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Chapter 7 Formulas
Hint: Simplify all ratios/fractions ā€“ make sure they have the same units!
Ways to prove Triangles are Similar (same angles, sides are proportional)
AA~, SAS~, SSS~
Midsegment = half of the base
Ratio of sides is the SAME as ratio of perimeters
How to find scale factor: find two sides that are corresponding and put one value over the other,
then simplify!
Chapter 8 Area Formulas
Sum of the interior angles of a polygon: (š’ āˆ’ šŸ) āˆ™ šŸšŸ–šŸŽ°
Area of a Rectangle: š‘ā„Ž
Area of a Square:
Area of a parallelogram: š‘ā„Ž
Area of a rhombus:
Sum of the exterior angles: 360 °
š‘‘ 1 š‘‘2
2
Arc length=
Area of a circle: šœ‹š‘Ÿ 2
Area of a sector =
aāˆ™p
2
Area of a Trapezoid:
š’Žš’†š’‚š’”š’–š’“š’† š’š’‡ š’„š’†š’š’•š’“š’‚š’ š’‚š’š’ˆš’š’†
āˆ™
šŸ‘šŸ”šŸŽ
Circumference of a circle: 2Ļ€r or Ļ€d
Area of a regular polygon:
Area of a Triangle:
š‘ 2
2Ļ€r
š’Žš’†š’‚š’”š’–š’“š’† š’š’‡ š’„š’†š’š’•š’“š’‚š’ š’‚š’š’ˆš’š’†
āˆ™
šŸ‘šŸ”šŸŽ
šœ‹š‘Ÿ 2
Perimeter: š‘› āˆ™ š‘ 
Chapter 9 Surface Area & Volume Formulas
B = AREA of the base
SURFACE AREA FORMULAS
P = PERIMETER of the base
VOLUME FORMULAS
Prism: 2B + Ph
Prism: Bh
Cylinder: 2šœ‹š‘Ÿ 2 + 2šœ‹š‘Ÿā„Ž
Cylinder: šœ‹š‘Ÿ 2 ā„Ž
1
1
Pyramid: B + 2 š‘ƒš‘™
Pyramid: 3 šµā„Ž
Cone: šœ‹š‘Ÿ 2 + šœ‹š‘Ÿš‘™
Cone: šœ‹š‘Ÿ 2 ā„Ž
Sphere: 4šœ‹š‘Ÿ 2
Sphere: 3 šœ‹š‘Ÿ 3
1
3
4
š‘ā„Ž
2
ā„Ž(š‘1 +š‘2 )
2
Chapter 10 Formulas
BELOW ARE THE PERFECT SQUARES
1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225
Pythagorean Theorem: š‘Ž2 + š‘ 2 = š‘ 2 Use for finding sides of right triangles
45Ėš-45Ėš-90Ėš triangle:
HYPOTENUSE = leg ā€¢ āˆš2
š‘„āˆš 2
30Ėš- 60Ėš - 90Ėš triangles
Hypotenuse = 2 ā€¢ short leg
Long leg = short leg ā€¢ āˆš3
TRIGONOMETRY for RIGHT Triangles!
SOH
CAH
š’š’‘š’‘š’š’”š’Šš’•š’†
š¬š¢š§ šœ½ = š’‰š’šš’‘š’š’•š’†š’š’–š’”š’†
š’‚š’…š’‹š’‚š’„š’†š’š’•
šœšØš¬ šœ½ = š’‰š’šš’‘š’š’•š’†š’š’–š’”š’†
TOA
š’š’‘š’‘š’š’”š’Šš’•š’†
š­ššš§ šœ½ = š’‚š’…š’‹š’‚š’„š’†š’š’•
Use the inverse functions to find ANGLES
š’š’‘š’‘š’š’”š’Šš’•š’†
Ī˜ = sin-1(š’‰š’šš’‘š’š’•š’†š’š’–š’”š’†)
š’‚š’…š’‹š’‚š’„š’†š’š’•
Ī˜ = cos-1(š’‰š’šš’‘š’š’•š’†š’š’–š’”š’†)
š’š’‘š’‘š’š’”š’Šš’•š’†
Ī˜ = tan-1(š’‚š’…š’‹š’‚š’„š’†š’š’•)
CHAPTER 11 Formulas
A
x°
Pythagorean
Theorem
š‘Ž2 + š‘ 2 = š‘ 2
r
Semicircle=180
If hyp is the diameter
Then angle = 90
Opposite angles
add up to 180
ANGLE RELATIONSHIPS
Angle ON Circle
Central Angle
1
angle = arc
Arc Length Formula
x°
B arc length of AB = 360° ā€¢ 2Ļ€r
1
angle = arc
angle = arc
2
2
Angle INSIDE Circle
1
angle = (arc + arc)
2
Angle OUTSIDE Circle
1
angle = 2 (large arc ā€“ small arc)
SEGMENT RELATIONSHIPS
aāˆ™b=cāˆ™d
b(a + b) = d(c + d)
a2 = c(b + c)
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