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Geo 2nd Sem Final Review
Answer Section
MULTIPLE CHOICE
1. B
2. D
3. A
4. C
5. A
6. A
7. B
8. B
9. B
10. D
11. B
12. D
13. A
14. B
15. A
16. A
17. B
COMPLETION
18. 24
19. x=20
20. l = 6
S = 448 u2
21. x = 120
22. 345
23. V = 400 units2
SHORT ANSWER
24. Yes; ASA Congruence Postulate. Since LMP NPM and NMP LPM (given), and MP
MP (reflexive property of congruence), two pairs of corresponding angles are congruent and two
corresponding included sides are congruent.
25. The triangles are not similar because the sides are not in proportion:7/8 14/18
26. x = 22
27. x = 15; y = 12
28. x = 110; y = 70
29. y 3.5x 4
30. WXYZ is a kite. The diagonals are perpendicular and the quadrilateral has two pairs of consecutive
congruent sides, but opposite sides are not congruent.
31. m1 = 120°; m2 = 75°
32.m1 = 29°; m2 = 66°; m3 = 37°
33. m1 72.5 m2 145
34. m1 90 m2 90 m3 45
35. 174.22547.06 in2
36. A 112.5353.43 ft
37. C 1031.42cm; A 2578.54 cm2
38. mAB 2.929.16 cm
39. A 7.2622.91 cm2
40. 263.89 in2
41. 1198.43 cm3
42. 384 m2
43. 12
44. r = 8; angles 28.161.9 90
45. mK 60 ; KL 4.5; JL 7.8
46. QR 2 5 4.5mP 48.2mR 41.8
47. c 18.0 mA 33.7 mB =56.3
48. ERROR
49. mWYX 360û 75û 285 ; since WZ is a perpendicular bisector of UY, WZ is a diameter, so mWTZ
180 .
50. x = 115
51. x = 7
52. x = 22.5
53. x = 4; y 3 5
54. sinR = 0.8000; cosR = 0.6000; tanR 1.3333 sinT = 0.6000; cosT = 0.8000; tanT = 0.7500
55. sinP 0.9459cosP 0.3243tanP 2.9167 sinN 0.3243cosN 0.9459tanN 0.3429
56. 168
57. no
58. FE BC, so FE BC since congruent chords have congruent arcs.
59. mABD 60 .
60. mCED 35
61. 1:9
62. 0.611 or 61.1%
63.2/3
64. 62°
65. 118°
66. 242°
67. ERROR
68. V = 276 u3 SA= 295.2 u2
69. x = 3.333 y = 3.75
70. x = 17.5
71. x = 10.5 y = 48/7
72. x = 12 y = 6
73. x=110
74. x = 115
75. 6
76. x = 70
OTHER
77. Since QPR PRS, PQ Ä RS (alternate interior angles converse). Since one pair of opposite sides
are congruent and parallel, PQRS must be a parallelogram.
78. rectangle; one pair of opposite sides are both congruent and parallel, so it is a parallelogram. Since it
has at least one right angle, all the angles of the parallelogram are right angles, so it is a rectangle.
79. square; The diagonals bisect each other and are congruent so the quadrilateral is a parallelogram and a
rectangle. The diagonals are perpendicular so the parallelogram is a rhombus. So it is a square.
80. There is not enough information about opposite sides to decide if PQRS is a parallelogram.
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