is named 3-hexanol Once the numbering system is determined by the location of the OH group, other branches, alkyl or halogen are named in the usual way CH3 | CH3 -CH2 - C - OH is named | 2-methyl-2-butanol CH3 CH3 CH2 CH3 | | CH3 C CH2 CH2 CCH3 | | CH3 CH CH3 | OH Find the longest C chain which contains the OH group is named 3-ethyl-3,6,6-trimethyl-2-heptanol If a carbon chain has more than one OH group attached it is called a polyhydroxy compound. Draw a structural diagram of 1,2-ethanediol. CH2 OH | CH2 OH the common name for this is ethylene glycol the principal component of antifreeze. CH2 OH | CH3CH2 - C-OH | CH2 OH Its name is 2-ethyl-1,2,3-propantriol The insect repellent “6-12” (2-ethyl1,3-hexanediol) has the structural formula: H H H H H H | | | | | | H - C - C --- C - C - C - C - H | | | | | | OH CH2 OH H H H | CH3 What is the name of the structure below: OH | CH / \ CH2 CH2 | | CH CH / \ / \ OH CH2 OH 1,3,5-cyclohexanetriol CH3CH=CH-CH2-OH is named 2-buten-1-ol CH2=CH-CH2OH is named 2-propen-1-ol the OH group takes precedence in numbering 3-buten-2-ol has the formula: H H H H | | | / H-C-C-C=C | | \ H OH H If there is a choice of chains, the most unsaturated is chosen as long as it still contains the OH group Example - What is the name of: CH3 - CH = C - CH2 - OH | CH2CH2CH3 the parent chain is The complete name is 2 - propyl - 2 - buten -1- ol Remembering the compounds with triple bonds are called alkynes, the structural diagram for 2-propyn-1-ol is H | H-C-C C-H | OH CH3-CH2-C-CH2-CH-CH3 | | CH3 CH2OH 2,4 - dimethyl-1-hexanol is The formula for 2,2,5-trimethyl-3-hexene-1,5-diol is CH3 OH | | CH2-C-CH=CH-C-CH3 | | | OH CH3 CH3 H2C H CH2 H O H2C H CH2 H O H2C H CH2 H O H2C H CH2 H O H2C H CH2 H O H2C H CH2 H O H2C H CH2 H O ethanol H O H H C H H C H H H C C H H O H H H H C C H H O H H H H C C H O H H H H H C C H O H H H H H C H H C H O H H H H C C H O H H Addition Reaction Hydration of an Alkene to an alcohol C2H4 + H2O ethene C2H5OH ethanol The presence of the OH group makes them polar so they are soluble in water and other polar solvents and can form H bonds which is a stronger intermolecular force that dipole-dipole attractions found between polar molecules. As the non-polar hydrocarbon chain grows in the higher molecular weight alcohols the polarity decreases so the solubility diminishes but they can be used to dissolve both non-polar and polar substances. Larger molecular weight alcohols also have stronger intermolecular forces so BP increases. Oxygen atoms can bond in the middle of a chain of carbon atoms. When this happens the compounds formed are called ethers. Example CH3-CH2-O-CH2-CH2-CH2-CH3 The longest chain is used as the parent chain. This 4 carbon chain is called butane the side chain is 2 C’s + the O The side chain is called ethoxy ethoxybutane Sketch 1,2-dimethoxycyclopentane Parent chain is cyclopentane side chains are methoxy attached to consecutive carbons in the 5 Carbon ring CH2 / \ CH2 CH-O-CH3 | | CH2---CH-O-CH3 Name this structure CH2=CH-CH-CH2-CH-CH2-CH3 | | CH3-CH2-O O-CH2-CH2-CH3 parent chain is 1-heptene side chains are 3-ethoxy and 5-propoxy complete name is 3-ethoxy-5-propoxy-1-heptene H H H C C O H H H C H H 2-propanol H H H C H O C H H C H H H H H C C O H H H H C O C H H H H H C H 2-propanol H C H H H H H C C O H H H C H O C H H H H H C H H C H 2-propanol H H H H H H C H C C O H C H H HH O C H H H C H 2-propanol H H H H C C H H O C H C H H H C H H H C H O H H H H H H H C H C H CH H H C H O C H C O H H H 2-methylethoxypropane H H Dehydration of Alcohols to Ethers 2C3H7OH 2-propanol H2SO4 C6H14O +H2O 2- methylethoxy propane The difference in En of C and O, and the V shape of the C – O – C bond make ethers slightly polar. Their MP and BP lie in between those of corresponding alcohols and hydrocarbons. They mix readily with both polar and nonpolar substances so make excellent solvents for organic reactions. The C-O bond is quite stable making ethers generally unreactive, another property of a good solvent. Both these families have C = O groups replacing a H atom on the carbon chains. Aldehydes have this C = O group at the end of a chain, Ketones have the C = O group in the middle portion of the chain. Here are some examples of aldehydes and ketones. Decide which is which. A. CH3HC=O aldehyde B. CH3CH2C = O ketone | CH3 C. (CH3)2CHCCH(CH3)2 || ketone O E. CH3COCH3 ketone D. HCHO aldehyde F. HCOC2H5 aldehyde Aldehydes end in _______________al Ketones end in _______________one ethanal is CH3-C=O | H propanone is CH3-C-CH3 || O Pentanone has 2 possible structures. They are CH3CCH2CH2CH3 2 - pentanone || O and CH3CH2CCH2CH3 3 - pentanone || O Name this structure CH3 | O=CCHCH2CH3 | CH3 the parent chain is 3-methyl-2-pentanone 2,3-hexanedione is C-C-C-C-C-C || || O O 1,4-cyclohexanedione is CH2 / \ CH2 C=O | | O=C CH2 \ / CH2 3-penten-2-one is The functional group takes precedence over the double bond C-C-C=C-C || O 3-hydroxypentanal is C-C-C-C-C || | O OH 5-chloro-3-heptenal is C-C-C=C-C-C-C || | O Cl Name this CH3C=O | CH2CH-CH3 | I 4-iodo-2-pentanone 2,5-heptadien-4-one has the structural formula CH3CH=CH-C-CH=CHCH3 || O KMnO4 or Cr2O72- in H2SO4 O 1-propanol H H O H H C C C H H H H KMnO4 or Cr2O72- in H2SO4 O H H O H 1-propanol H C C C H H H H KMnO4 or Cr2O72- in H2SO4 O H H O H H C C C H H H H KMnO4 or Cr2O72- in H2SO4 O H H O H H C C C H H H H KMnO4 or Cr2O72- in H2SO4 O H H O H H C C C H H H H KMnO4 or Cr2O72- in H2SO4 OH H O H H C C C H H H H KMnO4 or Cr2O72- in H2SO4 O H H O H H C C C H H H H KMnO4 or Cr2O72- in H2SO4 O H H H O H C C C H H H H KMnO4 or Cr2O72- in H2SO4 O H H dehydration reaction H O H C C C H H H H propanal KMnO4 or Cr2O72- in H2SO4 O 2-propanol H H H C C H H C OH H H KMnO4 or Cr2O72- in H2SO4 O 2-propanol H H H C C H H OH C H H KMnO4 or Cr2O72- in H2SO4 O H 2-propanol H H C C H H C OH H H KMnO4 or Cr2O72- in H2SO4 O H 2-propanol H H C C H H OH C H H KMnO4 or Cr2O72- in H2SO4 H H 2-propanol H C C H O H OH C H H KMnO4 or Cr2O72- in H2SO4 H H H C C H O H C OH H H KMnO4 or Cr2O72- in H2SO4 H H H C C H O H C H O H H KMnO4 or Cr2O72- in H2SO4 H O H H H C C H O H C H H KMnO4 or Cr2O72- in H2SO4 Notice when the OH H group is not O on the end a H ketone is made propanone H H C C H O H C H H Oxidation of Alcohols to Aldehydes or Ketones 1-propanol C3H7OH + O 2-propanol propanal C3H6O + H2O propanone The C = O bond is polar so aldehydes and ketones are soluble in water and their MP and BP lie between corresponding hydrocarbons and alcohols since the O – H bond is more polar. They also can mix with non-polar substances due to the presence of hydrocarbon chains. The longer the chains the more nonpolar they are, the less soluble they are in polar solvents and the more soluble they are in nonpolar solvents. Again as their molecular weights increase so do their MP and BP due to increased VdW forces. Ethanoic Acid is CH3C=O | OH the name of this is CH3CH2CH=CHCOOH 2-pentenoic acid 4-hydroxy-3-iodo-2-heptenoic acid is C-C-C-C-C=C-C=O | | | OH I OH Name this CH3-CH-CH2-CH2-CH3 | COOH 2-methylpentanoic acid KMnO4 or Cr2O72- in H2SO4 H O O H C C C H H H H propanal KMnO4 or Cr2O72- in H2SO4 H O O H C C C H H H H propanal KMnO4 or Cr2O72- in H2SO4 H O O H C C C H H H H propanal KMnO4 or Cr2O72- in H2SO4 H O O H C C C H H H H propanal KMnO4 or Cr2O72- in H2SO4 H O O H C C C H H H H propanal KMnO4 or Cr2O72- in H2SO4 H O H C C C H H O H H propanal KMnO4 or Cr2O72- in H2SO4 ` H O C H C C O H H H H propanal KMnO4 or Cr2O72- in H2SO4 ` H O C O H H C C H H H propanal KMnO4 or Cr2O72- in H2SO4 H O C H C O H C H H H Propanoic acid ` Oxidation of Aldehydes to Carboxylic Acids C3H6O + O propanal C2H5COOH propanoic acid Organic acids are polar and form H bonds so they are soluble in water. As molecular weights increase, intermolecular forces increase so BP and MP increase. As the hydrocarbon chain grows, the polarity decreases so the solubility in polar solvents decrease. H H C H C O H O H H H H H C C C O H H H H H C H C O H O H H H H H C C C O H H H H H C H C O H O H H H H H C C C O H H H H H C H C O H O H H H H H C C C O H H H H H C H C O H H O H H H H H C C C O H H H H C H C O H H O H H H H H C C C O H H H H C H C O H H O H H H H H C C C O H H H H C H H C H O H H H C O C H C O H H H H H H C C O H H H H H O H C C C H O H H H H H H H C C H O H H O H C C C H O H H H H H C C H O H H O C O H C H H C H H H H H H C C H O ethyl propanoate H H C O H C H H C H H O H Making Esters from Alcohols and Acids C2H5OH + C2H5COOH C2H5COOC2H5 + H2O C - C - C - C - OH Alcohol is called 1-butanol O=C-C-C-C-C | Acid is called OH Pentanoic acid When they combine H2O is removed (a dehydration synthesis) O=C-C-C-C-C | OH C - C - C - C - OH C - C - C - C - OH C - C - C - C - OH O=C-C-C-C-C | O | C-C-C-C O=C-C-C-C-C | O 1-butyl pentanoate | C-C-C-C When naming esters you name the alcohol 1st (remove the letters anol from the end and add the letters yl at the end. If the alcohol is 1-butanol then the name is 1-butyl. The acid name is second. If the acid is pentanoic drop the last 3 letters (oic) and add the letters oate. In this instance it becomes pentanoate. The complete name becomes O=C-C-C-C | This ester’s Ethyl butanoate name is O | Remember the double bonded oxygen atom is always joined to C - C the acid Remember alcohol Ethanol becomes 1st Acid 2nd Butanoic becomes ethyl butanoate What is this ester’s name? O=C-C | 2-pentylethanoate O | C-C-C-C-C Remember alcohol 2-pentanol becomes 2-pentyl 1st Acid 2nd ethanoic becomes ethanoate Draw the structural diagram for 2,3,3trichloro-2-hexylmethanoate Remember alcohol 1st Cl Cl | | C-C-C-C-C-C | | OH Cl OH | O=C Cl Cl | | C-C-C-C-C-C | | O Cl | O=C Esters lack the OH group from the parent acid and alcohol so they are less polar. This means they have lower MP and BP than their corresponding acids and alcohols are less soluble in water and are not acidic. Smaller molecular weight esters have relatively weak intermolecular forces so they have strong odours. NH2 groups can be attached as side chains to carbon parent chains. These groups are called amines. Here is an example. 1,2-diaminopropane is CH2-CH-CH3 | | NH2 NH2 What is the name of this structure? F-C=C-C-C-C-NH2 | NH2 3,5-diamino-1-fluoro-1-pentene notice the double bond takes precedence over the side chains. When a functional group is present like alcohols (OH), aldehydes (C=O), ketones, or acids, they take precedence over the double or triple bonds. The hydrogens on the amines can be replaced by methyls (CH3), ethyls (C2H5) , halides (F), etc. CH3-CH-CH3 | N / \ CH H 3 CH2H5 When this happens the side chain is called N-ethyl-N-methyl-2-amino propane H H H H C C H Cl H H N H H H H H C C H Cl H H N H H H H H C C H Cl H H N H H H H H C C H Cl H H N H H H H H C C H Cl H H N H H H H H C C H Cl H H N H H H H H C C H Cl H H N H H H H C C H Cl H H H N H H H H C C H H H Cl N H H H H H C C H H H Cl N H H H H H C C H H H Cl N H aminoethane H Making Amines From Alkyl Halides CH3CH2Cl + NH3 C2H5NH2 + HCl Amines are named as side chains. Name this compound NH2 CH C H3C H2N Draw 2,2 diamino-6-methyl3,5-octadiene CH CH3 Parent chain is 2-pentene 4,4-diamino-2-pentene NH2 H3C H2N C CH C CH CH3 CH2 CH H3C N – H and C – H bonds are both polar and N – H bonds exhibit H bonding properties so amines are quite soluble in water. Neither bond is as polar as O – H so they have lower MP and BP than their corresponding alcohols. As molecular weight increases so does BP and MP unless no H bonding occurs. Match these MP to the diagrams 8oC, -33oC, 6oC. H NH H H3C H NH H3C H3C NH Remember the carboxylic acids Ethanoic Acid is If the OH group is replaced by an CH3C=O amine the resulting | functional group is NH OH2 called an amide. Ethanamide Amides are named from the parent 3-ethyl-2-pentenamide is CH3-CH2-CH=CH-C=O | | C2H5 N / \ H H If the H’s on the NH2 are replaced by a methyl and an ethyl CH3-CH2-CH=CH-C=O | | C2 H5 N / \ H H CH C The name is 3 2 H5 N-ethyl-N-methyl-3-ethyl-2-pentenamide Sketch the following N-ethylbutanamide CH3-CH2-CH2-C=O | N / \ C2H5 H H H H C C H H N H H H H C C C O H H H O H H H H C C H H N H H H H C C C O H H H O H H H H C C H H N H H H H C C C O H H H O H H H H C C H H N H H H H C C C O H H H O H H H H C C H H N H H H H C C C O H H H O H H H H C C H H N H H H H C C C O H H H O H H H H C C H H N H H H O H H C C C O H H H H H H C C H H N H H H O H H C C C O H H H H H H C C H H N H H O H H H C C C O H H H H H H C C H H N H H O H H H C C C O H H H H H H C C H H N H H O H H H C C C O H H H H H H C C H H N H H O N-ethylpropanamide H H H C C C O H H H Making Amides From Amines and Acids C2H5NH2 + C2H5CO2H C2H5CONHC2H5 + H2O Amides are generally insoluble in water due to the relative cancellation of the 4 different polar regions (the two N – H s, the C = O and the C - N). The lower molecular weight amides are slightly soluble due to the presence of H bonding. Amides which have alkyl groups attached to the N atom have weaker intermolecular forces (due to lack of H bonding) so have lower MP and BP. The lone pair of electrons found on the N atom makes it attractive to H atoms so amines are weak bases. NO2 groups can be attached as side chains to carbon parent chains. These nitro groups as named as side chains much like halogens (Cl), ethers (OCH3) and hydroxys (OH). Here is an example. 3-nitro-1-hexene has the structure CH2=CH-CH-CH2-CH2-CH3 | NO2 Sketch 1-methyl-2,3,4-trinitro-1,3,5cyclohexatriene (TNT) NO2 C NO2 NO2 C C C C C CH3 This structure is also called trinitrotoluene (TNT). A benzene H ring with a methyl group is called H toluene. Benzene is also drawn like this Br and when functional groups are attached at adjacent locations the Cl Br F prefix ortho(o) is used. Here are examples of o-dichlorobenzene If functional groups are on carbons separated by one Cl F Cl F Br empty carbon the prefix used is meta (m) Here are examples Cl Br F of m -difluorobenzene. If functional groups are on carbons separated by two empty carbons the prefix used is para (p) Here are examples of p -dibromobenzene. 20 different amino acids are used to assemble protein. Like the name implies amino acids have amino and carboxylic acid groups on adjacent carbons. Each of the 20 different amino acids has a different R group. R OH | | H-C-C=O | NH2 If the R group is methyl the amino acid is called alanine. Its structure is CH3 OH | | H-C-C=O | NH2 If the rules presented previously were used to name alanine it would be called 2 - aminopropanoic acid If serine is named 2-amino-3hydroxypropanoic acid what is its structure? 2-amino-3-hydroxypropanoic acid H OH | | OH-CH2-C-C=O | NH2 Most of the dry mass of living organisms is composed of proteins. Proteins are composed of long chains of the 20 different amino acids linked end to end. Here is an example of how amino acids are chemically bonded. The product produced from 2 amino acids is called a dipeptide. Here is how dipeptides form. When 2 different amino acids combine the amino group of one amino acid always reacts with the carboxyl group of the other amino acid. Notice water is eliminated so this kind of reaction is called a dehydration synthesis. The product is called a dipeptide. H OH | | H-C-C=O | NH2 CH3 OH | | H-C-C=O | N / \ H H H OH | | H-C-C=O | NH2 CH3 OH | | H-C-C=O | N / \ H H CH3 OH | | H-C-C=O | N H2O + \ H H | H-C-C=O | NH2 Remember a peptide linkage occurs between the amino group of one amino acid and the carboxyl group of another. Water is always eliminated in this dehydration synthesis. Show how a peptide bond forms from 2 amino acids if one has an R group which is a hydroxy and the other’s R group is an ethyl. OH OH | | H-C-C=O | C2H5 OH H-N-H | | H-C-C=O | H-N-H OH OH | | H-C-C=O | N-H C2H5 + H20 | H-C-C=O | H-N-H To watch a movie showing polypeptide formation click here Making Aspartame - A dipeptide HO O NH2 180x's sweeter than sugar Phenylalanine Systematic name? 2-amino-3-phenyl-propanoic acid Making Aspartame - A dipeptide HO OH O NH2 O Aspartic acid Systematic name? Aminobutandioic acid Making Aspartame HO O N H H HO OH O NH2 O Making Aspartame HO O N H H HO OH O NH2 O Making Aspartame HO O N H H HO OH O NH2 O Making Aspartame HO O HN OH O NH2 O Methyl ester of a Dipeptide H3C methanol OH HO O HN OH O NH2 O Methyl ester of a Dipeptide H3C methanol OH HO O HN OH O NH2 O Methyl ester of a Dipeptide H3C methanol OH HO O HN OH O NH2 O Methyl ester of a Dipeptide H3C O O HN OH O NH2 O Methyl ester of a Dipeptide 10% of ingested aspartame is changed into methanol which is poisonous Doseage from 1 diet drink is minimal Sucralose is probably better as an artificial sweetner. Show where this hydrolysis happens. H3C O O HN OH O NH2 O Methyl ester of a Dipeptide H3C O H O H O HN OH O NH2 O Methyl ester of a Dipeptide H3C OH HO O HN O Methanol is further oxidized into methanal, then methanoic acid. Draw these reactions. Methanoic acid can be toxic at high levels due to its inhibition of cytochrome c oxidase the last enzyme in the electron transport chain in the mitochondria. It OH the electrons to oxygen. transfers Complete inhibition is fatal. NH O 2 sucralose Sucrose -white sugar Notice the similarites between sucralose and sucrose. Compare to aspartame sucralose H3C Aspartame O O HN OH O Sucrose -white sugar NH2 O Making Acetylsalicylic Acid (ASA) Aspirin HO H3C O O O OH + HO O O + O O H 3C CH3 OH O H3C Salicylic acid Acetic anhydride Ethanoyl ethanoate ASA Ethanoic acid Acetic acid 5% is vinegar Let's focus on the acetic anhydride. O H3C O O CH3 O CH3 OH H3C HO O All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) Let's focus on the acetic anhydride. O H3C O O CH3 O CH3 OH H3C HO O All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) Let's focus on the acetic anhydride. O H3C O O O CH3 O O H3C CH3 All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) Let's focus on the acetic anhydride. O H3C O O O H3C CH3 All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) O O CH3 When an anhydride is placed in water it will undergo the reverse reaction (hydrolysis). Water is added and it reforms the 2 original molecules, in this case the ethanoic acid. O H3C O O H O H CH3 Let's focus on the acetic anhydride. O O H3C O CH3 O All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) O H3C O CH3 When an anhydride is placed in water it will undergo the reverse reaction (hydrolysis). Water is added and it reforms the 2 original molecules, in this case the ethanoic acid. O H3C O OH HO H CH3 Let's focus on the acetic anhydride. O H3C O O O H3C CH3 All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) O O CH3 When an anhydride is placed in water it will undergo the reverse reaction (hydrolysis). Water is added and it reforms the 2 original molecules, in this case the ethanoic acid. O H3C O OH OH H CH3 Let's focus on the acetic anhydride. O H3C O O O H3C CH3 All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) O O CH3 When an anhydride is placed in water it will undergo the reverse reaction (hydrolysis). Water is added and it reforms the 2 original molecules, in this case the ethanoic acid. O H3C O OH OH H CH3 Let's focus on the acetic anhydride. O H3C O O O H3C CH3 All anhydrides are created by the elimination of water. This anhydride is formed by the reaction of 2 acetic acid molecules with the elimination of water (dehydration) O O CH3 When an anhydride is placed in water it will undergo the reverse reaction (hydrolysis). Water is added and it reforms the 2 original molecules, in this case the ethanoic acid. O H3C O OH HO CH3 Now the ethanoic acid can undergo an esterification with the alcohol group of the salicylic acid to form the ASA HO O CH3 OH HO O Now the ethanoic acid can undergo an esterification with the alcohol group of the salicylic acid to form the ASA HO O CH3 OH HO O Now the ethanoic acid can undergo an esterification with the alcohol group of the salicylic acid to form the ASA HO O CH3 OH HO O Now the ethanoic acid can undergo an esterification with the alcohol group of the salicylic acid to form the ASA HO O CH3 O O ASA will sometimes smell like alcohol. This happens when the ester is hydrolyzed by water to reform the salicylic acid and ethanoic acid HO O CH3 O O ASA will sometimes smell like alcohol. This happens when the ester is hydrolyzed by water to reform the salicylic acid and ethanoic acid HO O CH3 O O H O H ASA will sometimes smell like alcohol. This happens when the ester is hydrolyzed by water to reform the salicylic acid and ethanoic acid HO O CH3 O H O O H ASA will sometimes smell like alcohol. This happens when the ester is hydrolyzed by water to reform the salicylic acid and ethanoic acid HO O CH3 OH HO O ASA will sometimes smell like alcohol. This happens when the ester is hydrolyzed by water to reform the salicylic acid and ethanoic acid HO O HO CH3 OH O Nylon is composed of gigantic molecules made up of a repeating subunit called a monomer. These extremely large molecules made up of large numbers of monomers are called polymers. Dupont, in Kingston, makes a kind of nylon called nylon 6,6. It is made from a 6 carbon dicarboxylic acid and a 6 carbon diamino compound. 1,6-diaminohexane (hexamethylene diamine) is one of these compounds and hexandioic acid (adipic acid) is the other. These molecules are combined end to end by releasing water in a dehydration synthesis. Show how this is done. O=C-(CH2)4-C=O CH2-(CH2)4-CH2 | | | | OH OH H-N-H H-N-H hexandioic acid 1,6-diaminohexane O=C-(CH2)4-C-N-CH2-(CH2)4-CH2 | || | | OH O H H-N-H This n means this basic monomer is repeated over and over To watch a movie click here. n Polymers made by the removal of water are called condensation polymers. Polyesters, like Dacron, are examples of this type of polymer. Esters are made by combining alcohols and acids. To watch a movie of polyester formation click here Dacron is made from 1,2-ethanediol (ethylene glycol) and paradibenzoic acid (pphthalic acid). Show how this polymer is made from these 2 monomers. HO O O C C O HO C OH HO CH2 CH2 OH HO O C O CH2 CH2 O O O C C OH O O CH C HO O CH2 CH2 OH CH2 CH2 OH Addition Polymerization Alkene monomers can be combined by breaking double bonds. For movie click here. ethene H H C C H H C + H H C H H H C H H C H H H C H C H H H H H C C + H H H C C H H H polyethylene Addition polymerization has 3 steps Initiation - a peroxide becomes a free radical( a compound with an unshared electron) When the free radical collides with a monomer it steals only 1e1- from the double bond leaving behind another free radical. This begins the 2nd stage called elongation. The chain continues to grow until 2 free radicals collide and form a stable polymer. This stage is called the termination of the polymerization. Show how addition polymers can be made from Propene, chloroethene, and phenylethene (styrene). These polymers are called polypropylene, polyvinyl chloride, and polystyrene. propene H C H H C +H C C H H H H H H H H3C polypropylene C C H H H CH2 CH2 CH2 H C H HC CH H3C + C C H H CH3 CH3 H H C C CH3H n chloroethene HC CH2 HC + Cl CH2 Cl CH2 HC + Cl CH2 CH CH2 Cl Polyvinyl chloride (PVC) CH2 Cl CH Cl CH3 H H C C H Cl n Phenylethene (styrene) CH CH2 CH + CH CH2 + | | | | | | -C – C – C – C – C – C – | | | | | | H H C H polystyrene CH2 C n Addition polymerization occurs in 3 stages: Initiation, propagation and termination. An initiating molecule like peroxide falls apart and makes a free radical with a single electron. This highly reactive particle starts the polymerization process. To go to a web site and read more click here. Plastics are polymers made from monomers of substituted ethene. Examples include: Teflon Plexiglass Methyl-2-propenoate tetrafluoroethene 1-methoxy-2-propenal F F F C F CH C C F F C C F H2C F n H3C O O H H C C H COOCH3 n Monomers used to make synthetic rubber CH3 H2C C Cl CH isoprene CH2 H2C C CH CH2 neoprene Name these monomers. 2-methyl-1,3-butadiene 2-chloro-1,3-butadiene The presence of the more electronegative Cl makes it more polar and less miscible with other hydrocarbons. Carbohydrate Polymers – starch, cellulose, glycogen monomer + monomer + monomer + monomer polymer OH OH O O + OH OH OH OH OH O + OH OH OH OH + OH OH OH OH The orientation of these bonds and the degree of cross-linking determines what it is. Typical Fats (Triglycerides) Linoleic acid, (omega 6) H H glycerol O C CH2 C CH2 CH2 CH2 CH2 CH2 C CH2 OH CH2 H HO C C H CH2 CH2 CH2 CH2 CH3 H H O C CH2 C C CH2 CH2 CH2 CH2 C CH2 OH HO CH Linolenic acid, H C H CH2 CH2 H CH2 C H (omega 3) C CH2 H2C CH3 OH O C H CH2 C C H CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 HO CH3 CH2 CH2 CH2 Oleic acid (monounsaturate) CH2 Typical Fats (Triglycerides) Linoleic acid, (omega 6) H H glycerol O C CH2 C CH2 CH2 CH2 CH2 CH2 C CH2 OH CH2 H HO C C H CH2 CH2 CH2 CH2 CH3 H H O C CH2 C C CH2 CH2 CH2 CH2 C CH2 OH HO CH Linolenic acid, H C H CH2 CH2 H CH2 C H (omega 3) C CH2 H2C CH3 OH O C H CH2 C C H CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 HO CH3 CH2 CH2 CH2 Oleic acid (monounsaturate) CH2 Soap Making Saponification H H O C CH2 C CH2 CH2 CH2 CH2 CH2 C CH2 OH CH2 H + NaOH CH HO C C H CH2 CH2 CH2 CH2 CH3 H H O C CH2 C CH2 CH2 CH2 CH2 C CH2 OH + NaOH HO CH CH2 H C H C H CH2 2 C H C CH2 + NaOH H2C CH3 OH O C H CH2 C C H CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH3 CH2 CH2 CH2 HO CH2 Soap Making Saponification soap H H O C CH2 C CH2 CH2 CH2 CH2 CH2 C CH2 OH CH2 H C C H CH2 CH2 CH2 CH2 HOCH2 CH2 O C CH2 C CH2 CH2 CH2 CH2 CH2 C CH2 OH HO Na HO CH CH CH2 H C H C H HO Na Na CH3 H H glycerol C H C CH2 H2C CH3 OH O C H CH2 C C H CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH3 CH2 CH2 CH2 Na HOCH2 HONa CH2 Most soaps are made from palmitin and stearin from palm oil and olive oil. OH O C CH2 CH2 CH2 CH2 H2C CH2 CH2 CH2 H2C CH2 CH2 CH2 CH2 CH2 CH2 CH2 CH2 Stearic acid CH3 CH2 H2C CH2 CH2 CH3 OH H2C CH2 CH2 CH2 C CH2 CH2 Palmitic acid CH2 CH2 CH2 O Show, using structural diagrams, how sodium stearate is made. See pg. 134 There are 2 classes of fats which are essential in the human diet because they cannot be biosynthesized by the human body. These fats are called essential fatty acids (EFA) and as the name implies they contain the carboxyl functional group (COOH). They fall into 2 categories omega 3 and omega 6. All of these essential fatty acids are unsaturates. Essential omega 3 fatty acids include: α-linolenic acid (ALA), eicosapentaenoic acid (EPA), and docosahexaenoic acid (DHA). alpha-linolenic acid (18:3, ALA), eicosapentaenoic acid (20:5, EPA), and docosahexaenoic acid (22:6, DHA). These three polyunsaturates have either 3, 5 or 6 double bonds in a carbon chain of 18, 20 or 22 carbon atoms, respectively. All double bonds are in the cis-configuration, i.e. the 2 H atoms are on the same side of the double bond. ALA – alpha-linolenic acid (18:3) (18 carbons, 3 double bonds at positions 3,6,9 from the terminal methyl end; found in (flax seed oil) EPA – Eicosahexaenoic acid (20:5) 3,6,9,12,15 DHA - Docosohexanoic acid (22:6) 3,6,9,12,15,18 ? All three found in seaweed, cold water fish Shortening is a semisolid fat used in food preparation, especially baked goods, and is so called because it inhibits the formation of long gluten strands in wheat-based doughs, giving them a "short" texture (as in shortbread). Shortening can be made from animal fat (lard), but is more commonly a hydrogenated vegetable oil that is solid at room temperature. Shortening has a higher smoke point than butter and margarine, and it has 100% fat content, compared to 80% for butter and margarine. Crisco, a popular brand, was first produced in 1911. Despite its worldwide usage and availability, vegetable shortening is believed to be damaging to human health since it generally contains trans fats. Denmark banned it from foods in 2003. Lard - rendered and clarified pork fat, the quality of which depends on the area the fat came from and the method of rendering. The very best is leaf lard, which comes from the fat around the animal's kidneys. The Nutritional Value for: lard Carbs Protein Cholesterol Weight Fat Saturated Fat Quantity (grams) (grams) (milligrams) (grams) (grams) (grams) 1 cup 0 0 195 205 205 80.4 1 tbsp 0 0 12 13 13 5.1 Toward the late 20th century lard began to be regarded as less healthy than vegetable oils such as olive and sunflower due to its high saturated fatty acid and cholesterol content. Tallow is a solid fat extracted from the tissues and fatty deposits of animals, especially from suet (the fat of cattle and sheep). Pure tallow is white, odorless and tasteless; it consists chiefly of triglycerides of stearic (CH3(CH2)16COOH ), palmitic (CH3(CH2)14COOH ), and oleic acids (18 carbon, monounsaturated, omega 9 fatty acid). Draw the carbon skeleton. A triglyceride is made by an esterification involving 1,2,3-propantriol and 3 fatty acids. Show how a triglyceride is made from oleic, stearic and palmitic acids. Tallow is usually obtained commercially by heating suet (the hard fatty tissues around the kidneys of cattle and sheep) under pressure in closed vessels. Tallow is used to make soap and candles. It was formerly in common use as a lubricant. but·ter (bŭt'ər) n. 1.A soft yellowish or whitish emulsion of butterfat, water, air, and sometimes salt, churned from milk or cream and processed for use in cooking and as a food. The Nutritional Value for: butter Description Quantity salted salted salted 1 PAT 1 tbsp 1/2 cup unsalted unsalted unsalted 1 PAT 1 tbsp 1/2 cup Cholesterol Weight Fat Saturated Fat (milligrams) (grams) (grams) (grams) 11 5 4 2.5 31 14 11 7.1 247 113 92 57.1 11 31 247 5 14 113 4 11 92 2.5 7.1 57.1 canola oil (kə′nōl·ə ′öil) (food engineering) An edible vegetable oil derived from rapeseed that is low in saturated fatty acids (less than 7%), high in monosaturated fatty acids (60%), and high in polyunsaturated fatty acids (30%). Here's a comparison of some to the more common fats and oils. The lower the saturated fat, the better For more information click here