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Active Learning Lecture Slides
For use with Classroom Response Systems
Chapter 4: Discrete Probability Distributions
Elementary Statistics:
Picturing the World
Fifth Edition
by Larson and Farber
© 2012 Pearson Education, Inc.
Slide 4- 1
True or false:
The number of kittens in a litter is an
example of a discrete random variable.
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 4- 2
True or false:
The number of kittens in a litter is an
example of a discrete random variable.
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 4- 3
Determine the probability distribution’s
missing probability value.
x
P(x)
0
1
2
3
0.25
0.30
?
0.10
A. 0.25
B. 0.65
C. 0.15
D. 0.35
© 2012 Pearson Education, Inc.
Slide 4- 4
Determine the probability distribution’s
missing probability value.
x
P(x)
0
1
2
3
0.25
0.30
?
0.10
A. 0.25
B. 0.65
C. 0.15
D. 0.35
© 2012 Pearson Education, Inc.
Slide 4- 5
Let x represent the number of televisions
in a household:
x
P(x)
0
1
2
3
0.05
0.20
0.45
0.30
Find the mean.
A. 2
B. 1.5
C. 6
D. 0.25
© 2012 Pearson Education, Inc.
Slide 4- 6
Let x represent the number of televisions
in a household:
x
P(x)
0
1
2
3
0.05
0.20
0.45
0.30
Find the mean.
A. 2
B. 1.5
C. 6
D. 0.25
© 2012 Pearson Education, Inc.
Slide 4- 7
Let x represent the number of televisions
in a household:
x
P(x)
0
1
2
3
0.05
0.20
0.45
0.30
Find the standard deviation.
A. 1.29
B. 0.837
C. 0.146
D. 1.12
© 2012 Pearson Education, Inc.
Slide 4- 8
Let x represent the number of televisions
in a household:
x
P(x)
0
1
2
3
0.05
0.20
0.45
0.30
Find the standard deviation.
A. 1.29
B. 0.837
C. 0.146
D. 1.12
© 2012 Pearson Education, Inc.
Slide 4- 9
Forty-three percent of marriages end in
divorce. You randomly select 15 married
couples. Find the probability exactly 5 of
the marriages will end in divorce.
A. 0.160
B. 0.015
C. 0.039
D. 0.333
© 2012 Pearson Education, Inc.
Slide 4- 10
Forty-three percent of marriages end in
divorce. You randomly select 15 married
couples. Find the probability exactly 5 of
the marriages will end in divorce.
A. 0.160
B. 0.015
C. 0.039
D. 0.333
© 2012 Pearson Education, Inc.
Slide 4- 11
Forty-three percent of marriages end in
divorce. You randomly select 15 married
couples. Find the mean number of
marriages that will end in divorce.
A. 2.15
B. 8.55
C. 6.45
D. 2.85
© 2012 Pearson Education, Inc.
Slide 4- 12
Forty-three percent of marriages end in
divorce. You randomly select 15 married
couples. Find the mean number of
marriages that will end in divorce.
A. 2.15
B. 8.55
C. 6.45
D. 2.85
© 2012 Pearson Education, Inc.
Slide 4- 13
Find the probability using the standard
normal distribution.
P(z < 1.49)
A. 0.9319
B. 0.0681
C. 0.6879
D. 0.3121
© 2012 Pearson Education, Inc.
Slide 5- 14
Find the probability using the standard
normal distribution.
P(z < 1.49)
A. 0.9319
B. 0.0681
C. 0.6879
D. 0.3121
© 2012 Pearson Education, Inc.
Slide 5- 15
Find the probability using the standard
normal distribution.
P(z ≥ –2.31)
A. 0.0104
B. 0.0087
C. 0.9896
D. 0.9913
© 2012 Pearson Education, Inc.
Slide 5- 16
Find the probability using the standard
normal distribution.
P(z ≥ –2.31)
A. 0.0104
B. 0.0087
C. 0.9896
D. 0.9913
© 2012 Pearson Education, Inc.
Slide 5- 17
Find the probability using the standard
normal distribution.
P(–2.14 < z < 0.95)
A. 0.1170
B. 0.0681
C. 0.1873
D. 0.8127
© 2012 Pearson Education, Inc.
Slide 5- 18
Find the probability using the standard
normal distribution.
P(–2.14 < z < 0.95)
A. 0.1170
B. 0.0681
C. 0.1873
D. 0.8127
© 2012 Pearson Education, Inc.
Slide 5- 19
IQ scores are normally distributed with a
mean of 100 and a standard deviation of
15. Find the probability a randomly
selected person has an IQ score greater
than 120.
A. 0.9082
B. 0.0918
C. 0.6293
D. 0.3707
© 2012 Pearson Education, Inc.
Slide 5- 20
IQ scores are normally distributed with a
mean of 100 and a standard deviation of
15. Find the probability a randomly
selected person has an IQ score greater
than 120.
A. 0.9082
B. 0.0918
C. 0.6293
D. 0.3707
© 2012 Pearson Education, Inc.
Slide 5- 21
IQ scores are normally distributed with a
mean of 100 and a standard deviation of
15. Find the probability a randomly
selected person has an IQ score between
100 and 120.
A. 0.9082
B. 0.0918
C. 0.4082
D. 0.5918
© 2012 Pearson Education, Inc.
Slide 5- 22
IQ scores are normally distributed with a
mean of 100 and a standard deviation of
15. Find the probability a randomly
selected person has an IQ score between
100 and 120.
A. 0.9082
B. 0.0918
C. 0.4082
D. 0.5918
© 2012 Pearson Education, Inc.
Slide 5- 23
Find the z-score that has 2.68% of the
distribution’s area to its right.
A. z = 0.9963
B. z = –1.93
C. z = –0.0037
D. z = 1.93
© 2012 Pearson Education, Inc.
Slide 5- 24
Find the z-score that has 2.68% of the
distribution’s area to its right.
A. z = 0.9963
B. z = –1.93
C. z = –0.0037
D. z = 1.93
© 2012 Pearson Education, Inc.
Slide 5- 25
IQ scores are normally distributed with a
mean of 100 and a standard deviation of
15. What IQ score represents the 98th
percentile?
A. 131
B. 69
C. 113
D. 145
© 2012 Pearson Education, Inc.
Slide 5- 26
IQ scores are normally distributed with a
mean of 100 and a standard deviation of
15. What IQ score represents the 98th
percentile?
A. 131
B. 69
C. 113
D. 145
© 2012 Pearson Education, Inc.
Slide 5- 27
American children watch an average of 25
hours of television per week with a
standard deviation of 8 hours. A random
sample of 40 children is selected. What is
the probability the mean number of hours
of television they watch per week is less
than 22?
A. 0.3520
B. 0.0089
C. 0.9911
D. 0.6480
© 2012 Pearson Education, Inc.
Slide 5- 28
American children watch an average of 25
hours of television per week with a
standard deviation of 8 hours. A random
sample of 40 children is selected. What is
the probability the mean number of hours
of television they watch per week is less
than 22?
A. 0.3520
B. 0.0089
C. 0.9911
D. 0.6480
© 2012 Pearson Education, Inc.
Slide 5- 29
Use a correction for continuity to convert
the following interval to a normal
distribution interval.
The probability of getting at least 80
successes
A. x > 80.5
B. x > 79.5
C. x < 80.5
D. x < 79.5
© 2012 Pearson Education, Inc.
Slide 5- 30
Use a correction for continuity to convert
the following interval to a normal
distribution interval.
The probability of getting at least 80
successes
A. x > 80.5
B. x > 79.5
C. x < 80.5
D. x < 79.5
© 2012 Pearson Education, Inc.
Slide 5- 31
A random sample of 42 textbooks has a
mean price of $114.50 and a standard
deviation of $12.30.
Find a point estimate for the mean price of
all textbooks.
A. $42
B. $12.30
C. $114.50
D. $2.73
© 2012 Pearson Education, Inc.
Slide 6- 32
Find the critical value zc necessary to form
a 98% confidence interval.
A. 2.33
B. 2.05
C. 0.5040
D. 0.8365
© 2012 Pearson Education, Inc.
Slide 6- 33
Find the critical value zc necessary to form
a 98% confidence interval.
A. 2.33
B. 2.05
C. 0.5040
D. 0.8365
© 2012 Pearson Education, Inc.
Slide 6- 34
A random sample of 42 textbooks has a
mean price of $114.50 and a standard
deviation of $12.30.
Find a 98% confidence interval for the
mean price of all textbooks.
A. (111.38, 117.62)
B. (110.08, 118.92)
C. (110.78, 118.22)
D. (109.61, 119.39)
© 2012 Pearson Education, Inc.
Slide 6- 35
A random sample of 42 textbooks has a
mean price of $114.50 and a standard
deviation of $12.30.
Find a 98% confidence interval for the
mean price of all textbooks.
A. (111.38, 117.62)
B. (110.08, 118.92)
C. (110.78, 118.22)
D. (109.61, 119.39)
© 2012 Pearson Education, Inc.
Slide 6- 36
Determine the minimum sample size needed
to construct a 95% confidence interval for the
mean age of employees at a company. The
estimate must be accurate to within 0.5 year.
Assume the standard deviation is 4.8 years.
A. 18
B. 19
C. 354
D. 355
© 2012 Pearson Education, Inc.
Slide 6- 37
Determine the minimum sample size needed
to construct a 95% confidence interval for the
mean age of employees at a company. The
estimate must be accurate to within 0.5 year.
Assume the standard deviation is 4.8 years.
A. 18
B. 19
C. 354
D. 355
© 2012 Pearson Education, Inc.
Slide 6- 38
Find the critical value tc necessary to form
a 95% confidence interval with a sample
size of 15.
A. 1.960
B. 2.145
C. 2.131
D. 2.120
© 2012 Pearson Education, Inc.
Slide 6- 39
Find the critical value tc necessary to form
a 95% confidence interval with a sample
size of 15.
A. 1.960
B. 2.145
C. 2.131
D. 2.120
© 2012 Pearson Education, Inc.
Slide 6- 40
A random sample of 15 DVD players has a
mean price of $64.30 and a standard
deviation of $5.60.
Find a 95% confidence interval for the
mean price of all DVD players.
A. (61.20, 67.40)
B. (61.47, 67.13)
C. (61.22, 67.38)
D. (61.10, 67.51)
© 2012 Pearson Education, Inc.
Slide 6- 41
A random sample of 15 DVD players has a
mean price of $64.30 and a standard
deviation of $5.60.
Find a 95% confidence interval for the
mean price of all DVD players.
A. (61.20, 67.40)
B. (61.47, 67.13)
C. (61.22, 67.38)
D. (61.10, 67.51)
© 2012 Pearson Education, Inc.
Slide 6- 42
In a survey of 250 Internet users, 195 have
high-speed Internet access at home.
Find a point estimate for the proportion of
all Internet users who have high-speed
Internet access at home.
A. 1.28
B. 0.78
C. 0.22
D. 195
© 2012 Pearson Education, Inc.
Slide 6- 43
In a survey of 250 Internet users, 195 have
high-speed Internet access at home.
Find a point estimate for the proportion of
all Internet users who have high-speed
Internet access at home.
A. 1.28
B. 0.78
C. 0.22
D. 195
© 2012 Pearson Education, Inc.
Slide 6- 44
In a survey of 250 Internet users, 195 have
high-speed Internet access at home.
Find a 90% confidence interval for the
proportion of all Internet users who have
high-speed Internet access at home.
A. (1.19, 1.38)
B. (0.728, 0.832)
C. (0.731, 0.829)
D. (0.737, 0.823)
© 2012 Pearson Education, Inc.
Slide 6- 45
In a survey of 250 Internet users, 195 have
high-speed Internet access at home.
Find a 90% confidence interval for the
proportion of all Internet users who have
high-speed Internet access at home.
A. (1.19, 1.38)
B. (0.728, 0.832)
C. (0.731, 0.829)
D. (0.737, 0.823)
© 2012 Pearson Education, Inc.
Slide 6- 46
You want to estimate, with 95% confidence,
the proportion of households with pets.
Your estimate must be accurate within 3%
of the population proportion. No
preliminary estimate is available. Find the
minimum sample size needed.
A. 1141
B. 3267
C. 1068
D. 1067
© 2012 Pearson Education, Inc.
Slide 6- 47
You want to estimate, with 95% confidence,
the proportion of households with pets.
Your estimate must be accurate within 3%
of the population proportion. No
preliminary estimate is available. Find the
minimum sample size needed.
A. 1141
B. 3267
C. 1068
D. 1067
© 2012 Pearson Education, Inc.
Slide 6- 48
State the null and alternative hypotheses.
A company claims the mean lifetime of its
AA batteries is more than 16 hours.
A. H0: μ > 16 Ha: μ ≤ 16
B. H0: μ < 16 Ha: μ ≥ 16
C. H0: μ ≤ 16 Ha: μ > 16
D. H0: μ ≥ 16 Ha: μ < 16
© 2012 Pearson Education, Inc.
Slide 7- 49
State the null and alternative hypotheses.
A company claims the mean lifetime of its
AA batteries is more than 16 hours.
A. H0: μ > 16 Ha: μ ≤ 16
B. H0: μ < 16 Ha: μ ≥ 16
C. H0: μ ≤ 16 Ha: μ > 16
D. H0: μ ≥ 16 Ha: μ < 16
© 2012 Pearson Education, Inc.
Slide 7- 50
State the null and alternative hypotheses.
A student claims the mean cost of a
textbook is at least $125.
A. H0: μ > 125 Ha: μ ≤ 125
B. H0: μ < 125 Ha: μ ≥ 125
C. H0: μ ≤ 125 Ha: μ > 125
D. H0: μ ≥ 125 Ha: μ < 125
© 2012 Pearson Education, Inc.
Slide 7- 51
State the null and alternative hypotheses.
A student claims the mean cost of a
textbook is at least $125.
A. H0: μ > 125 Ha: μ ≤ 125
B. H0: μ < 125 Ha: μ ≥ 125
C. H0: μ ≤ 125 Ha: μ > 125
D. H0: μ ≥ 125 Ha: μ < 125
© 2012 Pearson Education, Inc.
Slide 7- 52
True or false:
Testing the claim that at least 88% of
students have a cell phone would be a
right-tail test.
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 7- 53
True or false:
Testing the claim that at least 88% of
students have a cell phone would be a
right-tail test.
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 7- 54
You are testing the claim that the mean cost of a
new car is more than $25,200. How should you
interpret a decision that rejects the null
hypothesis?
A. There is enough evidence to reject the claim.
B. There is enough evidence to support the
claim.
C. There is not enough evidence to reject the
claim.
D. There is not enough evidence to support the
claim.
© 2012 Pearson Education, Inc.
Slide 7- 55
You are testing the claim that the mean cost of a
new car is more than $25,200. How should you
interpret a decision that rejects the null
hypothesis?
A. There is enough evidence to reject the claim.
B. There is enough evidence to support the
claim.
C. There is not enough evidence to reject the
claim.
D. There is not enough evidence to support the
claim.
© 2012 Pearson Education, Inc.
Slide 7- 56
True or false:
Given H0: μ = 40 Ha: μ ≠ 40 and P = 0.0436.
You would reject the null hypothesis at the
0.05 level of significance.
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 7- 57
True or false:
Given H0: μ = 40 Ha: μ ≠ 40 and P = 0.0436.
You would reject the null hypothesis at the
0.05 level of significance.
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 7- 58
Find the critical value, z0, for a left-tailed
test at the 0.10 level of significance.
A. z0 = –1.645
B. z0 = 1.645
C. z0 = –1.28
D. z0 = 1.28
© 2012 Pearson Education, Inc.
Slide 7- 59
Find the critical value, z0, for a left-tailed
test at the 0.10 level of significance.
A. z0 = –1.645
B. z0 = 1.645
C. z0 = –1.28
D. z0 = 1.28
© 2012 Pearson Education, Inc.
Slide 7- 60
Find the standardized test statistic z for the
following situation:
Claim: μ >15; x  13.6 s = 3.4
n = 40
A. z = 2.60
B. z = –2.60
C. z = –0.07
D. z = 12.90
© 2012 Pearson Education, Inc.
Slide 7- 61
Find the standardized test statistic z for the
following situation:
Claim: μ >15; x  13.6 s = 3.4
n = 40
A. z = 2.60
B. z = –2.60
C. z = –0.07
D. z = 12.90
© 2012 Pearson Education, Inc.
Slide 7- 62
Find the critical value(s), t0, for a two-tailed
test, α = 0.05, and n = 8.
A. –t0 = –1.96 and t0 = 1.96
B. –t0 = –2.306 and t0 = 2.306
C. –t0 = –1.895 and t0 = 1.895
D. –t0 = –2.365 and t0 = 2.365
© 2012 Pearson Education, Inc.
Slide 7- 63
Find the critical value(s), t0, for a two-tailed
test, α = 0.05, and n = 8.
A. –t0 = –1.96 and t0 = 1.96
B. –t0 = –2.306 and t0 = 2.306
C. –t0 = –1.895 and t0 = 1.895
D. –t0 = –2.365 and t0 = 2.365
© 2012 Pearson Education, Inc.
Slide 7- 64
How many 4-letter television call signs are
possible, if each sign must start with either
a K or a W?
A. 456,976
B. 35,152
C. 16
D. 104
© 2012 Pearson Education, Inc.
Slide 3- 65
How many 4-letter television call signs are
possible, if each sign must start with either
a K or a W?
A. 456,976
B. 35,152
C. 16
D. 104
© 2012 Pearson Education, Inc.
Slide 3- 66
The spinner shown is spun one time. Find
the probability the spinner lands on blue.
A. 0.375
B. 0.5
C. 0.125
D. 0.25
© 2012 Pearson Education, Inc.
Slide 3- 67
The spinner shown is spun one time. Find
the probability the spinner lands on blue.
A. 0.375
B. 0.5
C. 0.125
D. 0.25
© 2012 Pearson Education, Inc.
Slide 3- 68
The bar graph shows the cell phone provider
for students in a class. One of these students
is chosen at random. Find the probability
that their provider is not AT&T.
A. 0.3
B. 0.6
C. 0.125
D. 0.4
© 2012 Pearson Education, Inc.
Slide 3- 69
The bar graph shows the cell phone provider
for students in a class. One of these students
is chosen at random. Find the probability
that their provider is not AT&T.
A. 0.3
B. 0.6
C. 0.125
D. 0.4
© 2012 Pearson Education, Inc.
Slide 3- 70
One card is selected at random from a
standard deck, then replaced, and a second
card is drawn. Find the probability of
selecting two face cards.
A. 0.050
B. 0.053
C. 0.038
D. 0.462
© 2012 Pearson Education, Inc.
Slide 3- 71
One card is selected at random from a
standard deck, then replaced, and a second
card is drawn. Find the probability of
selecting two face cards.
A. 0.050
B. 0.053
C. 0.038
D. 0.462
© 2012 Pearson Education, Inc.
Slide 3- 72
One card is selected at random from a
standard deck, not replaced, and then a
second card is drawn. Find the probability of
selecting two face cards.
A. 0.050
B. 0.053
C. 0.446
D. 0.038
© 2012 Pearson Education, Inc.
Slide 3- 73
One card is selected at random from a
standard deck, not replaced, and then a
second card is drawn. Find the probability of
selecting two face cards.
A. 0.050
B. 0.053
C. 0.446
D. 0.038
© 2012 Pearson Education, Inc.
Slide 3- 74
The table shows the favorite pizza topping
for a sample of students. One of these
students is selected at random. Find the
probability the student is male, given that
they prefer pepperoni.
Cheese
A. 0.333
B. 0.6
Pepperoni Sausage Total
Male
8
5
2
15
Female
2
4
3
9
Total
10
9
5
24
C. 0.208
D. 0.556
© 2012 Pearson Education, Inc.
Slide 3- 75
The table shows the favorite pizza topping
for a sample of students. One of these
students is selected at random. Find the
probability the student is male, given that
they prefer pepperoni.
Cheese
A. 0.333
B. 0.6
Pepperoni Sausage Total
Male
8
5
2
15
Female
2
4
3
9
Total
10
9
5
24
C. 0.208
D. 0.556
© 2012 Pearson Education, Inc.
Slide 3- 76
True or False:
The following events are mutually exclusive.
Event A: Being born in California
Event B: Watching American Idol
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 3- 77
True or False:
The following events are mutually exclusive.
Event A: Being born in California
Event B: Watching American Idol
A. True
B. False
© 2012 Pearson Education, Inc.
Slide 3- 78
The table shows the favorite pizza topping
for a sample of students. One of these
students is selected at random. Find the
probability the student is female or prefers
sausage.
Cheese
A. 0.458
B. 0.583
Pepperoni Sausage Total
Male
8
5
2
15
Female
2
4
3
9
Total
10
9
5
24
C. 0.125
D. 0.556
© 2012 Pearson Education, Inc.
Slide 3- 79
The table shows the favorite pizza topping
for a sample of students. One of these
students is selected at random. Find the
probability the student is female or prefers
sausage.
Cheese
A. 0.458
B. 0.583
Pepperoni Sausage Total
Male
8
5
2
15
Female
2
4
3
9
Total
10
9
5
24
C. 0.125
D. 0.556
© 2012 Pearson Education, Inc.
Slide 3- 80
There are 15 dogs entered in a show. How
many ways can first, second, and third place
be awarded?
A. 45
B. 455
C. 2,730
D. 3,375
© 2012 Pearson Education, Inc.
Slide 3- 81
There are 15 dogs entered in a show. How
many ways can first, second, and third place
be awarded?
A. 45
B. 455
C. 2,730
D. 3,375
© 2012 Pearson Education, Inc.
Slide 3- 82
There are 13 students in a club. How many
ways can four students be selected to attend
a conference?
A. 17,160
B. 52
C. 28,561
D. 715
© 2012 Pearson Education, Inc.
Slide 3- 83
There are 13 students in a club. How many
ways can four students be selected to attend
a conference?
A. 17,160
B. 52
C. 28,561
D. 715
© 2012 Pearson Education, Inc.
Slide 3- 84
Find the class width:
A. 3
Class
1– 5
Frequency, f
21
6 – 10
11 – 15
16 – 20
16
28
13
B. 4
C. 5
D. 19
© 2012 Pearson Education, Inc.
Slide 2- 85
Find the class width:
A. 3
Class
1– 5
Frequency, f
21
6 – 10
11 – 15
16 – 20
16
28
13
B. 4
C. 5
D. 19
© 2012 Pearson Education, Inc.
Slide 2- 86
Estimate the frequency of the class with
the greatest frequency.
60
Ages of Concert Attendees
A. 28
B. 21
C. 58
D. 53
Frequency
50
40
30
20
10
0
18
28
38
48
58
Age
© 2012 Pearson Education, Inc.
Slide 2- 87
Estimate the frequency of the class with
the greatest frequency.
60
Ages of Concert Attendees
A. 28
B. 21
C. 58
D. 53
Frequency
50
40
30
20
10
0
18
28
38
48
58
Age
© 2012 Pearson Education, Inc.
Slide 2- 88
What is the maximum data entry?
Key: 3 | 8 = 38
A. 96
B. 38
C. 9
D. 41
3
4
5
6
7
8
9
8
0
1
3
0
2
1
9
2
1
3
0
2
1
7
4
3
1
3
4
8
8
1
4
5
© 2012 Pearson Education, Inc.
9 9
2 4 7 8 8 8 8 9
7 7 8 9 9
6
Slide 2- 89
What is the maximum data entry?
Key: 3 | 8 = 38
A. 96
B. 38
C. 9
D. 41
3
4
5
6
7
8
9
8
0
1
3
0
2
1
9
2
1
3
0
2
1
7
4
3
1
3
4
8
8
1
4
5
© 2012 Pearson Education, Inc.
9 9
2 4 7 8 8 8 8 9
7 7 8 9 9
6
Slide 2- 90
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the mean.
A. 78.5
B. 79
C. 474
D. 78
© 2012 Pearson Education, Inc.
Slide 2- 91
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the mean.
A. 78.5
B. 79
C. 474
D. 78
© 2012 Pearson Education, Inc.
Slide 2- 92
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the median.
A. 78.5
B. 79
C. 79.5
D. 78
© 2012 Pearson Education, Inc.
Slide 2- 93
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the median.
A. 78.5
B. 79
C. 79.5
D. 78
© 2012 Pearson Education, Inc.
Slide 2- 94
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the mode.
A. 78.5
B. 79
C. 79.5
D. 78
© 2012 Pearson Education, Inc.
Slide 2- 95
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the mode.
A. 78.5
B. 79
C. 79.5
D. 78
© 2012 Pearson Education, Inc.
Slide 2- 96
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the standard deviation.
A. 2.2
B. 6
C. 2
D. 4.8
© 2012 Pearson Education, Inc.
Slide 2- 97
The heights (in inches) of a sample of
basketball players are shown:
76
79
81
78
82
78
Find the standard deviation.
A. 2.2
B. 6
C. 2
D. 4.8
© 2012 Pearson Education, Inc.
Slide 2- 98
Determine the type of correlation between
the variables.
A. Positive linear correlation
B. Negative linear correlation
C. No linear correlation
© 2012 Pearson Education, Inc.
Slide 9- 99
Determine the type of correlation between
the variables.
A. Positive linear correlation
B. Negative linear correlation
C. No linear correlation
© 2012 Pearson Education, Inc.
Slide 9- 100
Calculate the correlation coefficient r, for
temperature (x) and number of cups of
coffee sold per hour (y).
x 65 60 55 50 45 40 35 30 25
y 8 10 11 13 12 16 19 22 23
A. 0.946
B. –0.973
C. –2.469
D. 81.760
© 2012 Pearson Education, Inc.
Slide 9- 101
Calculate the correlation coefficient r, for
temperature (x) and number of cups of
coffee sold per hour (y).
x 65 60 55 50 45 40 35 30 25
y 8 10 11 13 12 16 19 22 23
A. 0.946
B. –0.973
C. –2.469
D. 81.760
© 2012 Pearson Education, Inc.
Slide 9- 102
Find the t test statistic to determine if the
correlation coefficient for temperature (x)
and number of cups of coffee sold per hour
(y) is significant.
x 65 60 55 50 45 40 35 30 25
y 8 10 11 13 12 16 19 22 23
A. 10.8
B. –0.973
C. –11.1
D. –1.8
© 2012 Pearson Education, Inc.
Slide 9- 103
Find the t test statistic to determine if the
correlation coefficient for temperature (x)
and number of cups of coffee sold per hour
(y) is significant.
x 65 60 55 50 45 40 35 30 25
y 8 10 11 13 12 16 19 22 23
A. 10.8
B. –0.973
C. –11.1
D. –1.8
© 2012 Pearson Education, Inc.
Slide 9- 104
Find the equation of the regression line for
temperature (x) and number of cups of
coffee sold per hour (y).
x 65 60 55 50 45 40 35 30 25
y 8 10 11 13 12 16 19 22 23
A. yˆ  0.383 x  32.139
B. yˆ  2.469 x  81.760
C. yˆ  76.516x  16.381
D. yˆ  .4 x  33
© 2012 Pearson Education, Inc.
Slide 9- 105
Find the equation of the regression line for
temperature (x) and number of cups of
coffee sold per hour (y).
x 65 60 55 50 45 40 35 30 25
y 8 10 11 13 12 16 19 22 23
A. yˆ  0.383 x  32.139
B. yˆ  2.469 x  81.760
C. yˆ  76.516x  16.381
D. yˆ  .4 x  33
© 2012 Pearson Education, Inc.
Slide 9- 106
The equation of the regression line for
temperature (x) and number of cups of
coffee sold per hour (y) is
yˆ  0.383x  32.139
Predict the number of cups of coffee sold
per hour when the temperature is 48º.
A. 41.4
B. 30.7
C. 13.8
D. 50.5
© 2012 Pearson Education, Inc.
Slide 9- 107
The equation of the regression line for
temperature (x) and number of cups of
coffee sold per hour (y) is
yˆ  0.383x  32.139
Predict the number of cups of coffee sold
per hour when the temperature is 48º.
A. 41.4
B. 30.7
C. 13.8
D. 50.5
© 2012 Pearson Education, Inc.
Slide 9- 108
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