Download Mechanical Mobility and Impedance - FEIS

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project

Document related concepts
no text concepts found
Transcript
Mechanical Mobility and
Impedance
Mike Brennan
UNESP, Ilha Solteira
São Paulo
Brazil
Mechanical Mobility and Impedance
• The response of a structure to a harmonic force can be expressed
in terms of its mobility or impedance
At frequency ω the velocity can
be written in complex notation
v(t) = Vejωt
F V
General linear
system
The mobility is defined as
Mobility =
V ( jω )
F ( jω )
V is the complex amplitude.
Similarly for the force f(t) = Fejωt
The impedance is defined as
Impedance =
F ( jω )
V ( jω )
• If the force and velocity are at the same point this is a ‘point’ mobility
• If they are at different points it is a ‘transfer’ mobility
Note that both mobility and impedance are frequency domain quantities
Frequency Response Functions (FRFs)
Accelerance =
Acceleration
Force
Velocity
Mobility =
Force
Displacement
Receptance =
Force
Apparent Mass =
Impedance =
Force
Acceleration
Force
Velocity
Force
Dynamic Stiffness =
Displacement
Mobility and Impedance Methods
• The total response of a set of coupled components can be expressed
in terms of the mobility of the individual components
• In the simplest case each component has two inputs (one at each end)
which permit coupling
F1
F2
General linear
system
V1
V2
• The two parameters at each input point are force, F, and velocity, V.
Simple Idealised Elements
• Spring
k
f1
x1
f2
x
x2
f1 = k ( x1 − x2 )
f2 = k ( x2 − x1 )
f1 = −f2
• no mass
• force passes through
it unattenuated
Assume f = Fe jωt and x = Xe jωt
Also, block one end so that x2 = 0
k
F
So
F = kX
KV
V
then F =
Because X =
jω
jω
So the impedance of a spring is
given by
Zk =
F
k
=
V
jω
Note that the force is in quadrature with the
velocity. Thus a spring is a reactive
element that does not dissipate energy
Simple Idealised Elements
• Viscous damper
c
f1
v1
c
F
f2
v2
f1 = c (v1 − v 2 )
f2 = c (v 2 − v1 )
f1 = −f2
• no mass or elasticity
• force passes through
it unattenuated
Assume f = Fe jωt and v = Ve jωt
Also, block one end so that v 2 = 0
V
So
F = cV
So the impedance of a damper is
given by
Zc =
F
=c
V
Note that the force is in phase with the
velocity. Thus a damper is a resistive
element that dissipates energy
Simple Idealised Elements
• Mass
f1
f2
m
xɺɺ
f1 + f2 = mxɺɺ
f2 = mxɺɺ − f1
• rigid
• force does not pass
through it unattenuated
ɺɺ jωt
Assume f = Fe jωt and xɺɺ = Xe
Also, set one end to be free
so that f2 = 0
F
m
ɺɺ
X
So
ɺɺ
F = mX
ɺɺ = jωV then F = j ω mV
Because X
So the impedance of a mass is
given by
Zm =
F
= jωm
V
Note that the force is in quadrature with the
velocity. Thus a mass is a reactive
element that does not dissipate energy
Impedances of Simple Elements - Summary
• Spring Zk =
k
− jk
=
jω
ω
• Damper Zc = c
• Mass Zm = jω m
Zm
Zk
Zc
Re
Log |impedance|
Im
Zm
Zc
Zk
Log frequency
Mobilities of Simple Elements - Summary
• Spring Yk =
jω
k
• Damper Yc =
1
−j
1
Y
=
=
• Mass m
jωm ωm
c
Yk
Ym
Yc
Re
Log |mobility|
Im
Yk
Yc
|Ym|
Log frequency
Mobility and Impedance of Simple
Elements
• Can define ‘the impedance’ of a
spring in terms of the relative
velocity of the two ends.
• Can only define ‘the mobility’ of
a spring if one end is blocked.
• Can define ‘the impedance’ of a
damper in terms of the relative
velocity of the two ends.
• Can only define ‘the mobility’ of
a damper if one end is blocked.
• Can only define ‘the impedance’
of a mass if one end is free.
• Can define ‘the mobility’ of a
mass in terms of the sum of the
forces at the two ends.
(velocity at both ends is same).
(force at both ends is same).
Examples of impedance / mobility
mass
F = mXɺɺ Zmass = j ωm
− jk
spring
F = kX Z spring =
damper
F = cXɺ Z damper = c
infinite beam
infinite plate
ω
−j
Ymass =
ωm
jω
Yspring =
k
1
Ydamper =
c
1/ 4
3/ 4
Z beam = 2(1 + j )
ω 1/ 2(EI )(
ρA )
Z plate = 8h
2
Eρ
12(1 − ν 2 )
= 2.3c L ρh 2
Area A, second moment of area I, thickness h, Young’s modulus E, density ρ, Poisson’s
ratio ν
c L = E / ρ(1 − ν 2 )
11
Notes on impedance / mobility
•
Real part of point impedance (or mobility) is always
positive (dissipation). Imaginary part can be positive
(mass-like) or negative (spring-like).
•
Infinite plate impedance is real and independent of
frequency (equivalent to a damper).
•
Beam impedance has a damper part and a mass part,
both frequency dependent.
•
Impedance/mobility of a finite structure tends to that
of the equivalent infinite structure at high frequency
and/or high damping.
12
Related documents