Download OR (a) 100 k: (b) 8 k: (c) 1 M:

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Design exercise: Need to drive a 100 kohm
load and get rid of the 20 kHz “noise”
0.05 ms
1 ms
Step 1: choose circuit
100k
OR
100k
Step 2: choose R
(a) 100 k:
(b) 8 k:
(c) 1 M:
(b) 2 kHz
(c) 200 Hz
Step 3: f3db
(a) 20 kHz
Step 4: choose C
Z3db
1
RC
Recap:
Vin
Voltage divider
Z2
Vout = I Z1
Z1
= Vin
Impedance of capacitor:
Z2
Low pass filter
Z1 + Z2
Zc = 1/jZC
Z2
Z1
Z1 Î f when Z Î 0
Z1
Z1
Z2 Î f when Z Î 0
High pass filter
Diodes (PN junction)
(1) do not obey ohms law
(2) Current only flows in one direction
P
N
Reversed bias: no current flows
P
N
Forward bias: current flows
Diodes
current
Simplified behavior of an ideal diode
I
0.6V
V
V
Vdiode = 0.6 V
V
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