Download When a magnetic material undergoes cyclic magnetization, two kinds of... on it. Hysteresis and eddy current losses are called as... UNIT- I DC MACHINES

UNIT- I DC MACHINES
1. What is core loss? What is its significance in electric machines?
When a magnetic material undergoes cyclic magnetization, two kinds of power losses occur
on it. Hysteresis and eddy current losses are called as core loss. It is important in determining
heating, temperature rise, rating & efficiency of transformers, machines & other A.C run
magnetic devices.
2. What is eddy current loss?
When a magnetic core carries a time varying flux, voltages are induced in all possible path
enclosing flux. Resulting is the production of circulating flux in core. These circulating
current do no useful work are known as eddy current and have power loss known as eddy
current loss.
3. Write down the emf equation for d.c.generator?
E=(ФNZ/60)(P/A)V.
p--->noof poles Z--->Total noof conductor
Ф--->flux per pole ,N--->speed in rpm.
4. How does d.c. motor differ from d.c. generator in construction?
Generators are normally placed in closed room and accessed by skilled operators only.
Therefore on ventilation point of view they may be constructed with large opening in the
frame. Motors have to be installed right in the place of use which may have dust, dampness,
inflammable gases, chemicals….etc. to protect the motors against these elements, the motor
frames are made either partially closed or totally closed or flame proof.
.
5. What is back emf in d.c. motor?
As the motor armature rotates, the system of conductor come across alternate north and south
pole magnetic fields causing an emf induced in the conductors. The direction of the emf
induced in the conductor is in opposite to current. As this emf always opposes the flow of
current in motor operation it is called as back emf.
6. What is the function of no-voltage release coil in d.c. motor starter?
As long as the supply voltage is on healthy condition the current through the NVR coil
produce enough magnetic force of attraction and retain the starter handle in ON position
against spring force. When the supply voltage fails or becomes lower than a prescribed value
then electromagnet may not have enough force to retain so handle will come back to OFF
position due to spring force automatically.
7. Define critical field resistance of dc shunt generator?
Critical field resistance is defined as the resistance of the field circuit
which will cause the shunt generator just to build up its emf at a specified field.
8.What are the conditions to be fulfilled by for a dc shunt generator to build back emf?
The generator should have residual flux, the field winding should be connected in such a
manner that the flux setup by field in same direction as residual flux, the field resistance
should be less than critical field resistance, load circuit resistance should be above critical
resistance.
9.Define armature reaction in dc machines?
The interaction between the main flux and armature flux cause disturbance called as armature
reaction.
10.What are two unwanted effects of armature reactions?and What is the function of
carbon brush used in dc generators?
Cross magnetizing effect & demagnetizing effect.
The function of the carbon brush is to collect current from commutator and supply to external
load circuit and to load.
UNIT-II TRANSFORMERS
1. Mention the difference between core and shell type transformers?
In core type, the windings surrounded the core considerably and in shell
type thecore surround the windings i.e winding is placed inside the core.
2.What is the purpose of laminating the core in a transformer? & Give the emf equation
of a transformer and define each term?
To reduce the eddy current loss in the core of the transformer.
Emf induced in primary coil E1= 4.44fФmN1 volt emf induced in secondary
coil E2 =4.44 fФmN2.
f--->freq of AC input
Фm---->maximum value of flux in the core
N1,N2--->Number of primary & secondary turns.
When a transformer is loaded with a constant primary voltage, the secondary voltage
decreases for lagging PF load, and increases for leading PF load because of its internal
resistance and leakage reactance. The change in secondary terminal voltage from no load to
full load expressed as a percentage of no load or full load voltage is termed as
regulation.
%regulation down=(V2noload-V2F.L)*100/V2noload
%regulationup=(V2noload-V2F.L)*100/V2F.L
4. Full load copper loss in a transformer is 1600W. what will be the loss at half load?
If x is the ratio of actual load to full load then copper loss = x2(F.L copper loss) here Wc =
(0.5)2 – 1600=400W.
5. Define all day efficiency of a transformer?
It is computed on the basis of energy consumed during a certain period, usually a day of 24
hrs. all day efficiency=output in kWh/input in kWh tor 24 hrs.
6. Why transformers are rated in kVA?
Copper loss of a transformer depends on current & iron loss on voltage. Hence total losses
depends on Volt-Ampere and not on PF. That is why the rating of transformers are in kVA
and not in kW.
7. How transformers are classified according to their construction?
1. core type
2.shell type. In core type, the winding (primary and secondary) surround the core and
in shell type, the core surround the winding.
8.Why are breathers used in transformers?
Breathers are used to entrap the atmospheric moisture and thereby not allowing it to pass on
to the transformer oil. Also to permit the oil inside the tank to expand and contract as its
temperature increases and decreases.
9.What is the function of transformer oil in a transformer? And Can the voltage
regulation go –ive? If so under what condition?
It provides good insulation & Cooling.
Yes, if the load has leading PF.
10.Distinguish power transformers & distribution transformers?
Power transformers have very high rating in the order of MVA. They are used in generating
and receiving stations. Sophisticated controls are required. Voltage ranges will be very high.
Distribution transformers are used in receiving side. Voltage levels will be medium. Power
ranging will be small in order of kVA. Complicated controls are not needed.
UNIT-III SYNCHRONOUS MACHINES
1. What are the principal advantages of rotating field type construction?
Relatively small amount of power required for field system can easily supplied to rotating
system using slip rings and brushes, more space is available in the stator part of the
machine to provide more insulation, it is easy to provide cooling system, stationary system of
conductors can easily be braced to prevent deformation.
2. What are the advantages of salient type pole construction used in sy.machines?
They allow better ventilation, the pole faces are so shaped radial air gap length increases
from pole center to pole tips so flux distortion in air gap is sinusoidal so emf is also
sinusoidal.
3. Define the term voltage regulation of alternator.
The voltage regulation of an alternator is defined as the change in terminal voltage from no
load to load condition expressed as a fraction or percentage of terminal voltage at load
condition,the speed and excitation conditions remaining same.
4.What is hunting? & List the different torque in synchronous motor.
When a synchronous motor is used for driving a varying load,then a condition known as
hunting is produced. Hunting may also be caused if supply frequency is pulsating.
Starting torque, Running torque, Pull-in torque and Pull-out torque.
5.Lit the advantages of synchronous motor.
i) By varying the field excitation,the magnitude of current drawn by the motor can be
changed by any amount. This helps in achieving stepless control of power factor.
ii) The motor windings have high thermal stability to short circuit currents.
iii)The faults can be removed easily.
6.What are the uses of damper windings in a synchronous motor?
A synchronous motor cannot start by itself . In order to make the motor self-starting,a squirrel
cage winding(also called damper winding) is provided on the rotor.The damper winding
consists of copper bars embedded in the pole faces of the salient poles of the rotor. It start the
motor like a induction concept.
7. Explain pull in torque of synchronous motor.
A synchronous motor is started as induction motor till it runs 2 to 5% below the synchronous
speed. Afterwards ,excitation is switched on and the rotor pulls into step with the
synchronously rotating stator field. The amount of torque at which the motor will pull into
step is called Pull in torque.
8. Why are alternators rated in KVA and not in KW?
As load increases I2R loss also increases, as the current is directly related to apparent power
delivered by generator, the alternator has only their apparent power in VA/KVA/MVA as
their power rating.
9. Why the sy.impedance method of estimating voltage regulation is is considered as
pessimistic method?
Compared to other method, the value of voltage regulation obtained by this method is always
higher than the actual value so it is called as pessimistic method.
10. Why MMF method of estimating voltage regulation is considered as optiimistic
method?
Compared to EMF method, MMF method involves more noof complex calculation steps.
Further the OCC is referred twice and SCC is referred once while predetermining the voltage
regulation for each load condition. Reference of OCC takes core saturation effect. As this
method require more effort, final result is very close to actual value, hence this method is
called as optiimistic method.
UNIT-IV INDUCTION MACHINES
1. What are the 2 types of 3phase induction motor?
Squirrel cage and slip ring induction motor.
2 Write two extra features of slip ring induction motor?
Rotor has 3phase winding. extra resistance can be added in rotor circuit for improving PF
with the help of three slip rings.
3. Why an induction motor is called as rotating transformer?
The rotor receives same electrical power in exactly the same way as the secondary of a two
winding transformer receiving its power from primary. That is why induction motor is called
as rotating transformer.
4. Why an induction motor never runs at its synchronous speed?
If it runs at sy.speed then there would be no relative speed between the two, hence no rotor
emf, so no rotor current, then no rotor torque to maintain rotation.
5. What are slip rings?
The slip rings are made of copper alloys and are fixed aroud the shaft insulating it. Through
these slip rings and brushes rotor winding can be connected to external circuit.
6. What are the advantage of cage motor?
Since the rotor have low resistance, the copper loss is low and efficiency is very high. On
account of simple construction of rotor it is mechanically robust, initial cost is less,
maintenance cost is less, simple starting arrangement.
7. Give the condition for maximum torque for 3phase induction motor, when it is
running?
The rotor resistance and reactance should be same for max.torque i.e. R2=Sx2.
8. List out the method for speed control of 3phase cage type induction motor?
By changing supply frequency
By changing noof poles
By operating the two
motors in cascade.
UNIT V SPECIAL MACHINES
1. Name the two winding of single phase induction motor?
Running and starting winding.
2.What are methods available for making single phase induction motor a self starting?
By slitting the single phase, by providing shading coil in the poles.
3.What is the function of capacitor in single phase induction motor?
To make phase difference between starting and running winding, to improve PF and to get
more torque.
4. State any 4 use of single phase induction motor?
Fans, wet grinders, vacuum cleaner, small pumps, compressors, drills. Explain why single
phase induction motor is not a self starting one? When motor fed supply from single phase,
its stator winding produces an alternating flux, which doesn’t develops any torque.
5. What kind of motors used in ceiling fan and wet grinders?
Ceiling fan- Capacitor start and capacitor run single phase induction motor,
wetgrinders-Capacitor start capacitor run single phase induction motor.
6.What is the application of shaded pole induction motor?
Because of its small starting torque, it is generally used for small toys, instruments,hair
driers, ventilators..etc.
7. In which direction a shaded pole motor runs?
The rotor starts rotation in the direction from unshaded part to the shaded part.
8.Why single phase induction motor have low PF?
The current through the running winding lags behind the supply
voltage by large angle so only single phase induction motor have low PF.
9. Differentiate between “capacitor start” & “Capacitor start capacitor run” single
phase induction motor?
Capacitor start – capacitor is connected series with starting winding, but it will be
disconnected from supply when motor pick up its speed. Capacitor start capacitor run-starting
winding and capacitor will not be disconnected from supply even though motor pickup its
speed.
UNIT-1 DC MACHINES
1.Explan with the help of neat diagram,construction and Principle of operation of DC
Generator.
2.Derive the emf equation of DC Generator.
3.Discuss in detail about armature reaction and commutation.
4.What are the classifications of DC Generators?Explain the characteristics of self excited
generators.
5.Explan with the help of neat diagram, construction and Principle of operation of DC
Motor.
6.Derive an expression for armature torque of a DC motor.
7. Sketch and explain the speed-current, speed-torque and torque-current characteristics of a
shunt motor, series motor and compound motor
8.Describe the speed control of DCshunt motor using Ward-Leonard system.List merits and
Demerits.
9.Explain the principle and operation of Starters in DC motors.
UNIT-II TRANSFORMERS
1.Explain the construction and Principle of operation of Transformer.
2.Derive an expression for E.M.F equation of a single phase Transformer.
3.Derive the equivalent circuit parameters and thereby find the regulation and efficiency of
transformer by performing OC and SC tests.
4.Draw and explain the phasor diagram of transformer under resistive load, inductive load
and capacitive load.
5.What are the tests conducted to know the performance of a transformer?Explain with
connection diagrams.
6.Derive the condition for obtaining maximum efficiency of a single phase transformer.
UNIT-III SYNCHRONOUS MACHINES
1.Explain the construction and principle of operation of Synchronous machine.
2.Derive the emf equation of synchronous machine.
3.Draw and explain the vector diagram , when the alternator is loaded with resistive,inductive
and capacitive load.
4. Explain the various methods of starting of synchronous motors.
5. Explain the various torque of synchronous motor.
6.Discuss in detail the procedure of constructing V and inverted V curves .
7.Explain the methods of speed control of synchronous motor.
UNIT –IV INDUCTION MACHINES
1.
2.
3.
4.
5.
Explain the construction and principle of operation of Induction machine.
Derive the torque equation and condition for maximum torque of induction motor.
Derive the equivalent circuit of induction motor.
Explain the various starting methods of induction motor.
Explain the speed control of induction motor.
UNIT –V SPECIAL MACHINES
1.Describe in detail double field revolving theory.
2.Explain the principle and operation of Repulsion type and Universal motor.
3.Draw the characteristics, principle and application of a capacitor start, capacitor run single
phase induction motor.
4. Explain the principle and working of PMSM and SRM
5. Explain the principle and working of BLDC and Hysteresis motor.
UNIT_I
Explain with the help of neat diagram, construction and Principle of operation of DC
Generator.
Generator Principle
An electrical generator is a machine which converts mechanical energy (or power) into
electrical energy.
The energy conversion is based on the principle of the production of dynamically (or
motionally) induced e.m.f.
whenever a conductor cuts magnetic flux, dynamically induced e.m.f. is produced in it
according to Faraday’s
Laws of Electromagnetic Induction. This e.m.f. causes a current to flow if the conductor
circuit is closed.
Hence, two basic essential parts of an electrical generator are (i) a magnetic field and (ii) a
conductor or conductors which can so move as to cut the flux.
Construction
A single-turn rectangular copper coil ABCD rotating about its own axis in a magnetic field
provided by either permanent magnet is or electromagnets. The two ends of the coil are
joined to two slip-rings ‘a’ and ‘b’ which are insulated from each other and from the central
shaft.
Two collecting brushes (of carbon or copper) press against the slip-rings. Their function is to
collect the current induced in the coil and to convey it to the external load resistance R.The
rotating coil may be called ‘armature’ and the magnets as ‘field magnets’.
Working
Imagine the coil to be rotating in clock-wise direction . As the coil assumes successive
positions in the field, the flux linked with it changes. Hence, an e.m.f. is induced in it which
is proportional to the rate of change of flux linkages (e = Nddt). When the plane of the coil
is at right
angles to lines of flux i.e. when it is in position, 1, then flux linked with the coil is maximum
but rate
of change of flux linkages is minimum.
It is so because in this position, the coil sides AB and CD do not cut or shear the flux, rather
they
slide along them i.e. they move parallel to them. Hence, there is no induced e.m.f. in the coil.
Let us
take this no-e.m.f. or vertical position of the coil as the starting position. The angle of rotation
or
time will be measured from this position.
As the coil continues rotating further, the rate of change of flux linkages (and hence induced
e.m.f. in it) increases, till position 3 is reached where 90º. Here, the coil plane is horizontal
i.e.
parallel to the lines of flux. As seen, the flux linked with the coil is minimum but rate of
change of
flux linkages is maximum. Hence, maximum e.m.f. is induced in the coil when in this
position
In the next quarter revolution i.e. from 90º to 180º, the flux linked with the coil gradually
increases but the rate of change of flux linkages decreases. Hence, the induced e.m.f.
decreases
gradually till in position 5 of the coil, it is reduced to zero value.
So, we find that in the first half revolution of the coil, no (or minimum) e.m.f. is induced in it
when in position 1, maximum when in position 3 and no e.m.f. when in position 5. The
direction of
this induced e.m.f. can be found by applying Fleming’s Right-hand rule which gives its
direction
from A to B and C to D. Hence, the direction of current flow is ABMLCD. The current
through the load resistance R flows from M to L during the first half revolution of the coil.
In the next half revolution i.e. from 180º to 360º, the variations in the magnitude of e.m.f. are
similar to those in the first half revolution. Its value is maximum when coil is in position 7
and
minimum when in position 1. But it will be found that the direction of the induced current is
from D
to C and B to A as shown inFig. Hence, the path of current flow is along DCLMBA which
is just the reverse of the previous direction of flow.
Therefore, we find that the current which we obtain from such a simple generator reverses its
direction after every half revolution. Such a current undergoing periodic reversals is known
as alternating
current. It is, obviously, different from a direct current which continuously flows in one and
the same direction. It should be noted that alternating current not only reverses its direction, it
does
not even keep its magnitude constant while flowing in any one direction. The two half-cycles
may be
called positive and negative half-cycles respectively
For making the flow of current unidirectional in the external circuit, the slip-rings are
replaced
by split-rings . The split-rings are made out of a conducting cylinder which is cut into two
halves or segments insulated from each other by a thin sheet of mica or some other insulating
material
As before, the coil ends are joined to these segments on which rest the carbon or copper
brushes.
In the first half revolution current flows along (ABMNLCD) i.e. the
brush No. 1 in contact with segment „a‟ acts as the positive end of the supply and „b‟ as the
negative
end. In the next half revolution the direction of the induced current in the coil has
reversed. But at the same time, the positions of segments „a‟ and „b‟ have also reversed with
the
It should be noted that the position of brushes is so arranged that the change over of segments
„a‟
and „b‟ from one brush to the other takes place when the plane of the rotating coil is at right
angles to
the plane of the lines of flux. It is so because in that position, the induced e.m.f. in the coil is
zero.
Another important point worth remembering is that even now the current induced in the coil
sides is alternating as before. It is only due to the rectifying action of the split-rings (also
called
commutator) that it becomes unidirectional in the external circuit. Hence, it should be clearly
understood
that even in the armature of a d.c. generator, the induced voltage is alternating.
2.Derive the emf equation of DC Generator.
Let Φ = flux/pole in weber
Z = total number of armature conductors
= No. of slots . No. of conductors/slot
P = No. of generator poles
A = No. of parallel paths in armature
N = armature rotation in revolutions per minute (r.p.m.)
E = e.m.f. induced in any parallel path in armature
Generated e.m.f. Eg = e.m.f. generated in any one of the parallel paths i.e. E.
Average e.m.f. generated/conductor = dΦ /dt
Now, flux cut/conductor in one revolution dΦ = P ΦWb
No. of revolutions/second = N/60
Time for one revolution, dt = 60/N second
Hence, according to Faraday’s Laws of Electromagnetic Induction,
E.M.F. generated/conductor = dΦ /dt=ΦPN/60 volt
For a simplex wave-wound generator
No. of parallel paths = 2
No. of conductors (in series) in one path = Z/2
E.M.F. generated/path = ΦPN/60(z/2)
For a simplex lap-wound generator
No. of parallel paths = P
No. of conductors (in series) in one path = Z/P
E.M.F. generated/path = ΦPN/60(z/A)
3.Discuss in detail about armature reaction
By armature reaction is meant the effect of magnetic field set up by armature current on the
distribution of flux under main poles of a generator. The armature magnetic field has two
effects :
(i) It demagnetises or weakens the main flux and
(ii) It cross-magnetises or distorts it.
age and the second to the sparking at the brushes.
These effects are well illustrated in Fig. which shows the flux distribution of a bipolar
generator when there is no current in the armature conductors. For convenience, only two
poles have been considered, though the followingremarks apply to multipolar fields as
well. Moreover, the brushes are shown touchingthe armature conductors directly, although
in practice, they touch commutator segments,
It is seen that
(a) the flux is distributed symmetrically
with respect to the polar axis, which is
the line joining the centres of NS poles.
(b) The magnetic neutral axis or plane (M.N.A.) coincides with the geometrical neutral axis or
plane (G.N.A.)
Magnetic neutral axis may be defined as the axis along which no e.m.f. is produced in the
armature
conductors because they then move parallel to the lines of flux.
Or M.N.A. is the axis which is perpendicular to the flux passing through the armature.
Bbrushes are always placed along M.N.A. Hence, M.N.A. is also called
‘axis of commutation’ because reversal of current in armature conductors takes place across
this axis.
vector OFm which represents,both in magnitude and direction, them.m.f. producing the main
flux and alsoM.N.A. which is perpendicular to OFm. the field (orflux) set up by the armature
conductors alonewhen carrying current, the field coils beingunexcited. The direction of the
armature current is the same as it would actually bewhen the generator is loaded. It may even
befound by applying Fleming’s Right-hand Rule.The current direction is downwards in
conductors under N-pole and upwards in thoseunder S-pole. The downward flow is
represented by crosses and upward flow bydots.
The m.m.fs. of the armature conductors combine to send flux downwards
through the armature. The direction of the lines of force can be found by applying cork-screw
rule.
The armature m.m.f. (depending on the strength of the armature current) is shown separately
both in
magnitude and direction by the vector OFA which is parallel to the brush axis.
So far, we considered the main m.m.f. and armature m.m.f. separately as if they existed
independently,
which is not the case in practice. Under actual load conditions, the two exist simultaneously
in
It is seen that the flux through the armature is no longer uniform and symmetrical about the
pole
axis, rather it has been distorted. The flux is seen to be crowded at the trailing pole tips but
weakened
or thinned out at the leading pole tips (the pole tip which is first met during rotation by
armature
conductors is known as the leading pole tip and the other as trailing pole tip). The
strengthening and
weakening of flux is separately shown for a four-pole machine in Fig. . As seen, air-gap flux
density under one pole half is greater than that under the other pole half.
the resultant m.m.f. OF which is found by vectorially combining OFm and
OFA.
The new position of M.N.A., which is always perpendicular to the resultant m.m.f. vector OF,
isalso shown in the figure. With the shift of M.N.A., say through an angle θ, brushes are also
shifted soas to lie along the new position of M.N.A. Due to this brush shift (or forward lead),
the armatureconductors and hence armature current is redistributed. Some armature
conductors which were earlier
under the influence of N-pole come under the influenceof S-pole and vice-versa. This
regrouping is shown inwhich also shows the flux due
toarmatureconductors.Incidentally,brush position shifts in thesame direction as the direction
of armature rotation.All conductors to the left of new position of M.N.A.but between the two
brushes, carry current downwardsand those to the right carry current upwards. The armature
m.m.f. is found to lie in the direction of the newposition of M.N.A. (or brush axis). The
armature m.m.f.is now represented by the vector OFA which is not vertical
but is inclined by an angle θ to the left. It can now be resolved into two rectangular
components,
OFd parallel to polar axis and OFC perpendicular
to this axis. We find that
(i) component OFC is at right angles to the vector
OFm representing the main m.m.f. It produces distortion in the main field and is hence
called the cross-magnetising or distorting component of the armature reaction.
(ii) The component OFd is in direct opposition of OFm which represents the main m.m.f. It
exerts a demagnetising influence on the main pole flux. Hence, it is called the demagnetising
or
weakening component of the armature reaction.
It should be noted that both distorting and demagnetising effects will increase with increase
in
the armature current.
Demagnetising and Cross-magnetising Conductors
The exact conductors which produce these distorting and demagnetising effects are shown in
Fig. 27.6 where the brush axis has been given a forward lead of θ so as to lie along the new
position
of M.N.A. All conductors lying within angles AOC = BOD = 2θ at the top and bottom of the
armature,
are carrying current in such a direction as to send the flux through the armature from right to
left.
This fact may be checked by applying crockscrew rule. It is these conductors which act in
direct
opposition to the main field and are hence called the demagnetising armature conductors.
Fig.
4.Explan with the help of neat diagram, construction and Principle of operation of DC
Motor.
Construction of DC Motor
A DC Motor like we all know is a device that deals in the conversion of Electrical
energy to mechanical energy and this is essentially brought about by two major parts required
for the construction of dc motor, namely.
1)
Stator – The static part that houses the field windings and receives the supply
and
2)
Rotor – The rotating part that brings about the mechanical rotations.
Other than that there are several subsidiary parts namely the
3)
Yoke or casting of dc motor.
4)
Magnetic poles of dc motor.
5)
Field winding of dc motor.
6)
Armature winding of dc motor.
7)
Commutator of dc motor.
8)
Brushes of dc motor.
All these parts put together configures the total construction of a dc motor\, that has been
pictorially represented in the diagram below
Now let’s do a detailed discussion about all the essencial parts of dc motor.
Construction of yoke of dc motor
The magnetic frame or the yoke of dc machine made up of cast iron or steel and
forms an integral part of the stator or the static part of the motor. Its main function is to form
a protective covering over the inner sophisticated parts of the motor and provide support to
the armature. It also supports the field system by housing the magnetic poles and field
windings of the dc motor.
.
Construction of Magnetic poles of dc motor
The magnetic poles are structures fitted onto the inner wall of the yoke with
screws. The construction of magnetic poles basically comprises of two parts namely, the pole
core and the pole shoe stacked together under hydraulic pressure and then attached to the
yoke. These two structures are assigned for different purposes, the pole core is of small cross
sectional area and its function is to just hold the pole shoe over the yoke, whereas the pole
shoe having a relatively larger cross-sectional area spreads the flux produced over the air gap
between the stator and rotor to reduce the loss due to reluctance. The pole shoe also carries
slots for the field windings that produce the field flux.
Construction of field winding of dc motor
The field windings of the dc motor are made with field coils (copper wire) wound
over the slots of the pole shoes in such a manner that when field current flows through it, then
adjacent poles have opposite polarity are produced.
The field windings basically form an electromagnet, that produces field flux within which the
rotor armature of the dc motor rotates, and results in the effective flux cutting.
Construction of Armature winding of dc motor
The armature of the dc motor is attached to the rotor, or the rotating part of the
machine, and as a result is subjected to altering magnetic field in the path of its rotation
which directly results in magnetic losses. For this reason the rotor is made of armature core,
that’s made with several low-hysteresis silicon steel laminations, to reduce the magnetic
losses like hysteresis and eddy current loss respectively. These laminated steel sheets are
stacked together to form the cylindrical structure of the armature core.
The armature core are provided with slots made of the same material as the core to
which the armature windings made with several turns of copper wire distributed uniformly
over the entire periphery of the core. The slot openings a shut with fibrous wedges to prevent
the conductor from plying out due to the high centrifugal force produced during the rotation
of the armature, in presence of supply current and field.
Construction of Brushes of DC Motor
The brushes of dc motor are made with carbon or graphite structures, making
sliding contact over the rotating commutator. The brushes are used to relay the current from
external circuit to the rotating commutator form where it flows into the armature windings.
∴ the commutator and brush unit of the dc motor is concernied with transmitting the
power from the static electrical circult to the mechanically rotating region or the rotor.
Operation of DC motor
Motor Principle
An Electric motor is a machine which converts electric energy into mechanical energy. Its
action
is based on the principle that when a current-carrying conductor is placed in a magnetic field,
it
experiences a mechanical force whose direction is given by Fleming’s Left-hand Rule and
whose
magnitude is given by F = BIl Newton.
Constructionally, there is no basic differencebetween a d.c. generator and a d.c. motor. In
fact, the same d.c. machine can be used interchangeably as a generator or as a motor. D.C.
motors are also like generators, shunt-wound or series-wound or compound-wound. In Fig.
29.1 a part of multipolar d.c. motor is shown. When its field magnets are excited and its
armature conductors are supplied with current from the supply mains, they experience a
force tending to rotate the armature. Armature conductors under N-pole are assumed to carry
current downwards (crosses) and those under S-poles, to carry current upwards (dots). By
applying Fleming’s Left-hand Rule, the direction of the force on each conductor can be
found. It is shown by small arrows placed above each conductor. It will beseen that each
conductor can be found. It will be seen that each conductor experiences a force F which tends
to rotate the armature in anticlockwise direction. These forces collectively produce a riving
torque which sets the armature rotating. It should be noted that the function of a commutator
in the motor is the same as in a generator
5.Describe the speed control of DCshunt motor using Ward-Leonard system.
Speed Control of Shunt motors
(i) Variation of Flux or Flux Control Method
(ii)
It is seen from above that N ∝ 1/Φ. By decreasing the flux, thespeed can be increased and
vice versa. Hence, the name flux or field control method. The flux of a d.c. motor can be
changed by changing Ish with help of a shunt field rheostat Since Ish is relatively small,
shunt field rheostat has to carry only a small current, which means I2R loss is small, so that
rheostat is small in size. This method is, therefore, very efficient. In non-interpolar
machine, the speed can be increased by this method in the ratio2 : 1. Any further weakening
of flux Φ adversely affects the communication and hence puts a limit to the maximum speed
obtainable with the method. In machines fitted with interpoles, aratio of maximum to
minimum speed of 6 : 1
(ii) Armature or Rheostatic Control Method
This method is used when speeds below the no-load speed are required. As the supply
voltage
is normally constant, the voltage across the armature is varied by inserting a variable rheostat
or
resistance (called controller resistance) in series with the armature circuit as shown in fg As
controller resistance is increased, p.d. across the armature is decreased, thereby decreasing
the
armature speed. For a load constant torque, speed is approximately proportional to the p.d.
across the
armature. From the speed/armature current characteristic, it is seen that greater the
resistance in the armature circuit, greater is the fall in the speed.
(iii) Voltage Control Method
(a) Multiple Voltage Control
In this method, the shunt field of the motor is connected permanently to a fixed exciting
voltage,
but the armature is supplied with different voltages by connecting it across one of the several
different voltages by means of suitable switchgear. The armature speed will be approximately
proportional to these different voltages. The intermediate speeds can be obtained by adjusting
the shunt field regulator.
The method is not much used, however.
(b) Ward-Leonard System
This system is used where an unusually wide (upto 10 : 1) and very sensitive speed control is
required as for colliery winders, electric excavators, elevators and the main drives in steel
mills and blooming and paper mills. The arrangement is illustrated in Fig.
M1 is the main motor whose speed control is required. The field of this motor is permanently
connected across the d.c. supply lines. By applying a variable voltage across its armature, any
desired speed can be obtained. This variable voltage is supplied by a motor-generator set
which consists of either a d.c. or an a.c. motor M2 directly coupled to generator G.
The motor M2 runs at an approximately constant speed. The output voltage of G is directly
fed to
the main motor M1. The voltage of the generator can be varied from zero up to its maximum
value by means of its field regulator. By reversing the direction of the field current of G by
means of the reversing switch RS, generated voltage can be reversed and hence the direction
of rotation of M1. It should be remembered that motor generator set always runs in the same
direction. Despite the fact that capital outlay involved in this system is high because (i) a
large output
machine must be used for the motor generator set and (ii) that two extra machines are
employed, still it is used extensively for elevators, hoist control and for main drive in steel
mills where motor of ratings 750 kW to 3750 kW are required. The reason for this is that the
almost unlimited speed control in either direction of rotation can be achieved entirely by field
control of the generator and the resultant economies in steel production outwiegh the extra
expenditure on the motor generator set. A modification of the Ward-Leonard system is
known as Ward-Leonard-Ilgner system which uses a smaller motor-generator set with the
addition of a flywheel whose function is to reduce fluctuations in the power demand from the
supply circuit. When main motor M1 becomes suddenly overloaded, the driving motor M2 of
the motor generator set slows down, thus allowing the inertia of the flywheel to supply a part
of the overload. However, when the load is suddenly thrown off the main motor M1, then M2
speeds up, thereby again storing energy in the flywheel. hen the Ilgner system is driven by
means of an a.c. motor (whether induction or synchronous)
another refinement in the form of a ‘slip regulator’ can be usefully employed, thus giving an
additional control.
The chief disadvantage of this system is its low overall efficiency especially at light loads.
But as said earlier, it has the outstanding merit of giving wide speed control from maximum
in one direction hrough zero to the maximum in the opposite direction and of giving a smooth
acceleration
6.Explain the operation of commutation
The currents induced in armature conductors of a d.c. generator are alternating. To make their flow
unidirectional in the external circuit, we need a commutator. Moreover, hese currents flow in one
direction when armature conductors are under N-pole and in the opposite direction when they are
under S-pole. As conductors pass out of the influence of a N-pole and enter that of S-pole, the current
in them is reversed. This reversal of current takes place along magnetic neutral axisor brush axis i.e.
when the brush spans and hence shortcircuits that particular coil undergoing reversal of current
through it. This process by which current in the short-circuited oil is reversed while it crosses the
M.N.A. is called ommutation. The brief period during which coil remains short-circuited is known as
commutation period Tc. If the current reversal i.e. the change from + I to zero and then to I is
completed by the end of short circuit or ommutation period, then the commutation is ideal. If current
eversal is not complete by that time, then sparking is produced between the brush and the commutator
which results in progressive damage to both. Let us discuss the process of commutation or current
reversal in more detail with the help of Fig where ring winding has been used for simplicity. The
brush width
is equal to the width of one commutator segment and one mica insulation. In Fig. (a) coil B is about to
be short circuited because brush is about to come in touch with commutator segment ‘a’. It is assumed
that each coil carries 20 A, so that brush current is 40 A. It is so because every coil meeting at the
brush supplies half the
brush current lap wound or wave wound. Prior to the beginning of short circuit, coil B belongs to the
group of coils lying to the left of the brush and carries 20 A from left to right. In Fig.(b) coil B has
entered its period of short-circuit and is approximately at one-third of this period. The current
through coil B has reduced down from 20 A to 10 A because the other 10 A flows via segment ‘a’. As
area of contact of the brush is more with segment ‘b’ than with segment ‘a’, it receives 30 A from the
ormer, the total again being 40 A.
Fig. (c) shows the coil B in the middle of its short-circuit period. The current through it has decreased
to zero. The two currents of value 20 A each, pass to the brush directly from coil A and C as shown.
The brush contact areas with the two segments ‘b’ and ‘a’ are equal.
In Fig (d), coil B has become part of the group of coils lying to the right of the brush. It is seen that
brush contact area with segment ‘b’ is decreasing rapidly whereas that with segment ‘a’ is increasing.
Coil B now carries 10 A in the reverse direction which combines with 20 A supplied by coil A to
make up 30 A that passes from segment ‘a’ to the brush. The other 10 A is supplied by coil C and
passes from segment ‘b’ to the brush, again giving a total of 40 A at the brush. Fig. (e) depicts the
moment when coil B is almost at the end of commutation or shortcircuit period. For ideal
commutation, current through it should have reversed by now but, as shown, it is carrying 15 A only
(instead of 20 A). The difference of current between coils C and B . 5 A in this case, jumps directly
from segment b to the brush through air thus producing spark. If the changes of current through coil B
are plotted on a time base (as in Fig.) it will be represented by a horizontal line AB i.e. a constant
current of 20 A up to the time of beginning of commutation. From the finish of commutation, the
current will be represented by another horizontal line CD. Now, again the current value is FC = 20 A,
although in the reversed direction. The way in which current changes from its positive value of 20 A
(= BE) to zero and then to its negative value of 20 A (= CF) depends on the conditions under which
the coil B undergoes commutation. If the current varies at a uniform rate i.e. if BC is a straight line,
then it is referred to as linear commutation. However, due to the production of self-induced e.m.f. in
the coil (discussed below) the variations follow the dotted curve. It is seen that, in that case, current in
coil B has reached only a value of KF = 15 A in the reversed direction, hence the difference of 5 A
(20 A − 15 A) passes as a spark. So, we conclude that sparking at the brushes, which results in poor
commutation is due to the inability of the current in the short-circuited coil to reverse completely by
the end of short-circuit
1.Explain the construction single phase transformer.
Transformer Construction
The simple elements of a transformer consist of two coils having mutual inductance and a
laminated steel core. The two coils are insulated from each other and the steel core. Other
necessary parts are : some suitable container for assembled core and windings ; a suitable
medium for insulating the core and its windings from
its container ; suitable bushings (either of porcelain, oil-filled or capacitor-type) for insulating
and bringing out the terminals of windings from the tank. In all types of transformers, the
core is constructed of transformer sheet steel laminations assembled to provide a continuous
magnetic path with a minimum of air-gap included. The steel used is of high silicon content,
sometimes heat treated to produce a high permeability and a low hysteresis loss at the
usual operating flux densities. The eddy current loss is minimised by laminating the core, the
laminations being insulated from each other by a light coat of core-plate varnish or by an
oxide layer on the surface. The
thickness of laminations varies from 0.35 mm for a frequency of 50 Hz to 0.5 mm for a
frequency of 25 Hz. The core laminations (in the form of strips) are joined as shown in Fig. .
It is seen that the joints in the alternate layers are staggered in order to avoid the presence of
narrow gaps right through the cross-section of the core. Such staggered joints are said to be
‘imbricated’. Constructionally, the transformers are of two general types, distinguished from
each other merely by the manner in which the primary and secondary coils are placed around
the laminated core. The two types are known as (i) core-type and (ii) shelltype. Another
recent development is spiral-core or wound-core type, the trade name being spirakore
transformer. In the so-called core type transformers, the windings surround a considerable
part of the core whereas in shell-type transformers, the core surrounds a considerable
portion of the windings as shown schematicallyin Fig. (a) and (b) respectively
In the simplified diagram for the core type transformers [Fig. A], the primary and secondary
winding are shown located on the opposite legs (or limbs) of the core, but in actual
construction, these are always interleaved to reduce leakage flux. As shown in Fig., half the
primary and half the secondary winding have been placed side by side or concentrically on
each limb, not primary on one limb (or leg) and the secondary on the other.
In both core and shell-type transformers, the individual laminations are cut in the form of
long strips of L’s, E’s and I’s as shown in Fig. The assembly of the complete core for the two
types of transformers is shown in Fig.The coils used are form-wound and are of the
cylindrical type. The general form of these coils may be circular or oval or rectangular. In
small size core-type transformers, a simple rectangular core is used with cylindrical coils
which are either circular or rectangular in form. But for large-size core-type transformers,
round or circular cylindrical coils are used which are so wound as to fit over a cruciform core
section as shown in Fig. (a). The circular cylindrical coils are used in most of the core-type
transformers because of their mechanical strength. Such cylindrical coils are wound in helical
layers with the
different layers insulated from each other by paper, cloth, micarta board or cooling ducts. Fig.
(c) shows the general arrangement of these coils with respect to the core. Insulating cylinders
of fuller board are used to separate the cylindrical windings from the core and from each
other. Since the lowvoltage (LV) winding is iseasiest to insulate, it is placed nearest to the
core (Fig.)
Shell-type Transformers
form of pancakes. The different layers of such multi-layer discs are insulated from each other
by paper. The complete winding consists of stacked discs with insulation space between the
coils–the spaces forming horizontal cooling and insulating ducts. A shell-type transformer
may have a simple rectangular form as shown in Fig. or it may have distributed form as
shown in Fig. A very commonly-used shell-type transformer is the one known as Berry
Transformer–so called after the name of its designer and is cylindrical in form. The
transformer core consists of laminations arranged in groups which radiate out from the centre
as shown in section in Fig. It may be pointed out that cores and coils of transformers must be
provided with rigid mechanical bracing in order to prevent movement and possible insulation
damage. Good bracing reduces vibration and the objectionable noise–a humming sound–
during operation. The spiral-core transformer employs the newest development in core
construction. The core is assembled of a continuous strip or ribbon of transformer steel
wound in the form of a circular or elliptical cylinder. Such construction allows the core flux
to follow the grain of the iron. Cold-rolled steel of high silicon content enables the designer
to use considerably higher operating flux densities with lower loss per kg. The use of higher
flux density reduces the weight per kVA. Hence, the advantages of such construction are (i) a
relatively more rigid core (ii) lesser weight and size per kVA rating (iii) lower iron losses at
higher operating flux densities and (iv) lower cost of manufacture.
2.Explain the principle of operation of transformer.
A transformer is a static (or stationary) piece of apparatus by means of which electric power
in one circuit is transformed into electric power of the same frequency in another circuit.
The physical basis of a transformer is mutual induction between two circuits linked by a
common magnetic flux. In its simplest form, it consists of two inductive coils which are
electrically separated but magnetically linked through a path of low reluctance as shown in
Fig. The two coils possess high mutual inductance. If one coil is connected to a source of
alternating voltage, an alternating flux is set up in the laminated core, most of which is linked
with the other coil in which it produces mutually-induced e.m.f. (according to Faraday’s
Laws of Electromagnetic Induction e = MdI/dt). If the second coil circuit is closed, a current
flows in it and so electric energy is transferred (entirely magnetically) from the first coil to
the second coil. The first coil, in which electric energy is fed from the a.c. supply mains, is
called primary winding and the other from which energy is drawn out, is called secondary
winding. In brief, a transformer is a device that
1. transfers electric power from one circuit to another
2. it does so without a change of frequency 3. it accomplishes this by electromagnetic
induction and
4. where the two electric circuits are in mutual inductive influence of each other
3.Derive the emf equation of transformer
4.Derive the equivalent circuit of transformer.
The transformer shown diagrammatically in Fig.(a) can be resolved into an equivalent
circuit in which the resistance and leakage reactance of the transformer are imagined to be
external to the winding whose only function then is to transform the voltage (Fig.(b)). The
no-load current I0 is simulated by pure inductance X0 taking the magnetising component Iμ
and a non-inductive resistance R0 taking the working component Iw connected in parallel
across the primary circuit. The value of E1 is obtained by subtracting vectorially I1 Z1
fromV1. The value of X0 = E1/I0 and of R0 = E1/Iw. It is clear that E1 and E2 are related to
each other by expression E2/E1 = N2/N1 = K.
To make transformer calculations simpler, it is preferable to transfer voltage, current and
impedance either to the primary or to the secondary. In that case, we would have to work in
one winding only which is
more convenient.
The primary equivalent of the secondary induced voltage is E2′ = E2/K = E1.
Similarly, primary equivalent of secondary terminal or output voltage is V2′ = V2/K.
Primary equivalent of the secondary current is I2′ = KI2.
For transferring secondary impedance to primary K2 is used.
R2′ = R2/K2, X2′ = X2/K2, Z2′ = Z2/K2
The same relationship is used for shifting an external load impedance to the primary.
The secondary circuit is shown in Fig. (a) and its equivalent primary values are shown in
Fig.b
The total equivalent circuit of the transformer is obtained by adding in the primary
impedance as shown in Fig.. This s known as the exact equivalent circuit but it presents a
somewhat harder circuit
problem to solve. A simplification can be made by transferring the exciting circuit across the
terminals as in Fig. or in Fig. (a). It should be noted that in this case X0 = V1/Iμ.
5. What are the tests conducted to know the performance of a transformer?Explain
with connection diagrams.
Open-circuit or No-load Test
The purpose of this test is to determine no-load loss or core loss and no-load I0 which is
helpful in finding X0 and R0. One winding of the transformer whichever is convenient but
usually high voltage winding – is left open and the other is connected to its supply of normal
voltage and frequency. A wattmeter W, voltmeter V and an ammeter A are connected in the
lowvoltage winding i.e. primary winding in the present case. With normal voltage applied to
the primary, normal flux will be set up in the core, hence normal iron losses will occur which
are recorded by the wattmeter. As the primary no-load current I0 (as measured by ammeter)
is small (usually 2 to 10% of rated load current), Cu loss is negligibly small in primary and
nil in secondary (it being open). Hence, the wattmeter reading represents practically the core
loss under no-load condition (and which is the same for all loads . It should be noted that
since I0 is itself very small, the pressure coils of the wattmeter and the voltmeter are
connected such that the current in them does not pass through the current coil of the
wattmeter. Sometimes, a high-resistance voltmeter is connected across the secondary. The
reading of the voltmeter gives the induced e.m.f. in the secondary winding. This helps to find
transformation ratio K. The no-load vector diagram is shown in Fig. If W is the wattmeter
reading (in Fig. ), Then
Short circuit test
This is an economical method for determining the following :
(i) Equivalent impedance (Z01 or Z02), leakage reactance (X 01 or X 02) and total resistance
(R01 or R02) of the transformer as referred to the winding in which the measuring
instruments are placed.
(ii) Cu loss at full load (and at any desired load). This loss is used in calculating the
efficiency of the transformer. (iii) Knowing Z01 or Z02, the total voltage drop in the
transformer as referred
to primary or secondary can be calculated and hence regulation of the transformer
determined.
In this test, one winding, usually the low-voltage winding, is solidly short-circuited by a thick
conductor (or through an ammeter which may serve the additional purpose of indicating rated
load current) as shown
A low voltage (usually 5 to 10% of normal primary voltage) at correct frequency (though for
Cu losses it is not essential) is applied to the primary and is cautiously increased till full-load
currents are flowing both in primary and secondary (as indicated by the respective
ammeters). Since, in this test, the applied voltage is a small percentage of the normal voltage,
the mutual flux Φ produced is also a small percentage of its normal value . Hence, core losses
are very small with the result that the tmeter reading represent the full-load Cu loss or I2R
loss for the whole transformer i.e. both primary Cu loss and secondary Cu loss. The
equivalent circuit of the transformer under short-circuit condition is shown in Fig. If Vsc is
the voltage required to circulate rated load currents, then Z01 = Vsc/I1
In Fig. the equivalent circuit vector diagram for the short-circuit test is shown. This diagram
is the same as shown in except that all the quantities are referred to the primary side. It is
obvious that the entire voltage VSC is consumed in the impedance drop of the two
windings.If R1 can be measured, then knowing R01, we can find R2′ = R01 − R1. The
impedance triangle can then be divided into the appropriate equivalent triangles for primary
and secondary as shown in Fig.
6.Derive the condition for obtaining maximum efficiency of a single phase transformer
Efficiency of a Transformer
As is the case with other types of electrical machines, the efficiency of a transformer at a
particular load and power factor is defined as the output divided by the input–the two being
measured in the same units (either watts or kilowatts).
But a transformer being a highly efficient piece of equipment, has very small loss, hence it is
impractical to try to measure transformer, efficiency by measuring input and output. These
quantities are nearly of the same size. A better method is to determine the losses and then to
calculate the efficiency from
It may be noted here that efficiency is based on power output in watts and not in voltamperes, although losses are proportional to VA. Hence, at any volt-ampere load, the
efficiency depends on power factor, being maximum at a power factor of unity.
Efficiency can be computed by determining core loss from no-load or open-circuit test and
Cu loss
from the short-circuit test.
UNIT-III
1.Explain the construction and principle of operation of Alternators
A.C. generators or alternators (as they are usually called) operate on the same fundamental
principles of electromagnetic induction as d.c. generators. They also consist of an armature
winding and a magnetic field. But there is one important difference between the two.
Whereas in d.c. generators, the armature rotates and
the field system is stationary, the arrangement in alternators is just the reverse of it. In their
case, standard construction consists of armature winding mounted on a stationary element
called stator and field windings on a rotating element called rotor. The details of construction
are shown in Fig. The stator consists of a cast-iron frame, which supports the armature core,
having slots on its inner periphery for housing the armature conductors. The rotor is like a
flywheel having alternate N and S poles fixed to its outer rim. The magnetic poles are excited
(or magnetised) from direct current supplied by a d.c. source at 125 to 600 volts. In most
cases, necessary exciting (or magnetising) current is obtained from a small d.c. shunt
generator which is belted or mounted on the shaft of the alternator itself. Because the field
magnets are rotating, this current is supplied through two slip rings. As the exciting voltage is
relatively small, the slip-rings and brush gear are of light construction. Recently, brushless
excitation systems have been developed in which a 3-phase a.c. exciter and a group of
rectifiers supply d.c. to the alternator. Hence, brushes, slip-rings and commutator are
eliminated. When the rotor rotates, the stator conductors (being stationary) are cut by the
magnetic flux, hence they have induced e.m.f. produced in them. Because the magnetic poles
are alternately N and S, they induce an e.m.f. and hence current in armature conductors,
which first flows in one direction and then in the other.
Hence, an alternating e.m.f. is produced in the stator conductors
i)whose frequency depends on the number of N and S poles moving past a conductor
in one second and
(ii) whose direction is given by Fleming's Right-hand rule.
CONSTRUCTION
Stationary Armature
Advantages of having stationary armature (and a rotating field system) are : 1. The output
current can be led directly from fixed terminals on the stator (or armature windings) to the
load circuit, without having to pass it through brush-contacts.
2. It is easier to insulate stationary armature winding for high a.c. voltages, which may have
as high a value as 30 kV or more.
3. The sliding contacts i.e. slip-rings are transferred to the low-voltage, low-power d.c. field
circuit which can, therefore, be easily insulated.
4. The armature windings can be more easily braced to prevent any deformation, which
could be produced by the mechanical stresses set up as a result of short-circuit current and the
high centrifugal forces brought into play.
1. Stator Frame
In d.c. machines, the outer frame (or yoke) serves to carry the magnetic flux but in
alternators, it is not meant
for that purpose. Here, it is used for holding the armature stampings and windings in
position. Lowspeed
large-diameter alternators have frames which because of ease of manufacture, are cast in
sections. Ventilation is maintained with the help of holes cast in the frame itself. The
provision of radial ventilating spaces
in the stampings assists in cooling the machine. But, these days, instead of using castings,
frames are generally fabricated from mild steel plates welded together in such a way as to
form a frame having a box type section.
In Fig. is shown the section through the top of a typical stator.
2. Stator Core
The armature core is supported by the stator frame and is built up of laminations of special
magnetic iron or steel alloy. The core is laminated to minimise loss due to eddy currents. The
laminations are stamped out in complete rings (for smaller machine) or in segments (for
larger machines). The laminations are insulated from each other and have spaces between
them for allowing the cooling air to pass through. The slots for housing the armature
conductors lie along the inner periphery of the core and are stamped out at the same time
when laminations are formed. Different shapes of the armature slots are shown in Fig. The
wide-open type slot (also used in d.c. machines) has the advantage of permitting easy
installation of form-wound coils and their easy removal in case of repair. But it has the
disadvantage of distributing the air-gap flux into bunches or tufts, that produce ripples in the
wave of the generated e.m.f. The semi-closed type slots are better in this respect, but do not
allow the use of form-wou nd coils. The wholly-closed type slots or tunnels do not disturb the
air-gap flux but
(i) they tend to increase the inductance of the windings
(ii) the armature conductors have to be threaded through, thereby increasing initial labour and
cost of winding and
(iii) they present a complicated problem of endconnections.
Hence, they are rarely used.
Rotor
Two types of rotors are used in
alternators (i) salient-pole type and
(ii) smooth-cylindrical type.
(i) Salient (or projecting) Pole Type
It is used in low-and medium-speed (engine driven) alternators. It has a large number of
projecting (salient) poles, having their cores bolted or dovetailed onto a heavy magnetic
wheel of cast-iron, or steel of good magnetic quality (Fig.)Such generators are characterised
by their large diameters and short axial lengths. The poles and pole-shoes (which cover 2/3 of
pole-pitch) are laminated to minimize heating due to eddy currents. In large machines, field
windings consist of rectangular copper strip wound on edge.
(ii) Smooth Cylindrical Type
It is used for steam turbine-driven alternators i.e. turboalternators, which run at very high
speeds. The rotor consists of a smooth solid forged steel cylinder, having a number of slots
milled out at intervals along the outer periphery (and parallel to the shaft) for accommodating
field coils. Such rotors are designed mostly for 2-pole (or 4-pole) turbo-generators running at
3600 r.p.m. (or 1800 r.p.m.). Two (or four) regions corresponding to the
central polar areas are left unslotted, as shown in Fig.(a) and (b).
The central polar areas are surrounded by the field windings placed in slots. The field coils
are so arranged around these polar areas that flux density is maximum on the polar central
line and gradually falls away on either side. It should be noted that in this case, poles are nonsalient i.e. they do not project out from the surface of the rotor. To avoid excessive peripheral
velocity, such rotors have very small diameters (about 1 metre or so). Hence, turbogenerators are characterised by small diameters and very long axial (or rotor) length. The
cylindrical construction of the rotor gives better balance and quieter-operation and also less
windage losses.
Damper Windings
Most of the alternators have their pole-shoes slotted for receiving copper bars of a grid or
damper winding (also known as squirrel-cage winding). The copper bars are short-circuited at
both ends by heavy copper rings (Fig. ). These dampers are useful in preventing the hunting
(momentary speed fluctuations) in generators and are needed in synchronous motors to
provide the starting torque. Turbo-generators usually do not have these damper
windings (except in special case to assist in synchronizing) because the solid field-poles
themselves act as efficient dampers. It should be clearly understood that under normal
running conditions, damper winding does not carry any current because rotor runs at
synchronous speed. The damper winding also tends to maintain balanced 3-voltage under
unbalanced load conditions
2.Draw and explain the vector diagram , when the alternator is loaded with
resistive,inductive and capacitive load.
Alternator on Load
As the load on an alternator is varied, its terminal voltage is also found to vary as in d.c.
generators.
This variation in terminal voltage V is due to the following reasons:
1. voltage drop due to armature resistance Ra
2. voltage drop due to armature leakage reactance XL
3. voltage drop due to armature reaction
(a) Armature Resistance
The armature resistance/phase Ra causes a voltage drop/phase of IRa which is in phase with
the armature current I. However, this voltage drop is practically negligible.
(b) Armature Leakage Reactance
When current flows through the armature conductors, fluxes are set up which do not cross the
air-gap, but take different paths. Such fluxes are known as leakage fluxes. Various types of
leakage fluxes are shown in Fig.
The leakage flux is practically independent of saturation, but is dependent on I and its phase
angle with terminal voltage V. This leakage flux sets up an e.m.f. of self-inductance which is
known as reactance e.m.f. and which is ahead of I by 90°. Hence, armature winding is
assumed to possess leakage reactance XL (also known as Potier rectance XP) such that
voltage drop due to this equals IXL.
A part of the generated e.m.f. is used up in overcoming this reactance e.m.f.
∴ E = V + I (R + jXL )
This fact is illustrated in the vector diagram of Fig.
(c) Armature Reaction
As in d.c. generators, armature reaction is the effect of armature flux on the main field flux.
In the case of alternators, the power factor of the load has a considerable effect on the
armature reaction.
We will consider three cases : (i) when load of p.f. is unity (ii) when p.f. is zero lagging and
(i) when p.f. is zero leading.
Before discussing the diagrams, following symbols should be clearly kept in mind.
E0 = No-load e.m.f. This being the voltage induced in armature in the absence of three
factors. Hence, it represents the maximum value of the induced e.m.f.
E = Load induced e.m.f. It is the induced e.m.f. after allowing for armature reaction. E is
vectorially less than E0 by IXa. Sometimes, it is written as Ea
V = Terminal voltage, It is vectorially less than E0 by IZS or it is vectorially less than E by
IZ where
I = armature current/phase and φ = load p.f. angle.
In Fig. (a) is shown the case for unity p.f., in Fig.(b) for lagging p.f. and in Fig.(c)
for leading p.f. All these diagrams apply to one phase of a 3-phase machine. Diagrams for the
other phases can also be drawn similary.
3. Explain the various methods of starting of synchronous motors.
1.DC motor method
2.Induction motor Method
3.Damper winding method
4 Slip ring Induction motor method
The rotor (which is as yet unexcited)is speeded up to synchronous near synchronous speed
by some arrangement and then excited by the d.c. source. The moment this (near)
synchronously rotating rotor is
excited, it is magnetically locked into position with the stator i.e., the rotor poles are engaged
with the stator poles and both run synchronously in the same direction. It is because of this
interlocking of stator and rotor poles that the motor has either to run synchronously or not at
all. The synchronous speed is given by the usual relation NS = 120 f / P.
However, it is important to understand that the arrangement between the stator and rotor
poles is not an absolutely rigid one. As the load on the motor is increased, the rotor
progressively tends to fall back in phase (but not in speed as in d.c. motors) by some angle
(Fig.) but it still continues to run synchronously.The value of this load angle or coupling
angle (as it is called) depends on the amount of load to be met by the motor. In other words,
the torque developed by the motor depends on this angle.
The working of a synchronous motor is, in many ways, similar to the transmission of
mechanical power by a shaft. In Fig.are shown two pulleys P and Q transmitting power from
the driver to the load. The two pulleys are assumed to be keyed together (just as stator and
rotor poles are interlocked) hence they run at exactly the same (average) speed. When Q is
loaded, it slightly falls behind owing to the twist in the shaft (twist angle corresponds to α in
motor), the angle of twist, in fact, being a measure of the torque transmitted. It is clear that
unless Q is so heavily loaded as to break the
coupling, both pulleys must run at exactly the same (average) speed.
4.Derive the emf equation of synchronous machine.
Equation of Induced E.M.F.
5.Discuss in detail the procedure of constructing V and inverted V curves
The V-curves of a synchornous motor show how armature current varies with its field current
when motor input is kept constant. These are obtained by plotting a.c. armature current
against d.c.
field current while motor input is kept constant and are so called because of their shape
(Fig.). There is a family of such curves, each corresponding to a definite power intake. In
order to draw these curves experimentally,
the motor is run from constant voltage and constant-frequency bus-bars. Power input to
motor is kept constant at a definite value. Next, field current is increased in small steps and
corresponding armature currents are
noted. When plotted, we get a V-curve for a particular constant motor input. Similar curves
can be drawn by keeping motor input constant at different values. A family of such curves is
shown in Fig. Detailed procedure for graphic construction of V-curves is given below :
1. First, constant-power lines are drawn.
2. Then, with A as the centre, concentric circles of different radii AB, AB1, AB2, etc. are
drawn
where AB, AB1, AB2, etc., are the back e.m.fs corresponding to different excitations. The
intersections of these circles with lines of constant power give positions of the working points
for specific loads and excitations (hence back e.m.fs). The vectors OB, OB1, OB2 etc.
represent different values of ER (and hence currents) for different excitations. Back e.m.f.
vectors AB, AB1 etc., have not been drawn purposely in order to avoid confusion
3. The different values of back e.m.fs like AB, AB1, AB2, etc., are projected on the
magnetisation
and corresponding values of the field (or exciting) amperes are read from it.
4. The field amperes are plotted against the corresponding armature currents, giving us ‘V’
curves.
6. Explain the various torque of synchronous motor.
Different Torques of a Synchronous Motor
Various torques associated with a synchronous
motor are as follows:
1. starting torque
2. running torque
3. pull-in torque and
4. pull-out torque
(a) Starting Torque
It is the torque (or turning effort) developed by the motor when full voltage is applied to its
stator (armature) winding. It is also sometimes called breakaway torque. Its value may be as
low as 10% as in the case of centrifugal pumps and as high as 200 to 250% of full-load
torque as in the case of loaded reciprocating two-cylinder compressors.
(b) Running Torque
As its name indicates, it is the torque developed by the motor under running conditions. It is
determined by the horse-power and speed of the driven machine. The peak horsepower
determines the maximum torque that would be required by the driven machine. The motor
must have a breakdown or a maximum running torque greater than this value in order to
avoid stalling.
(c) Pull-in Torque
A synchronous motor is started as induction motor till it runs 2 to 5% below the synchronous
speed. Afterwards, excitation is switched on and the rotor pulls into step with the
synchronously rotating stator field. The amount of torque at which the motor will pull into
step is called the pull-in torque.
Torque motors are designed to privide maximum torque at locked rotor or near stalled
conditions
(d) Pull-out Torque
The maximum torque which the motor can develop without pulling out of step or
synchronism is called the pull-out torque.
Normally, when load on the motor is increased, its rotor progressively tends to fall back in
phase by some angle (called load angle) behind the synchronously-revolving stator magnetic
field though it keeps running synchronously. Motor develops maximum torque when its rotor
is retarded by an angle of 90º (or in other words, it has shifted backward by a distance equal
to half the distance between adjacent poles).
UNIT-IV
6. Explain the and principle of operation of Induction machine.
Production of Rotating Field It will be shown that when stationarycoils, wound for two or
three phases, are supplied by two or three-phase supply respectively, auniformly-rotating (or
revolving) magnetic flux of constant value is produced.
Two-phase Supply
The principle of a 2Φ, 2-pole stator having two identical windings, 90 space degreesThe flux
due to the current flowing in each phase winding is assumed sinusoidal and is represented in .
The assumed positive directions of fluxes are those shown in Fig. Let Φ1 and Φ2 be the
instantaneous values of the fluxes set up by the two windings. The resultant flux Φr at any
time is the vector sum of these two fluxes (Φ 1 and Φ2) at that time. We will consider
conditions at intervals of 1/8th of a time period i.e. at intervals corresponding to
angles of 0º, 45º, 90º, 135º and 180º.
(a) When = 0º i.e. corresponding to point 0 in Fig (a) When Φ1 = 0º i.e. corresponding to
point 0 in Fig. Φ1= 0, but Φ2 is maximum i.e. equal to Φm and negative.
Hence, resultant flux Φ r = Φ m and, being negative, is shown by a vector pointing
downwards .
(b) When = 45º i.e. corresponding to point 1 in Fig. At this instant, Φ 1 = Φ m / 2 and is
positive; Φ 2 = Φ m / 2 but is still negative. Their resultant, as shown in Fig. (ii), is
Φr=
although this resultant has shifted 45º
clockwise.
(c) When θ = 90º i.e. corresponding to point 2 in Fig. Here Φ 2 = 0, but Φ1 = Φ m and is
positive. Hence, Φ r = Φ m and has further shifted by an angle of 45º from its position in (b)
or by 90º from its original position in (a).
(d) When θ = 135º i.e. corresponding to point 3 in Fig. Here, Φ1 = Φm/ 2 and is positive, Φ2
= Φ m / 2 and is also positive. The resultant Φ r = Φ m and has further shifted clockwise by
another 45º,
(e) When = 180º i.e. corresponding to point 4 in Fig. 34.9. Here, Φ 1 = 0, Φ 2 = Φ m and is
positive.
Hence, Φ r = Φ m and has shifted clockwise by another 45º or has rotated through an angle of
180º from its position at the beginning.
Hence, we conclude
1. that the magnitude of the resultant flux is constant and is equal to Φ m — the maximum
flux due to either phase.
2. that the resultant flux rotates at synchronous speed given by Ns = 120 f/P rpm.
However, it should be clearly understood that in this revolving field, there is no actual
revolution
of the flux. The flux due to each phase changes periodically, according to the changes in the
phase
current, but the magnetic flux itself does not move around the stator. It is only the seat of the
resultant
flux which keeps on shifting synchronously around the stato r.
2. Explain the construction of Induction machine.
a) a stator and (b) a rotor.
(a) Stator
The stator of an induction motor is, in principle, the same as that of a synchronous motor or
generator. It is made up of a number of stampings, which are slotted to receive the windings .
The stator carries a 3-phase winding and is fed from a 3-phase supply. It is wound for a
definite number of poles the exact number of poles being determined by the requirements of
speed. Greater the number of poles, lesser the speed and vice versa. It will be shown in Art.
34.6 that the stator windings, when supplied with 3-phase currents, produce a magnetic flux,
which is of constant magnitude but which revolves (or rotates) at synchronous speed (given
by Ns = 120 f/P). This revolving magnetic flux induces an e.m.f. in the rotor by mutual
induction
(b) Rotor
(i) Squirrel-cage rotor : Motors employing this type of rotor are known as squirrel-cage
induction
motors.
(ii) Phase-wound or wound rotor : Motors employing this type of rotor are variously known
as ‘phase-wound’ motors or ‘wound’ motors or as ‘slip-ring’ motors.
Squirrel-cage Rotor
Almost 90 per cent of induction motors are squirrel-cage type, because this type of rotor has
the simplest and most rugged construction imaginable and is almost indestructible. The rotor
consists of a cylindrical laminated core with parallel slots for carrying the rotor conductors
which, it should be noted are not wires but consist of heavy bars of copper, aluminium or
alloys. One bar is placed in each slot, rather the bars are inserted from the end when semiclosed slots are used. The rotor bars are brazed or electrically welded or bolted to two heavy
and stout short-circuiting end-rings, thus giving us, what is so picturesquely called, a squirrelcase construction It should be noted that the rotor bars are permanently short-circuited on
themselves, hence it is not possible to add any external resistance in series with the rotor
circuit for starting purposes. The rotor slots are usually not quite parallel to the shaft but are
purposely given a slight skew . This is useful in two ways :
(i) it helps to make the motor run quietly by reducing the magnetic hum and
(ii) it helps in reducing the locking tendency of the rotor i.e. the tendency of the rotor teeth to
remain under the stator teeth due to direct magnetic attraction between the two.In small
motors, another method of construction is used. It consists of placing the entire rotor core in a
mould and casting all the bars and end-rings in one piece. The metal commonly used is an
aluminium alloy. Another form of rotor consists of a solid cylinder of steel without any
conductors or slots at all. The motor operation depends upon the production of eddy currents
in the steel rotor.
Phase-wound Rotor
This type of rotor is provided with 3-phase, double-layer, distributed winding consisting of
coils as used in alternators. The rotor is wound for as many poles as the number of stator
poles and is always wound 3-phase even when the stator is wound two-phase. The three
phases are starred internally. The other three winding terminals are brought out and
connected to three insulated slip-rings mountedon the shaft with brushes resting on them
.These three brushes are further externally connected to a 3-phase star-connected Rheostat.
This makes possible the introduction of additional resistance in the rotor circuit during the
starting period for increasing
the starting torque of the motor, as shown in Figand for changing its speed-torque/current
characteristics. When running under normal conditions, the slip-rings are automatically
short-circuited by means of a metal collar, which is pushed along the shaft and connects
all the rings together. Next, the brushes are automatically lifted from the slip-rings to reduce
the frictional losses and the wear and tear. Hence, it is seen that under normal running
conditions, the wound rotor is short-circuited on itself just like the squirrel-case rotor.
1. Frame. Made of close-grained alloy cast iron.
2. Stator and Rotor Core. Built from high-quality low-loss silicon steel laminations and
flash-enamelled on both sides.
3. Stator and Rotor Windings. Have moisture proof tropical insulation embodying mica and
high quality varnishes. Are carefully spaced for most effective air circulation and are rigidly
braced to withstand centrifugal forces and any short-circuit stresses.
4. Air-gap. The stator rabbets and bore are machined carefully to ensure uniformity of airgap.
5. Shafts and Bearings. Ball and roller bearings are used to suit heavy duty, toruble-free
running and for enhanced service life.
6. Fans. Light aluminium fans are used for adequate circulation of cooling air and are
securely keyedonto the rotor shaft.
7. Slip-rings and Slip-ring Enclosures. Slip-rings are made of high quality phosphor-bronze
and are of moulded construction.
3.Derive the equivalent circuit of induction motor.
When motor is loaded, the rotor current I2 is given by
From the above relation it appears that the rotor circuit which actually consists of a fixed
resistance R2 and a variable reactance sX2 (proportional to slip) connected across Er = sE2
[Fig.]can belooked upon as equivalent to a rotor circuit having a fixed reactance X2
connected in series with a variable resistance R2/s (inversely proportional to slip) and
supplied with constant voltage E2, as shown in Fig. (b).
Equivalent Circuit of an Induction Motor
As in the case of a transformer , in this case also, the secondary values may be
transferred to the primary and vice versa. As before, it should be remembered that when
shifting impedance or resistance from secondary to primary, it should be divided by K2
whereas current should be multiplied by K. The equivalent circuit of an induction motor
where all values have been referred to primary i.e. stator is shown in Fig.
As shown in Fig. the exciting circuit may be transferred to the left, because inaccuracy
involved is negligible but the circuit and hence the calculations are very much simplified.
This is known as the approximate equivalent circuit of the induction motor.
If transformation ratio is assumed unity i.e. E2/E1 = 1, then the equivalent circuit is as shown
In fig.
4.Derive the torque equation and condition for maximum torque of induction motor.
Condition for maximum torque
From the above, it is found
1. that the maximum torque is independent of rotor resistance as such.
2. however, the speed or slip at which maximum torque occurs is determined by the rotor
resistance. As seen from above, torque becomes maximum when rotor reactance equals its
resistance. Hence, by varying rotor resistance (possible only with slip-ring motors) maximum
torque can be made to occur at any desired slip (or motor speed).
3. maximum torque varies inversely as standstill reactance. Hence, it should be kept as small
as possible.
4. maximum torque varies directly as the square of the applied voltage.
5. for obtaining maximum torque at starting (s =1), rotor resistance must be equal to rotor
reactance
5. Explain the various starting methods of induction motor
Starting of Induction Motors
It has been shown earlier that a plain induction motor is similar in action to a polyphase
transformer with a short-circuited rotating secondary. Therefore, if normal supply voltage is
applied to the stationary motor, then, as in the case of a transformer, a very large initial
current is taken by the primary, at least, for a short while. It would be remembered that
exactly similar conditions exist in the case of a d.c
motor, if it is thrown directly across the supply lines, because at the time of starting it, there is
no back e.m.f. to oppose the initial inrush of current. only 1.5 to 2.5 times their full-load
torque. This initial excessive current is objectionable because it will produce large linevoltage drop that, in turn, will affect the operation of other electrical equipment connected to
the same lines. Hence, it is not advisable to line-start motors of rating above 25 kW to40 kW.
that the starting torque of an induction motor can be improved by increasing the resistance of
the rotor circuit. This is easily feasible in the case of slip-ring motors but not in the case of
squirrel-cage motors. However, in their case, the initial in-rush of current is controlled
by applying a reduced voltage to the stator during the starting period, full normal voltage
being applied when the motor has run up to speed.
Squirrel-cage Motors
(a) Primary resistors (or rheostat) or reactors
(b) Auto-transformer (or autostarter)
(c) Star-delta switches
In all these methods, terminal voltage of the squirrel-cage motor is reduced during starting.
Slip-ring Motors
(a) Rotor rheostat
(b) Squirrel-cage Motors
(c) (a) Primary resistors
(d) Their purpose is to drop some voltage and hence reduce the voltage applied across the
motor
(e) terminals. In this way, the initial current drawn by the motor is reduced. However, it
should be noted
(f) that whereas current varies directly as the voltage, the torque varies as square of
applied voltage*
(g) * When applied voltage is reduced, the rotating flux Φ is reduced which, in turn,
decreases rotor e.m.f. and
(h) hence rotor current I2. Starting torque, which depends both on Φ1 and Φ2 suffers on
two counts when
(i) impressed voltage is reduced.
(j) If the voltage applied across the motor terminals
(k) is reduced by 50%, starting current is reduced by 50%, but
(l) torque is reduced to 25% of the full-voltage value.
(m) By using primary resistors (Fig. 35.18), the applied
(n) voltage/phase can be reduced by a fraction ‘x’ (and it
(o) additionally improves the power factor of the line slightly).
Ist = x Isc and Tst = x2 Tsc
It is obvious that the ratio of the starting torque to full-load torque is x2 of that obtained with
direct switching or across-the-line starting. This method is useful for the smooth starting of
small machines only.
(b) Auto-transformers
Such starters, known variously as auto-starters or compensators, consist of an autotransformer, with necessary switches. auto-transformers connected in open delta
(a)]. This method can be used both for star-and delta-connected motors. with starting
connections, a reduced voltage is applied across the motor terminals. When the motor
has ran up to say, 80% of its normal speed, connections are so changed that auto-transformers
are cut out and full supply voltage is applied across the motor. The switch making these
changes from ‘start’ to ‘run’ may be airbreak (for small motors) or may be oil-immersed (for
large motors) to reduce sparking. There is also provision for no-voltage and over-load
protection, along with a time-delay device, so that momentary interruption of voltage or
momentary over-load do not disconnect the motor from supply line. Most of the auto-starters
are provided with 3 sets of taps, so as to reduce voltage to 80, 65 or 50 per cent of the line
voltage, to suit the local conditions of supply. The V-connected auto-transformer is
commonly used, because it is cheaper, although the currents are unbalanced during starting
period. This is, however, not much objectionable firstly, because the current imbalance is
about 15 per cent and secondly, because balance is restored as soon as running conditions are
attained. The quantitative relationships between the motor current, line current, and torque
developed direct-switched to lines. The motor current is, say, 5 times the full-load current. If
V is the line voltage, then voltage/phase across motor is V / 3 .
(c) Star-delta Starter
This method is used in the case of motors which are built to run normally with a deltaconnected stator winding. It consists of a two-way switch which connects the motor in star
for starting and then in delta for normal running. The usual connections are shown in Fig.
When star-connected, the applied voltage over each motor phase is reduced by a factor of 1/ 3
and hence the torque developed becomes 1/3 of that which would have been developed if
motor were directly connected in delta. The line current is reduced to 1/3. Hence, during
starting period when motor is Y -connected, it takes 1/3rd as much starting current and
develops 1/3rd as much torque as would have been developed were itdirectly connected in
delta.
Relation Between Starting and F.L. Torque
where Isc is the current/phase which Δ-connected motor would have taken if switched on to
the supply directly (however, line current at start = 1/3 of line Isc)
6.Explain the speed control of induction motor.
A 3-phase induction motor is practically a constant-speed machine, more or less like a d.c.
shunt motor. The speed regulation of an induction motor (having low resistance) is usually
less than 5% at full-load. However, there is one difference of practical importance between
the two. Whereas d.c. shunt motors can be made to run at any speed within wide limits, with
good efficiency and speed regulation, merely by manipulating a simple field rheostat, the
same is not possible with induction motors. In their case, speed reduction is accompanied by
a corresponding loss of efficiency and good speed regulation. That is why it is much easier to
build a good adjustable-speed d.c. shunt motor than an adjustable speed induction motor.
Different methods by which speed control of induction motors is achieved, may be grouped
under two main headings :
1. Control from stator side
(a) by changing the applied voltage (b) by changing the applied frequency
(c) by changing the number of stator poles
2. Control from rotor side
(d) rotor rheostat control
(e) by operating two motors in concatenation or cascade
(f) by injecting an e.m.f. in the rotor circuit.
A brief description of these methods would be given below :
(a) Changing Applied Voltage
This method, though the cheapest and the easiest, is rarely used because
(i) a large change in voltage is required for a relatively small change in speed
(ii) this large change in voltage will result in a large change in the flux density thereby
seriously disturbing the magnetic conditions of the motor.
(b) Changing the Applied Frequency
This method is also used very rarely. We have seen that the synchronous speed of an
induction motor is given by Ns = 120 f/P. Clearly, the synchronous speed (and hence the
running speed) of an induction motor can be changed by changing the supply frequency f.
However, this method could only be used in cases where the induction motor happens to be
the only load on the generators, in which case, the supply frequency could be controlled by
controlling the speed of the prime movers of the generators. But, here again the range over
which the motor speed may be varied is limited by the economical speeds of the prime
movers. This method has been used to some extent on electrically driven ships.
(c) Changing the Number of Stator Poles
This method is easily applicable to squirrel-cage motors because the squirrel-cage rotor
adopts itself to any reasonable number of stator poles. From the above equation it is also clear
that the synchronous (and hence the running)speed of an induction motor could also be
changed by changing the number of stator poles. This change of number of poles is achieved
by having two or more entirely independent stator windings in the same slots. Each winding
gives a different number of poles and hence different synchronous speed. For example, a 36slot stator may have two 3-φ windings, one with 4 poles and the other with 6-poles.
With a supply frequency of 50-Hz, 4-pole winding will give Ns = 120 × 50/4 = 1500 r.p.m.
and the 6- pole winding will give Ns = 120 × 50/6 = 1000 r.p.m. Motors with four
independent stator winding are also in use and they give four different synchronous (and
hence running) speeds. Of course, one winding is used at a time, the others being entirely
disconnected. This method has been used for elevator motors, traction motors and also for
small motors driving machine tools.Speeds in the ratio of 2:1 can be produced by a single
winding if wound on the consequent-pole principle. In that case, each of the two stator
windings can be connected by a simple switch to give two speeds, each, which means four
speeds in all. For example, one stator winding may give 4 or 8-poles and the other 6 or 12poles. For a supply frequency of 50-Hz, the four speeds will be 1500, 750, 1000 and 500
r.p.m. Another combination, commonly used, is to group 2- and 4-pole winding with a 6- and
12-pole winding, which gives four synchronous speeds of 3000, 1500, 1000 and 500 r.p.m.
(d) Rotor Rheostat Control
In this method which is applicable to slip-ring motors alone, the motor speed is reduced by
introducing an external resistance in the rotor circuit. For this purpose, the rotor starter may
be used, provided it is continuously rated. This method is, in fact, similar to the armature
rheostat control method of d.c. shunt motors.
UNIT V
Explain the principle and operation of single phase induction motor.
Constructionally, this motor is, more or less, similar to a polyphase induction motor, except
that (i) its stator is provided with a single-phase winding and (ii) a centrifugal switch is used
in some types of motors, in order to cut out a winding, used only for starting purposes. It has
distributed stator winding and a squirrel-cage rotor. When fed from a single-phase supply, its
stator winding produces a flux (or field) which is only alternating i.e. one which alternates
along one space axis only. It is not a synchronously revolving (or rotating) flux, as in the case
of a two- or a three-phase stator winding fed from a 2-or 3-phase supply. Now, an alternating
or pulsating flux acting on a stationary squirrel-cage rotor cannot produce rotation (only a
revolving flux can). That is why a single-phase motor is not selfstarting.
However, if the rotor of such a machine is given an initial start by hand (or small motor) or
otherwise,in either direction, then immediately a torque arises and the motor accelerates to its
final speed (unless the applied torque is too high). This peculiar behaviour of the motor has
been explained in two ways :
(i) by two -field or doublefield
revolving theory and
(ii) by cross-field theory.
.
2.Explain the principle and operation of double field revolving theory of induction
motor.
This theory makes use of the idea that an alternating uni-axial quantity can be represented by
two oppositely-rotating vectors of half magnitude. Accordingly, an alternating sinusoidal
flux can be represented by two revolving fluxes, each equal to half the value of the
alternating flux and each rotating synchronously (Ns = 120f/P) in opposite direction
As shown in Fig. (a), let the alternating flux have a maximum value of Φm. Its component
fluxes A and B will each be equal to Φm /2 revolving in anticlockwise and clockwise
directions respectively
After some time, when A and B would have rotated through angle + θ and − θ, as in Fig. 36.1
(b),
the resultant flux would be
fullspeed.
zero, as shown in Fig. (e) and so on. If we plot the values of resultant flux against θ between
limits = 0º to = 360º, then a curve similar to the one shown in Fig is obtained. That is why
an alternating flux can be looked upon as composed of two revolving fluxes, each of half the
value and revolving synchronously in opposite directions. It may be noted that if the slip of
the rotor is s with respect to the forward rotating flux . Each of the two component fluxes,
while revolving round the stator, cuts the rotor, induces an e.m.f. and this produces its own
torque. Obviously, the two torques (called forward and backward torques) are oppositelydirected, so that the net or resultant torques is equal to their difference as shown in fig
3.Explain the principle and operation of Repulsion type and Universal motor.
Constructionally, it consists of the following :
1. Stator winding of the distributed non-salient pole type housed in the slots of a smoothcored
stator (just as in the case of split-phase motors). The stator is generally wound for four, six
or eight poles.
2. A rotor (slotted core type) carrying a distributed winding (either lap or wave) which is
connected to the commutator. The rotor is identical in construction to the d.c. armature.
3. A commutator, which may be one of the two types : an axial commutator with bars parallel
to the shaft or a radial or vertical commutator having radial bars on which brushes press
horizontally.
4. Carbon brushes (fitted in brush holders) which ride against the commutator and are used
for conducting current through the armature (i.e. rotor) winding.
Repulsion Principle
To understand how torque is developed by the repulsion principle, consider Fig. Which
shows a 2-pole salient pole motor with the magnetic axis vertical. For easy understanding, the
stator winding has been shown with concentrated salient-pole construction (actually it is of
distributed nonsalient type). The basic functioning of the machine will be the same with
either type of construction. As mentioned before, the armature is of standard d.c. construction
with commutator and brushes (which are short-circuited with a low-resistance jumper).
Suppose that the direction of flow of the alternating current in the exciting or field (stator)
winding is such that it creates a N-pole at the top and a S-pole at the bottom. The alternating
flux produced by the stator winding will induce e.m.f. in the armature conductors by
transformer action. The direction of the induced e.m.f. can be found by using Lenz’s law and
is as shown in Fig(a). However, the direction of the induced currents in the armature
conductors will depend on the positions of the short-circuited brushes. If brush axis is
colinear with magnetic axis of the main poles, the directions of the induced currents (shown
by dots and arrows) will be as indicated in Fig. (a)*. As a result, the armature will become an
electromagnet with a N-pole on its top, directly under the main N-pole and with a S-pole at
the bottom, directly over the main S-pole. Because of this face-toface
positioning of the main and induced magnetic poles, no torque will be developed. The two
forces of repulsion
on top and bottom act along Y Y′ in direct opposition to each other.** If brushes are shifted
through 90º to the position shown in Fig. (b) so that the brush axis is at right angles to the
magnetic axis of the main poles, the directions of the induced voltages at any time in the
respective armature conductors are exactly the same
as they were for the brush position of Fig. (a). However, with brush positions of Fig. (b), the
voltages induced in the armature conductors in each path between the brush terminals will
neutralize each other, hence there will be no net voltage across brushes to produce armature
current. If there is no armature current, obviously, no torque will be developed. If the brushes
are set in position shown in Fig. (a) so that the brush axis is neither in line with nor 90º from
the magnetic axis Y Y′ of the main poles, a net voltage will be induced between the brush
terminals which will produce armature current. The armature will again act as an electromagnet and develop its own N-and S-poles which, in this case, will not directly face the
respective main poles. As shown in Fig.(a), the armature poles lie along A A′ making an angle
of αY Y′).
Hence, rotor N-pole will be repelled by the main N-pole and the rotor S-pole will, similarly,
be repelled by the ain S-pole. Consequently, the rotor will rotate in clockwise direction (b)].
Since the forces are those of epulsion, it is appropriate to call the motor as repulsion motor.
It should be noted that if the brushes are shifted
counter-clockwise from YY ′, rotation will also be counter-clockwise. Obviously, direction of
rotation
of the motor is determined by the position of brushes with respect to the main magnetic axis.
It is worth noting that the value of starting torque developed by such a motor will depends on
the amount of brush-shift whereas direction of rotation will depend on the direction of shift .
Maximum starting torque is developed at some position where brush axis makes, an angle
lying between 0º and 45º with the magnetic axis of main poles. Motor speed can also be
controlled by means of brush shift. Variation of starting torque of a repulsion motor with
brush-shift is shown in Fig.A straight repulsion type motor has high starting torque (about
350 per cent) and moderate starting current (about 3 to 4 times full-load value). Principal
shortcomings of such a motor are :
1. speed varies with changing load, becoming dangerously high at no load.
2. low power factor, except at high speeds.
3. tendency to spark at brushes.
4.Explain the operation of Hysterisis motor.
The operation of this motor depends on the presence of a continuously-revolving magnetic
flux. Hence, for the split-phase operation, its stator has two windings which remain
connected to the single-phase supply continuously both at starting as well as during the
running of the motor. Usually, shaded-pole principle is employed for this purpose giving
shaded-pole hysteresis motor. Alternatively, stator winding of the type used in capacitor-type
motor may be used giving capacitor- type shaded-pole motor. Obviously, in either type, no
centrifugal device is used.
The rotor is a smooth chrome-steel cylinder** having
high retentivity so that the hysteresis loss is high. It has no winding. Because of high
retentivity of the rotor material, it is very difficult to change the magnetic polarities once they
are induced in the rotor by the revolving flux. The rotor revolves synchronously because the
rotor poles magnetically lock up with the revolving stator poles of opposite polarity.
However, the rotor poles always lag behind the stator poles by an angle α. Mechanical power
developed by rotor is given by Pm = Ph (1 − s ) s where Ph is hysteres loss in rotor. Also Th
= 9.55 Pm /Ns. It is seen that hysteresis torque depends solely on the area of rotor’s hysteresis
loop. The fact that the rotor has no teeth or winding of any sort, results in making the motor
extremely quiet in operation and free from mechanical and magnetic vibrations. This makes
the motor particularly useful for driving tape-decks, tape-decks, turn-tables and other recision
audio equipment. Since, commercial motors usually have two poles, they run at 3,000 r.p.m.
at 50-Hz single-phase supply. In order to adopt such a motor for driving an electric clock and
other indicating devices, gear train is connected to the motor shaft for reducing the load
speed. The unit accelerates rapidly, changing from rest to full speed almost instantaneously.
It must do so because it cannot accelerate gradually as an ordinary motor it is either operating
at synchronous speed or not at all. Some unique features of a hysteresis motor are as under :
(i) since its hysteresis torque remains practically constant from locked rotor to synchronous
speed, a hysteresis motor is able to synchronise any load it can accelerate–something no
other motor does.
(ii) due to its smooth rotor, the motor operates quietly and does not suffer from magnetic
pulsations
caused by slots/salient-poles that are present in the rotors of other motors.
In Fig. is shown a two-pole shaded-pole type hysteresis motor used for driving ordinary
household electric clocks. The rotor is a thin metal cylinder and the shaft drives a gear train.
5.Explain the principle and working of PMSM motor.
(a) Construction and Performance
Such motors have a cage rotor having rare-earth permanent magnets instead of a wound field.
Such a motor starts like an induction motor when fed from a fixed-frequency supply. A
typical 2-pole and 4-pole surface-mounted versions of the rotor are shown in Fig. Since no
d.c. supply is needed for exciting the rotor, it can be made more robust and reliable. These
motors have outputs ranging from about 100 W upto 100 kW. The maximum synchronous
torque is designed to be around 150 per cent of the rated torque. If loaded beyond this point,
the motor loses synchronism and will run either as an induction motor or stall.
These motors are usually designed for direct-on-line (DOL) starting These motors are usually
designed for direct-on-line (DOL) starting. The efficiency and power factor of the permanentmagnet excited synchronous motors are each 5 to 10 points better than their reluctance motor
counterparts.
(b) Advantages
Since there are no brushes or sliprings, there is no sparking. Also, brush maintenance is
eliminated. Such motors can pull into synchronism with inertia loads of many times their
rotor inertia.
(c) Applications
These motors are used where precise speed must be maintained to ensure a consistent
product. With a constant load, the motor maintains a constant speed. Hence, these motors are
used for synthetic-fibre drawing where constant speeds are absolutely essential.
6.Explain the principle and working of SRM motor
The switched reluctance (SR) motor operates on the same basic principle as a variable
reluctance stepper motor
(a) Construction
Unlike a conventional synchronous motor, both the rotor and stator of a SR motor have
salient poles as shown in Fig. This doubly-salient arrangement is very effective for
electromagnetic energy conversion.
The stator carries coils on each pole, the coils on opposite poles being connected in series.
The eight stator coils shown in Figure are grouped to form four phases which are
independently energized from a four-phase converter. The laminated rotor has no windings or
magnets and is, therefore cheap
to manufacture and extremely robust. The motor shown in Fig. 39.22 has eight stator poles
and six rotor poles which is a widely-used arrangement although other pole combinations
(like 6/4 poles) are used to suit different applications.
(b) Working
Usual arrangement is to energize stator coils sequentially with a single pulse of current at
high
speed. However, at starting and low speed, a The motor rotates in the anticlockwise direction
when the stator phases are energized in the sequence 1, 2, 3, 4 and in clockwise direction
when energized in the sequence 1, 4, 3, 2. When the stator coils are energized, the nearest
pair of rotor poles is pulled into alignment with the appropriate stator poles by reluctance
torque.
Closed-loop control is essential to optimize the switching angles of the applied coil voltages.
The stator phases are switched by signals derived from a shaft-mounted rotor position
detectors such as Hall-effect devices or optical sensors Fig. . This causes the behaviour of the
SR motor to resemble that of a dc motor.
(c) Advantages and Disadvantages
Although the newest arrival on the drives scene, the SR motor offers the following
advantages:
(i) higher efficiency (ii) more power per unit weight and volume (iii) very robust because
rotor has no windings or slip rings (iv) can run at very high speed (upto 30,000 rpm) in
hazardous atmospheres (v) has versatile and flexible drive features and (vi) four-quadrant
operation is possible with appropriate drive circuitry.
However, the drawbacks are that it is (i) relatively unproven (ii) noisy and (iii) not wellsuited for smooth torque production.
(d) Applications
Even though the SR technology is still in its infancy, it has been successfully applied to a
wide range of applications such as (i) general purpose industrial drives (ii) traction (iii)
domestic appliances like food processors, vacuum cleaners and washing machines etc., and
(iv) office and business.equipment.