Download 3Distance - TuHS Physics

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project

Document related concepts
no text concepts found
Transcript
Astronomical Units of distance
•Astronomical units (a.u.)
•Parsecs (pc)
•Light Years (ly)
The Astronomical Unit - The Earth - Sun
distance.
Using Kepler’s Period/Radius relationship for the
Orbit of Mars and Earth around the Sun:
RE3 = RM3
TE2 TM2
And a triangulation of Mars to find how far Earth was
from Mars (RM - RE) since the periods were well
known, they now had two equations, and two
unknowns.
RE is of course, 1 A.U.
1 A.U. is 1.496 x 108 km = 1.5 x 108 km
Concept -1:
An astronomical unit (AU) is
8
1.5 x 10 km
Neptune is 4500 million
kilometers from the sun.
How far is this in AUs?
4500x106 km/(1.5x108km/AU) = 30AU
30AU
Parsecs - Parallax Seconds
The distance in parsecs is defined as 1/Ø where Ø is
the parallax angle in seconds
(1 second - 1/3600 of a degree)
From Douglas Giancoli’s Physics
Concept 0:
There are 3600 seconds to a
degree. (Parallax angles are
really small, and measured in
seconds)
How many arc seconds are
there in 3.2 degrees?
3.2o*3600”/o=11520”
11520”
45 arc seconds is how many
degrees?
o
45”/3600”/o=.0125
.0125o
Suppose Ø = 1.45 x 10-5o
x3600 = .0522” so parsecs
= 1/.0522 = 19.2 pc
Since d is 1 AU, if we
know Ø – the parallax
Angle we can find D –
The distance to the star.
You know that Tan(Ø ) = d/D, so
D = 1.5 x 108 km/Tan(1.45 x 10-5o) = 5.9 x 1014 km
From Douglas Giancoli’s Physics
Concept 1:
The distance in parsecs is
defined as 1/Ø where Ø is
the parallax angle in seconds
If a star has a parallax of .12”,
what is its distance in parsecs?
Parsecs = 1/arcseconds =
1/.12 = 8.3 pc
8.3 pc
If a star is 89 parsecs away,
what is its parallax in arc
seconds?
Parsecs = 1/arcseconds so 89 =
1/arseconds, arseconds = 1/89
= .0112”
.0112”
Concept 2:
You know that Tan(Ø ) = d/D
(Where d = 1.5 x 108 km)
A star has a parallax of .015” what
is its distance in parsecs and km?
Parsecs = 1/arcseconds =
1/.015 = 66.666 pc
Tan(angle) = 1.5E8km/D,
so D = 1.5E8km/ Tan(angle) =
1.5E8/tan(.015/3600)
15
= 2.06x10 km
2.06x1015 km
A star is 6.14 x 1014 km away.
What is its parallax in arc seconds?
How many parsecs is it away?
-1
Angle = tan (d/D) =
tan-1(1.5E8/6.14E14) =
1.4E-5 degrees x 3600 =
.0504 arcseconds
Parsecs = 1/ = 1/.0504 = 19.8 pc
19.8 pc
Light Year - The distance traveled by light in a year
1 ly = (2.998x108m/s)(365.2499d/y)(24h/d)(3600s/h)
1 ly = 9.46x1012 km = 1013 km
1 parsec = 1.496 x 108/Tan(1/3600) = 3.086 x 1013 km
= (3.086 x 1013 km)/(9.46x1012 km/ly) = 3.26 ly
A star is 4.3 light years from
Earth. How many parsecs is
this?
= 4.3 ly/(3.26 ly/pc) = 1.3 pc
1.3 pc
Our Galaxy is 100,000 ly wide.
How many meters wide is it?
(100,000ly)(9.46x1012*km/ly)(1000m/km) =
9.46x1020m
9.46x1020m
Related documents