Download ecet105-mmmmmmmmmmmmmmm

1. (TCO 1) Which lab instrument is used to generate power for a DC circuit? (Points : 5)
Power supply
Function generator
Oscilloscope
DMM
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MultipleChoice
2
Question 2. 2. (TCO 2) When is the output of a NOR gate LOW? (Points : 5)
All inputs LOW
One input LOW
One input HIGH
All inputs HIGH
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MultipleChoice
12
Question 3. 3. (TCO 3) Which decimal number is equivalent to 25? (Points : 5)
10
25
31
32
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MultipleChoice
13
Question 4. 4. (TCO 1) The figure below shows an oscilloscope screen capture of a periodic
signal. The oscilloscope settings are: time scale = 5 µs ÷ div and voltage scale = 5 V ÷ div. What
are the frequency and the peak voltage for the signal shown? The minimum value of the signal is
0V.
(Points : 5)
F=1/t
Where f=frequency and t=time(seconds)
There are 6 divisions each 5micro seconds
F=1/(6x5x10^-6)
1s=10^6 micro seconds
F=1/((3x10^-5)
=33333Hz
=33.33Khz
Peak voltage
=4 divisions x 5=20volts
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Essay
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Question 5. 5. (TCO 3) How many decimal numbers can be represented by 10-bits? What is the
largest unsigned
decimal number that can be represented by 10-bits? (Points : 5)
1 bit can represent 0 and 1
2 bit can represent 0, 1, 2, 3
n bit can represent 2^n - 1
So, 10 bits can encode 2^10-1 = 1023 different numbers - you can count from 0 to 1023 with 10
bits.
Decimal numbers:
S: signum (positive or negative)
M: mantisse
E: exponent
comparing it with scientific notation for numbers, example -3.5210 * 10^-4. "-" would be S,
"3.5210" would be the M part, "-4" would be the E part
machine numbers c represented by 10 bits
Will depend on how many bits M has, and how many bits E has. S is always 1-bit, so there are 9bit left for M+E. M can represent 2^M-1 different numbers. E can represent 2^E-1 exponents.
Together, M+E can represent (2^M-1)*(2^E-1) different numbers. Altogether, 10 bits can
represent
= 2*(2^M-1)*(2^(9-M)-1) signed decimal numbers
Largest unsigned machine number that can be represented with 10 bits:
-unsigned means, that S isn't there
- E is a signed integer so that decimal numbers become possible => (2^(E-1)-1) exponents at the
most
- the base of machine numbers is always 2 ,maximize (2^M-1)*2^((2^(E-1)-1) )
=> happens when E maximal (growth in exponent increases the overall number much faster than
growth in mantisse)
= M = 1; E = 9
= largest decimal number: (2^1-1)*2^(2^(9-1)-1)
= 1*2^(2^8-1)
= 2^255