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Lecture 14 Goals: • Chapter 10 • Understand spring potential energies & use energy diagrams • Chapter 11 Understand the relationship between force, displacement and work Recognize transformations between kinetic, potential, and thermal energies Define work and use the work-kinetic energy theorem Use the concept of power (i.e., energy per time) Assignment: HW7 due Wednesday, Mar. 10 For Tuesday: Read through Ch. 12, Sections 1-3, 5 & 6 Do not concern yourself with the integration process in regards to “center of mass” or “moment of inertia” Physics 207: Lecture 14, Pg 1 Energy for a Hooke’s Law spring dvx dvx dx dvx Fx m m m vx k ( x xeq ) dt dx dt dx Fx dx mvx dvx k ( x xeq )dx uf vxf ui 1 2 vxi 1 2 u x xeq dx du Fu du mvx dvx ku mv ku mv 2 i 2 i 1 2 2 f 1 2 2 f Associate ½ ku2 with the “potential energy” of the spring m Physics 207: Lecture 14, Pg 2 Energy for a Hooke’s Law spring 1 2 ku mv ku mv 2 i 1 2 2 i 1 2 2 f 1 2 2 f U si K i U sf K f constant Ideal Hooke’s Law springs are conservative so the mechanical energy is constant m Physics 207: Lecture 14, Pg 3 Energy diagrams In general: Ball falling Emech Spring/Mass system Emech U y K Energy Energy K U x Physics 207: Lecture 14, Pg 4 Equilibrium Example Spring: Fx = 0 => dU / dx = 0 for x=xeq The spring is in equilibrium position In general: dU / dx = 0 for ANY function establishes equilibrium U stable equilibrium U unstable equilibrium Physics 207: Lecture 14, Pg 5 Comment on Energy Conservation We have seen that the total kinetic energy of a system undergoing an inelastic collision is not conserved. Mechanical energy is lost: Heat (friction) Deformation (bending of metal) Mechanical energy is not conserved when non-conservative forces are present ! Momentum along a specific direction is conserved when there are no external forces acting in this direction. Conservation of momentum is a more general result than mechanical energy conservation. Physics 207: Lecture 14, Pg 6 Mechanical Energy Potential Energy (U) Kinetic Energy (K) If “conservative” forces (e.g, gravity, spring) then Before Emech = constant = K + U During 1 2 During Uspring+K1+K2 = constant = Emech After Mechanical Energy conserved Physics 207: Lecture 14, Pg 7 Energy (with spring & gravity) 1 h 0 -x 2 3 mass: m Given m, g, h & k, how much does the spring compress? Emech = constant (only conservative forces) At 1: y1 = h ; v1y = 0 At 2: y2 = 0 ; v2y = ? At 3: y3 = -x ; v3 = 0 Em1 = Ug1 + Us1 + K1 = mgh + 0 + 0 Em2 = Ug2 + Us2 + K2 = 0 + 0 + ½ mv2 Em3 = Ug3 + Us3 + K3 = -mgx + ½ kx2 + 0 Given m, g, h & k, how much does the spring compress? Em1 = Em3 = mgh = -mgx + ½ kx2 Solve ½ kx2 – mgx +mgh = 0 Physics 207: Lecture 14, Pg 8 Energy (with spring & gravity) 1 h mass: m 2 3 0 -x When is the child’s speed greatest? (A) At y1 (top of jump) (B) Between y1 & y2 (C) At y2 (child first contacts spring) (D) Between y2 & y3 (E) At y3 (maximum spring compression) Physics 207: Lecture 14, Pg 9 Inelastic Processes If non-conservative” forces (e.g, deformation, friction) Before then Emech is NOT constant After K1+2 < Emech (before) Accounting for this loss we introduce Thermal Energy (Eth , new) During 1 2 After where Esys = Emech + Eth = K + U + Eth Physics 207: Lecture 14, Pg 10 Energy & Work Impulse (Force vs time) gives us momentum transfer Work (Force vs distance) tracks energy transfer Any process which changes the potential or kinetic energy of a system is said to have done work W on that system DEsys = W W can be positive or negative depending on the direction of energy transfer Net work reflects changes in the kinetic energy Wnet = DK This is called the “Net” Work-Kinetic Energy Theorem Physics 207: Lecture 14, Pg 11 Circular Motion I swing a sling shot over my head. The tension in the rope keeps the shot moving at constant speed in a circle. How much work is done after the ball makes one full revolution? (A) W > 0 v (B) W = 0 (C) W < 0 (D) need more info Physics 207: Lecture 14, Pg 12 Examples of “Net” Work (Wnet) DK = Wnet Pushing a box on a smooth floor with a constant force; there is an increase in the kinetic energy Examples of No “Net” Work DK = Wnet Pushing a box on a rough floor at constant speed Driving at constant speed in a horizontal circle Holding a book at constant height This last statement reflects what we call the “system” ( Dropping a book is more complicated because it involves changes in U and K, U is transferred to K ) Physics 207: Lecture 14, Pg 13 Changes in K with a constant F xf vxf xi vxi Fx dx mv x dvx If F is constant xf vxf xi vxi Fx dx mvx dvx Fx ( x f xi ) Fx Dx 1 2 2 mv xf 1 2 2 mv xi DK Physics 207: Lecture 14, Pg 14 Net Work: 1-D Example (constant force) A force F = 10 N pushes a box across a frictionless floor for a distance Dx = 5 m. Finish Start F q = 0° Dx Net Work is F Dx = 10 x 5 N m = 50 J 1 Nm ≡ 1 Joule and this is a unit of energy Work reflects energy transfer Physics 207: Lecture 14, Pg 15 Units: Force x Distance = Work Newton x Meter = Joule [M][L] / [T]2 [L] [M][L]2 / [T]2 mks N-m (Joule) cgs Dyne-cm (erg) = 10-7 J Other BTU = 1054 J calorie= 4.184 J foot-lb = 1.356 J eV = 1.6x10-19 J Physics 207: Lecture 14, Pg 16 Net Work: 1-D 2nd Example (constant force) A force F = 10 N is opposite the motion of a box across a frictionless floor for a distance Dx = 5 m. Finish Start F q = 180° Dx Net Work is F Dx = -10 x 5 N m = -50 J Work reflects energy transfer Physics 207: Lecture 14, Pg 17 Work in 3D…. x, y and z with constant F: Fy ( y f yi ) Fy Dy 1 2 mv xf 2 1 2 mv yf 2 Fx ( x f xi ) Fx Dx Fz ( z f zi ) Fz Dz 1 2 Fx Dx Fy Dy Fz Dz with v 2 2 vx 2 vy 1 2 2 mv zf 2 mv f 1 2 1 2 mv xi 2 1 2 mv yi 2 1 2 mv zi 2 2 mvi DK 2 vz Physics 207: Lecture 14, Pg 18 Work: “2-D” Example (constant force) An angled force, F = 10 N, pushes a box across a frictionless floor for a distance Dx = 5 m and Dy = 0 m Start F Finish q = -45° Fx Dx Fx Dx = F cos(-45°) Dx = 50 x 0.71 Nm = 35 J (Net) Work is Work reflects energy transfer Physics 207: Lecture 14, Pg 19 Scalar Product (or Dot Product) A · B ≡ |A| |B| cos(q) Useful for performing projections. A î = Ax îî=1 îj=0 A q Ay î Ax Calculation can be made in terms of components. A B = (Ax )(Bx) + (Ay )(By ) + (Az )(Bz ) Calculation also in terms of magnitudes and relative angles. A B ≡ | A | | B | cos q You choose the way that works best for you! Physics 207: Lecture 14, Pg 20 Scalar Product (or Dot Product) Compare: A B = (Ax )(Bx) + (Ay )(By ) + (Az )(Bz ) with A as force F, B as displacement Dr and apply the Work-Kinetic Energy theorem Notice: F Dr = (Fx )(Dx) + (Fy )(Dz ) + (Fz )(Dz) Fx Dx +Fy Dy + Fz Dz = DK So here F Dr = DK = Wnet More generally a Force acting over a Distance does Work Physics 207: Lecture 14, Pg 21 Definition of Work, The basics Ingredients: Force ( F ), displacement ( D r ) Work, W, of a constant force F acts through a displacement D r : W = F ·D r F q Dr (Work is a scalar) “Scalar or Dot Product” F dr If we know the angle the force makes with the path, the dot product gives us F cos q and Dr If the path is curved r f and W dW F dr at each point F dr ri Physics 207: Lecture 14, Pg 22 Remember that a real trajectory implies forces acting on an object v path and time a a = atang + aradial a a a = a + a a =0 F = Ftang + Fradial Two possible options: Change in the magnitude of v a =0 Change in the direction of v a =0 Only tangential forces yield work! The distance over which FTang is applied: Work Physics 207: Lecture 14, Pg 23 Exercise Work in the presence of friction and non-contact forces A. B. C. D. A box is pulled up a rough (m > 0) incline by a rope-pulleyweight arrangement as shown below. How many forces (including non-contact ones) are doing work on the box ? Of these which are positive and which are negative? State the system (here, just the box) Use a Free Body Diagram Compare force and path v 2 3 4 5 Physics 207: Lecture 14, Pg 25 Lecture 14 Assignment: HW7 due Wednesday, March 10 For Tuesday: Read Chapter 12, Sections 1-3, 5 & 6 do not concern yourself with the integration process Physics 207: Lecture 14, Pg 26