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TO FIND THE SQUARE OF ANY TWO DIGIT NUMBER 1. The Square of a number ending in 5 may be formulated as follows: Ex:1 Square of 25 The number next to 2 is 3, so 2 ∗ 3 = 6 The Square of 5 is 25 So, The Square of 25 is 625 Ex:2 Square of 45 The number next to 4 is 5, so 4 ∗ 5 = 20 The Square of 5 is 25 So, The Square of 45 is 2025 Hence, to find the square of any two numbers ending in 5 is to multiply the preceding digit by the consecutive number and just put 25 to its side. 2. The Square of any number ending in 0 may be formulated as follows: Ex:1 Square of 30 Double the 0 ---- 00 Take the number in front of 0 i.e. 3 – square it. i.e. 3 ∗ 3 = 9 Put the doubled 0 along with 9 i.e. 900 So, The Square of 30 is 900. Ex:2 Square of 60 Double the 0 ---- 00 Take the number in front of 0 i.e. 6 – square it. i.e. 6 ∗ 6 = 36 Put the doubled 0 along with 36 i.e. 3600 So, The Square of 60 is 3600. Hence, to find the square of any two digit numbers ending in 0 is to multiply the number in front of 0, by itself i.e. square it and just place 00 to its side TO FIND THE SQUARE OF ANY NUMBER Number Square of number 0 0 1 1 Difference 1 3 2 4 5 3 9 7 4 16 9 5 25 6 36 7 49 11 15 8 64 17 9 81 19 10 100 21 11 121 23 12 144 25 13 169 27 14 196 29 15 225 31 16 256 Hence the square of one number is different from the square of another only by a odd number. Square of 6 is 36 Square of 7 is 49 Hence the difference between the square is 13 which is a odd number, Thus, odd number 13 can be derived directly by adding 5 and 7 which is two consecutive number. Ex:1 Square of 68 We know that square of 70 is 4900 682 137 (68 + 69) 692 139 (69 + 70) 70 2 Hence, the odd number existing between 68 and 70 square is 137 and 139 Hence, by subtracting the odd number we get the square of 68. i.e. 4900 – (137 +139) = 4900 – 276 =4624 Ex:2 Square of 69 We know that square of 70 is 4900 692 139 (69 + 70) 2 70 Hence, the odd number existing between 69 and 70 is 139 Hence, by subtracting the odd number we get the square of 69. i.e. 4900 –139 = 4761 Ex:3 Square of 67 We know that square of 65 is (6 * 7 ) 25=4225 652 131 (65 + 66) 662 133 (66 + 67) 67 2 Hence, the odd number existing between 65 and 67 square is 131 and 133 Hence, by adding the odd numbers to 65 square i.e. 4225 we get the square of 67. i.e. 4225 + (131 +133) = 4900 + 264 =4487 Ex:4 Square of 66 We know that square of 65 is (6 * 7 ) 25=4225 652 131 (65 + 66) 672 Hence, the odd number existing between 65 and 66 is 131 Hence, by adding the odd number to 65 square i.e. 4225+131 = 4356 The method of finding can be resolved to a formula: Square of 27 252 = 625 = 252 + [ (2 * 25) + 1] + [ (2*25) + 3 ] Let the nearest chosen number be N = N2 + [ (2N) + 1] + [ (2N) + 3 ] The rule can be extended for any number of items. Square of 42 Chosen Number is 40(i.e. N=40) its square is 402 = 1600. = N2 + [ (2N) + 1] + [ (2N) + 3 ] = 402 + [ (2 * 40) + 1] + [ (2*40) + 3 ] = 1600 + 81 +83 = 1600 +164 =1764 Square of 78 Chosen Number is 75(i.e. N=75) its square is 752 = 5625. = N2 + [(2N) + 1] + [(2N) + 3] + [(2N) + 5] = 752 + [(2 * 75) + 1] + [(2*75) + 3] + [(2*75) + 5] = 5625 + [151] + [153] + [155] = 5625 + 459 = 6084 This can be still simplified as 5625 + 3(150) + (1+3 +5) 5625 +3(150) + 32 Square of 78 Let the difference between the chosen number and given number be taken as K Let the given number be C (i.e. 78) C = 78 Let the chosen number be N (i.e. 75) N = 75 Let the difference between given number and chosen number be K (i.e. 3) K = 3 K=C – N C2 = N2 + K * 2N + Given number chosen number 782 752 = This is nothing but K2 Difference between given & chosen + 3 * 2 * 75 + a2 + 2ab + b2 = (a+b)2 @@****@@@^^^&^^^^^^%%% 32