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STATISTICS Basic Concept of Probability Ir. Mahmud Sudibandriyo MSc., PhD September 24, 2008 1 Topics ¾ Concepts and Definitions ¾ Compound Event Probabilities ¾ Enumeration Technique September 24, 2008 2 Concepts and Definitions Probability Experiment: activities where an outcome, response, or measurement is obtained. Sample space (S): A set of values which covers all possibility of outcome, response, or measurement. Event : A subset of all outcome, response, or measurement in the sample space. Example: we inspect 3 pumps one by one in sequence, we note G for a pump in a good condition and F for a fail pump.. S S = {GGG,GGF,GFG,FGG,GFF,FGF,FFG,FFF} A If A is an event where we find one fail pump, then: A = {GGF, GFG, FGG} September 24, 2008 3 Probability: Probability = 1 if the event is definitely occurs Probability = 0 if the event is impossible. Classical Definition: P(A) = fA/N and P(Ā) = 1- P(A) exp: probability to get Ace in bridge cards is 4/52 probability to get non Ace is 1 – 4/52 = 48/52 Relative Frequency Definition: P (A) = lim fA/N NÆ∞ Subjective Definition: based on expert judgment exp: what is the probability of PERSIJA to win the game against PSIS ? September 24, 2008 4 Compound Event Probabilities Compound Event: a combination of 2 or more simple events Conditional probability: P (A|B) = P (A∩B)/ P(B) ; P(B) >0 exp: In PC production, 60% is installed word processor (A), 40% is installed with spreadsheet (B), 30% is installed with both of them. If one buy a PC with spreadsheet in it, what the probability this computer is also installed with word processor ? P(A) = 0.6 ; P(B) = 0.4 ; P (A∩B) = 0.3 ; P(A|B)=0.3/0.4=0.75 B A 0.3 September 24, 2008 0.3 0.1 A∩B 0.1 0.3 5 Independent and Dependent Event Independent event : P(A|B) = P(A) or P(B|A) = P(B) exp: A: “heads on the fifth toss”, B: “heads on the sixth toss” Dependent event : exp. conditional probability Mutually Exclusive P(A|B) = 0 and P(B|A) = 0 exp: A: “drawing an ace from a deck of cards” B: “drawing a King” since both ace and king cannot be drawn in a single draw, they are thus mutually exclusive A September 24, 2008 B 6 Laws of Probabilities in Compound Event Multiplication Law Independent Event P(A and B and C and…) = P(A∩B∩C∩…)= P(A).P(B).P(C)… exp: Probability of heads on both the fifth and sixth tosses P(A).P(B) = ½ . ½ = ¼ Dependent Event P(A and B) = P(A∩B) = P(A|B).P(B) = P(B|A).P(A) exp: see Ref. Book p. 51 September 24, 2008 7 Addition Law P(A or B) = P(AUB) = P(A)+P(B) – P(A∩B) P(A or B or C) = P(AUBUC) = P(A)+P(B)+P(C)-P(A∩B) -P(A∩C) – P(B∩C) + P(A∩B∩C) Exp: see Ref. book p. 52-53 Bayes Formulation A combination of conditional probability and multiplication law Exp: see Ref. Book p 55 September 24, 2008 8 Enumeration Technique Probability Tree A1 A2 P(A1) P(A2) B1 P(B1|A1) B2 P(B2|A1) B3 P(B3|A1) B1 P(B1|A2) B2 P(B2|A2) B3 P(B3|A2) P(A1∩B1) P(A1∩B2) P(A1∩B3) P(A2∩B1) P(A2∩B2) P(A2∩B3) Exp. See textbook p. 56-57 September 24, 2008 9 Combinatorial Analysis Permutation An arrangement of r out of n objects with attention given to the order of arrangement n! n Pr = P ( n, r ) = Pn , r = P = (n − r )! n r Exp: the number of permutation of the letters a,b,c taken two at a time is 3P2 = 3.2/1 = 6 Combination A selection of r out of n objects with no attention given to the n! n Pr = n Cr = r!(n − r )! r! order of arrangement Exp: 3C2 = 6/2 = 3 September 24, 2008 10