Survey
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
OSCILLATOR Bollen 1 AGENDA What is oscillation Frequency = 1 / total time Analog oscillation Variationa WIEN bridge oscillator Summary High pass and low pass combined Relaxatin oscillator RC circuit 15k and 10 nF Voltage diviver 15k and 15k Comparator Signals and output Charge Discharge Bollen 2 What is oscillation Circuit powered by Vcc and Vee No input signal, only output signal Wienbridge Oscillator; output signal is sine wave (used for making radio frequencies) Relaxation Oscillatoer; output signal is a “digital” block signal (used for clock or count circuits) Bollen 3 What is analog oscillation WIEN bridge oscillator Barkhausen criterium: Loopgain = 1 Total phase = 0 or 360 Bollen 4 WIEN bridge oscillator Oscillator for High frequency Sine signals It uses 2 filters; High pass and low pass For one frequency the phase = 0 degrees !!!! Bollen 5 High Pass and Low Pass combinated Bollen 6 WIEN bridge oscillator Barkhausen criterium: Loopgain = 1 Total phase = 0 or 360 Bollen 7 WIEN bridge oscillator Uout Uin R 1 After “short” mathematics; R2 1 jwC1 1 R2 jwC2 1 jwC1 wR2C2 Uout Uin w R1C2 R2C1 R2C2 j w2 R1R2C1C2 1 w2 R1 R2C1C2 1 0 f oscillation Bollen 1 2 RC for R1 R2 R and C1 C2 C 8 WIEN bridge oscillator Uout Uin 1 R2 jwC1 1 R2 jwC1 1 R2 jwC1 1 R1 jwC2 R 1 2 jwC1 1 R2 jwC1 1 1 1 R1 R2 R2 jwC2 jwC1 jwC1 Bollen 9 WIEN bridge oscillator 1 R2 jwC1 Uout Uin R R R1 R2 1 R2 1 2 jwC1 jwC2 w2C1C2 jwC1 R2 Uout C1 1 Uin jwR1 R2C1 R1 R2 j R2 C2 wC2 Bollen 10 WIEN bridge oscillator R2 Uout C1 1 Uin jwR1 R2C1 R1 R2 j R2 C2 wC2 wR2C2 Uout Uin w R1C2 R2C1 R2C2 j w2 R1R2C1C2 1 For phase = o degrees; imaginair part = 0 w2 R1 R2C1C2 1 0 f oscillation Bollen for R1 R2 R and C1 C2 C 1 2 RC 11 WIEN bridge oscillator wR2C2 Uout Uin w R1C2 R2C1 R2C2 j w2 R1R2C1C2 1 For R1 = R2 = R And C1 = C2 = C At oscillation IM = 0 Au = 1/3 so amplificaton should be +3 Rf = 2 Rs Bollen 12 WIEN bridge oscillator Bollen 13 What is “digital” oscillation Relaxation oscillator RC-circuit 15k and 10nF; charge / discharge Voltage divider 15k and 15k; high treshold / low treshold Comparator Output: block Vcc / Vee Bollen 14 RC-circuit 15k and 10nF Vin = Vcc = +12 for charge And = Vee = -12 for discharge Vc V final V final Vinitial e Bollen t RC 15 Voltage divider 15k and 15k Vin = +12 volt = opamp output high or Vin = - 12 volt = opamp output low V treshold up = +6 V for +12 opamp output V treshold low = -6 V for – 12 opamp output Bollen 16 Comparator Inverting input; Uc, capacitor voltage Non inverting input; Treshold voltage, high (+6 Volt) or low (-6 volt) Output: Bollen Vout A0 V V 17 Signals and output Blue = output signal (+12 Volt or – 12 Volt) Green = treshold signal (+6 Volt of – 6 Volt) Red = capacitor signal Bollen Vc V final V final Vinitial e 18 t RC Charge Calculate 2nd charge track! Why? Vc V final V final Vinitial e Vinitial 6 V switch at Vc 6 Volt 6 12 12 6 e tch arg e 0,165 ms Bollen t 15 k .10 n t RC R = 15 k C = 10 nF Vfinal = +12 V Vinitial = -6 V Switch at Vc = +619 Volt Discharge Vc V final V final Vinitial e t RC Vinitial 6 V switch at Vc 6 Volt 6 12 12 6 e tdisch arg e 0,165 us t 15 k .10 n R = 15 k C = 10 nF Vfinal = -12 V Vinitial = +6 V Bollen Switch at Vc = -620Volt Frequency = 1 / (total time) tch arg e 0,165 ms tdisch arg e 0,165 ms ttotal 0,33 ms Bollen f oscillator 3, 0321kHz Variations 1 By using diodes; Charge time and Discharge time are different !! Treshold remains the same So … duty cylce is controlable; up time ≠ down time Bollen 22 Variations 2 Frequency control by changing the voltage divider Vtreshold up Vtreshold low Bollen 23 Summary 1 Analyse yourself .. .. .. Conclusion? Bollen 24 Summary 2 Analyse yourself .. .. .. Conclusion? Bollen 25