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Download Finding Protons, Neutrons, and Electrons from Nuclear Notation
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Finding Protons, Neutrons, and Electrons from Nuclear Notation Video Example 2 Given the nuclear notation: Mass # = #p + #n Atomic # = # of p’s neutrons 125 electrons = 83 protons – 3 = 80 electrons Given the nuclear notation: Mass # = #p + #n Atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Given the nuclear notation: Mass # = #p + #n Atomic # = # of p’s 208 83 Bi 3 Find the number125 of protons, neutrons neutrons, and electrons in one atom of this isotope. electrons = 83 protons – 3 = 80 electrons Mass # = #p + #n Atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. Mass # = #p + #n Atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. Mass # = #p + #n Atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons Atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons atomic # = # of p’s neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 3 125 electrons = 83 protons – 3 = 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 125 electrons = 83 protons – 3 = 3 A +3 charge means there are 3 LESS electrons than protons. 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 125 electrons = 83 protons – 3 = 3 A +3 charge means there are 3 LESS electrons than protons. 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 125 electrons = 83 protons – 3 = 3 A +3 charge means there are 3 LESS electrons than protons. 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 125 electrons = 83 protons – 3 = 3 A +3 charge means there are 3 LESS electrons than protons. 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 125 electrons = 83 protons – 3 = 3 A +3 charge means there are 3 LESS electrons than protons. 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons neutrons 208 83 Bi 125 electrons = 83 protons – 3 = 3 A +3 charge means there are 3 LESS electrons than protons. 80 electrons Find the number of protons, neutrons, and electrons in one atom of this isotope. protons + neutrons protons 208 83 Bi 3 125 neutrons electrons = 83 protons – 3 = An atom of 208 Bi 3 has: 83 A +3 charge means there are 3 LESS electrons than protons. 80 electrons 83 protons 125 neutrons 80 electrons protons + neutrons protons 208 83 Bi 3 125 neutrons electrons = 83 protons – 3 = An atom of 208 Bi 3 has: 83 A +3 charge means there are 3 LESS electrons than protons. 80 electrons 83 protons 125 neutrons 80 electrons protons + neutrons protons 208 83 Bi 3 125 neutrons electrons = 83 protons – 3 = An atom of 208 Bi 3 has: 83 A +3 charge means there are 3 LESS electrons than protons. 80 electrons 83 protons 125 neutrons 80 electrons protons + neutrons protons 208 83 Bi 3 125 neutrons electrons = 83 protons – 3 = An atom of 208 Bi 3 has: 83 A +3 charge means there are 3 LESS electrons than protons. 80 electrons 83 protons 125 neutrons 80 electrons
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