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VARIABLE-FREQUENCY NETWORK PERFORMANCE Variable-Frequency Response Analysis Network performance as function of frequency. Transfer function Sinusoidal Frequency Analysis Bode plots to display frequency response data VARIABLE FREQUENCY-RESPONSE ANALYSIS In AC steady state analysis the frequency is assumed constant (e.g., 60Hz). Here we consider the frequency as a variable and examine how the performance varies with the frequency. Variation in impedance of basic components Resistor Z R R R0 Inductor Z L jL L90 Capacitor Zc 1 1 90 jC C Frequency dependent behavior of series RLC network 2 1 ( j ) 2 LC jRC 1 j RC j ( LC 1) Z eq R jL j C jC jC " Simplifica tion in notation" j s s 2 LC sRC 1 Z eq ( s) sC (RC ) ( LC 1) | Z eq | C 2 2 2 1 LC 1 Z eq tan RC 2 Simplified notation for basic components Z R ( s) R, Z L ( s) sL, ZC 1 sC For all cases seen, and all cases to be studied, the impedance is of the form am s m am 1s m 1 ... a1s a0 Z ( s) bn s n bn1s n1 ... b1s b0 Moreover, if the circuit elements (L,R,C, dependent sources) are real then the expression for any voltage or current will also be a rational function in s 1 sC sL R sRC VS 2 VS R sL 1/ sC s LC sRC 1 s j jRC Vo VS 2 ( j ) LC jRC 1 Vo ( s) R j (15 2.53 103 ) Vo 100 2 3 3 ( j ) (0.1 2.53 10 ) j (15 2.53 10 ) 1 NETWORK FUNCTIONS Some nomenclature When voltages and currents are defined at different terminal pairs we define the ratios as Transfer Functions INPUT Voltage Current Current Voltage OUTPUT TRANSFER FUNCTION SYMBOL Voltage Voltage Gain Gv(s) Voltage Transimpedance Z(s) Current Current Gain Gi(s) Current Transadmittance Y(s) If voltage and current are defined at the same terminals we define Driving Point Impedance/Admittance EXAMPLE To compute the transfer functions one must solve the circuit. Any valid technique is acceptable I 2 ( s) Transadmittance V1 ( s) Transfer admittance V ( s) Gv ( s ) 2 Voltage gain V1 ( s) YT ( s) EXAMPLE VOC ( s) sL V1 ( s) sL R1 We will use Thevenin’s theorem 1 sLR1 1 R1 || sL sC sL R1 sC s 2 LCR1 sL R1 ZTH ( s ) sC ( sL R1 ) ZTH ( s) I 2 ( s) Transadmittance V1 ( s) Transfer admittance V ( s) Gv ( s ) 2 Voltage gain V1 ( s) YT ( s) ZTH (s) VOC (s) sL V1 ( s ) sL R1 VOC ( s) sC ( sL R1 ) I 2 ( s) s 2 LCR1 sL R1 sC ( sL R1 ) R2 ZTH ( s) R2 sC ( sL R1 ) I 2 ( s) R2 V2 ( s ) s 2 LC YT ( s) 2 s ( R1 R2 ) LC s( L R1R2C ) R1 Gv ( s) V2 ( s ) R2 I 2 ( s) R2YT ( s ) V1 ( s ) V1 ( s) POLES AND ZEROS (More nomenclature) am s m am 1s m 1 ... a1s a0 H ( s) bn s n bn1s n1 ... b1s b0 Arbitrary network function Using the roots, every (monic) polynomial can be expressed as a product of first order terms H ( s) K 0 ( s z1 )( s z2 )...( s zm ) ( s p1 )( s p2 )...( s pn ) z1, z2 ,..., zm zeros of the network function p1, p2 ,..., pn poles of the network function The network function is uniquely determined by its poles and zeros and its value at some other value of s (to compute the gain) EXAMPLE zeros : z1 1, poles : p1 2 j 2, p2 2 j 2 H (0) 1 H ( s) K 0 ( s 1) s 1 K0 2 ( s 2 j 2)( s 2 j 2) s 4s 8 1 H (0) K 0 1 8 H ( s) 8 s 1 s 2 4s 8 SINUSOIDAL FREQUENCY ANALYSIS A0e j ( t ) B0 cos( t ) H (s ) A0 H ( j )e j ( t ) B0 | H ( j ) | cos t H ( j ) Circuit represented by network function To study the behavior of a network as a function of the frequency we analyze the network function H ( j ) as a function of . Notation M ( ) | H ( j ) | ( ) H ( j ) H ( j ) M ( )e j ( ) Plots of M ( ), ( ), as function of are generally called magnitude and phase characteristics. 20 log10 (M ( )) BODE PLOTS vs log10 ( ) ( ) HISTORY OF THE DECIBEL Originated as a measure of relative (radio) power P2 |dB (over P1 ) 10 log P2 P1 V2 V22 I 22 PI R P2 |dB (over P1 ) 10 log 2 10 log 2 R V1 I1 2 V |dB 20 log10 | V | By extension I |dB 20 log10 | I | G |dB 20 log10 | G | Using log scales the frequency characteristics of network functions have simple asymptotic behavior. The asymptotes can be used as reasonable and efficient approximations General form of a network function showing basic terms Poles/zeros at the origin Frequency independent K 0 ( j ) N (1 j1 )[1 2 3 ( j3 ) ( j3 )2 ]... H ( j ) (1 ja )[1 2 b ( jb ) ( jb )2 ]... log( AB ) log A log B First order terms N log( ) log N log D D Quadratic terms for complex conjugate poles/zeros | H ( j ) |dB 20 log10 | H ( j ) | 20 log10 K 0 N 20 log10 | j | 20 log10 | 1 j1 | 20 log10 | 1 2 3 ( j3 ) ( j3 ) 2 | ... 20 log10 | 1 ja | 20 log10 | 1 2 b ( jb ) ( jb ) 2 | .. z1z2 z1 z2 H ( j ) 0 N 90 Display each basic term z1 2 z1 z2 1 1 separately and add the 3 3 tan tan ... 1 z2 results to obtain final 1 (3 ) 2 2 bb tan 1 a tan 1 ... 1 (b ) 2 answer Let’s examine each basic term Constant Term the x - axis is log10 this is a straight line Poles/Zeros at the origin ( j ) N | ( j ) N |dB N 20 log10 ( ) ( j ) N N 90 | 1 j |dB 20 log10 1 ( ) 2 1 j Simple pole or zero (1 j ) tan 1 1 | 1 j |dB 0 low frequency asymptote (1 j ) 0 1 | 1 j |dB 20 log10 high frequency asymptote (20dB/dec) The two asymptotes meet when 1(corner/break frequency) (1 j ) 90 Behavior in the neighborhood of the corner corner octave above octave below distance to FrequencyAsymptoteCurve asymptote Argument 3dB 3 45 1 0dB 2 6dB 7db 1 63.4 0 .5 0dB 1dB 1 26.6 Asymptote for phase Low freq. Asym. High freq. asymptote Simple zero Simple pole Quadratic pole or zero t 2 [1 2 ( j ) ( j ) ] [1 2 ( j ) ( )2 ] 2 | t 2 |dB 20 log10 1 ( ) 2 2 t 2 tan 1 2 2 1 | t2 |dB 0 low frequency asymptote 2 1 ( ) 2 t2 0 1 | t2 |dB 20 log10 ( )2 high freq. asymptote 40dB/dec t2 180 1 | t2 |dB 20 log10 (2 ) Corner/break frequency t2 90 1 2 2 | t2 |dB 20 log10 2 1 2 Resonance frequency These graphs are inverted for a zero Magnitude for quadratic pole t 2 tan 1 1 2 2 Phase for quadratic pole 1 2Q 2 2 LEARNING EXAMPLE Draw asymptotes for each term Generate magnitude and phase plots Gv ( j ) 10(0.1 j 1) ( j 1)(0.02 j 1) Breaks/corners : 1,10,50 Draw composites dB 40 20 10 |dB 20dB / dec 0 20dB / dec 20 90 45 / dec 45 / dec 0.1 1 10 100 90 1000 asymptotes DETERMINING THE TRANSFER FUNCTION FROM THE BODE PLOT This is the inverse problem of determining frequency characteristics. We will use only the composite asymptotes plot of the magnitude to postulate a transfer function. The slopes will provide information on the order A. different from 0dB. There is a constant Ko A B C K 0 |dB 20 K 0 D E K 0 |dB 10 20 B. Simple pole at 0.1 ( j / 0.1 1)1 C. Simple zero at 0.5 ( j / 0.5 1) D. Simple pole at 3 ( j / 3 1)1 E. Simple pole at 20 G ( j ) 10( j / 0.5 1) ( j / 0.1 1)( j / 3 1)( j / 20 1) ( j / 20 1)1 If the slope is -40dB we assume double real pole. Unless we are given more data LEARNING EXAMPLE A function with complex conjugate poles t 2 [1 2 ( j ) ( j )2 ] Put in standard form G ( j ) G ( j ) Draw composite asymptote 25 j ( j 0.5) ( j ) 2 4 j 100 0.5 j ( j / 0.5 1) ( j / 10) 2 j / 25 1 2 1 / 25 0.2 0.1 dB 40 20 1 | t2 |dB 20 log10 (2 ) 0 8dB 20 90 90 Behavior close to corner of conjugate pole/zero is too dependent on damping ratio. Computer evaluation is better 0.01 0.1 1 10 270 100 Evaluation of frequency response using MATLAB G ( j ) Using default options 25 j ( j 0.5) ( j ) 2 4 j 100 » num=[25,0]; %define numerator polynomial » den=conv([1,0.5],[1,4,100]) %use CONV for polynomial multiplication den = 1.0000 4.5000 102.0000 50.0000 » freqs(num,den) > pzmap(num,den) VARIABLE-FREQUENCY NETWORK PERFORMANCE Resonant Circuits The resonance phenomenon and its characterization Filter Networks Networks with frequency selective characteristics: low-pass, high-pass, band-pass RESONANT CIRCUITS These are circuits with very special frequency characteristics… And resonance is a very important physical phenomenon Parallel RLC circuit Series RLC circuit Z ( j ) R jL 1 jC Y ( j ) G jC 1 jL The reactance of each circuit is zero when L 1 0 C 1 LC The frequency at which the circuit becomes purely resistive is called the resonance frequency Properties of resonant circuits At resonance the impedance/admittance is minimal Z ( j ) R jL | Z |2 R 2 (L 1 jC Y ( j ) G 1 2 ) C 1 jL | Y |2 G 2 (C jC 1 2 ) L Current through the serial circuit/ voltage across the parallel circuit can become very large (if resistance is small) Quality Factor : Q 0 L R 1 0CR Given the similarities between series and parallel resonant circuits, we will focus on serial circuits EXAMPLE Determine the resonant frequency, the voltage across each element at resonance and the value of the quality factor I 1 0 L 50 0C VC 1 j 0 C I j 50 5 250 90 Q 1 1 2000rad / sec 3 6 LC (25 10 H )(10 10 F ) At resonance Z 2 V 100 I S 5A Z 2 0 0 L (2 103 )(25 103 ) 50 VL j0 LI j50 5 25090 (V ) 0 L R 50 25 2 At resonance VS Q | VS | R | VC | Q | VS | | VL | 0 L M ( ) Resonance for the series circuit Z ( j ) R jL | Z |2 R 2 (L 1 jC 1 2 ) C 1 1/ 2 0 2 2 1 Q ( ) 0 BW 0 Q Claim : The voltage gain is V 1 Gv R V1 1 jQ ( 0 ) 0 Gv At resonance : 0 L QR, 0C R 1 R jL jC 1 QR Z ( j ) R j Gv R Z R Z ( j ) Half power frequencie s ( ) tan 1 Q ( 0 ) 0 QR j 0 QR 0 R 1 jQ( 0 ) 0 M ( ) | Gv |, ( ) | Gv LO 2 1 1 0 1 2Q 2Q The Q factor 0 L 1 R 0CR For series circuit : High Q Low R For parallel circuit : High Q High R (low G) Q High Q Small BW M dissipates Stores as E field Stores as M field Capacitor and inductor exchange stored energy. When one is at maximum the other is at zero EXAMPLE The Tacoma Narrows Bridge Opened: July 1, 1940 Collapsed: Nov 7, 1940 Likely cause: wind varying at frequency similar to bridge natural frequency 0 2 0.2 FILTER NETWORKS Networks designed to have frequency selective behavior COMMON FILTERS Low-pass filter High-pass filter Band-reject filter Band-pass filter Simple low-pass filter 1 V 1 jC Gv 0 V1 R 1 1 jRC jC 1 Gv ; RC 1 j M ( ) | Gv | 1 1 2 Gv ( ) tan 1 1 1 M max 1, M 2 1 half power frequency BW 1 Simple high-pass filter Gv V0 R jCR V1 R 1 1 jCR jC Gv j ; RC 1 j M ( ) | Gv | Gv ( ) 1 2 2 tan 1 1 1 M max 1, M 2 1 half power frequency LO 1 Simple band-pass filter Band-pass V Gv 0 V1 M ( ) LO R 1 R j L C RC HI RC 2 2 LC 1 2 1 M 1 M ( 0) M ( ) 0 LC 0 M ( LO ) ( R / L) 1 LC 1 M ( HI ) 2 R / L2 4 20 2 ( R / L) R / L2 4 20 2 BW HI LO R L Simple band-reject filter 1 1 0 j0 L LC C 0 at 0 the capacitor acts as open circuit V0 V1 0 at the inductor acts as open circuit V0 V1 LO , HI are determined as in the band - pass filter Sketch the magnitude characteristic of the Bode plot for Gv ( j ) 1 1 jC Gv ( j ) 1 1 jRC R jC RC (10 103 )(20 106 F ) 0.2rad / s Break/corner frequency : 5rad/s low frequency asymptote of 0dB/dec High frequency asymptote of - 20dB/dec Sketch the magnitude characteristic of the Bode plot for Gv ( j ) 20dB/dec. Crosses 0dB at Gv ( j ) RC (25 103 )(20 106 F ) 0.5rad / s R R 1 jC 1 2rad / s jRC 1 jRC Break/corner frequency : 2rad/s low frequency asymptote of 0dB/dec High frequency asymptote of - 20dB/dec