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MTH-4101 C1 10/5/11 11:59 AM Page 1 E inequalities II MTH-4101-2 quations and MTH-4101-2 EQUATIONS AND INEQUALITIES II This course was produced in collaboration with the Service de l'éducation des adultes de la Commission scolaire catholique de Sherbrooke and the Department of the Secretary of State of Canada. Author: Monique Pagé Content revision: Jean-Paul Groleau Daniel Gélineau Mireille Moisan-Sanscartier Consultant in adult education: Serge Vallières Coordinator for the DGFD: Jean-Paul Groleau Coordinator for the DFGA: Ronald Côté Photocomposition and layout: Multitexte Plus Translation: Consultation en éducation Zegray Linguistic revision: Kay Flanagan and Leslie Macdonald Translation of updated sections: Claudia de Fulviis Reprint: 2006 © Société de formation à distance des commissions scolaires du Québec All rights for translation and adaptation, in whole or in part, reserved for all countries. Any reproduction, by mechanical or electronic means, including micro-reproduction, is forbidden without the written permission of a duly authorized representative of the Société de formation à distance des commissions scolaires du Québec (SOFAD). Legal Deposit – 2006 Bibliothèque et Archives nationales du Québec Bibliothèque et Archives Canada ISBN 978-2-89493-279-7 Answer Key MTH-4101-2 Equations and Inequalities II TABLE OF CONTENTS Introduction to the Program Flowchart ................................................. 0.4 The Program Flowchart .......................................................................... 0.5 How to Use this Guide ............................................................................ 0.6 General Introduction ............................................................................... 0.9 Intermediate and Terminal Objectives of this Module ......................... 0.10 Diagnostic Test on the Prerequisites ..................................................... 0.13 Answer Key for the Diagnostic Test on the Prerequisites .................... 0.21 Analysis of the Diagnostic Test Results ................................................. 0.27 Information for Distance Education Students ....................................... 0.29 UNITS 1. 2. 3. 4. 5. 6. 7. Graphing a System of Equations ............................................................ 1.1 Solving a System of Equations by Comparison ..................................... 2.1 Solving a System of Equations by Substitution .................................... 3.1 Solving a System of Equations by Elimination Through Addition....... 4.1 Solving a System of Equations: Four Possible Methods ....................... 5.1 Solving Everyday Problems .................................................................... 6.1 Graphing a System of Inequalities ......................................................... 7.1 Final Summary........................................................................................ 8.1 Answer Key for the Final Review ........................................................... 8.11 Terminal Objectives ................................................................................ 8.18 Self-Evaluation Test................................................................................ 8.21 Answer Key for the Self-Evaluation Test .............................................. 8.35 Analysis of the Self-Evaluation Test Results ........................................ 8.49 Final Evaluation...................................................................................... 8.51 Answer Key for the Exercises ................................................................. 8.53 Glossary ................................................................................................... 8.159 List of Symbols ........................................................................................ 8.163 Bibliography ............................................................................................ 8.164 Review Activities ..................................................................................... 9.1 © SOFAD 0.3 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II INTRODUCTION TO THE PROGRAM FLOWCHART Welcome to the World of Mathematics! This mathematics program has been developed for the adult students of the Adult Education Services of school boards and distance education. The learning activities have been designed for individualized learning. If you encounter difficulties, do not hesitate to consult your teacher or to telephone the resource person assigned to you. The following flowchart shows where this module fits into the overall program. It allows you to see how far you have progressed and how much you still have to do to achieve your vocational goal. There are several possible paths you can take, depending on your chosen goal. The first path consists of modules MTH-3003-2 (MTH-314) and MTH-4104-2 (MTH-416), and leads to a Diploma of Vocational Studies (DVS). The second path consists of modules MTH-4109-1 (MTH-426), MTH-4111-2 (MTH-436) and MTH-5104-1 (MTH-514), and leads to a Secondary School Diploma (SSD), which allows you to enroll in certain Gegep-level programs that do not call for a knowledge of advanced mathematics. The third path consists of modules MTH-5109-1 (MTH-526) and MTH-5111-2 (MTH-536), and leads to Cegep programs that call for a solid knowledge of mathematics in addition to other abiliies. If this is your first contact with this mathematics program, consult the flowchart on the next page and then read the section “How to Use This Guide.” Otherwise, go directly to the section entitled “General Introduction.” Enjoy your work! 0.4 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II THE PROGRAM FLOWCHART CEGEP MTH-5112-1 MTH-5111-2 MTH-536 MTH-5104-1 MTH-5103-1 Introduction to Vectors MTH-5109-1 Geometry IV MTH-5108-1 Trigonometric Functions and Equations MTH-5107-1 Exponential and Logarithmic Functions and Equations Optimization II MTH-5106-1 Real Functions and Equations Probability II MTH-5105-1 Conics MTH-5102-1 Statistics III MTH-5101-1 MTH-436 MTH-426 MTH-4110-1 MTH-216 MTH-116 © SOFAD The Four Operations on Algebraic Fractions Sets, Relations and Functions MTH-4108-1 Quadratic Functions MTH-4107-1 Straight Lines II MTH-4106-1 Factoring and Algebraic Functions MTH-4105-1 Exponents and Radicals MTH-4103-1 MTH-4102-1 MTH-4101-2 Complement and Synthesis I MTH-4109-1 MTH-4104-2 MTH-314 Optimization I MTH-4111-2 Trades DVS MTH-416 Complement and Synthesis II MTH-5110-1 MTH-526 MTH-514 Logic Statistics II Trigonometry I Geometry III Equations and Inequalities II MTH-3003-2 Straight Lines I MTH-3002-2 Geometry II MTH-3001-2 The Four Operations on Polynomials MAT-2008-2 Statistics and Probabilities I MTH-2007-2 Geometry I MTH-2006-2 Equations and Inequalities I MTH-1007-2 Decimals and Percent MTH-1006-2 The Four Operations on Fractions MTH-1005-2 The Four Operations on Integers 0.5 You ar e h er e 25 hours = 1 credit 50 hours = 2 credits 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II HOW TO USE THIS GUIDE Hi! My name is Monica and I have been asked to tell you about this math module. What’s your name? Whether you are registered at an adult education center or at Formation à distance, ... Now, the module you have in your hand is divided into three sections. The first section is... I’m Andy. ... you have probably taken a placement test which tells you exactly which module you should start with. ... the entry activity, which contains the test on the prerequisites. 0.6 You’ll see that with this method, math is a real breeze! My results on the test indicate that I should begin with this module. By carefully correcting this test using the corresponding answer key, and recording your results on the analysis sheet ... © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II ... you can tell if you’re well enough prepared to do all the activities in the module. And if I’m not, if I need a little review before moving on, what happens then? In that case, before you start the activities in the module, the results analysis chart refers you to a review activity near the end of the module. I see! In this way, I can be sure I have all the prerequisites for starting. START The starting line shows where the learning activities begin. Exactly! The second section contains the learning activities. It’s the main part of the module. ? The little white question mark indicates the questions for which answers are given in the text. The target precedes the objective to be met. The memo pad signals a brief reminder of concepts which you have already studied. ? Look closely at the box to the right. It explains the symbols used to identify the various activities. The boldface question mark indicates practice exercices which allow you to try out what you have just learned. The calculator symbol reminds you that you will need to use your calculator. ? The sheaf of wheat indicates a review designed to reinforce what you have just learned. A row of sheaves near the end of the module indicates the final review, which helps you to interrelate all the learning activities in the module. FINISH Lastly, the finish line indicates that it is time to go on to the self-evaluation test to verify how well you have understood the learning activities. © SOFAD 0.7 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II There are also many fun things in this module. For example, when you see the drawing of a sage, it introduces a “Did you know that...” It’s the same for the “math whiz” pages, which are designed especially for those who love math. For example. words in boldface italics appear in the glossary at the end of the module... A “Did you know that...”? Yes, for example, short tidbits on the history of mathematics and fun puzzles. They are interesting and relieve tension at the same time. Must I memorize what the sage says? No, it’s not part of the learning activity. It’s just there to give you a breather. They are so stimulating that even if you don’t have to do them, you’ll still want to. And the whole module has been arranged to make learning easier. ... statements in boxes are important points to remember, like definitions, formulas and rules. I’m telling you, the format makes everything much easier. The third section contains the final review, which interrelates the different parts of the module. Great! There is also a self-evaluation test and answer key. They tell you if you’re ready for the final evaluation. Thanks, Monica, you’ve been a big help. I’m glad! Now, I’ve got to run. See you! 0.8 Later ... This is great! I never thought that I would like mathematics as much as this! © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II GENERAL INTRODUCTION MOVING TOWARDS A SOLUTION Ideally detectives would like to find the guilty person in a case quickly, based on the available information: pharmacists or cooks would like to find the exact proportions of the ingredients for their new creation on their first attempt; agronomists would like to know the ideal quantity of fertilizer for a given lot just by looking at it. In short, all of us are looking for quick, easy and definitive solutions! Unfortunately, instant solutions rarely exist. As a result of the vast quantity of information which we must consider in order to solve the numerous problems we encounter, we must interrelate this varied information, arrive at possible solutions and make use of reliable tools to evaluate these solutions. A gardener must judge the quantity of fertilizer which is best for a garden, given the information recorded about the garden in previous years and the results of experiments carried out by agronomists. The gardener must know the method used to dilute products to obtain an appropriate mixture and the exact time when the fertilizer must be spread. To find the solution to growing the best possible plants, he or she must consider all these factors. To reach the objective of this module, you must be able to solve everyday problems by translating the relationships which exist between the givens in a problem using a system of equations or inequalities. You must first master methods for solving these systems algebraically as well as for representing them graphically. The latter is the concrete visualization of information. It allows you to spot the required information and gives an overall view of the possible solutions for a specific situation. © SOFAD 0.9 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II INTERMEDIATE AND TERMINAL OBJECTIVES OF THE MODULE Module MTH-4101-2 consists of seven units and requires fifty hours of study distributed as follows. Each unit covers either an intermediate or a terminal objective. The terminal objectives appear in boldface. Objectives Number of Hours* % (evaluation) 1 4 10% 2 to 5 10 40% 6 8 30% 7 6 20% * Two hours are allotted for the final evaluation. 1. Graphing a System of Equations To solve a system of two equations of the first degree in two variables of the form Ax + By + C = 0 graphically. The coefficients A, B and C are rational numbers ( ). The steps in the solution must be described. 2. Solving a System of Equations by Comparison To solve a system of two equations of the first degree in two variables of the form Ax + By + C = 0 algebraically by applying the method of solving by comparison. The coefficients A, B and C are real numbers ( ). The steps in the solution must be described. 0.10 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 3. Solving a System of Equations by Substitution To solve a system of two equations of the first degree in two variables of the form Ax + By + C = 0 algebraically by applying the method of solving by substitution. The coefficients A, B and C are real numbers ( ). The steps in the solution must be described. 4. Solving a System of Equations by Elimination Through Addition To solve a system of two equations of the first degree in two variables of the form Ax + By + C = 0 algebraically by applying the method of solving by elimination through addition. The coefficients A, B and C are real numbers ( ). The steps in the solution must be described. 5. Solving a System of Equations: Four Possible Methods To solve a system of two equations of the first degree in two variables of the form Ax + By + C = 0 by applying one of these methods: • the graphic method • the algebraic method by comparison • the algebraic method by substitution • the algebraic method by elimination through addition. The coefficients A, B and C are real numbers ( ). The steps in the solution must be described. 6. Solving Everyday Problems To solve word problems which must be expressed as a system of two equations of the first degree in two variables in order to be solved. The situations presented are borrowed from everyday life. The numbers used are rational numbers ( ). The five steps in the solution must be described. © SOFAD 0.11 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 7. Graphing a System of Equations To solve a system of two inequalities of the first degree in two variables of the form Ax + By + C ≤ 0 or of the form Ax + By + C ≥ 0 by applying graphic methods of solution. The coefficients A, B and C are real numbers ( ). 0.12 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II DIAGNOSTIC TEST ON THE PREREQUISITES Instructions 1° Answer as many questions as you can. 2° You may use a calculator. 3° Write your answers on the test paper. 4° Do not waste any time. If you cannot answer a question, go on to the next one immediately. 5° When you have answered as many questions as you can, correct your answers using the answer key which follows the diagnostic test. 6° To be considered correct, answers must be identical to those in the key. For example, if you are asked to describe the steps involved in solving a problem, your answer must contain all the steps. 7° Transcribe your results onto the chart which follows the answer key. It gives an analysis of the diagnostic test results. 8° Do only the review activities listed for each of your incorrect answers. 9° If all your answers are correct, you have the prerequisites to begin working on this module. © SOFAD 0.13 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 1. Calculate the numerical value of the following algebraic expressions. The steps in the solution of the problem and the answer are required. Round your answers to the nearest hundredth, if necessary. a) 8[3(3 + 2 × 23) – 7] – (4 – 2 × 7) ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... b) 23 + 7 × 2 – 7 + 3 – 8 × 2 – 13 + 4 4 ×3+ 2 7(2 × 3 – 5) ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... 0.14 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II c) [0.5(2.4 – 4.2)] ÷ (7.2 + 3.7 ÷ 4.2) ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... 2. a) Using the given tables of values, plot the points corresponding to the ordered pairs described in the Cartesian plane, and graph the lines through these points. y 1 1 x x 0 2 4 5 y 2 4 6 7 x –3 –3 –3 –3 y –1 0 4 5 x –1 0 4 6 y –2 –2 –2 –2 ➀ ➁ ➂ © SOFAD 0.15 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II b) Which of the preceding tables of values contains ordered pairs which satisfy the equation x = y – 2 ? Answer: ................................... 3. For each of the equations below, complete a table of values and graph the corresponding line. ➀ 3x + y = 6 ➁ y=5 ➂ x+3=9 y x ➀ y 1 x ➁ 1 x y x ➂ y 4. Given the algebraic expression 4x + 48, identify 3 a) the variable: .......................................... b) the coefficient: ....................................... c) the inverse of the constant term: ......... d) the inverse of the coefficient: ................ 0.16 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 5. Solve the following equations. A complete solution is required. Round your answers to the nearest hundredth, if necessary. a) 3x – 7 = 2x + 8 ....................................................................................................................... ....................................................................................................................... b) 7x + 4 – 2x = 4x – 3 3 8 ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... c) 4x – 2 = 6x + 2 7 3 ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... © SOFAD 0.17 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II d) 0.5x – 2.4 = 0.2x – 3 0.5 0.7 ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... 6. Using the distributive property, isolate the variable y in the following equations. a) 3(2y – 4) + 10y – 6 = 2(9y + 3) ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... b) 8(2 – 3y) (3 – 4 y)2 = 3 4 ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... ....................................................................................................................... 0.18 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 7. Yolanda earns a gross weekly salary of $404.00. She works 8 hours per day, 5 days a week. If 24% of this amount is withheld each week for various deductions, calculate her annual net salary (52 weeks). ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... © SOFAD 0.19 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 8. Louise and Paul prepare their budget. Louise sets aside 1 of her weekly net 4 1 of his own pay. If Louise's pay for her savings and Paul does as well with 5 and Paul's annual net salaries amount to $l9 825.00 and $20 930.00 respectively, calculate how much money Paul sets aside weekly for his current expenses. ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... 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........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... ........................................................................................................................... 0.20 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II ANSWER KEY FOR THE DIAGNOSTIC TEST ON THE PREREQUISITES 1. a) 8[3(3 + 2 × 23) – 7] – (4 – 2 × 7) 8[3(3 + 46) – 7] – (4 – 14) 8[3(49) – 7] – (– 10) 8[147 – 7] + 10 8[140] + 10 1120 + 10 1130 b) 23 + 7 × 2 – 7 + 3 – 8 × 2 – 13 + 4 4×3+2 7(2 × 3 – 5) 23 + 14 – 7 + 3 – 16 – 13 + 4 12 + 2 7(6 – 5) 37 – 7 + 3 – 3 + 4 14 7(1) 30 + 3 – 7 7 14 33 – 14 14 14 19 or 1 5 14 14 c) [0.5(2.4 – 4.2)] ÷ (7.2 + 3.7 ÷ 4.2) [0.5(– 1.8)] ÷ (7.2 + 0.88) – 0.9 ÷ 8.08 – 0.11 © SOFAD 0.21 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II y 2. a) ➀ • ➁ • • • • • 1 • • 1 • • x • •➂ b) ➀ 3. ➀ y = – 3x + 6 ➁ y=5 ➂ x=6 y ➀ x 0 1 2 y 6 3 0 ➁ ➂ • ••• ➀ x 0 1 • 1 2 ➁ 1 y 5 5 5 x 6 6 6 y 0 1 2 • • • • x ➂ 0.22 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II b) 4 3 4. a) x 5. a) c) – 48 3x – 7 = 2x + 8 3x – 2x = 8 + 7 x = 15 b) 7x + 4 – 2x = 4x – 3 3 8 21x + 96 – 16x = 96x – 72 24 24 24 24 24 21x + 96 – 16x = 96x – 72 21x – 16x – 96x = – 72 – 96 – 91x = – 168 x = – 168 – 91 x = 168 = 24 or 1 11 or 1.85 91 13 13 c) 4x – 2 = 6x + 2 3 7 7(4x – 2) = 3(6x + 2) 28x – 14 = 18x + 6 28x – 18x = 6 + 14 10x = 20 x = 20 10 x= 2 d) 0.5x – 2.4 = 0.2x – 3 0.7 0.5 0.5(0.5x – 2.4) = 0.7(0.2x – 3) 0.25x – 1.2 = 0.14x – 2.1 0.25x – 0.14x = – 2.1 + 1.2 0.11x = – 0.9 x = – 0.9 0.11 x = – 8.18 © SOFAD 0.23 d) 3 4 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 6. a) 3(2y – 4) + 10y – 6 = 2(9y + 3) 6y – 12 + 10y – 6 = 18y + 6 6y + 10y – 18y = 6 + 6 + 12 – 2y = 24 y = 24 –2 y = – 12 b) 8(2 – 3y) (3 – 4y)2 = 4 3 16 – 24y 6 – 8y = 4 3 3(16 – 24y) = 4(6 – 8y) 48 – 72y = 24 – 32y – 72y + 32y = 24 – 48 – 40y = – 24 y = – 24 – 40 y = 3 or 0.6 5 7. • We want to determine Yolanda’s annual net salary. • State the problem in mathematical language. [$404 – ($404 × 24%)] × 52 • Estimate the result. $400.00 – $400 × 25 100 × 50 = [$400 – $100] × 50 = [$300] × 50 = $15 000 • Solve the problem. $404.00 – $404 × 24 100 × 52 = [$404 – $96.96] × 52 = [$307.04] × 52 = $15 966.08 0.24 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II • The result is close to the estimate. • Yolanda’s net annual salary is $15 966.08. 8. • We want to determine how much money Paul sets aside weekly for his current expenses. • State the problem in mathematical language. $20 930 – $20 930 × 1 ÷ 52 5 • Estimate the result. $20 000 – $20 000 × 1 ÷ 50 = ($20 000 – $4 000) ÷ 50 = 5 $16 000 ÷ 50 = $320 • Solve the problem. $20 930 – $20 930 × 1 ÷ 52 = ($20 930 – $4 186) ÷ 52 = 5 $16 744 ÷ 52 = $322 • The result is close to the estimate. • Paul sets aside $322 weekly for his current expenses. © SOFAD 0.25 1 2 3 Answer Key 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II ANALYSIS OF THE DIAGNOSTIC TEST RESULTS Question 1. a) b) c) 2. a) b) 3. 4. a) b) c) d) 5. a) b) c) d) 6. a) b) 7. 8. Answer Correct Incorrect Section Review Page Before Going to Unit(s) 9.2 9.2 9.2 9.3 9.3 9.3 9.4 9.4 9.4 9.4 9.4 9.4 9.4 9.4 9.4 9.4 9.1 9.1 9.19 9.19 9.19 9.25 9.25 9.25 9.36 9.36 9.36 9.36 9.36 9.36 9.36 9.36 9.36 9.36 9.4 9.4 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 1 and 6 1 and 6 • If all your answers are correct, you may begin working on this module. • For each incorrect answer, find the related section listed in the Review column. Do the review activities for that section before beginning the units listed in the right-hand column under the heading Before Going to Unit(s). © SOFAD 0.27 1 2 3 Answer Key 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II INFORMATION FOR EDUCATION STUDENTS DISTANCE You now have the learning material for MTH-4101-2 together with the homework assignments. Enclosed with this material is a letter of introduction from your tutor indicating the various ways in which you can communicate with him or her (e.g. by letter, telephone) as well as the times when he or she is available. Your tutor will correct your work and help you with your studies. Do not hesitate to make use of his or her services if you have any questions. DEVELOPING EFFECTIVE STUDY HABITS Distance education is a process which offers considerable flexibility, but which also requires active involvement on your part. It demands regular study and sustained effort. Efficient study habits will simplify your task. To ensure effective and continuous progress in your studies, it is strongly recommended that you: • draw up a study timetable that takes your working habits into account and is compatible with your leisure time and other activities; • develop a habit of regular and concentrated study. © SOFAD 0.29 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II The following guidelines concerning the theory, examples, exercises and assignments are designed to help you succeed in this mathematics course. Theory To make sure you thoroughly grasp the theoretical concepts: 1. Read the lesson carefully and underline the important points. 2. Memorize the definitions, formulas and procedures used to solve a given problem, since this will make the lesson much easier to understand. 3. At the end of an assignment, make a note of any points that you do not understand. Your tutor will then be able to give you pertinent explanations. 4. Try to continue studying even if you run into a particular problem. However, if a major difficulty hinders your learning, ask for explanations before sending in your assignment. Contact your tutor, using the procedure outlined in his or her letter of introduction. Examples The examples given throughout the course are an application of the theory you are studying. They illustrate the steps involved in doing the exercises. Carefully study the solutions given in the examples and redo them yourself before starting the exercises. 0.30 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Exercises The exercises in each unit are generally modelled on the examples provided. Here are a few suggestions to help you complete these exercises. 1. Write up your solutions, using the examples in the unit as models. It is important not to refer to the answer key found on the coloured pages at the end of the module until you have completed the exercises. 2. Compare your solutions with those in the answer key only after having done all the exercises. Careful! Examine the steps in your solution carefully even if your answers are correct. 3. If you find a mistake in your answer or your solution, review the concepts that you did not understand, as well as the pertinent examples. Then, redo the exercise. 4. Make sure you have successfully completed all the exercises in a unit before moving on to the next one. Homework Assignments Module MTH-4101-2 contains three assignments. The first page of each assignment indicates the units to which the questions refer. The assignments are designed to evaluate how well you have understood the material studied. They also provide a means of communicating with your tutor. When you have understood the material and have successfully done the pertinent exercises, do the corresponding assignment immediately. Here are a few suggestions. 1. Do a rough draft first and then, if necessary, revise your solutions before submitting a clean copy of your answer. © SOFAD 0.31 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 2. Copy out your final answers or solutions in the blank spaces of the document to be sent to your tutor. It is preferable to use a pencil. 3. Include a clear and detailed solution with the answer if the problem involves several steps. 4. Mail only one homework assignment at a time. After correcting the assignment, your tutor will return it to you. In the section “Student’s Questions”, write any questions which you may wish to have answered by your tutor. He or she will give you advice and guide you in your studies, if necessary. In this course Assignment 1 is based on units 1 to 5. Assignment 2 is based on units 6 and 7. Assignment 3 is based on units 1 to 7. CERTIFICATION When you have completed all the work, and provided you have maintained an average of at least 60%, you will be eligible to write the examination for this course. 0.32 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II START UNIT 1 GRAPHING A SYSTEM OF EQUATIONS 1.1 SETTING THE CONTEXT A Sticky Story Mr Fixit has been running the family maple sugar business for the last few years. One of his barrels, the same age as he is, is filled with 40 litres of maple sap. Unfortunately, 2 litres of this precious liquid are escaping per hour through a recently formed crack at the bottom of the barrel. Mr Fixit quickly places another barrel beneath the first. The spill is now being picked up by the second barrel, which is in good condition and already contains 10 litres of maple sap. © SOFAD 1.1 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Fig. 1.1 Mr Fixit saves the day Mr Fixit learned in a mathematics course that many everyday situations can be translated into algebraic expressions. He begins to wonder how the levels of sap in the two barrels will change and at which point the two barrels will contain the same amount. To find the answer, the situation can be translated into two equations of the first degree, where • x represents the time elapsed in hours since the start of the leak • y represents the volume of sap in litres, in each barrel. An equation is a sentence formed by two mathematical expressions containing one or more variables and related by the = sign. For example: 5x + 4 = 7 is an equation of the first degree. 1.2 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Let x be the number of hours since the start of the leak. • The first equation deals with the barrel which is being emptied. Let 2x be the volume of sap lost, since 2 L are lost per hour, y the volume of sap when the barrels contain the same amount of sap, 40 L the volume of sap at the start. Then, ➀ 2x + y = 40. • The second equation deals with the second barrel, which is being filled. Let 2x be the volume of sap saved, y the volume of sap when the barrels contain the same amount of sap, 10 L the volume of sap at the start. Then, ➁ 2x + 10 = y. N.B. You will learn how to translate this type of situation into equations in Unit 6. For the moment, concentrate on what Mr Fixit is leading up to. The two variables x and y are related to each other, that is, the volume of sap y in one barrel depends on the time elapsed x since the start of the leak. You are therefore faced with two equations dealing with the same context; since these two barrels cannot be separated, these two equations cannot be separated. It is therefore the set of both these equations which represents the situation at hand. This set is called a system of equations. A system of equations of the first degree is a set of equations which must be solved simultaneously. © SOFAD 1.3 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II ➀ 2x + y = 40 The equations ➁ 2x + 10 = y represent a system of equations. You must find which values of x and y satisfy these two equations simultaneously (at the same time). To do so, equip yourself with a pencil, ruler and graph paper and solve this problem graphically. To reach the objective of this unit, you should be able to graph a system of equations of the first degree in two variables, to specify the relative positions of the two lines and state the solution(s) of the system. The first step consists in graphing each of the equations in the system after having completed a table of values. To complete a table of values easily, it is recommended that you isolate one of the two variables. Take Mr Fixit's equations and isolate y to obtain the form: y = mx + b. You therefore have: ➀ 2x + y = 40 ➁ 2x + 10 = y y = – 2x + 40 y = 2x + 10 The original system has thereby been converted into an equivalent system of equations: ➀ y = – 2x + 40 ➁ y = 2x + 10 1.4 © SOFAD 1 Answer Key 2 3 MTH-4101-2 ? Equations and Inequalities II Then complete a table of values for each of these equations. ➀ ➁ x y = – 2x + 40 x 0 – 2(0) + 40 = 40 0 2 – 2(2) + 40 = 36 2 4 – 2(4) + 40 = 32 4 8 – 2(8) + 40 = 24 6 y = 2x + 10 10 10 No doubt you obtained the ordered pair (10, 20) for equation ➀ and the ordered pairs (0, 10), (2, 14), (4, 18), (6, 22) and (10, 30) for equation ➁. Take the ordered pair (4, 32) from equation ➀. This ordered pair is a solutionpair of equation ➀, since if x is replaced by 4 and y by 32 in this equation, the equation is satisfied or remains true. In effect, y = – 2x + 40 becomes 32 = – 2(4) + 40 32 = – 8 + 40 32 = 32. An ordered pair is a solution-pair of an equation of the first degree in two variables if, after substitution, the ordered pair satisfies the equation or expresses a true statement. Let us leave Mr Fixit's calculations for a moment. Before graphing these equations, you need some practice in converting them to the form y = mx + b and in preparing tables of values for equations in two variables. © SOFAD 1.5 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Exercise 1.1 1. Transform each of these systems of equations to a system of the form: ➀ y = m1x + b1 ➁ y = m2x + b2 a) ➀ 3x – 6y – 12 = 0 ➁ 3x – 6y + 6 = 0 b) ➀ 8x – 2y + 3x = 5 + 12x – 4y ➁ 10x + y + 3 = 5 – 3y + 10x c) ➀ 3x = 4y ➁ x= 1.6 2y + 1 3 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II d) ➀ 3(x – 1) + 2(y + 3) = 8 ➁ 4x – (y – 6) = 9 2. Complete the two tables of values for the following system of equations. ➀ 10x + y + 27 = 10y + x ➁ x+y=7 ➀ ➁ ➀ x © SOFAD ➁ y x 1.7 y 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Since you now know how to derive solution-pairs for an equation, move on to the next step, that of graphing the equation. Mr Fixit must now transfer the solution-pairs for each equation in his system to the same Cartesian plane. The graphs of these equations are lines. The procedure used is summarized below: Mr Fixit has to: 1. Establish his system of equations. ➀ 2x + y = 40 ➁ 2x + 10 = y 2. Transform these equations to the form y = mx + b. ➀ y = – 2x + 40 ➁ y = 2x + 10 3. Complete the tables of values. x y x y 0 40 0 10 2 36 2 14 4 32 4 18 8 24 6 22 10 20 10 30 N.B. Each table of values lists a set of solution-pairs to be plotted in the Cartesian plane. A minimum of 3 ordered pairs per equation is required to graph these lines correctly. 1.8 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Volume of sap in a barrel in litres 4. Graph each of these equations. y 60 50 40• (0, 40) (2, 36) • (4, 32) • 30 + – 2x 2 4 6 1 (10, 30) • • (8, 24)(10, 20) • (6, 22) 20 • •(4, 18) •(2, 14) 10 • (0, 10) 0 ➁ y 0= 8 2x +y =4 Scale used: x-axis 0.5 cm ^ = 1h y-axis ^ 5L 0.5 cm = 0 ➀ x 10 Time elapsed in hours since the start of the leak Fig. 1.2 Intersecting lines representing Mr Fixit's system of equations ? Do these two lines meet at a point? ................................................................. ? What is this point called in mathematical language? ........................................................................................................................... In effect, these two lines meet at a point called the point of intersection. This point is common to the two lines and it is called the solution-pair of the system of equations. The graphic solution of a system of equations consists in determining the coordinates of the point that is common to the two lines of the system, if there is a point of intersection. © SOFAD 1.9 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II We will now return to Mr Fixit, who is completing the last step in his Volume of sap in litres investigation. y 60 50 10 lled x+ g fi n i e el b arr 2 y= 40 b (7.5, 25) 30 • 20 bar rel 10 0 2 4 6 8 y= – 2x bei +4 ng 0 em pti ed Scale used: x-axis 0.5 cm ^ = 1h y-axis ^ 5L 0.5 cm = x 10 Time elapsed in hours Fig. 1.3 Mr Fixit's graph From the graph representing his system of equations, Mr Fixit can "read" the coordinates of the point of intersection of the two lines. This pair of coordinates (7.5, 25) is the solution-pair of the system since it satisfies both equation ➀ and equation ➁ simultaneously. It is also the only solution-pair of the system given that it is the only place where the two lines intersect, that is, the only place where the x and y variables take the same values in both equations simultaneously. He can therefore state, proof in hand, that the two barrels will contain the same amount of sap, namely 25 litres, after 7 1 hours have elapsed. This is what the 2 ordered pair (7.5, 25) indicates. 1.10 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Did you know that graphic, graph or graphing derive from the same Greek verb graphein, which means to write? Graphs are representations or illustrations of data in a plane, that is, a form of display which provides information. They are used in fields as varied as medicine, economics and weather forecasting. For example, an electrocardiogram is a graphic record (graph) of the electrical activity (electro) of the heart (cardio). R P T Q Normal electrocardiogram P wave, atrial depolarization; QRS wave, ventricular depolarization; T wave, ventricular repolarization. Fig. 1.4 S Electrocardiogram The daily volume of stock market transactions in a given period, as summarized in the graph in Figure 1.5, is another example of the use of graphs. © SOFAD 1.11 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II DAILY VOLUME OF TRANSACTIONS: 5 492 000 13 000 12 000 11 000 10 000 9 000 8 000 7 000 6 000 5 000 4 000 3 000 2 000 FEBRUARY MARCH APRIL Fig. 1.5 Transactions on the stock market *Source: La Presse, April 16 1988 Another type of graph, a circle graph, is used to represent the portions of a family budget in the form of "pie slices." It is in current use in written as well as electronic media. culture and leisure C hotel, restaurants H dressing transport food F D T He health, hygiene Ho F: 28.4% D: 10.0% H: 20.7% He: 11.8% T: 10.3% C: 8.8% Ho: 10.0% ——— 100% housing Fig. 1.6 A typical family budget 1.12 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Exercise 1.2 1. Given the system of equations ➀ 5x – 3y = 14 and ➁ 2x + y = 10. a) Determine at least 3 solution-pairs for each equation by completing a table of values for each. ➀ ➁ ➀ x ➁ y x y b) In the Cartesian plane which follows, plot the points corresponding to these pairs and graph the 2 lines representing this system of equations. y 1 1 © SOFAD 1.13 x 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II c) What are the coordinates of the point of intersection of the two lines? ................................. d) Demonstrate that the ordered pair corresponding to the point of intersection is a solution-pair for each of the equations in the system. ➀ 5x – 3y = 14 ➁ 2x + y = 10 To solve a system of equations of the first degree in two variables graphically: 1. Transform each of the equations in the system to the form y = mx + b. 2. Determine at least 3 solution-pairs for each equation and complete a table of values. 3. Graph each equation in the same Cartesian plane. 4. Identify the point of intersection of the two lines, if there is one. 5. Determine the solution of the system of equations. N.B. It is recommended that you verify the solution of the system by substituting the values obtained for the x and y variables in the original equations. Is there always only one solution to a system of equations? Interesting question! However, the answer is not obvious. Look at the following examples. 1.14 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Example 1 Given the following system of equations: ➀ 2x – y = – 5 ➁ 2x – y = 3. 1. Transform the equations in the system to the form y = mx + b. ➀ 2x – y = – 5 ➁ 2x – y = 3 – y = – 2x – 5 – y = –2x + 3 y = 2x + 5 y = 2x – 3 2. Determine at least 3 solution-pairs for each equation and complete the tables of values. ➀ © SOFAD ➁ x y x y –2 1 0 –3 0 5 2 1 1 7 5 7 1.15 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 3. Graph each equation in the same Cartesian plane. y •➀ •➁ • • • 1 1 x • Fig. 1.7 Parallel lines representing the system of equations 2x – y = – 5 and 2x – y = 3 4. Identify the point of intersection of the two lines, if there is one. There is no point of intersection since the two lines are parallel. 5. Determine the solution of the system of equations. This system has no solution since there is no point common to the two lines. Therefore, there are systems for which no common solution exists. These systems are composed of distinct parallel lines. Now take a look at another case where a unique solution cannot be found. 1.16 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II Example 2 Given the system of equations: y =1 ➀ x + 2 6 ➁ x+ y =2 3 1. Transform the equations in the system to the form y = mx + b. y ➀ x + =1 2 6 3x + y = 6 6 6 6 3x + y = 6 y =2 3 3x + y = 6 3 3 3 3x + y = 6 ➁ x+ y = – 3x + 6 y = – 3x + 6 As you can see, these two equations are identical. 2. Determine at least 3 solution-pairs for each equation and complete the tables of values. N.B. Only one table of values is needed here since the 2 equations in the system are identical. ➀ and ➁ © SOFAD x y 0 6 1 3 2 0 1.17 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 3. Graph each equation in the same Cartesian plane. y ➀ and ➁ • • 1 1 • x Fig. 1.8 Coinciding lines representing the system of equations y y ➀ x + = 1 and ➁ x + =2 2 6 3 4. Identify the point of intersection of the two lines, if there is one. There are an infinite number of points of intersection since these two lines coincide. 5. Determine the solution of the system of equations. This system has an infinite number of solutions since the two lines are superimposed. Thus, systems exist for which there are an infinite number of solutions. These systems are composed of coinciding lines. Now for a summary! 1.18 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II In solving a system of equations of the first degree in two variables graphically, three situations can occur: 1. The two lines can intersect and, in this case, the solution of the system is a unique solution-pair; 2. The two lines can be parallel and distinct and, in this case, there is no solution; 3. The two lines can coincide and, in this case, there exist an infinite number of solutions. Intersecting lines Parallel and distinct lines y Coinciding lines y x y x x Fig. 1.9 Various types of lines that result from systems of equations Now see whether you can identify these lines in the following practice exercises. © SOFAD 1.19 1 Answer Key 2 3 MTH-4101-2 ? Equations and Inequalities II 1.2 PRACTICE EXERCISES 1. Transform each of the following equations to the form y = mx + b. a) x + y =6 2 c) x – 1 = y 2 y–2 b) x – 2 – = –2 2 3 d) 0.15x + 0.3y = 1.2 e) 3(x – 3) + 4 = 5(y – 2) + 3x 1.20 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 2. Solve the following systems of equations of the first degree in two variables graphically by following the procedure presented in this unit. Determine the solution as well as the types of lines which represent each system. a) ➀ 2x – 5y = 20 ➁ 3x + 2y = 11 1. ➀ ➁ 2. Tables of values 3. Graph y ➀ x y x ➁ x y 4. ............................................................................................................... 5. • Solution-pair: ................................................................................... • Type of lines: ................................................................................... © SOFAD 1.21 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II b) ➀ 22x – 6y = 24 ➁ 6y –15x = – 3 1. ➀ ➁ 2. Tables of values 3. Graph y ➀ x y ➁ x x y 4. ............................................................................................................... 5. • Solution-pair: ................................................................................... • Type of lines: ................................................................................... 1.22 © SOFAD 1 Answer Key 2 3 MTH-4101-2 c) ➀ x + 5 ➁ x + 3 Equations and Inequalities II y =7 2 y =7 4 1. ➀ ➁ 2. Tables of values 3. Graph ➀ x y y ➁ x y x 4. ............................................................................................................... 5. • Solution-pair: ................................................................................... • Type of lines: ................................................................................... © SOFAD 1.23 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II d) ➀ – 0.5x + y – 3 = 0 ➁ x – 2y + 6 = 0 1. ➀ ➁ 2. Tables of values 3. Graph ➀ x y y x ➁ x y 4. ............................................................................................................... 5. • Solution-pair: ................................................................................... • Type of lines: ................................................................................... 1.24 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II e) ➀ x + y – 2 = 0 2 ➁ x +y–5 =0 2 1. ➀ ➁ 2. Tables of values 3. Graph ➀ x y y ➁ x x y 4. ............................................................................................................... 5. • Solution-pair: ................................................................................... • Type of lines: ................................................................................... © SOFAD 1.25 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II f) ➀ 4x + y = 19 ➁ y=5 1. ➀ ➁ 2. Tables of values 3. Graph y ➀ x y x ➁ x y 4. ............................................................................................................... 5. • Solution-pair: ................................................................................... • Type of lines: ................................................................................... 1.26 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II g) ➀ x = 4 ➁ 2y = 6 1. ➀ ➁ 2. Tables of values 3. Graph ➀ x y y ➁ x x y 4. ............................................................................................................... 5. • Solution-pair: ................................................................................... • Type of lines: ................................................................................... © SOFAD 1.27 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 3. In each case, identify among the 3 given systems of equations the system which corresponds to the graph on the right. Give your answer by recording the letter corresponding to your choice in the space provided at the bottom of the list. y =3 a) A: ➀ 2x + 5 3 ➁ x – 2y = 4 B: ➀ – 6x + ➁ 2x – y = – 29 6 y =8 3 C: ➀ 7x + 2y = 31 2 ➁ x – 5y = – 23 3 y (6, 5) • (–9, 4) • 1 x 1 • (10, –2) The graph in the figure above corresponds to the system of equations described in ............................ . 1.28 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II b) A: ➀ 0.5x + 2y = 19 B: ➀ x – 2 ➁ 1x– 1y = 1 ➁ x + 7 5 7 y = 11 5 2 y =6 2 C: ➀ x – y =0 10 7 ➁ x – y = –3 y (0, 12) • • (7, 10) 1 1 • (3, 0) x The graph in the figure above corresponds to the system of equations described in ............................ . © SOFAD 1.29 1 Answer Key 2 3 MTH-4101-2 1.3 Equations and Inequalities II SUMMARY ACTIVITY 1. Complete the following sentences by writing the missing term(s) in the blank spaces. A system of equations of the first degree in two variables is a set of at least .................... equations of the first degree in ................... variables for which you wish to determine the common ....................... . This system is represented graphically with as many ................... as there are equations. The solution of the system is the point ................ to these lines. There are ........... possible types of systems. A system of ................... lines has a unique solution. In this case, the solution is given by a solution- ............................. representing the point which is ...................... to the two lines in the graph. A system of .................. and ................ lines does not have a solution. A system of ..................... and .................... lines has an infinite number of common ............... . In this case the solution comprises the set of ............... the points that are common to these ................. lines. 1.30 © SOFAD 1 Answer Key 2 3 MTH-4101-2 Equations and Inequalities II 2. Complete the flowchart of the steps involved in solving a system of equations of the first degree in two variables graphically by describing each of the operations performed in the lefthand column. ➀ x+y–5=0 1. ➁ 9x – 2y – 23 = 0 ➁ y = 9x – 23 2 2 ➀ y = –x + 5 ➀ 2. ➁ x y x y –3 8 0 – 23 2 0 5 2 4 1 –5 2 13 2 4 y 3. (– 3, 8)• • 4, 13 2 (0, 5) • 2 • (4, 1) 2 • ➁ • x 2, – 5 2 0, – 23 2 ➀ 4. These two lines intersect at point (3, 2). 5. Solution: (3, 2) Type of lines: intersecting © SOFAD 1.31 1 Answer Key 2 3 MTH-4101-2 1.4 Equations and Inequalities II THE MATH WHIZ PAGE The Hare and the Tortoise, a Well-known Fable You no doubt have heard the famous fable of the hare and the tortoise? Here is a modern version of it. The hare and tortoise are getting ready for a big race. Sure of himself, the hare gives his friend a 2 000 metre lead; he knows that he is much faster than the tortoise. The tortoise only advances at a rate of 50 m/min while the hare moves at 350 m/min. The following table of values shows their respective positions. Hare: Tortoise: time in min 0 2 distance covered in m 0 700 time in min 0 2 2 000 2 100 distance covered in m 4 4 When will the hare overtake the tortoise? Complete the table of values below and use the Cartesian plane which follows to determine the time required! 1.32 © SOFAD 1 Answer Key 2 3 Distance in metres MTH-4101-2 Equations and Inequalities II y Scale used: x-axis ^ 0.5 min 0.5 cm = y-axis 0.5 cm ^ = 100 m Time in minutes x Fig. 1.10 The hare and the tortoise What are the coordinates of the point of intersection? ...................... How far from the start will the hare overtake the tortoise? .............. © SOFAD 1.33